I have a table with part numbers. sometimes people put xxx at the end of the part number when they want to include all of the different possible endings (a lot like the wildcard ### in Access). How do I write a query that will give me all of the part numbers and replace anything ending in xxx with ###?
So if my table has:
1234
1235-xxx
1236
How do I write a query that will give me:
1234
1235-###
1236
In Access, you can use the replace function to change some text into some other text: http://office.microsoft.com/en-ca/access-help/replace-function-HA001228898.aspx
Together with a select statement and the iif function to choose the exact rows that need the replacement, it's a fairly simple operation:
select
iif(
part_num like '*-xxx'
, replace(part_num, '-xxx', '-###')
, part_num
)
from my_table
Related
I have value in my db
like
1,12,13,25,44,414,2114
I have to find exact 14 from the db.
but it also return the value 414 and 2114
but i want exact 14.
How can i achieve this through sql query Please help
i have tried this but didn't worked.
Select * from tb_name where columnNAme like '%value%'
If you want search exactly 14, then you need search %,14,%, but 14 may appears at start or at end of string, so you need add commas to column also.
Well, you can use:
select * from tb_name where concat(',',columnNAme ,',') like '%,14,%'
Side note, comma separated values in one column is bad database design
Select * from tb_name where columnNAme like 'value'
% - The percent sign represents zero, one, or multiple characters
SELET * FROM database WHERE column LIKE 14 should work fine, just double checked it on my database.
If this doesn't work can you show your query please?
Above answer is correct, I didn't see your query before I posted this.
one of my table contains column path stores the URL example:\xyz\attachments, \abc\attachments, etc total i have 16 combinations to replace
i found rows by using rlike in where clause 'abc|xyz|'
have to update xyz with xxx or abc with yyyy
i am not sure how to update these part of the values of column. Is it possible using single query or i have to write 16 queries to do that? please advise here
This is not reliable, but is doable. Basically nested replace() calls:
UPDATE ...
SET yourfield = REPLACE(REPLACE(yourfield, '\\xyz', 'newtext'), '\\abc', 'othertext')
Note that if xyz or abc can appear in multiple places in either string, you may end up replacing something that shouldn't have been.
So here is a MySQL Query:
SELECT TestSite . * , LoggedCarts . *
FROM TestSite, LoggedCarts
WHERE TestSite.email = 'LoggedCarts.Bill-Email'
LIMIT 0 , 30
It is returning an empty result set, when it should be returning four results based on the tables below.
First Table: LoggedCarts - Column: Bill-Email
casedilla#hotmail.com
crazyandy#theholeintheground.com
Second Table: TestSite - Column: email
samuel#lipsum.com
taco#flavoredkisses.com
honeybadger#dontcare.com
casedilla#hotmail.com
messingwith#sasquatch.com
The goal is to get a MySQL statement that returns the rows in Table: TestSite that don't match the rows in Table: LoggedCarts.
Note: I understand that the use of a hyphen in a column name requires special care when constructing a query, involving backticks to tell MySQL there are special characters. I would change the column names to match up, however the Table: LoggedCarts has data fed via post from a Yahoo Shopping Cart and without heavy preparation before insertion setting the name to anything but the key sent in the post data is daunting.
However, if it turns out rebuilding the data prior to insertion is easier than using a JOIN statement or for some reason using two columns with different names as the comparison columns just doesn't work, I will go through and rebuild the database and PHP code.
Single quotes indicate a string literal. You need to use backticks for identifiers. Also, each component of an identifier must be quoted individually.
SELECT TestSite . * , LoggedCarts . *
FROM TestSite, LoggedCarts
WHERE TestSite.email = LoggedCarts.`Bill-Email`
LIMIT 0 , 30
From the manual:
If any components of a multiple-part name require quoting, quote them individually rather than quoting the name as a whole. For example, write `my-table`.`my-column`, not `my-table.my-column`.
With a bit of research inspired by somne of the hints given, I found the solution I was looking for here: SELECT * WHERE NOT EXISTS
Does exactly what I need it to do, and as a bonus, I like the shorthand syntax that is used that allows you to put in an alias for the table name and use the alias throughout the statement.
SELECT *
FROM TestSite e
WHERE NOT EXISTS
(
SELECT null
FROM LoggedCarts d
WHERE d.`Bill-Email` = e.email
)
Ok, so here is the issue.
I have a table with some columns and 'subject' is one of the columns.
I need to get the first 10 letters from the 'subject' field no matter the 'subject' field contains a string with 100 letters.
For example,
Table - tbl.
Columns - id, subject, value.
SQL Query:
SELECT subject FROM tbl WHERE id ='$id';
The result I am getting is, for example
Hello, this is my subject and how are you
I only require the first 10 characters
Hello, thi
I can understand that I can remove the rest of the characters using php substr() but that's not possible in my case. I need to get the excess characters removed by MySQL. How can this be done?
Using the below line
SELECT LEFT(subject , 10) FROM tbl
MySQL Doc.
SELECT SUBSTRING(subject, 1, 10) FROM tbl
Have a look at either Left or Substring if you need to chop it up even more.
Google and the MySQL docs are a good place to start - you'll usually not get such a warm response if you've not even tried to help yourself before asking a question.
I have this table under user_name='high'
function_description :
akram is in a date
test
akram is studying
test4
kheith is male
test3
I want a query that returns results of field that have at least an 'akram'
SELECT *
FROM functions
WHERE 'isEnabled'=1
AND 'isPrivate'=1
AND user_name='high'
AND function_description LIKE '%akram%'
and this returns absolutely nothing!
Why?
You are listing the column names as if they are strings. This is why it returns nothing.
Try this:
SELECT *
FROM functions
WHERE user_name='high'
AND function_description LIKE '%akram%'
edit: After trying to re-read your question... are isEnabled and isPrivate columns in this table?
edit2: updated.. remove those unknown columns.
You are comparing strings 'isEnabled' with integer 1, which likely leads to the integer being converted to a string, and the comparison then fails. (The alternative is that the string is converted to an integer 0 and the comparison still fails.)
In MySQL, you use back-quotes, not single quotes, to quote column and table names:
SELECT *
FROM `functions`
WHERE `isEnabled` = 1
AND `isPrivate` = 1
AND `user_name` = 'high'
AND `function_description` LIKE '%akram%'
In standard SQL, you use double quotes to create a 'delimited identifier'; in Microsoft SQL Server, you use square brackets around the names.
Please show the schema more carefully (column names, sample values, types if need be) next time.