In a MySQL database, I need to create a new closure table (called closure_new) that integrates a two column foreign key to another table, concept. This means adding rows to closure_new that are not in closure. How do I set up the SQL to accomplish this?
Here is my first attempt at the code for populating closure_new:
INSERT INTO `closure_new`
SELECT o.subtypeId, d.id, d.effectiveTime
FROM concept d
JOIN closure o
ON o.subtypeId = d.id;
Note that my first attempt only addresses subtypeId/subtype_effectiveTime and might not address it completely. The SQL also needs to incorporate supertypeId/supertype_effectiveTime. How do I write the SQL to populate the closure_new table with records for each of the effectiveTime values associated with each subtypeId and each supertypeId?
Here is the concept table:
CREATE TABLE `concept` (
`id` BIGINT NOT NULL DEFAULT 0,
`effectiveTime` VARCHAR(8) NOT NULL DEFAULT '',
`some other fields`,
PRIMARY KEY (`id`,`effectiveTime`)
) ENGINE=InnoDB;
Here is the old closure table:
CREATE TABLE `closure` (
`id` int(11) UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
`subtypeId` BIGINT(20) NOT NULL ,
`supertypeId` BIGINT(20) NOT NULL ,
PRIMARY KEY (`id`)
);
Here is the closure_new table that needs to be populated with the script I started to write above:
CREATE TABLE `closure_new` (
`id` int(11) UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
`subtypeId` BIGINT(20) NOT NULL ,
`subtype_effectiveTime` VARCHAR(8) NOT NULL DEFAULT '',
`supertypeId` BIGINT(20) NOT NULL ,
`supertype_effectiveTime` VARCHAR(8) NOT NULL DEFAULT '',
FOREIGN KEY (`supertypeId`, `supertype_effectiveTime`) references concept(`id`, `effectiveTime`),
FOREIGN KEY (`subtypeId`, `subtype_effectiveTime`) references concept(`id`, `effectiveTime`)
); ENGINE=InnoDB;
Try this:
insert into closure_new
(subtypeId, subtype_effectiveTime, supertypeId, supertype_effectiveTime)
select cl.id, co.effectiveTime, co.id, co.effectiveTime from closure cl inner join concept co
Your data better match or you will have some foreign key constraint issues
Not sure if I completely understand what you're after, but how about:
INSERT INTO `closure_new` (subtypeId, subtype_effectiveTime, supertypeId, supertype_effectiveTime)
SELECT subCon.id, subCon.effectiveTime, superCon.id, superCOn.effectiveTimed.effectiveTime
FROM closure o, concept subCon, concept superCon
where subcon.Id = o.subtypeId and supercon.Id = o.supertypeId
Or possibly, you could just create view with that select statement.
Related
I am creating an inventory management app in node.js that uses MySQL as a database. I have a weak entity “rental_item” that holds the items in a particualr rental. The issue is that the rental may not come back all at once so I need a way of marking the “rental_returned” boolean in the rental table true only when all of the “item_returned” entires are true.
Here is my table structure:
CREATE TABLE `rental` (
`rental_id` int NOT NULL AUTO_INCREMENT,
`renter_id` int NOT NULL,
`date_in` date NOT NULL,
`date_out` date NOT NULL,
`sig_path` varchar(50) NOT NULL,
`doc_path` varchar(50) NOT NULL,
`col_name` varchar(50) NOT NULL,
`col_path` varchar(50) NOT NULL,
`cost` decimal(15,2) NOT NULL,
`rental_returned` tinyint(1) NOT NULL DEFAULT '0',
PRIMARY KEY (`rental_id`),
UNIQUE KEY `doc_path` (`doc_path`),
UNIQUE KEY `col_path` (`col_path`),
UNIQUE KEY `sig_path` (`sig_path`),
KEY `renter_key` (`renter_id`),
CONSTRAINT `renter_key` FOREIGN KEY (`renter_id`) REFERENCES `renter` (`renter_id`)
)
CREATE TABLE `rental_item` (
`rental_id` int NOT NULL,
`i_ID` varchar(20) NOT NULL,
`item_returned` tinyint(1) NOT NULL DEFAULT '0',
KEY `rental_key` (`rental_id`),
KEY `rental_item_key` (`i_ID`),
CONSTRAINT `rental_item_key` FOREIGN KEY (`i_ID`) REFERENCES `item` (`i_ID`),
CONSTRAINT `rental_key` FOREIGN KEY (`rental_id`) REFERENCES `rental` (`rental_id`) ON DELETE CASCADE
)
I am currently doing this through the mysql2 node.js module and just checking for all the values of a given rental_id. I then found out about triggers and thought this way could be better. I fiddled round with things like this Trigger with table join, but couldn’t wrap my head around how to get the rental_id of the entry that was updated from rental_item, then check that all entires in rental_item with that id have item_returned = 1, and finally update the rental table to show that all the items/the complete rental has been returned.
I understand that this sould be an update after trigger on rental_item but dont know how to handle the conditionals or loops needed.
Use NEW.rental_id to get the ID of the row that was updated.
CREATE TRIGGER rental_returned AFTER UPDATE ON rental_item
FOR EACH ROW
UPDATE rental
SET rental_returned = (
NOT EXISTS (
SELECT *
FROM rental_item
WHERE rental_id = NEW.rental_id
AND item_returned = 0))
WHERE rental_id = NEW.rental_id
I want to get data just from only one specific user but I get data from both users. Why is that? I don't understand. How can I solve this?.
I have three tables:
/*User*/
CREATE TABLE `User` (
`IDUser` INT NOT NULL AUTO_INCREMENT,
`Name` VARCHAR(50) NOT NULL,
PRIMARY KEY (`IDUser`)
);
/*Category*/
CREATE TABLE `Category` (
`IDCategory` CHAR(3) NOT NULL,
`FK_User` INT NOT NULL,
`CategoryName` VARCHAR(40) NOT NULL,
PRIMARY KEY (`IDCategory`, `FK_User`)
);
/*Product*/
CREATE TABLE `Product` (
`IDProduct` VARCHAR(18) NOT NULL,
`FK_User` INT NOT NULL,
`ProductName` VARCHAR(150) NOT NULL,
`FK_Category` CHAR(3) NOT NULL,
PRIMARY KEY (`IDProduct`, `FK_User`)
);
ALTER TABLE `Product` ADD FOREIGN KEY (`FK_User`) REFERENCES `User`(`IDUser`);
ALTER TABLE `Product` ADD FOREIGN KEY (`FK_Category`) REFERENCES `Category`(`IDCategory`);
ALTER TABLE `Category` ADD FOREIGN KEY (`FK_User`) REFERENCES `User`(`IDUser`);
insert into User(Name) values('User1');
insert into User(Name) values('User2');
insert into Category(IDCategory,FK_User,CategoryName) values('CT1',1,'Category1User1');
insert into Category(IDCategory,FK_User,CategoryName) values('CT1',2,'Category1User2');
If two different users insert both the same product with the same ID:
insert into Product values('001',1,'shoe','CT1');
insert into Product values('001',2,'shoe','CT1');
Why do I keep getting data from both users if I try a query like this one:
SELECT P.IDProduct,P.ProductName,P.FK_Category,C.CategoryName
FROM Product P inner join Category C on P.FK_Category=C.IDCategory
WHERE P.FK_User=1
this is the result I get:
You are getting two rows because both categories have the same IDCategory value which is the value you are JOINing on. You need to also JOIN on the FK_User values so that you don't also get User2's category values:
SELECT P.IDProduct,P.ProductName,P.FK_Category,C.CategoryName
FROM Product P
INNER JOIN Category C ON P.FK_Category=C.IDCategory AND P.FK_User = C.FK_User
WHERE P.FK_User=1
You need to add p.FK_User=C.Fk_User this condition in your join clause
SELECT P.IDProduct,P.ProductName,P.FK_Category,C.CategoryName
FROM Product P inner join Category C
on P.FK_Category=C.IDCategory and p.FK_User=C.Fk_User
WHERE P.FK_User=1
A PRIMARY KEY is a UNIQUE key. Shouldn't CategoryID be unique? That is, shouldn't Category have PRIMARY KEY(CategoryId)?
(Check other tables for a similar problem.)
I've came across an issue and I cant think of a way to solve it.
I need to insert country names in several languages into a table on my mysql db.
I found these links link1 (en) , link2 (de) etc but I dont know how to proceed in order to finally have a table looking like this:
CREATE TABLE `country` (
`id` varchar(2) NOT NULL,
`en` varchar(64) NOT NULL,
`de` varchar(64) NOT NULL,
...
...
PRIMARY KEY (`id`)
) ENGINE=MYISAM DEFAULT CHARSET=utf8;
Well, I finally figured it out so I'm posting to maybe help others.
I created 2 tables (country_en) and (country_de) and then ran the following statement:
DROP table if exists `countries`;
CREATE TABLE `countries` (
id varchar(2), el varchar(100), de varchar(100)
);
INSERT INTO `countries`
SELECT country_en.id, el, de
FROM country_en
JOIN country_de ON (country_en.id = country_de.id);
which creates the table countries and joins the other 2 tables on their common key id
I can suggest you another table design. Create languages table, and modify a little country table: add lang_id field and create foreign key - FOREIGN KEY (lang_id)
REFERENCES languages (id). Then populate languages and country tables.
For example:
CREATE TABLE languages(
id VARCHAR(2) NOT NULL,
name VARCHAR(64) NOT NULL,
PRIMARY KEY (id)
) ENGINE = INNODB;
CREATE TABLE country(
id VARCHAR(2) NOT NULL,
lang_id VARCHAR(2) NOT NULL DEFAULT '',
name VARCHAR(64) NOT NULL,
PRIMARY KEY (id, lang_id),
CONSTRAINT FK_country_languages_id FOREIGN KEY (lang_id)
REFERENCES languages (id) ON DELETE RESTRICT ON UPDATE RESTRICT
)
ENGINE = INNODB;
-- Populate languages
INSERT INTO languages VALUES
('en', 'English'),
('de', 'German');
-- Populate names from 'en' table
INSERT INTO country SELECT id, 'en', name FROM country_en;
-- Populate names from 'de' table
INSERT INTO country SELECT id, 'de', name FROM country_de;
...Where country_en and country_deare tables from your links.
I have the following tables; which will be holding information about various types of articles.
I need some help with coming up with a proper schema for this.
Tables are:
CREATE TABLE IF NOT EXISTS `math_articles` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`title` char(250) NOT NULL,
`body` text,
PRIMARY KEY (`id`),
UNIQUE KEY `title` (`title`)
)
CREATE TABLE IF NOT EXISTS `news_articles` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`title` char(250) NOT NULL,
`body` text,
PRIMARY KEY (`id`),
UNIQUE KEY `title` (`title`)
)
CREATE TABLE IF NOT EXISTS `other_articles` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`title` char(250) NOT NULL,
`body` text,
PRIMARY KEY (`id`),
UNIQUE KEY `title` (`title`)
)
CREATE TABLE IF NOT EXISTS `references` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`article_from_table_name` text NOT NULL,
`from_id` int(11) NOT NULL,
`article_to_table_name` text NOT NULL,
`to_id` int(11) NOT NULL,
PRIMARY KEY (`id`)
)
inserting test data:
INSERT INTO `TEST`.`math_articles` (
`id` ,
`title` ,
`body`
)
VALUES (
NULL , 'fibonacci sequences', 'fib sequences are: 0,1,1,2,3,5...also see article Leonardo of Pisa'
);
Since this math_articles.title = 'fibonacci sequences' mentions that article 'Leonardo of Pisa' my program will insert in to other_articles table the following data:
INSERT INTO `TEST`.`other_articles` (
`id` ,
`title` ,
`body`
)
VALUES (
NULL , 'Leonardo of Pisa', 'Leonardo of Pisa also known as Leonardo of Pisa, Leonardo Pisano, Leonardo Bonacci, Leonardo Fibonacci, or, most commonly, simply Fibonacci, was.....'
);
The schema problem regarding table references
Since the table other_articles.title = 'Leonardo of Pisa' was referenced in the table math_articles.title = 'fibonacci sequences' i was to save this reference in the references table as follows:
not sure/problem insert into references table
INSERT INTO `TEST`.`references`
(`id`, `article_from_table_name`, `from_id`, `article_to_table_name`, `to_id`)
VALUES
(NULL, 'math_articles', '1', 'other_articles', '1');
Whats the best way of going about saving these references?
My issues with the references table schema!
The data type of the two columns article_from_table_name and article_to_table_name is text but they are actual tables in my database.
from_id and to_id should be forign keys of their prespective tables as
from_id = article_from_table_name.id and to_id = article_to_table_name.id
I don't know how to define this in the schema.
what if i delete the article math_articles.title = 'fibonacci sequences' then the references table to also be updated, I know I should use some sort of "ON DELETE CASCADE' trigger.
Regards
Your database design is causing most of your issues here. Your three articles tables, maths, news and other should all be the same table with a type column to distinguish between the different types. Then it will be straight forward to set up a references table that contains two foreign keys to the articles table, one for the source article and one for the reference article.
I usually manage referential integrity in the application itself rather than in the database layer so that all your business logic is in one place. So if you delete an article then any reference entries should be deleted by the application itself.
Hope that helps!
In class, we are all 'studying' databases, and everyone is using Access. Bored with this, I am trying to do what the rest of the class is doing, but with raw SQL commands with MySQL instead of using Access.
I have managed to create databases and tables, but now how do I make a relationship between two tables?
If I have my two tables like this:
CREATE TABLE accounts(
account_id INT NOT NULL AUTO_INCREMENT,
customer_id INT( 4 ) NOT NULL ,
account_type ENUM( 'savings', 'credit' ) NOT NULL,
balance FLOAT( 9 ) NOT NULL,
PRIMARY KEY ( account_id )
)
and
CREATE TABLE customers(
customer_id INT NOT NULL AUTO_INCREMENT,
name VARCHAR(20) NOT NULL,
address VARCHAR(20) NOT NULL,
city VARCHAR(20) NOT NULL,
state VARCHAR(20) NOT NULL,
PRIMARY KEY ( customer_id )
)
How do I create a 'relationship' between the two tables? I want each account to be 'assigned' one customer_id (to indicate who owns it).
If the tables are innodb you can create it like this:
CREATE TABLE accounts(
account_id INT NOT NULL AUTO_INCREMENT,
customer_id INT( 4 ) NOT NULL ,
account_type ENUM( 'savings', 'credit' ) NOT NULL,
balance FLOAT( 9 ) NOT NULL,
PRIMARY KEY ( account_id ),
FOREIGN KEY (customer_id) REFERENCES customers(customer_id)
) ENGINE=INNODB;
You have to specify that the tables are innodb because myisam engine doesn't support foreign key. Look here for more info.
as ehogue said, put this in your CREATE TABLE
FOREIGN KEY (customer_id) REFERENCES customers(customer_id)
alternatively, if you already have the table created, use an ALTER TABLE command:
ALTER TABLE `accounts`
ADD CONSTRAINT `FK_myKey` FOREIGN KEY (`customer_id`) REFERENCES `customers` (`customer_id`) ON DELETE CASCADE ON UPDATE CASCADE;
One good way to start learning these commands is using the MySQL GUI Tools, which give you a more "visual" interface for working with your database. The real benefit to that (over Access's method), is that after designing your table via the GUI, it shows you the SQL it's going to run, and hence you can learn from that.
CREATE TABLE accounts(
account_id INT NOT NULL AUTO_INCREMENT,
customer_id INT( 4 ) NOT NULL ,
account_type ENUM( 'savings', 'credit' ) NOT NULL,
balance FLOAT( 9 ) NOT NULL,
PRIMARY KEY ( account_id )
)
and
CREATE TABLE customers(
customer_id INT NOT NULL AUTO_INCREMENT,
name VARCHAR(20) NOT NULL,
address VARCHAR(20) NOT NULL,
city VARCHAR(20) NOT NULL,
state VARCHAR(20) NOT NULL,
)
How do I create a 'relationship' between the two tables? I want each account to be 'assigned' one customer_id (to indicate who owns it).
You have to ask yourself is this a 1 to 1 relationship or a 1 out of many relationship. That is, does every account have a customer and every customer have an account. Or will there be customers without accounts. Your question implies the latter.
If you want to have a strict 1 to 1 relationship, just merge the two tables.
CREATE TABLE customers(
customer_id INT NOT NULL AUTO_INCREMENT,
name VARCHAR(20) NOT NULL,
address VARCHAR(20) NOT NULL,
city VARCHAR(20) NOT NULL,
state VARCHAR(20) NOT NULL,
account_type ENUM( 'savings', 'credit' ) NOT NULL,
balance FLOAT( 9 ) NOT NULL,
)
In the other case, the correct way to create a relationship between two tables is to create a relationship table.
CREATE TABLE customersaccounts(
customer_id INT NOT NULL,
account_id INT NOT NULL,
PRIMARY KEY (customer_id, account_id),
FOREIGN KEY customer_id references customers (customer_id) on delete cascade,
FOREIGN KEY account_id references accounts (account_id) on delete cascade
}
Then if you have a customer_id and want the account info, you join on customersaccounts and accounts:
SELECT a.*
FROM customersaccounts ca
INNER JOIN accounts a ca.account_id=a.account_id
AND ca.customer_id=mycustomerid;
Because of indexing this will be blindingly quick.
You could also create a VIEW which gives you the effect of the combined customersaccounts table while keeping them separate
CREATE VIEW customeraccounts AS
SELECT a.*, c.* FROM customersaccounts ca
INNER JOIN accounts a ON ca.account_id=a.account_id
INNER JOIN customers c ON ca.customer_id=c.customer_id;
Adding onto the comment by ehogue, you should make the size of the keys on both tables match. Rather than
customer_id INT( 4 ) NOT NULL ,
make it
customer_id INT( 10 ) NOT NULL ,
and make sure your int column in the customers table is int(10) also.
Certain MySQL engines support foreign keys. For example, InnoDB can establish constraints based on foreign keys. If you try to delete an entry in one table that has dependents in another, the delete will fail.
If you are using a table type in MySQL, such as MyISAM, that doesn't support foreign keys, you don't link the tables anywhere except your diagrams and queries.
For example, in a query you link two tables in a select statement with a join:
SELECT a, b from table1 LEFT JOIN table2 USING (common_field);
Here are a couple of resources that will help get started: http://www.anchor.com.au/hosting/support/CreatingAQuickMySQLRelationalDatabase and http://code.tutsplus.com/articles/sql-for-beginners-part-3-database-relationships--net-8561
Also as others said, use a GUI - try downloading and installing Xampp (or Wamp) which run server-software (Apache and mySQL) on your computer.
Then when you navigate to //localhost in a browser, select PHPMyAdmin to start working with a mySQL database visually. As mentioned above, used innoDB to allow you to make relationships as you requested. Makes it heaps easier to see what you're doing with the database tables. Just remember to STOP Apache and mySQL services when finished - these can open up ports which can expose you to hacking/malicious threats.
One of the rules you have to know is that the table column you want to reference to has to be with the same data type as
The referencing table . 2 if you decide to use mysql you have to use InnoDB Engine because according to your question that’s the engine which supports what you want to achieve in mysql .
Bellow is the code try it though the first people to answer this question
they 100% provided great answers and please consider them all .
CREATE TABLE accounts(
account_id INT NOT NULL AUTO_INCREMENT,
customer_id INT( 4 ) NOT NULL ,
account_type ENUM( 'savings', 'credit' ) NOT NULL,
balance FLOAT( 9 ) NOT NULL,
PRIMARY KEY (account_id)
)ENGINE=InnoDB;
CREATE TABLE customers(
customer_id INT NOT NULL AUTO_INCREMENT,
name VARCHAR(20) NOT NULL,
address VARCHAR(20) NOT NULL,
city VARCHAR(20) NOT NULL,
state VARCHAR(20) NOT NULL,
PRIMARY KEY ( account_id ),
FOREIGN KEY (customer_id) REFERENCES customers(customer_id)
)ENGINE=InnoDB;
create table departement(
dep_id int primary key auto_increment,
dep_name varchar(100) not null,
dep_descriptin text,
dep_photo varchar(100) not null,
dep_video varchar(300) not null
);
create table newsfeeds(
news_id int primary key auto_increment,
news_title varchar(200) not null,
news_description text,
news_photo varchar(300) ,
news_date varchar(30) not null,
news_video varchar(300),
news_comment varchar(200),
news_departement int foreign key(dep_id) references departement(dep_id)
);