How to write MySQL query in CakePHP format? - mysql

Question

i have faced in a problem.
Can you please write this query in cakephp format
Table
id from_id to_id is_active message
--- ------- ----- --------- -------
1 1 8 1 Hello
2 8 1 1 Yes
3 1 8 1 How are you?
4 1 8 1 Are you with me?
Code :
<?php
$qry = mysql_query("SELECT * FROM messages WHERE (from_id='8' OR to_id='1') AND (from_id='1' OR to_id='8') AND id_active='1'"));
$res = mysql_fetch_array($qry);
?>
Edit
I have written but getting null value
my code:
$condition = array('OR'=>array('Message.from_id'=>1,'Message.to_id'=>8),'OR'=>array('Message.from_id'=>8,'Message.to_id'=>1),'Message.is_active'=>1);
$message=$this->Message->find("all",array('conditions'=>$condition));
pr($message);
Output:
array
(
)

Answer 1

Hi if you would like to list the conversation try out this:
$this->Message->find('all' ,
array(
'conditions'=>array(
'AND'=>array(
'OR'=>array(
array('AND'=>array('from_id'=>1, 'to_id'=>'8')),
array('AND'=>array('from_id'=>8, 'to_id'=>'1'))
),
'is_active'=>1
)
)
)
);
The good query is:
SELECT Message.id, Message.from_id, Message.to_id, Message.is_active, Message.message FROM c23dev1.messagess AS Message WHERE ((((((from_id = 1) AND (to_id = 8))) OR (((from_id = 8) AND (to_id = 1))))) AND (is_active = '1'))

Answer 2

I can recommend using Dogmatic69's converter. That gave this result for your query:
'conditions' => array(
array(
'or' => array(
'from_id' => '8',
'to_id' => '1',
),
),
'id_active' => '1',
),
I'm not sure what your original SQL query is actually trying to return, but if you want all messages between user 7 and user 8, your query should be something like:
SELECT *
FROM messages
WHERE ((from_id='7' AND to_id='8') OR (from_id='8' AND to_id='7'))
AND is_active='1';
Here's a SQLFiddle example.