I am looking to load all posts, sorted by newest first, but also limit them to three per user. I have no idea how to do that though! Here's the SQL I have currently to create the table and select the posts.
SELECT p.title, u.firstname, u.lastname
FROM post p
JOIN user u
ON p.user_id=u.id
ORDER
BY u.id, p.ctime DESC
#LIMIT TO 3 by user
;
This is what you can do
select
u.*,
p.*
from
user u
left join
(
select
p1.*
FROM
post p1
where
(
select
count(*)
from
post p2
WHERE
p1.user_id = p2.user_id
AND p1.id <= p2.id
) <= 3
order by p1.id desc
) p ON u.id = p.user_id
order by u.id
Took help from MySQL Limit LEFT JOIN Subquery after joining
Something like this might work
SELECT u.*,up.* FROM user u LEFT JOIN
(
SELECT `p`.`title`, `u`.`firstname`, `u`.`lastname`
FROM `post` `p`
ORDER
BY `p`.`ctime` DESC
LIMIT 3
)
up on up.user_id = u.id
Related
I have a Spring MVC blog with functionality for Post and Comment voting. I want to return the top 3 users based on number of votes they've received on all their posts and comments.
tables:
users u [id, username]
posts p [id, u.id]
comments c [id, p.id, u.id]
post_votes pv [p.id, u.id, type (1 or -1)]
comment_votes cv [c.id, u.id, type (1 or -1)]
The following statement gives me total votes per user by querying two separate voting tables and then adding the totals together:
SELECT
(SELECT SUM(type)
FROM posts_votes pv
JOIN posts p ON p.id = pv.post_id
JOIN users u ON u.id = p.user_id
WHERE u.id LIKE ?1)
+
(SELECT SUM(type)
FROM comments_votes cv
JOIN comments c ON c.id = cv.comment_id
JOIN users u ON u.id = c.user_id
WHERE u.id LIKE ?1)
That works fine with a WHERE clause per user id... But now I'm trying to find just the top 3 users that have the most votes and I'm having too much difficulty. This is what I have so far:
SELECT u.id, u.username, IFNULL(SUM(pv.type), 0) AS totalPostVotes
FROM posts_votes pv
JOIN posts p ON p.id = pv.post_id
JOIN users u ON u.id = p.user_id
GROUP BY u.id ORDER BY totalPostVotes DESC LIMIT 3
That above statement works by itself giving me: u.id, u.username, and totalPostVote in descending order. So does the one below for comments:
SELECT u.id, u.username, IFNULL(SUM(cv.type), 0) AS totalCommentVotes
FROM comment_votes cv
JOIN comments c ON c.id = cv.comment_id
JOIN users u ON u.id = c.user_id
GROUP BY u.id ORDER BY totalCommentVotes DESC LIMIT 3
Great! But I want that third column SUM result to be essentially "totalVotes" and contain the sum of both of those subqueries. Then I'll GROUP BY u.id ORDER BY totalVotes DESC LIMIT 3.
Something like this:
SELECT u.id, u.username, SUM(
(SELECT IFNULL(SUM(pv.type), 0) AS totalPostVotes
FROM posts_votes pv
JOIN posts p ON p.id = pv.post_id
JOIN users u ON u.id = p.user_id
GROUP BY u.id ORDER BY totalPostVotes DESC LIMIT 1)
+
(SELECT IFNULL(SUM(cv.type), 0) AS totalCommentVotes
FROM comments_votes cv
JOIN comments c ON c.id = cv.comment_id
JOIN users u ON u.id = c.user_id
GROUP BY u.id ORDER BY totalCommentVotes DESC LIMIT 1))
AS totalVotes from users u
GROUP BY u.id, u.username ORDER BY totalVotes DESC LIMIT 3
id | username | totalVotes
2 user2 11
1 user1 11
29 user29 11
What's happening is the result of totalVotes is indeed the correct vote count, 11, for the "top" user, but none of those users are the real top user, and the correct vote is being repeated 3 times in the guise of other users. I'm not even sure how users are being sorted at that point because they're not in an order I recognize.
The subqueries work separately (they give me the correct user) when I add SELECT "u.id, u.username " IFNULL(SUM()) but then if I run the whole block, I get the error "Operand should contain 1 column(s)" So I delete them and revert to only SELECT IFNULL(SUM())
I'm also noticing the subqueries are only allowed LIMIT 1. How would I get the top 3, then? Should I do a UNION somewhere or is "+" sufficient? This is rather confusing. Can someone please help me with this? Any help is appreciated. Thanks in advance!
Updated code, thank you Peter:
SELECT
u.username,
pv_sum.total AS postTotal,
cv_sum.total AS commentTotal,
IFNULL(pv_sum.total, 0) + IFNULL(cv_sum.total, 0) as totalVotes
FROM users u
LEFT JOIN (
SELECT p.user_id, IFNULL(SUM(pv.type), 0) AS total
FROM posts p
JOIN posts_votes pv ON pv.post_id = p.id
GROUP BY p.user_id
) pv_sum ON pv_sum.user_id = u.id
LEFT JOIN (
SELECT c.user_id, IFNULL(SUM(cv.type), 0) AS total
FROM comments c
JOIN comments_votes cv ON cv.comment_id = c.id
GROUP BY c.user_id
) cv_sum ON cv_sum.user_id = u.id
GROUP BY u.username, postTotal, commentTotal
ORDER BY totalVotes DESC LIMIT 3;
Don't place your subqueries in your SELECT-part, but join them on the users-table:
SELECT
u.username,
pv_sum.total AS postTotal,
cv_sum.total as commentTotal,
IFNULL(pv_sum.total, 0) + IFNULL(cv_sum.total, 0) as totalVotes
FROM users u
LEFT JOIN (
SELECT p.user_id, IFNULL(SUM(pv.type), 0) AS total
FROM posts p
JOIN post_votes pv ON pv.post_id = p.id
GROUP BY p.user_id
) pv_sum ON pv_sum.user_id = u.id
LEFT JOIN (
SELECT c.user_id, IFNULL(SUM(cv.type), 0) AS total
FROM comments c
JOIN comment_votes cv ON cv.comment_id = c.id
GROUP BY c.user_id
) cv_sum ON cv_sum.user_id = u.id
GROUP BY u.id
ORDER BY totalVotes DESC
LIMIT 3;
Fiddle: http://sqlfiddle.com/#!9/980cb2/11
What I want:
SELECT u.username, u.last_activity
FROM users_userprofile
WHERE u.id IN (
SELECT DISTINCT(p.user_id) FROM forums_post p
WHERE p.thread_id = 423993
ORDER BY p.created_at DESC
LIMIT 4
);
This doesn't work because of LIMIT in subquery. I want to keep order of subquery but I want to get username and last_activity instead of user_id.
Any suggestion how I could achieve this?
Replace the subquery with a view:
CREATE VIEW subv AS SELECT p.user_id FROM forums_post p
WHERE p.thread_id = 423993
ORDER BY p.created_at DESC
LIMIT 4;
SELECT u.username, u.last_activity
FROM users_userprofile
WHERE u.id IN (SELECT * FROM subv);
you could use join for the table and the subquery instead of using where in:
SELECT u.username, u.last_activity
FROM users_userprofile u
JOIN (
SELECT p.user_id FROM forums_post p
WHERE p.thread_id = 423993
ORDER BY p.created_at DESC
LIMIT 4
) q
on u.user_id=q.user_id
Why woldn't you do it with a JOIN? There seems to be no performance impact because WHERE and LIMIT clauses are the same. It won't JOIN the whole tables:
SELECT p.user_id, u.username, u.last_activity
FROM users_userprofile u
JOIN forums_post p ON p.user_id = u.id
WHERE p.thread_id = 423993
GROUP BY p.user_id ORDER BY MAX(p.created_at) DESC
LIMIT 4
I have a users table and a payments table, for each user, those of which have payments, may have multiple associated payments in the payments table. I would like to select all users who have payments, but only select their latest payment. I'm trying this SQL but i've never tried nested SQL statements before so I want to know what i'm doing wrong. Appreciate the help
SELECT u.*
FROM users AS u
INNER JOIN (
SELECT p.*
FROM payments AS p
ORDER BY date DESC
LIMIT 1
)
ON p.user_id = u.id
WHERE u.package = 1
You need to have a subquery to get their latest date per user ID.
SELECT u.*, p.*
FROM users u
INNER JOIN payments p
ON u.id = p.user_ID
INNER JOIN
(
SELECT user_ID, MAX(date) maxDate
FROM payments
GROUP BY user_ID
) b ON p.user_ID = b.user_ID AND
p.date = b.maxDate
WHERE u.package = 1
SELECT u.*, p.*
FROM users AS u
INNER JOIN payments AS p ON p.id = (
SELECT id
FROM payments AS p2
WHERE p2.user_id = u.id
ORDER BY date DESC
LIMIT 1
)
Or
SELECT u.*, p.*
FROM users AS u
INNER JOIN payments AS p ON p.user_id = u.id
WHERE NOT EXISTS (
SELECT 1
FROM payments AS p2
WHERE
p2.user_id = p.user_id AND
(p2.date > p.date OR (p2.date = p.date AND p2.id > p.id))
)
These solutions are better than the accepted answer because they work correctly when there are multiple payments with same user and date. You can try on SQL Fiddle.
SELECT u.*, p.*, max(p.date)
FROM payments p
JOIN users u ON u.id=p.user_id AND u.package = 1
GROUP BY u.id
ORDER BY p.date DESC
Check out this sqlfiddle
SELECT u.*
FROM users AS u
INNER JOIN (
SELECT p.*,
#num := if(#id = user_id, #num + 1, 1) as row_number,
#id := user_id as tmp
FROM payments AS p,
(SELECT #num := 0) x,
(SELECT #id := 0) y
ORDER BY p.user_id ASC, date DESC)
ON (p.user_id = u.id) and (p.row_number=1)
WHERE u.package = 1
You can try this:
SELECT u.*, p.*
FROM users AS u LEFT JOIN (
SELECT *, ROW_NUMBER() OVER(PARTITION BY userid ORDER BY [Date] DESC) AS RowNo
FROM payments
) AS p ON u.userid = p.userid AND p.RowNo=1
There are two problems with your query:
Every table and subquery needs a name, so you have to name the subquery INNER JOIN (SELECT ...) AS p ON ....
The subquery as you have it only returns one row period, but you actually want one row for each user. For that you need one query to get the max date and then self-join back to get the whole row.
Assuming there are no ties for payments.date, try:
SELECT u.*, p.*
FROM (
SELECT MAX(p.date) AS date, p.user_id
FROM payments AS p
GROUP BY p.user_id
) AS latestP
INNER JOIN users AS u ON latestP.user_id = u.id
INNER JOIN payments AS p ON p.user_id = u.id AND p.date = latestP.date
WHERE u.package = 1
#John Woo's answer helped me solve a similar problem. I've improved upon his answer by setting the correct ordering as well. This has worked for me:
SELECT a.*, c.*
FROM users a
INNER JOIN payments c
ON a.id = c.user_ID
INNER JOIN (
SELECT user_ID, MAX(date) as maxDate FROM
(
SELECT user_ID, date
FROM payments
ORDER BY date DESC
) d
GROUP BY user_ID
) b ON c.user_ID = b.user_ID AND
c.date = b.maxDate
WHERE a.package = 1
I'm not sure how efficient this is, though.
SELECT U.*, V.* FROM users AS U
INNER JOIN (SELECT *
FROM payments
WHERE id IN (
SELECT MAX(id)
FROM payments
GROUP BY user_id
)) AS V ON U.id = V.user_id
This will get it working
Matei Mihai given a simple and efficient solution but it will not work until put a MAX(date) in SELECT part so this query will become:
SELECT u.*, p.*, max(date)
FROM payments p
JOIN users u ON u.id=p.user_id AND u.package = 1
GROUP BY u.id
And order by will not make any difference in grouping but it can order the final result provided by group by. I tried it and it worked for me.
My answer directly inspired from #valex very usefull, if you need several cols in the ORDER BY clause.
SELECT u.*
FROM users AS u
INNER JOIN (
SELECT p.*,
#num := if(#id = user_id, #num + 1, 1) as row_number,
#id := user_id as tmp
FROM (SELECT * FROM payments ORDER BY p.user_id ASC, date DESC) AS p,
(SELECT #num := 0) x,
(SELECT #id := 0) y
)
ON (p.user_id = u.id) and (p.row_number=1)
WHERE u.package = 1
This is quite simple do The inner join and then group by user_id and use max aggregate function in payment_id assuming your table being user and payment query can be
SELECT user.id, max(payment.id)
FROM user INNER JOIN payment ON (user.id = payment.user_id)
GROUP BY user.id
If you do not have to return the payment from the query you can do this with distinct, like:
SELECT DISTINCT u.*
FROM users AS u
INNER JOIN payments AS p ON p.user_id = u.id
This will return only users which have at least one record associated in payment table (because of inner join), and if user have multiple payments, will be returned only once (because of distinct), but the payment itself won't be returned, if you need the payment to be returned from the query, you can use for example subquery as other proposed.
Been stuck with this fairly simple MySQL query for a day now! Can't believe how quickly I've forgotten the basics. I have 3 tables - user, post and favourite_post. The post table has a user_id that is a FK to user table.
The favourite_post table has
user_id REFERENCES user(id)
post_id REFERENCES post(id)
timestamp
When a user favourites a post, his user_id, the post_id and timestamp are inserted into the favourite_post table.
I use the following query to retrieve the 15 more recent posts
SELECT post.id, post.text, post.timestamp, post.user_id, user.username
FROM post
INNER JOIN user
ON post.user_id = user.id
ORDER BY post.id
DESC LIMIT 15;
What I need to do along with that is check if each post has been favourited by the current user(say user_id = 1) by joining with the favourite_post table.
SELECT p.id, p.text, p.timestamp, p.user_id, u.username,
IF(ISNULL(fp.post_id), 'No', 'Yes') has_favourite
FROM post p
INNER JOIN user u
ON p.user_id = u.id
LEFT JOIN favourite_post fp
ON p.id = fp.post_id
AND u.id = fp.user_id
ORDER BY p.id DESC
LIMIT 15;
Try this:
SELECT p.id, p.text, fp.timestamp, p.user_id, u.username
FROM post p INNER JOIN user u
ON p.user_id = u.id
LEFT JOIN favourite_post fp
ON fp.user_id = p.user_id AND fp.post_id = p.id
WHERE p.user_id = your_user_id
ORDER BY p.id DESC
LIMIT 15;
i have users table and i have posts table i want select from users the top users that have the big amount of posts from posts table and order them by numbers of posts
i can make it by array_count_values() by i cant order it
now i think if i make it by one mysql query by left and join will be more better
table structure
posts
id | auther_id
i tried this
SELECT COUNT(1) cnt, u.user_id
FROM users u
LEFT JOIN posts p
ON p.author_id=u.user_id
GROUP BY u.user_id
ORDER BY cnt DESC
LIMIT 20
it gave me this
alt text http://img511.imageshack.us/img511/6707/31154352.gif
see the arrow
what is this
i just have 2 posts under user_id 5
what is this first row
You need to aggregate the posts by user using GROUP BY u.user_id, get a COUNT value for the number of posts and ORDER BY that number, in descending order:
SELECT COUNT(1) cnt, u.user_id
FROM users u
LEFT JOIN posts p
ON p.author_id=u.user_id
GROUP BY u.user_id
ORDER BY cnt DESC
LIMIT 20
SELECT u.user_id, COUNT(*) as post_count
FROM users u
INNER JOIN posts p
USING (user_id)
GROUP BY u.user_id
ORDER BY post_count
i used this and its worked
is it true
SELECT COUNT( 1 ) cnt, a.auther_id
FROM `posts` a
LEFT JOIN users u ON a.auther_id = u.id
GROUP BY a.auther_id
ORDER BY cnt DESC
LIMIT 20