SQL statement returning in wrong format - mysql

I'm writing a query to return a post id and a timestamp in one object. I have the post ID and the timestamp returning, but the timestamp key is post_id, and it should be timestamp. Also, it's storing it as a individual item in the array, and I want it to be combined with the post_id. Here's my sql statement:
$meta_key = '_birs_client_id';
$meta_value = $client_id[0]->post_id;
$adjusted_time = strtotime("+1 day");
$timestamp_meta_key = '_birs_appointment_timestamp';
$sql = "SELECT post_id FROM wp_habitera_postmeta WHERE meta_key = %s AND meta_value = %d
UNION
SELECT meta_value FROM wp_habitera_postmeta WHERE meta_key = %s";
$appointments = $wpdb->get_results($wpdb->prepare($sql, $meta_key, $meta_value, $timestamp_meta_key));
Here's an example subset of my return from the sql statement:
[19] => stdClass Object
(
[post_id] => 996
)
[20] => stdClass Object
(
[post_id] => 999
)
[21] => stdClass Object
(
[post_id] => 1002
)
[22] => stdClass Object
(
[post_id] => 1398370500
)
[23] => stdClass Object
(
[post_id] => 1398284100
)
[24] => stdClass Object
(
[post_id] => 1398196800
)
This is the format I'm trying to get:
[18] => stdClass Object
(
[post_id] => 993
[timestamp] => 1398370500
)
Can someone tell me how to get it in this format?
EDIT
here's a picture of the database I'm working with that should help clarify:
http://i59.tinypic.com/10sgml3.png
the 2 rows I'm interested in are the timestamp and appointment id. The column before the timestamp column "1000" is the post id that matches up with the column after the post id column "1000" again.

EDIT > My last answer was rubbish, edited to try to give an answer to the question.
A UNION won't help you to solve the problem: all the values retrieved from the DDBB are concatenated, the first query will retrieve the values of the field post, and the second one the values of the timestamp, but with the UNION you're telling MySQL to put them together in the same field. What you'll need to do is JOIN the table with itself to get the values you want as different fields, but for that you need to establish the a relationship between the rows. I can't say what is that relationship without knowing the structure of your table and the data it has, but if you write that relation rule in the query below you'll have the query you want:
SELECT post_id, meta_value as timestamp
FROM wp_habitera_postmeta wphp1
INNER JOIN wp_habitera_postmeta wphp2
ON ( RELATION_RULE_BETWEEN_ROWS_ON_YOUR_TABLE )
WHERE meta_value = %d

Related

MySQL query with Doctrine 2 and different results

So here's the thing.
I'm querying the database using Doctrine 2.5 and I'd like to use Doctrine's createQuery() method to do it. The reason is that Doctrine 2 hydrates the results in a camelCase manner, and my column names are all with underscores. And since most of the simple queries work fine with createQuery (or even with the query builder) I'd like to move all native MySQL queries to Doctrine's DQL (to get all results in camelCase so that's a standarized results). Either that or you guys can teach me how to make Doctrine 2 return the results in the same way that the columns are in the database... xD
I have the following query:
$sql = '
SELECT sp.*, so.user_id
FROM shop_order so
INNER JOIN shop_payment sp ON(so.payment_id=sp.id)
WHERE so.id = '.$orderID;
$stmt = $em->getConnection()->prepare($sql);
$stmt->execute();
$result = $stmt->fetch();
This results in the following result:
Array
(
[id] => 14
[payment_type_id] => 2
[flag] => boleto_bb
[tid] =>
[billet] => 1
[parcel_quantity] =>
[cart_name_holder] =>
[cart_date_holder] => 1999-12-01
[cart_number_holder] => 0
[datecreated] => 2017-08-30 14:51:25
[dateupdate] => 2017-08-30 16:36:18
[status] => 2
[user_id] => 16
)
But if I do it like this:
$query = $em->createQuery('
SELECT sp, so.userId
FROM ShopOrder so
INNER JOIN ShopPayment sp WITH (so.paymentId = sp.id)
WHERE so.id = ' . $orderID);
$result = $query->getArrayResult();
I get the following result:
Array
(
[0] => Array
(
[0] => Array
(
[id] => 14
[paymentTypeId] => 2
[flag] => boleto_bb
[tid] =>
[billet] => 1
[parcelQuantity] =>
[cartNameHolder] =>
[cartDateHolder] => DateTime Object
(
[date] => 1999-12-01 00:00:00.000000
)
[cartNumberHolder] => 0
[datecreated] => DateTime Object
(
[date] => 2017-08-30 14:51:25.000000
)
[dateupdate] => DateTime Object
(
[date] => 2017-08-30 16:36:18.000000
)
[status] => 2
)
[userId] => 16
)
)
How can I get the first result from the createQuery method?

cakephp resultset for multiple joins and aggregate function...i.e. complex queries

I am using cakephp in one of my project. What i need is to handle complex query using single model and single array out.Since I am new to cakephp i got stucked really very bad here :
$rs = $this->User->query("
SELECT (wd.wajebaat_amt) as commited,
SUM(pd.sila_waje) as paid,
(wd.wajebaat_amt-sum(pd.sila_waje)) as balance,
FROM wajebaat_details as wd
LEFT JOIN waje_pay_details as pd ON (pd.waje_id=wd.waje_id)
WHERE wd.hof_id="123" and wd.year="2010"
GROUP BY wd.waje_id");
print_r($rs); exit();
// it displays output as
Array
(
[0] => Array
(
[wd] => Array
(
[commited] => 252000
)
[0] => Array
(
[paid] => 253829
[balance] => -1829
)
)
)
//however i need it following format
Array
(
[0] => Array
(
[wd] => Array
(
[commited] => 252000
[paid] => 200000
[balance] => 52000
)
)
)
You can use Hash (utility) method format() in cakephp 2.5 to convert the nested array into string,in previous version of cakephp the method is set(),
Hash::format(array $data, array $paths, $format)
Example :
$result = Hash::format($rs,array('{n}.wd.commited','{n}.wd.0.paid','{n}.wd.0.balance'),'%1$d,%2$d,%$d');
Output:
252000,2000000,52000
For More formating option refere cook book of cakephp

Properly joining tables without repeat data

I am trying to join tables to prevent too many database queries, but I don't like the way the data is returning.
The Query:
SELECT person.name, dog.dog_name FROM person JOIN dog ON person.id = dog.person_id
The return looks like this:
Array
(
[0] => Array
(
[name] => Jim
[dog_name] => Wolf
)
[1] => Array
(
[name] => Jim
[dog_name] => Frisky
)
[2] => Array
(
[name] => Tina
[dog_name] => Pokedot
)
[3] => Array
(
[name] => Tina
[dog_name] => Spiky
)
)
Is it possible to have the query instead return something like:
Array
(
[0] => Array
(
[name] => Jim
[dog_name] => array(Wolf, Frisky)
)
[1] => Array
(
[name] => Tina
[dog_name] => array(Pokedot, Spiky)
)
)
The closest solution is:
SELECT person.name, GROUP_CONCAT(dog.dog_name) AS dog_names
FROM person JOIN dog ON person.id = dog.person_id
GROUP BY person.id
This returns a string which is a comma-separated list of dog names, not a PHP array. You'll have to explode() that string in application code.
Note that the default length limit for GROUP_CONCAT() is 1024 characters, and it is controlled by the configuration option group_concat_max_len.
I agree with the comment from #KonstantinWeitz, it's worthwhile to let the RDBMS do what it's best at, and then use PHP code to post-process the results into a format you want.
For example, here's how I'd do it to return the array you described:
$peoplesdogs = array();
$stmt = $pdo->query("SELECT person.name, dog.dog_name FROM person JOIN dog ON person.id = dog.person_id");
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
$peoplesdogs[$row["name"]]["name"] = $row["name"];
$peoplesdogs[$row["name"]]["dog_name"][] = $row["dog_name"];
}
return array_values($peoplesdogs);

CakePHP has and belongs to many conditions with NOT EXISTS

$conditions = Array
(
[table] => products_pages
[alias] => ProductsPage
[type] => inner
[foreignKey] =>
[conditions] => Array
(
[0] => ProductsPage.product_id = Product.id
)
)
I'm trying to set up NOT EXISTS conditions, like the following SQL statement:
SELECT * FROM products_pages,products
WHERE NOT EXISTS (SELECT id
from products_pages
where products_pages.product_id = products.id)
So basically select any product that doesn't exist in the products_pages table.
What is the proper way to format that SQL statement for CakePHP and replace it here:
[conditions] => Array
(
[0] => (What's the proper way to insert above SQL here?
)
Would really appreciate your help guys, I've been trying to figure this out for about 5 hours with no luck. Thanks!
You can always use query if you don't find the way to do it with CakePHP:
http://book.cakephp.org/2.0/en/models/retrieving-your-data.html#model-query
In this case security wouldn't be compromised as you are not using any input.
Anyway, something simple would be just to do it in more than one step:
//selecting the products in the productcs_pages table
$productsWithPages = /* query to get them*/
//getting an array of IDs
$productsWidthPagesIds = Hash::extract($productsWithPages, '{n}.Product.id');
//doing the NOT IN to select products without pages
$productsWithoutPages= $this->Product->find('all',
array('conditions' =>
array( 'NOT' => array('Product.id' => $productsWidthPagesIds )
)
);

mysql if condition in query can't get tablename from mysql_field_table

This query works:
SELECT Article.id,
Article.post_time,
Article.post_locked,
Article.comments_locked, Article.title,
IF(CHAR_LENGTH(Article.content)>2000,
RPAD(LEFT(Article.content,2000),2003,'.'),
Article.content) as content,
Article.tags, Category.*,
User.id, User.user_name,
Comment.comment_count
FROM `articles` as `Article`
LEFT JOIN `categories` as `Category` ON `Article`.`category_id` = `Category`.`id`
LEFT JOIN `users` as `User` ON `Article`.`user_id` = `User`.`id`
LEFT OUTER JOIN (SELECT article_id, count(*) comment_count FROM `comments`) as `Comment` ON `Article`.id = `Comment`.article_id
WHERE '1'='1'
ORDER BY `Article`.`id` DESC
But when I loop through the resultset to assign the table name along with the field using 'mysql_field_table', the 'content' returns a table name of nothing, while all others have their correct table:
Array (
[0] => Article
[1] => Article
[2] => Article
[3] => Article
[4] => Article
[5] =>
[6] => Article
[7] => Category
[8] => Category
[9] => User
[10] => User
[11] => Comment )
using
for ($i = 0; $i < $numOfFields; ++$i) {
array_push($table,mysql_field_table($this->_result, $i));
array_push($field,mysql_field_name($this->_result, $i));
}
Anyone ever try to do this? Have a solution? I want to return less data from my DB in my query. Or is it less intensive (on mysql, memory, cpu) to simply select all content and truncate the content via PHP? I thought returning less from DB would be better.
Thanks a bunch!!
Peace.
EDIT
to clear up, this is the result, you will see why it isnt what I want:
Array (
[0] => Array (
[Article] => Array (
[id] => 8
[post_time] => 1278606312
[post_locked] => 0
[comments_locked] => 0
[title] => Article 8
[tags] => test )
[] => Array (
[content] => my content for Article )
[Category] => Array (
[id] => 2
[name] => cat2 )
[User] => Array (
[id] => 3
[user_name] => user3 )
[Comment] => Array (
[comment_count] => 1 )
)
[1] => Array (
[Article] => Array (
[id] => 7
etc...
In order to use characters beyond the English alphabet and spaces in a column alias, the standard SQL means requires using double quotes (though MySQL supports using backticks IE: "`" too):
...,
IF(CHAR_LENGTH(Article.content)>2000,
RPAD(LEFT(Article.content,2000),2003,'.'),
Article.content) AS "Article.content",
...
no you cant use a as [tablename].[columnname]-like format for custom column names.
It would be weird anyway if it would work, because how can content be defined as 'Article.content' if it's not really part of the Article table dataset.
Just select the columns you need and join where needed.
But what's WHERE '1' = '1' doing in there? that will just evaluate to true as it is a boolean expression, but it won't affect your resultset.
But when I loop through the resultset
to assign the table name along with
the field using 'mysql_field_table',
the 'content' returns a table name of
nothing, while all others have their
correct table
Once you've done that magic on Article.content, to create the content field, it no longer belongs to the Article table. Rather, it belongs to the result set of that query. I believe that's the explanation for having no table associated with that field.
Imagine a GROUP BY query, with something like COUNT(*) as number. 'number' doesn't belong to any table.
If you really need the ability to know that the column had a particular source, could you have a view on top of Article which does this manipulation to content? Then the source would appear to be the view? Unfortunately, MySQL doesn't support declared computed columns in tables, that might also be useful to you in this case.
while ($row = mysql_fetch_row($this->_result)) {
$prev_table;
for ($i = 0;$i < $numOfFields; ++$i) {
if ($table[$i] == "") {
$tempResults[$prev_table][$field[$i]] = $row[$i];
}else {
$tempResults[$table[$i]][$field[$i]] = $row[$i];
}
$prev_table = $table[$i];
}
}
Oh well, mysql couldnt do what I wanted. I added the prev_table to take the one before ;)
Thanks to everyone for the help.