Grouping from highest to lowest - mysql

Question

I have a table like this:
+---------+--------------+---------+
| visitty | specialty | doctors |
+---------+--------------+---------+
| 1 | oncology | 3611 |
| 1 | neurology | 1931 |
| 1 | rheumatology | 1471 |
| 0 | oncology | 35 |
| 0 | rheumatology | 28 |
| 0 | neurology | 20 |
+---------+--------------+---------+
The above table was created by ordering the field doctors
Now, I'm trying to get the following result:
+---------+--------------+---------+
| visitty | specialty | doctors |
+---------+--------------+---------+
| 1 | oncology | 3611 |
| 0 | oncology | 35 |
| 1 | neurology | 1931 |
| 0 | neurology | 20 |
| 1 | rheumatology | 1471 |
| 0 | rheumatology | 28 |
+---------+--------------+---------+
Is there any way to do this?
In reply to Adil Miedl ... these were the criteria used in the query:
(PS: I think it can be a little confusing to underestand without the referenced tables)
SELECT
su.visitty, cs.specialty, COUNT(*) doctors
FROM
contacts c
INNER JOIN contact_groups ccgc ON c.id_contact = ccgc.id_contact
AND ccgc.status = 1
INNER JOIN groups ccg ON ccg.id_ccenter_groups = ccgc.id_ccenter_groups
AND ccg.status = 2
INNER JOIN distribuition ccd ON ccd.id_ccenter_groups = ccg.id_ccenter_groups
AND ccd.status = 2
INNER JOIN cds_contacts sc ON c.id_cds_account = sc.id_cds_account
LEFT JOIN cds_contacts_territories AS sct ON sc.id_contact = sct.id_contact
INNER JOIN cds_usuarios_territories AS sut ON sut.id_territory = sct.id_territory
INNER JOIN cds_usuarios AS su ON su.id_user = sut.id_user
INNER JOIN contact_specialties cs ON c.id_contact = cs.id_contact
and cs.status = 1
and cs.srsmain = 'Y'
WHERE
c.contact_type = 'Doctor'
AND ccd.release_date BETWEEN '2013-01-01 00:00:00' AND '2013-12-31 23:59:59'
GROUP by visitty , cs.specialty
ORDER BY doctors DESC;

Answer 1

You seem to want to order the specialties by the total of doctors in them. The query needs to calculate this value before doing the ordering:
select t.visitty, t.specialty, t.doctors
from table t join
(select specialty, sum(doctors) as numdoctors
from table t
group by specialty
) tsum
on t.specialty = tsum.specialty
order by tsum.doctors desc, tsum.specialty, t.doctors desc;