SQL select orders depending on status and date - mysql

Question

I have a table order_history that is similar to the following:
+-------------------------------------------------------------+
| order_history_id | order_id | order_status_id | date_addded |
+-------------------------------------------------------------+
| 1 | 1 | 1 | 2014-03-20 |
| 2 | 1 | 2 | 2014-03-21 |
| 3 | 1 | 3 | 2014-03-29 |
| 4 | 2 | 1 | 2014-03-20 |
| 5 | 2 | 2 | 2014-03-21 |
| 6 | 2 | 3 | 2014-04-02 |
| 7 | 3 | 1 | 2014-04-20 |
| 8 | 3 | 2 | 2014-04-21 |
| 9 | 3 | 3 | 2014-04-22 |
+-------------------------------------------------------------+
The order_status represents the status of an order
+-------------------------------+
| order_status_id | name |
+-------------------------------+
| 1 | received |
| 2 | processed |
| 3 | shipped |
+-------------------------------+
what i want to do is to pull out all the orders that have been received before 2014-04-01 but not shipped until after 2014-04-01.
So in this case the query would just return order_id 2 as this is the only order that was received before 2014-04-01 yet shipped after.
I can't even seem to get started... Any help, hints, or pointers much appreciated.

Answer 1

You can do so ,by joining your tables and count the statues shipped for each order by using expression in sum i.e SUM(os.name ='shipped') shipped
SELECT o.*
,SUM(os.name ='shipped') shipped
FROM
orders o
LEFT JOIN orders_status os USING(order_status_id)
WHERE o.date_addded < '2014-04-01'
GROUP BY o.order_id
HAVING shipped =0
Fiddle Demo

Answer 2

You can use INNER JOIN with this, if I get what you really want you can try this:
SELECT DISTINCT order_id
FROM order_history A
INNER JOIN order_status B
ON A.order_status_id = B.order_status_id
WHERE (A.order_Status_id = '1' AND A.date_added < #date) AND (A.order_status_id = '3' AND A.date_added < #date)

Answer 3

SELECT h1.order_id
FROM order_history h1
JOIN order_status s1
ON s1.order_status_id = h1.order_status_id
JOIN order_history h2
ON h2.order_id = h1.order_id
JOIN order_status s2
ON s2.order_status_id = h2.order_status_id
WHERE h1.date_addded < '2014-04-01'
AND s1.name = 'received'
AND h2.date_addded >= '2014-04-01'
AND s2.name = 'shipped';
Note: Too many 'd's in addded

Answer 4

SELECT r.order_id
FROM (
SELECT DISTINCT oh.order_id
FROM order_history AS oh
JOIN order_status AS os ON(oh.order_status_id = os.order_status_id)
WHERE os.name = 'received'
AND oh.date_addded < '2014-04-01'
) AS r
JOIN (
SELECT DISTINCT oh.order_id
FROM order_history AS oh
JOIN order_status AS os ON(oh.order_status_id = os.order_status_id)
WHERE os.name = 'shipped'
AND oh.date_addded > '2014-04-01'
) AS s ON (s.order_id = r.order_id)
demo

Answer 5

What about this simple and light query:
SELECT DISTINCT order_id
FROM order_history o1
JOIN order_history o2
ON o1.order_id = o2.order_id
AND o1.order_status_id=1 AND o1.date_added<'2014-04-01'
AND o2.order_status_id=3 AND o2.date_added>'2014-04-01';

Answer 6

Not tested, but try this:
SELECT A.ORDER_ID
FROM ORDER_HISTORY A, ORDER_HISTORY B
WHERE A.ORDER_ID = B.ORDER_ID
AND A.order_status_id = 1
AND A.date_addded < TO_DATETO_DATE ('2014-04-01', 'YYYY-MM-DD')
AND B.order_status_id = 3
AND B.date_addded > TO_DATETO_DATE ('2014-04-01', 'YYYY-MM-DD');