I want to get every record from my MySQL database which is greater than today.
Sample:
"Go to Lunch","2014-05-08 12-00-00"
"Go to Bed","2014-05-08 23-00-00"
Output should only:
"Go to Bed","2014-05-08 23-00-00"
I use the DateTime for the Date Column
Already searched:
MySQL Where date is greater than one month?
Datetime equal or greater than today in MySQL
But this does not work for me.
QUERY(FOR PHP):
SELECT `name`,`date` FROM `tasks` WHERE `tasks`.`datum` >= DATE(NOW())
OR (FOR PhpMyAdmin)
SELECT `name`,`date` FROM `tasks` WHERE `tasks`.`datum` >= 2014-05-18 15-00-00;
How can I write the working query?
Remove the date() part
SELECT name, datum
FROM tasks
WHERE datum >= NOW()
and if you use a specific date, don't forget the quotes around it and use the proper format with :
SELECT name, datum
FROM tasks
WHERE datum >= '2014-05-18 15:00:00'
I guess you looking for CURDATE() or NOW() .
SELECT name, datum
FROM tasks
WHERE datum >= CURDATE()
LooK the rsult of NOW and CURDATE
NOW() CURDATE()
2008-11-11 12:45:34 2008-11-11
SELECT *
FROM customer
WHERE joiningdate >= NOW();
Related
I am trying to create a query to get the records for last two days. In my table there is a field called dates. Values are as below:
05-08-2018 08:05:22
05-08-2018 10:15:42
dd-mm-yyyy hh:ii:ss
I have created the query.
SELECT id,title,description, dates
FROM post_feed where `dates` BETWEEN CURDATE() - INTERVAL 1 DAY AND CURDATE()
ORDER BY dates DESC LIMIT 100
When I run the query it return 0 records. It looks like issue with date format.
Seems like your dates are stored as varchar. You must convert them to date (e.g. by using STR_TO_DATE) before you can perform any comparison.
Assuming for example that today is Aug-05 and you want results for Aug-04 and 05 (inclusive):
SELECT id, title, description, dates
FROM post_feed
WHERE STR_TO_DATE(dates, '%d-%m-%Y') BETWEEN CURRENT_DATE - INTERVAL 1 DAY AND CURRENT_DATE
ORDER BY dates DESC
LIMIT 100
SQL Fiddle
Try this WHERE clause:
WHERE STR_TO_DATE(dates, '%d-%m-%Y %H:%i:%s') BETWEEN DATE_ADD(CURDATE(), INTERVAL -2 DAY) AND CURDATE()
Your second date is before your first date. Put greater date at first place & put lesser date at second place.
SELECT id,title,description, dates
FROM post_feed where CAST(`dates`as date) BETWEEN CURDATE() AND CURDATE() - INTERVAL 1 DAY
ORDER BY dates DESC LIMIT 100
Fix your data! Your query doesn't work because the "date" value are stored as text/varchar. This is easily fixed:
update post_feed
set dates = str_to_date(date, '%Y-%m-%d %H:%i:%s')
alter table post_feed
modify column datetime;
Voila! Your queries will now work.
In my database, I have a column with a check-in date and a column with a check-out date. I need to select every row that has a check-in date <= 7/30/2017 and a check-out date that is >= 7/30/2017.
This is the code I have now:
SELECT *
FROM `v_reservation_records`
WHERE cast(checkin as date) <= '7/30/2017'
AND cast(checkout as date) >= '7/30/2017'
Here is an example date from the DB:
2018-09-18
When I run this query, I do not get any results, but I know that I have a check-in date equal to 7/30/2017. What am I missing? Or is there an easier way to accomplish my goal?
Assuming that you are casting valid values for date
You should convert also the literal the date properly
SELECT *
FROM `v_reservation_records`
WHERE cast(checkin as date) <= str_to_date('7/30/2017' , '%d/%m/%Y')
AND cast(checkout as date) >= str_to_date('7/30/2017' , '%d/%m/%Y')
and you can also use between
SELECT *
FROM `v_reservation_records`
WHERE str_to_date('7/30/2017','%d/%m/%Y')
between cast(checkin as date) AND cast(checkout as date)
Try like this
SELECT *
FROM `v_reservation_records`
WHERE DATE_FORMAT(checkin, '%m/%d/%Y') between '7/30/2017'
AND '7/30/2017'
I am using a SQL query like:
SELECT * FROM game_list
WHERE start_date <= DATE(NOW()) AND end_date >= DATE(NOW())
ORDER BY game_id DESC;
Now, what time will this actually start and end? I mean I know on what date but what will the time be, is it midnight, 12 am, pm or what?
If i understand correctly you want to show a game only if current time is between start time and end time,in that case what you need is actually:
SELECT * FROM game_list
WHERE DATE(NOW()) >= start_date AND DATE(NOW()) <= end_date
ORDER BY game_id DESC;
This way it should work properly
The only problem i could see is if you don't format your start_date and end_date correctly.
If your value is full time stamp,you should simply use NOW() or CURRENT_TIMESTAMP directly as it contains both date AND time
If your start_date is year month day eg: 2012-05-12 you should use CURDATE()
If your value is simply a day number,like 1...2...3...4..etc you should use DAY()
I would doublecheck what start_date returns and decide accordingly,for reference i would take a look here date and time in mysql
If you are asking how the DATE function works: it simply extracts the date part of a datetime.
see http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date
SELECT DATE('2003-12-31 01:02:03');
-> '2003-12-31
This represents simply that day. Considered as datetime again it would become midnight(2003-12-31 00:00:00)
I think you want something like following
SELECT * FROM game_list
WHERE start_date <= DATE(NOW()) AND end_date >= DATE_SUB(NOW(), INTERVAL 1 DAY)
ORDER BY game_id DESC;
Above query fetch the records which starts before today and having end date greater than tomorrow's date
My table is using a datetime (YYYY-MM-DD HH:MM:SS) and i need to display today's entries.
my code is only :
SELECT *
FROM table
WHERE date = '$date'
ORDER BY score DESC
with
$date = date("Y-m-d");
well, as expected it doesnt work :| you guys have a solution here ?
Following from Pascal Martin, you could extract the date part from the date+time field:
SELECT * FROM table WHERE DATE(date) = '2009-12-19'
Source: MySQL - Date and Time Functions
Be aware however, that this query will not use an index on your date+time field, if you will be having one. (Stack Overflow: How does one create an index on the date part of DATETIME field in MySql)
Your date is "2009-12-19" (or something like that, depending on the day), which is interpreted as "2009-12-19 00:00:00".
In your database, you probably don't have any date that's exactly equal to that one, by the second : your dates are like "2009-12-19 12:15:32".
A solution is to compare like this :
select *
from table
where date >= '2009-12-19'
and date < '2009-12-20'
Which will be interpreted as :
select *
from table
where date >= '2009-12-19 00:00:00'
and date < '2009-12-20 00:00:00'
And, if you don't want to do the math to get the date of the following date, you can use the adddate function :
select *
from table
where date >= '2009-12-19'
and date < adddate('2009-12-19', interval 1 day)
So, in your case, something like this should do the trick :
select *
from table
where date >= '$date'
and date < adddate('$date', interval 1 day)
order by score desc
You probably want to format the data when you select it:
SELECT *, DATE_FORMAT(date, '%Y-%m-%d') AS dateformat FROM table
WHERE dateformat = '$date' ORDER BY score DESC
You are comparing datetime and date expression, that is why its not working. Use Date() method to return the date part from datetime and then do the comparison. WHERE DATE(date) = '$date' should do. You might have to use aliases to handle this name collision.
How to select data from mysql table past date to current date? For example, Select data from 1 january 2009 until current date ??
My column "datetime" is in datetime date type. Please help, thanks
Edit:
If let say i want to get day per day data from 1 january 2009, how to write the query? Use count and between function?
select * from *table_name* where *datetime_column* between '01/01/2009' and curdate()
or using >= and <= :
select * from *table_name* where *datetime_column* >= '01/01/2009' and *datetime_column* <= curdate()
All the above works, and here is another way if you just want to number of days/time back rather a entering date
select * from *table_name* where *datetime_column* BETWEEN DATE_SUB(NOW(), INTERVAL 30 DAY) AND NOW()
You can use now() like:
Select data from tablename where datetime >= "01-01-2009 00:00:00" and datetime <= now();
Late answer, but the accepted answer didn't work for me.
If you set both start and end dates manually (not using curdate()), make sure to specify the hours, minutes and seconds (2019-12-02 23:59:59) on the end date or you won't get any results from that day, i.e.:
This WILL include records from 2019-12-02:
SELECT *SOMEFIELDS* FROM *YOURTABLE* where *YOURDATEFIELD* between '2019-12-01' and '2019-12-02 23:59:59'
This WON'T include records from 2019-12-02:
SELECT *SOMEFIELDS* FROM *YOURTABLE* where *YOURDATEFIELD* between '2019-12-01' and '2019-12-02'