I've been trying to solve this without a post, but i can't find a fitting answer...
I have a SALE-Table and an APPOINTMENT-Table.
In both is a coloumn sale_id.
In APPOINTMENT is the column do_by(date) which can have several entries per sale_id.
What I need is the NEXT appointment PER matching sale_id.
Sth. like this:
appointment_id | sale_id | do_by
--------------------------------------
1365 | 160 | 27.05.2014
2546 | 173 | 29.05.2014
5483 | 265 | 01.06.2014
So far my Query only gives me the smallest do_by of ALL...
SELECT a.appointment_id, a.do_by, s.sale_id
FROM [Askus7].[CRM7].[APPOINTMENT] a, [Askus7].[CRM7].[SALE] s
WHERE (s.sale_id = a.sale_id) AND a.do_by =
(
SELECT MIN(a2.do_by)
FROM [Askus7].[CRM7].[APPOINTMENT] a2, [Askus7].[CRM7].[SALE] s2
WHERE s2.sale_id = a2.sale_id
AND s.sale_id = a.sale_id
)
Thx for your help!
Something like that? (untested)
SELECT a.appointment_id, ms.do_by, a.sale_id
(
SELECT a2.sale_id as sale_id, MIN(a2.do_by) as do_by
FROM [Askus7].[CRM7].[APPOINTMENT] a2 JOIN [Askus7].[CRM7].[SALE] s2
ON a2.sale_id=s2.sale_id
GROUP BY a2.sale_id
)ms
JOIN [Askus7].[CRM7].[APPOINTMENT] a
ON a.sale_id = ms.sale_id and a.do_by = ms.do_by;
warning: if you don't have do_by column indexed and your APPOINTMENT table is large, the query might be quite slow.
Related
I have two tables like this
rooms
id | number
1 | 111
2 | 112
occupied_rooms
id | check_in | check_out | room_id
1 | 2017-10-01 | 2017-10-04 | 1
I want to get all the unoccupied rooms according to date check_in and check_out for this I tried
select r.id
, r.number
from rooms r
left join occupied_rooms o
on r.id = o.room_id
where (o.check_in not between "2017-10-05" and "2017-10-08" )
or (o.check_in >= "2017-10-05" and o.check_out <= "2017-10-08"))
but this query giving me result like this. which is incorrect.
id | number
1 | 111
What is wrong with this query?
Thank you for your any help and suggestions
Just join the two tables on the condition that the id matches and the range of intended stay overlaps with the range in the occupied_rooms table.
SELECT r.*
FROM rooms r
LEFT JOIN occupied_rooms t
ON r.id = t.id AND
('2017-10-02' <= t.check_out AND '2017-10-03' >= t.check_in)
WHERE
t.id IS NULL; -- NULL value indicates the room did not overlap
-- with any existing reservations
You can also check out this great reference question on how to deal with overlapping ranges in SQL queries. It makes the problem you are facing much simpler.
Demo
Your data in table occupied_rooms meets the first condition in "where";
check_in date(2017-10-01) is not between "2017-10-05" and "2017-10-08" and your where is or.
Thus, the result is included this data.
Can you tell us what output you expect?
I have a table like this
itemid | propertyname | propertyvalue
___________|______________|_______________
1 | point | 12
1 | age | 10
2 | point | 15
2 | age | 11
3 | point | 9
3 | age | 10
4 | point | 13
4 | age | 11
I need a query to select all items where age greater than 10 and point less than 12.
I tried
`select itemid from table where (propertyname="point" and propertyvalue < 12)
and (propertyname="age" and propertyvalue >10)`
It gives no results. How can I make it work?
you can use an inner join
SELECT
a.itemid
FROM
yourTable a
INNER JOIN
yourTable b
ON
a.itemid=b.itemid
AND a.propertyname='point'
AND b.propertyname='age'
WHERE
a.propertyvalue<12
AND b.propertyvalue>10
ok so in table a youre lookin for all items with the name point and a value smaller 12 and in table b youre looking for all items with the name age and a value greater 10. Then you only have to look for items, which are in both tables. For this you connect the two tables over the itemid. To connect tables you use the join. Hope this will help you to understand. If not ask again :)
To join a table to itself in the same query you can include the table twice in the FROM clause, giving it a different alias each time. Then you simply proceed with building your query as if you were dealing with two separate tables that just happen to contain exactly the same data.
In the query below the table example is aliased as a and b:
SELECT a.itemid
FROM example a, example b
WHERE a.itemid = b.itemid
AND a.propertyname = 'point'
AND a.propertyvalue < 12
AND b.propertyname = 'age'
AND b.propertyname > 10
Try It:
SELECT itemid FROM test_table WHERE propertyname="point" AND propertyvalue < 12 AND itemid IN(SELECT itemid FROM test_table WHERE propertyname="age" AND propertyvalue >10)
http://sqlfiddle.com/#!9/4eafc6/1
PLs Try this
select itemid from table where (propertyname="point" and propertyvalue < 12)
or (propertyname="age" and propertyvalue >10);
Here's one idea...
SELECT item_id
, MAX(CASE WHEN propertyname = 'point' THEN propertyvalue END point
, MAX(CASE WHEN propertyname = 'age' THEN propertyvalue END age
FROM a_table
GROUP
BY item_id
HAVING age+0 > 10
AND point+0 < 12;
You can use an inner join. Meaning, it's like you're going to work with 2 tables: the first one you're going to select the name="age" and val>10, and the second one is where you're going to select name="point" and val<12.
It's like you're creating an instance of your table that doesn't really exist. It's just going to help you extract the data you need at the same time.
I'm stuck on this one. I have three tables:
Table 1:
**ORDERS**
| ORDER_NO | PRODUCT_NO | CLIENT_NO | UNITS | ORDER_DATE |
Table 2:
**CLIENTS**
| CLIENT_NO | NAME | LOCATION | SELLER_NO | OWES | OVERPAID | CREDIT_LIMIT |
Table 3:
**PRODUCTS**
| PRODUCT_NO | DESCRIPTION | UNIT_PRICE | AVAILABLE_STOCK |
Now, what I have to do is to update column OWES in table CLIENTS so it contains total amount of money of all the orders they made.
This is as far as I got:
update CLIENTS set OWES = (select sum(o.UNITS) from ORDERS o where CLIENTS.CLIENT_NO = o.CLIENT_NO);
That seems to work just fine to get a total number of orders, but than I have to multiply it by the price of given item (whichever the order was for) and I get myself confused.
I tried for example:
update CLIENTS set OWES = ( select sum(o.UNITS) from ORDERS o where CLIENTS.CLIENT_NO = o.CLIENT_NO)*(select UNIT_PRICE from PRODUCTS where PRODUCT_NO= any(select PRODUCT_NO from ORDERS));
But that returns ERROR 1242 (21000): Subquery returns more than 1 row
What am I doing wrong? Would it be better to use update CLIENTS as ( some complicated sub query goes here) ?
Can anyone help me out and be so kind to throw in some explanation why such solution and not some other? It just seem like I didn't get something on more basic level and now I'm struggling.
Thanks in advance.
I think you can just do a join in the subquery and do the appropriate aggregation:
update CLIENTS
set OWES = (select sum(o.UNITS * p.unit_price)
from ORDERS o join
products p
on o.product_no = p.product_no
where CLIENTS.CLIENT_NO = o.CLIENT_NO
);
Your syntax is a little off. The general syntax for updating from other tables is:
UPDATE table1
JOIN table2 ON table2.mycolumn = table1.mycolumn
JOIN (
SELECT foo, SUM(bar) as sumbar FROM table3) table3sum ON table3sum.foo = table1.foo
SET
table1.foo = table2.bar,
table1.baz = table3sum.sumbar
I'm having 2 tables. Table A contains a list of people who booked for an event, table B has a list of people the booker from table A brings with him/her. Both tables have many colums with unique data that I need to do certain calculations on in PHP , and as of now I do so by doing queries on the tables with a recursive PHP function to resolve it. I want to simplify the PHP and reduce the amount of queries that come from this recursive function by doing better MYSQL queries but I'm kind of stuck.
Because the table has way to many columns I will give an Excerpt of table A instead:
booking_id | A_customer | A_insurance
1 | 134 | 4
Excerpt of table B:
id | booking_id | B_insurance
1 | 1 | 0
2 | 1 | 1
3 | 1 | 1
4 | 1 | 3
The booking_id in table A is unique and set to auto increment, the booking_id in table b can occur many times (depending on how many guests the client from table A brings with him). Lets say I want to know every selected insurance from customer 134 and his guests, then I want the output like this:
booking_id | insurance
1 | 4
1 | 0
1 | 1
1 | 1
1 | 3
I have tried a couple of joins and this is the closest I've came yet, unfortunately this fails to show the row from A and only shows the matching rows in B.
SELECT a.booking_id,a.A_customer,a.A_insurance,b.booking_id,b.insurance FROM b INNER JOIN a ON (b.booking_id = a.booking_id) WHERE a.booking_id = 134
Can someone point me into the right direction ?
Please note: I have altered the table and column names for stackoverflow so it's easy for you guys to read, so it's possible that there is a typo that would break the query in it right now.
I think you need a union all for this:
select a.booking_id, a.insurance
from a
where a.a_customer = 134
union all
select b.booking_id, b.insurance
from a join
b
on a.booking_id = b.booking_id
where a.a_customer = 134;
The simplest way I can think of to achieve this is to use a UNION:
SELECT booking_id, A_insurance insurance
FROM A
WHERE booking_id = 134
UNION
SELECT booking_id, B_insurance insurance
FROM B
WHERE booking_id = 134
As my understanging of your isso is right, that should give you the result you need:
SELECT a.booking_id,a.insurance FROM a WHERE a.booking_id = 134
union
SELECT a.booking_id,b.insurance FROM b INNER JOIN a ON (b.booking_id = a.booking_id) WHERE a.booking_id = 134
I'm having a hard time wrapping my mind around this, any assistance is most appreciated.
I have two select statements with joins to 1 or more tables.
SELECT repinfo.repName, SUM(callstatssummary.CallsIn)
FROM repinfo
LEFT JOIN callstatssummary
ON repinfo.isaacID = callstatssummary.IsaacID AND callstatssummary.ShiftDate >= '2013-02-10' AND callstatssummary.ShiftDate <= '2013-02-16'
GROUP BY repinfo.repName;
The output of the first statement is a list of everyone in the repinfo table, with the sum of the total calls they took during the week. I used a left join to include people who didn't take calls in the result.
SELECT repinfo.repName, SUM(`1036`.afterRgu) - SUM(`1036`.priorRgu)
FROM repinfo
JOIN reporders
ON repinfo.repID = reporders.oRep
JOIN `1036`
ON reporders.workOrder = `1036`.workOrder AND `1036`.entryDate >= '2013-02-10' AND `1036`.entryDate <= '2013-02-16' AND `1036`.afterRgu >= `1036`.priorRgu
GROUP BY repinfo.repName;
The second statement outputs the number of products that each person sold during the week. The repinfo table has the information about the representative, which joins with the reporders table to match the work order. The 1036 table has detailed information about the orders.
I am looking to output something like this - essentially combine the output of the two select statements:
| repName | SUM(callstatssummary.CallsIn) | SUM(`1036`.afterRgu) - SUM(`1036`.priorRgu) |
______________________________________________________________________________________________
| Bruce W | 41 | 13 |
| Cathy M | 84 | 17 |
| Jonah S | NULL | 29 |
Any suggestions?
One way to combine those statements is to make each of them a derived-table / inline-view and join on repName.
Please note: Obviously you would want to join on a rep ID number (or whatever you call the primary key of the repinfo table) if two reps can have the same name.
select
r.repName, c.sumCallsIn, o.sumProdSold
from
repinfo r
left join (
SELECT repinfo.repName,
SUM(callstatssummary.CallsIn) sumCallsIn
FROM repinfo
LEFT JOIN callstatssummary
ON repinfo.isaacID = callstatssummary.IsaacID
AND callstatssummary.ShiftDate >= '2013-02-10'
AND callstatssummary.ShiftDate <= '2013-02-16'
GROUP BY repinfo.repName
) c
on c.repName = r.repName
left join (
SELECT repinfo.repName,
SUM(`1036`.afterRgu) - SUM(`1036`.priorRgu) sumProdSold
FROM repinfo
JOIN reporders
ON repinfo.repID = reporders.oRep
JOIN `1036`
ON reporders.workOrder = `1036`.workOrder
AND `1036`.entryDate >= '2013-02-10'
AND `1036`.entryDate <= '2013-02-16'
AND `1036`.afterRgu >= `1036`.priorRgu
GROUP BY repinfo.repName
) o
on r.repName = o.repName
order by r.repName;