I want to calculate total and unique clickouts based on country,partner and retailer.
I have achieved the desired result but i think its not a optimal solution and for longer data sets it will take longer time. how can I improve this query?
here is my test table, designed query and expected output:
"country_id","partner","retailer","id_customer","id_clickout"
"1","A","B","100","XX"
"1","A","B","100","XX"
"2","A","B","100","XX"
"2","A","B","100","GG"
"2","A","B","100","XX"
"2","A","B","101","XX"
DROP TABLE IF EXISTS x;
CREATE TEMPORARY TABLE x AS
SELECT test1.country_id, test1.partner,test1.retailer, test1.id_customer,
SUM(CASE WHEN test1.id_clickout IS NULL THEN 0 ELSE 1 END) AS clicks,
CASE WHEN test1.id_clickout IS NULL THEN 0 ELSE 1 END AS unique_clicks
FROM test1
GROUP BY 1,2,3,4
;
SELECT country_id,partner,retailer, SUM(clicks), SUM(unique_clicks)
FROM x
GROUP BY 1,2,3
Output:
"country_id","partner","retailer","SUM(clicks)","SUM(unique_clicks)"
"1","A","B","2","1"
"2","A","B","4","2"
And here is DDL and input data:
CREATE TABLE test (
country_id INT(11) DEFAULT NULL,
partner VARCHAR(256) CHARACTER SET utf8 DEFAULT NULL,
retailer VARCHAR(256) CHARACTER SET utf8 DEFAULT NULL,
id_customer BIGINT(20) DEFAULT NULL,
id_clickout VARCHAR(256) CHARACTER SET utf8 DEFAULT NULL)
ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO test VALUES(1,'A','B','100','XX'),(1,'A','B','100','XX'),
(2,'A','B','100','XX'),(2,'A','B','100','GG'),
(2,'A','B','100','XX'),(2,'A','B','101','xx')
SELECT
country_id,
partner,
retailer,
COUNT(id_clickout) AS clicks,
COUNT(DISTINCT CASE WHEN id_clickout IS NOT NULL THEN id_customer END) AS unique_clicks
FROM
test1
GROUP BY
1,2,3
;
COUNT(a_field) won't count any NULL values.
So, COUNT(id_clickout) will only count the number of times that it is NOT NULL.
Equally, the CASE WHEN statement in the unique_clicks only returns the id_customer for records where they clicked, otherwise it returns NULL. This means that the COUNT(DISTINCT CASE) only counts distinct customers, and only when they clicked.
EDIT :
I just realised, it's potentially even simpler than that...
SELECT
country_id,
partner,
retailer,
COUNT(*) AS clicks,
COUNT(DISTINCT id_customer) AS unique_clicks
FROM
test1
WHERe
id_clickout IS NOT NULL
GROUP BY
1,2,3
;
The only material difference in the results will be that any country_id, partner, retailed that previously showed up with 0 clicks will now not appear in the results at all.
With an INDEX on country_id, partner, retailed, id_clickout, id_customer or country_id, partner, retailed, id_customer, id_clickout, however, this query should be significantly faster.
I think this is what you are after:
SELECT country_id,partner,retailer,COUNT(retailer) as `sum(clicks)`,count(distinct id_clickout) as `SUM(unique_clicks)`
FROM test1
GROUP BY country_id,partner,retailer
Result:
COUNTRY_ID PARTNER RETAILER SUM(CLICKS) SUM(UNIQUE_CLICKS)
1 A B 2 1
2 A B 4 2
See result in SQL Fiddle.
Related
goal id total occurance of goal id total occurance when status is 1
1 5 3
This is schema of the table
CREATE TABLE `goal_objectives` (
`objective_id` int(11) NOT NULL ,
`objective_name` varchar(255) NOT NULL,
`objective_description` tinytext NOT NULL,
`goal_id` int(11) NOT NULL,
`objective_status` tinyint(4) NOT NULL
);
select goal_id, count(objective_status)as objective_done
from goal_objectives
where objective_status='1' group by goal_id;
select goal_id,count(goal_id) as total_current_goals
from goal_objectives
group by goal_id
order by goal_id DESC ;
I just want to show the combine result of these two queries.
Individually it returns required result but when i try to merge them is does not work
See the output in the link below:
https://i.imgur.com/6Rnac89.png
Use conditional aggregation:
select goal_id, count(*) as total_current_goals,
sum( objective_status = 1 ) as objective_done
from goal_objectives
group by goal_id
order by goal_id desc ;
Note that objective_status is a number. The comparison value should be a number, not a string.
I have a table that contains transaction data. The rows with the same 'group_id' are a part of the same transaction. I am running the following SQL query to show all the transactions:
SELECT * FROM transactions
When I run this query I get as expected a list of all the transactions. But this large list makes it difficult to seperate the data with a different group_id from the other data.
For that reason I want to add an empty row at the end of the group_id, so I get:
1
1
(empty row)
2
2
2
instead of:
1
1
2
2
2
Can someone help me with this?
Here is my database:
http://sqlfiddle.com/#!9/b9bf79/1
I do not suggest you do this at all but if you just want to separate two groups you could do this:
SELECT * FROM transactions WHERE group_id = 1
UNION ALL
(SELECT '','','','','','')
UNION ALL
SELECT * FROM transactions WHERE group_id = 2
Obviously this can added to if there are more group ids in the future but it is not a general purpose solution you are really better off dealing with appearance issues like this in application code.
you can use (abuse) rollup.
SELECT *
FROM transactions
group by group_id, id
with rollup
having group_id is not null
this will insert a row with id set to null after each group_id.
mysql will also sort by group_id because of the group by.
The group by id` makes sure that all rows are shown (your schema does not show it, but I assume id is unique? Otherwise you need to add other fields)
However only id will be null in the extra rows. The other columns repeat the value above.
You can filter them like this:
SELECT
id,
case id is not null when true then date else null end as date,
case id is not null when true then group_id else null end as group_id
-- ....
FROM transactions
group by group_id, id
with rollup
having group_id is not null
Alternatively:
select * from
(SELECT *
FROM transactions
union all
select distinct null, null, group_id, null, null,null from transactions
) as t
order by 3,1
but null values are sorted first, so the "gap" is in front of each section
I would like to have columns that look like this:
KILL, DEATH, WIN, playerName
this is the resultset that it should be applied on
and this is the query that i use to get that resultset:
SELECT SUM(amount) as amount, type.name as type, gamemode_statistics.Name as playerName
FROM gamemode_statistics INNER JOIN type ON gamemode_statistics.type_id = type.id
GROUP BY gamemode_statistics.type_id, playerName
i really have no clue on how to do this, i tried various ways but none of them solve my problem. Maybe i just configured my tables incorrectly?
If these are the only three values you want to show as column you can do so,this will give you the count of types
SELECT SUM(amount) as amount,
SUM(`type`='KILL') AS `KILL`,
SUM(`type`='DEATH') AS `DEATH`,
SUM(`type`='WIN') AS `WIN`,
gamemode_statistics.Name as playerName
FROM gamemode_statistics
INNER JOIN type ON gamemode_statistics.type_id = type.id
GROUP BY gamemode_statistics.type_id, playerName
You're looking for a pivot query, and MySQL doesn't support them directly. For a simple 3-column result, it's not too bad, but this cannot be made to work as a general solution for n-way arbitrary columns:
SELECT
SUM(IF type='KILL', amount, 0) AS KILL,
SUM(IF type='DEATH', amount, 0) AS DEATH
etc..
FROM ...
SELECT
ISNULL(SUM(CASE WHEN type='KILL'THEN amount ELSE 0 END),0) AS KILL,
ISNULL(SUM(CASE WHEN type='DEATH'THEN amount ELSE 0 END) AS DEATH
etc..
FROM ...
Consider putting your database into 3rd normal form. http://www.andrewrollins.com/2009/08/11/database-normalization-first-second-and-third-normal-forms/
CREATE TABLE players (
id int not null primary key auto_increment,
name text not null,
... other player data
);
Create TABLE player_stats(
player_id int not null primary key, -- this is a foreign key to the players table
kills int not null default 0
deaths not null default 0,
wins not null default 0,
... other stats
);
then the query becomes something like
SELECT name, wins
FROM players join player_stats on player_id = players.id
WHERE name = 'fred';
I have the following table setup in mysql:
CREATE TABLE `games_characters` (
`game_id` int(11) DEFAULT NULL,
`player_id` int(11) DEFAULT NULL,
`character_id` int(11) DEFAULT NULL,
KEY `game_id_key` (`game_id`),
KEY `character_id_key` (`character_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
My objective is to get a game_id where a list of character_ids are all present in this game_id.
An example set of data:
1, 1
1, 2
1, 3
2, 1
2, 2
3, 1
3, 4
Let's say i want to get the game_id where the character_id has 1, 2, and 3. How would I go about making an efficient query? Best idea I have had so far was joining the table to itself multiple times, but i assume there has to be a better way to do this.
Thanks
EDIT: for anyone curious this was the final solution I used as it proved the best query time:
SELECT game_ID
FROM (
SELECT DISTINCT character_ID, game_ID
FROM games_Characters
) AS T
WHERE character_ID
IN ( 1, 2, 3 )
GROUP BY game_ID
HAVING COUNT( * ) =3
Select game_ID from games_Characters
where character_ID in (1,2,3)
group by game_ID
having count(*) = 3
the above makes two assumptions
1) you know the characters your looking for
2) game_ID and character_ID are unique
I don't assume you can get the #3 for the count I knnow you can since you know the list of people you're looking for.
This ought to do it.
select game_id
from games_characters
where character_id in (1,2,3)
group by game_id
having count(*) = 3
If that's not dynamic enough for you you'll need to add a few more steps.
create temporary table character_ids(id int primary key);
insert into character_ids values (1),(2),(3);
select #count := count(*)
from character_ids;
select gc.game_id
from games_characters as gc
join character_ids as c
on (gc.character_id = c.id)
group by gc.game_id
having count(*) = #count;
Imagine this db structure:
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`correct` tinyint(1) NOT NULL DEFAULT '0'
I want to get the count of all entries with correct = 1, and the count of all entries with correct = 0, in one query.
How do I do this?
Using GROUP BY should solve the problem:
SELECT correct, COUNT(*) FROM table GROUP BY correct;
select count(case when correct = 0 then 1 end) as ZeroCount,
count(case when correct = 1 then 1 end) as OneCount
from MyTable
If you want the counts in one row:
SELECT SUM(correct=0) as number_of_zeros,SUM(correct=1) as number_of_ones
FROM table;
If you want them in multiple rows:
SELECT correct,COUNT(*)
FROM table
GROUP BY correct;