How do I link a button to url, so that when the button is pressed, it opens a web browser and goes to specific URL? (Windows phone 8). using windows phone silverlight 8
It's super simple!
WebBrowserTask namewhatevz = new WebBrowserTask();
namewhatevz.Uri = new uri("http://google.se", UriKind.Absolute);
namewhatevz.Show();
Regards!
Bachir Bouchemla
Just register a Click event on your button and in the event handler use LaunchUri:
To do so, go to your .xaml and edit your Button.
<Button x:Name="LinkButton" Click="Button_Click" Content="Click here" />
Your Button LinkButton now executes code behind function Button_Click when you click it.
Place the following function to code behind xaml.cs.
private void Button_Click(object sender, RoutedEventArgs e)
{
await Launcher.LaunchUriAsync(new Uri("www.google.com"));
}
Related
i wanna provide share option from my windows app to another apps in my windows phone, like android develpement. please any one tell, is it possible in windows phone. (using RT, not in silver Light) Thank You in advance.
For example: like the below image
I am using below code using "How to use ShareLinkTask namespace in Windows Phone 8.1?" link.
protected override void OnNavigatedTo(NavigationEventArgs e)
{
DataTransferManager dtManager = DataTransferManager.GetForCurrentView();
dtManager.DataRequested += dtManager_DataRequested;
}
private async void dtManager_DataRequested(DataTransferManager sender, DataRequestedEventArgs e)
{
e.Request.Data.Properties.Title = "Code Samples";
e.Request.Data.Properties.Description = "Here are some great code samples for Windows Phone.";
e.Request.Data.SetWebLink(new Uri("http://code.msdn.com/wpapps"));
}
// Click Button to share Web Link
private void btnShareLink_Click(object sender, RoutedEventArgs e)
{
Windows.ApplicationModel.DataTransfer.DataTransferManager.ShowShareUI();
}
but it displays a progress bar with a message Preparing content to share and then it disappears, with no UI for sharing.
what should I do.please help me.
In Windows Phone 8 (or 8.1), is there a way to prevent a ContentDialog from closing when the primary button is pressed under certain conditions? For example, say you have a Boolean done. When they click the primary button, I only want the ContentDialog to close if (done == true). Is this possible?
XAML:
<ContentDialog
...
Closing="ContentDialog_Closing">
C#:
private async void ContentDialog_Closing(ContentDialog sender, ContentDialogClosingEventArgs args)
{
if (!CanClose)
args.Cancel = true;
}
I have to develop an app for Windows Phone 8. I want the user to be briefly notified without force him to face a Message Box (and consequently having to press a button to dismiss it). Are there any alternatives? I'm from Android and something similar to a Toast would be perfect. Also having the opportunity to change the text color would be nice.
Thank you in advance.
There are toasts in Windows Phone as well but AFAIR they can be used only when your app is in the background. But there is a solution: ToastPrompt class from Coding4Fun toolkit which is visually equal to toast notification.
See details:
https://stackoverflow.com/a/13981508/1985167
You can use ToastPrompt from Coding4Fun toolkit,
like this,
private void ToastWrapWithImgAndTitleClick(object sender, RoutedEventArgs e)
{
var toast = GetToastWithImgAndTitle();
toast.TextWrapping = TextWrapping.Wrap;
toast.Show();
}
private static ToastPrompt GetToastWithImgAndTitle()
{
return new ToastPrompt
{
Title = "With Image",
TextOrientation = System.Windows.Controls.Orientation.Vertical,
Message = LongText,
ImageSource = new BitmapImage(new Uri("../../ApplicationIcon.png", UriKind.RelativeOrAbsolute))
};
}
Using the new AutoSuggestBox control in Windows Phone 8.1 (WinRT XAML), I am trying to keep the suggestion box open all the time -- even after the user clicks a suggestion.
I have no problem starting with the suggestion box open by programmatically setting AutoSuggestBox.IsSuggestionListOpen = true;
Then I hook the SuggestionChosen event like this:
private void AutoSuggestBox_SuggestionChosen(AutoSuggestBox sender, AutoSuggestBoxSuggestionChosenEventArgs args) {
sender.Text = args.SelectedItem.ToString();
sender.IsSuggestionListOpen = true;
}
But unfortunately the suggestion box still closes after selecting an item, even though I set IsSuggestionListOpen to true.
Any help with getting it to stay open after a selection would be appreciated.
The solution I found to this is to hook the LayoutUpdated event.
I have the AutoSuggestBox in a PickerFlyout, so I only want the suggestion box open if the PickerFlyout is open (obviously). So I set a Tag property on the button that opens the PickerFlyout to identify if the PickerFlyout is open or closed. Then in the LayoutUpdated event of the AutoSuggestBox I set the IsSuggestionListOpen property to true if the PickerFlyout is open (and false if it's not).
The code:
private void PickerFlyout_Opened(object sender, object e) {
ActivatePickerFlyoutButton.Tag = "open";
}
private void PickerFlyout_Closed(object sender, object e) {
ActivatePickerFlyoutButton.Tag = "closed";
}
private void AutoSuggestBox_LayoutUpdated(object sender, object e) {
AutoSuggestBox.IsSuggestionListOpen = ((ActivatePickerFlyoutButton.Tag as string).Equals("open"));
}
That is the only place I need to set the IsSuggestionListOpen property, since the LayoutUpdated event fires at all the right times.
I have a PhoneApplicationPage with some grids, images and a few buttons. If I tap outside my buttons, anywhere in the page (on an image, grid or whatever), I want to open a new page.
How can I detect a tap/click anywhere on the page?
I see at least two ways to do that:
Listen to the MouseLeftButtonUp event on your PhoneApplicationPage. It should be triggered by images and labels but not by buttons
Listen to the Tap event on your PhoneApplicationPage. However, this event will be triggered even when the user tap on a button. To prevent this, you can retrieve the list of controls at the tap coordinates in the event handler, and open the new page only if there's no button:
private void PhoneApplicationPage_Tap(object sender, System.Windows.Input.GestureEventArgs e)
{
var element = (UIElement)sender;
var controls = VisualTreeHelper.FindElementsInHostCoordinates(e.GetPosition(element), element);
if(controls.OfType<Button>().Any())
{
return;
}
// Open the new page
}