How to search ignoring spaces between words? - mysql

Question

I want search names using my search module with ignoring white spaces .
Ex: if i want to search a name like "A B Zilva"
i want to disply the results on dropdown even if i type the name like "AB Zilva".
currently search without space is not working
$db = JFactory::getDbo();
$searchp=$_GET["term"];
$searchp = str_replace(' ','%%', trim($searchp));
//$searchp= preg_split('/ /', $searchp);
$query = $db -> getQuery(true);
$query="SELECT * FROM content where title like '%".$searchp."%'AND categories_id=82 order by title ASC ";
$db -> setQuery($query);
// Load the results as a list of associated arrays.
$results = $db -> loadAssocList();
$json=array();
foreach ($results as $json_result) {
$json[] = array('value' => $json_result["title"], 'label' => $json_result["title"]);
}
Please advice .
update :
jQuery.extend( jQuery.ui.autocomplete.prototype, {
_renderItem: function( ul, item ) {
var term = this.element.val(),
regex = new RegExp( '(' + term + ')', 'gi' );
html = item.label.replace( regex , "<b>$&</b>" );
return jQuery( "<li></li>" )
.data( "item.autocomplete", item )
.append( jQuery("<a></a>").html(html) )
.appendTo( ul );
}
});

Answer 1

The problem with your code is that when you replace space with %%, you get a search like:
WHERE title like '%AB%%Zilva%'
but this won't match when the title is A B Zilva. You need to remove spaces from both the search string and the column in the database. Do it like this:
$searchp = str_replace(' ', '', $searchp);
and then change the SQL to:
WHERE REPLACE(title, ' ', '') LIKE '%$searchp%'
For the Javascript highlighting, I think you need to do this:
var term = this.element.val().replace(/ /g, '').replace(/.(?=.)/g, '$& *'),
This will create a regular expression that allows for spaces between any of the characters in the search string.