I am pretty new to MySQL, and am looking at a table (through a query) that has three date fields. However, they appear to be in seconds (but I could be wrong), but ultimately, I need to convert them to a valid date/time.
The numbers are:
1366272682
1366239600
1366272682
I think one of these dates is 18th April 2013.
Can someone let me know how I can convert them within the query (or indeed if I am right).
Thank you.
Those "numbers" are actually Unix Timestamps. Use FROM_UNIXTIME() to convert them into human friendly formats:
Returns a representation of the unix_timestamp argument as a value in 'YYYY-MM-DD HH:MM:SS' or YYYYMMDDHHMMSS.uuuuuu format, depending on whether the function is used in a string or numeric context.
For example:
SELECT FROM_UNIXTIME(1366272682, '%e%D %M %Y')
Related
Is there a way to convert a string such as "-1 week" or "-5 minutes" into a datetime value in MySQL similar to php's extremely convenient strtotime() function?
I have a table that stores a human-readable time interval (such as "2 minutes") in one column and a datetime in another column.
I would like to select the rows where more than the amount of time specified in interval has elapsed since datetime.
MySQL doesn't have an equivalent of PHP's strtotime() in the sense that there is nothing that will automatically attempt to parse and determine the format of a date string using by assuming multiple formats.
What it does have is STR_TO_DATE(str,format) which requires you specify the format of your date, time or date + time string. It is the equivalent of PHP's date_create_from_format(format, str) function (though the format of the format parameter are different).
Here are some examples given from the MySQL documentation. They show a date being passed along with the format string that lets it know how the date string is to be interpreted:
SELECT STR_TO_DATE('01,5,2013','%d,%m,%Y');
SELECT STR_TO_DATE('May 1, 2013','%M %d,%Y');
Alternatively, you can cast a string to a date, time or datetime type, but they require a specific format (YYYY-MM-DD hh:mm:ss.fraction) for it to work:
SELECT CAST("2019-11-21" AS DATE);
If you deviate too far from that format it will make a few assumptions but could produce an incorrect date.
I have a table that the data is a text in the format: 05/07/2019 (dd/mm/yyyy).
When I try to convert it to a date with
str_to_date(date_field,'%d/%m/%y')
I get the response in the format 2020-06-21 (yyyy-mm-dd). But the problem is that in the result all of the years are 2020 though this isn't the actual sitatuion.
Is there a way to solve this or do I need to recreate the DB with the date to be in date format?
If you are using the format dd/mm/yyyy you need to use capital Y
%Y Year as a numeric, 4-digit value
%y Year as a numeric, 2-digit value
So, in your case, you should use str_to_date(date_field,'%d/%m/%Y') because when you use y, it is taking only the first two digits for the year.
And, as I said in my comment (and Tim also said) if you are storing dates in a RDBMS, you should use ALWAYS proper date/datetime data types.
I want to get time from mysql dd/mm/YYYY H:M:S format.
I have tried,
SUBSTRING_INDEX(field, 'delimiter', index)
but am looking for a better solution.
have tried, DATE_FORMAT(field, "%H:%i:%s") but it returns NULL because my date format was not native (YYYY-mm-dd)
it was 02/05/2019 19:38:27
How to get time from this above format in a better way?
NOTE: I am storing date like above.. this fetching form SQL Server
I guess you can first use STR_TO_DATE followed by CAST(... AS time). Casting instead of formatting allows you to use the result in date/time calculations.
SELECT CAST(STR_TO_DATE('02/05/2019 19:38:27', "%d/%m/%Y %H:%i:%s") AS TIME)
Ideally you should teach SQL Server to export dates in yyyy-MM-dd hh:mm:ss format.
This is how i Resolved,
TIME(STR_TO_DATE(d.in_punch, "%d/%m/%Y %H:%i:%s"))
also as per #Salman A
CAST(STR_TO_DATE('02/05/2019 19:38:27', "%d/%m/%Y %H:%i:%s") AS TIME)
this also worked.
Hi I'm writing queries for MySQL, and now my database has a column containing the timestamp in this format: 7/14/2015 7:57:49 AM, but I need to use the DATEDIFF function, so how can I convert the timestamp into the format like: 2015-7-14 (or 2015-07-14, I'm not sure which one is correct; just the date)?
This should convert your string to just the date in a date format, then you can use DATEDIFF on the date fields in question:
SELECT STR_TO_DATE(LEFT(t,LOCATE(' ',t) - 1), '%m/%d/%Y') FROM my_table;
The LEFT function will take the substring to the left of the space, which is just your date, then STR_TO_DATE will convert that substring to a date the system can use.
(Not knowing your field and table names, I used t and my_table.)
You don't need to. The way MySQL displays timestamps has nothing to do with the way they're stored internally; as long as it's TYPE TIMESTAMP or some compatible type, the DATEDIFF() function will know what to do with it.
TIMESTAMPs are actually stored as a really huge integer representing (I think) milliseconds from Midnight UTC, January 1st, 1970. The display format is determined by a system global variable, and has nothing to do with the actual value.
Converting from a string to a DATETIME or TIMESTAMP is actually also fairly straightforward using the STR_TO_DATE() function; in your case the format string would be something like
STR_TO_DATE('%c/%e/%Y %l:%i:%s %p', datecol)
although you might have to experiment a bit to make it work reliably.
I have this query
SELECT *
FROM `users_profile`
WHERE DATE_FORMAT(dob,'%d-%m-%Y') BETWEEN '05-03-1996' AND '05-03-1915'
which should return two results which both have these dates in the dob column
08-02-1996
14-02-1996
But it dosen't return anthing!! What am I doing wrong!!??
Why would you take a perfectly good date and convert it to a (bad) string for comparison?
Do the comparison as dates and put the constants in the right order:
SELECT *
FROM `users_profile`
WHERE dob BETWEEN date('1915-03-05') and date('1996-03-05');
Also note that I changed the date format for the date constants to YYYY-MM-DD. This is the ISO standard format for dates. (Despite that), it is a really good idea to use.
I am assuming that dob really is a date, because that is what the function date_format() takes for its first argument.