Creating 5 random elements with ActionScript 3 - actionscript-3

Question

My requirements:
They need to be created on random positions.
You should be able to click and move them.
Once they touch each other, you're not able to move them anymore.
They change colors once they touch.
This is my code now,but it keeps creating balls an infinite amount of them
import flash.display.MovieClip;
import flash.events.Event;
import flash.events.MouseEvent;
//Criação das variavéis
var bolas:Array = new Array();
stage.addEventListener(MouseEvent.MOUSE_DOWN, startdd);
stage.addEventListener(MouseEvent.MOUSE_UP, stopdd);
function startdd(e:MouseEvent)
{
e.target.startDrag();
}
function stopdd(e:MouseEvent)
{
e.target.stopDrag();
}
for (var i:int = 0; i < 5; i++)
{
var ball:bolamc = new bolamc();
ball.x = Math.random() * (stage.stageWidth - ball.width);
ball.y = Math.random() * (stage.stageHeight - ball.height);
bolas.push(ball);
stage.addChild(ball);
}
ps: my friend is using the same code and its working properly (makes 5 balls and he's able to move them around)

Answer 1

You'll need to write most of the code yourself, but I can give you some guidance.
To create an element in a random spot on the screen, you can use Math.random(). Example:
var newElement:Element = new Element();
newElement.x = Math.random()*STAGE_WIDTH_GOES_HERE;
newElement.y = Math.random()*STAGE_HEIGHT_GOES_HERE;
addChild(newElement);
For clicking and dragging, here's a nice tutorial on Kirupa. You might need to adjust it to make it work with multiple objects.
For hit collision, you can loop through your elements and use hitTestObject() to determine if their bounding boxes are touching each other. If you need greater precision, you can try a pixel perfect collision class like this.
For changing the color of an object, you can use Color Transform, which has a tutorial on RepublicOfCode. Here's some basic example code from that page:
var myColorTransform = new ColorTransform();
myColorTransform.color = 0xFFFFFF;
myTargetObject.transform.colorTransform = myColorTransform;