Neural Network on Windows Phone 8.0 - windows-phone-8

Question

I am trying to write using aforge(neural network) framework on Windows Phone 8 application and I installed PCL version here.
I wrote below code:
Pivotpage.xaml.cs
_inputDataGelen = new double[4] { 0.067, 0.033, 0.057, 0.021 };
double compute = network.Compute(_inputDataGelen)[0]; // (1)
//MessageBox.Show("Output is "+ Math.Round(compute));
I am trying same code on desktop application and I am getting compute as 0.00112.. or 0.01283.., 0.02123.., 0.03231.., 0.04159... So if I round to one digit 0,1,2,3,4...
But when I tried on Windows Phone 8 project, I am getting compute like a 0.9999995345.
What is my problem.
Thanks in advance. (sorry my language.)

Answer 1

Desktop code:
ActivationNetwork network = null; //global variable
bool dongu = false;
...
...
network = new ActivationNetwork(
new BipolarSigmoidFunction(2), //activation func.
4, //input count
20, //hidden layer count
1); //output count
//Learning Network
BackPropagationLearning backprob = new BackPropagationLearning(network);
backprob.LearningRate = 0.1;
backprob.Momentum = 0.0;
int iteration = 1;
double hata = 0.0;
//loop
while(!dongu)
{
hata = backprob.RunEpoch(_inputData, _outputData);
iteration++;
if (iteration > 10000 || hata < 0.0001)
break;
}
double a1 = Convert.ToDouble(textBox3.Text);
double a2 = Convert.ToDouble(textBox4.Text);
double a3 = Convert.ToDouble(textBox5.Text);
double a4 = Convert.ToDouble(textBox6.Text);
//Actually devide 100. Not 1000.
double[] girdi = { a1/1000, a2/1000, a3/1000, a4/1000 }; //normalize
textBox1.Text = network.Compute(girdi)[0].ToString() + " compute"; //output ile aynı değer geliyor
double find = network.Output[0]*100; //denormalize
//textBox2.Text = (network.Output[0]).ToString() + " output"; //compute ile aynı değer geliyor
//tam sayıya yuvarlama
find = Math.Round(find,1);
if (find >= 0.0 && find <= 1.7) //bu aralık optimize edilebilir
{
//MessageBox.Show("Iris-setosa");
textBox7.Text = "1";
}
else if (find > 1.7 && find <= 2.6)
{
//MessageBox.Show("Iris-versicolor");
textBox7.Text = "2";
}
else if (find > 2.6 && find <= 3.7)
{
//MessageBox.Show("Iris-virginica");
textBox7.Text = "3";
}
Train set is here
#Anders Gustafsson, this code working on desktop. If I enter 5.1, 3.5, 1.4, 0.2 double numbers I am giving output is 1.