How does the following compare to a join statement?
SELECT t1.name, t2.salary
FROM employee t1, info t2
WHERE t1.name = t2.name;
would it be the equivalent to this?
SELECT t1.name, t2.salary
FROM employee t1,
INNER JOIN info t2
ON t1.name = t2.name;
or is it more like an outer join?
it will be like this without comma.
SELECT t1.name, t2.salary
FROM employee t1
INNER JOIN info t2
ON t1.name = t2.name;
To use INNER JOIN or LEFT or RIGHT or ... its up to you what results you want get.
related values or values which exist in other table and so on , here you can learn about the joins.
SOURCE
Related
I basically want to join the result of two INNER JOINs.
On this scheme I want to get the three arrows results combined.
I've tried INNER / LEFT combinations but it doesn't do the trick.
I think a nested request could be the solution but how ?
Thanks
The answer was actually simple : UNION
SELECT t1.*
FROM
(SELECT t1.*
FROM table1 t1 JOIN table2 t2 ON t2.id = i.client_id
UNION
SELECT t1.*
FROM t1 t1 JOIN table3 t3 ON t1.id = t3.client_id) as q1
;
I'd use logic to express the condition T1.id exists in T2 or T3 more directly, and certainly avoid use of DISTINCT or UNION.
Options could be to use EXISTS directly (As this is immure to the possibility of duplication cause by 1:many joins)...
SELECT
t1.*
FROM
table1 t1
WHERE
EXISTS (SELECT * FROM table2 t2 WHERE t2.t1_id = t1.id)
OR
EXISTS (SELECT * FROM table3 t3 WHERE t3.t1_id = t1.id)
Or to LEFT JOIN twice and then exclude unwanted rows. (This assumes that the joins are never 1:many, which would introduce duplication, and the unwanted need for a DISTINCT.)
SELECT
t1.*
FROM
table1 t1
LEFT JOIN
table2 t2
ON t1.id = t2.t1_id
LEFT JOIN
table3 t3
ON t1.id = t3.t1_id
WHERE
t2.t1_id IS NOT NULL
OR
t3.t1_id IS NOT NULL
I have 2 tables and result as shown in the image below: MySQL DB
What would be best way to join the two tables so we get the result as shown above.
SELECT * FROM (SELECT id, desc FROM table2) as T1
LEFT JOIN (SELECT * FROM table1) as T2 ON T1.id = T2.id
I guess my SQL is not working.
You can use a LEFT JOIN with COALESCE:
SELECT t1.id, COALESCE(t2.desc, t1.desc) AS desc, t1.D1, t1.D2
FROM table1 as T1
LEFT JOIN table2 as T2 ON T1.id = T2.id
Use a left join with coalesce to prioritize table 2's values if they are present, but fallback on table 1's values if not.
select t1.id,
coalesce(t2.desc, t1.desc) as desc,
t1.d1, t1.d2
from table1 t1
left join table2 t2
on t2.id = t1.id
order by t1.id
You can use ifnull:
SELECT t1.id, ifnull(t2.desc, t1.desc) AS desc, t1.D1, t1.D2
FROM table1 as T1
LEFT JOIN table2 as T2 ON T1.id = T2.id
coalesce or case .. when is also possible. All together with the left join
I am trying to get the soul count of a player in the game as well as all their other stats. The query I am trying is
SELECT t1.*, (SELECT COUNT(*) FROM t2 GROUP BY SoulLocationName WHERE SoulLocationName=t1.Name) AS SoulCount
FROM tblAvatar t1
JOIN tblAvatar t2 ON t1.Name = t2.SoulLocationName
Where am I going wrong?
Try this query
SELECT t1.*, t2.SoulCount
FROM tblAvatar t1
JOIN(SELECT SoulLocationName,COUNT(*) as SoulCount FROM tblAvatar GROUP BY SoulLocationName) t2 ON t1.Name = t2.SoulLocationName
SELECT t1.*,
COUNT(t2.SoulLocationName) as SoulCount
FROM tblAvatar t1
JOIN tblAvatar t2
ON t1.Name = t2.SoulLocationName
Suppose I have following tables: T1,T2 and T3.
How could I rephrase the following query using only left joins.
Select *
From T1
Right join T2 On T1.FK2=T2.PK
Right join T3 On T1.FK3=T3.PK
Following attempt is not correct:
Select *
From T2
Left join T1 On T1.FK2=T2.PK
Left join T3 On T1.FK3=T3.PK
T3 is On the wrong Side of the join. Is the following possible:
Select *
From T2
Left join T3 On T1.FK3=T3.PK
Left join T1 On T1.FK2=T2.PK
I can't Find a way to put both tables 2 and 3 On the left Side of 1 and use the correspondent fields to join all tables? The last query uses fields of table 1 before this table is mentioned in the query.
Or something like this?
Select *
From T2
Left join (
T3 left join T1
On T1.FK3=T3.PK)
On T1.FK2=T2.PK
Apparently brackets can help to order your joins. I wonder if this is really documented, i've found Nothing at first glance in the mysql docs.
Following query is correct and does not have any subqueries:
Select T1.Id Ida, t2.id idb, T3.id idc FROM T3
LEFT JOIN
(T2
LEFT JOIN T1 ON (T1.ID = T2.ID))
ON (T1.ID= T3.ID);
You need to use a subquery to first join t1 with t2 and then join the result with t3:
SELECT T.ID1 ID1, T.ID2 ID2, T3.ID ID3 FROM T3
LEFT JOIN
(SELECT T1.ID ID1, T2.ID ID2 FROM T2
LEFT JOIN T1 ON (T1.ID = T2.ID)) T
ON (T.ID1 = T3.ID);
SQL Fiddle
The first way is just to reverse the order that the tables are mentioned:
Select *
from t3 left outer join
t2
on T1.FK3 = T3.PK left outer join
t1
on T1.FK2 = T2.PK
But this won't work, because the first condition is on t1 and not t2. And t2 hasn't yet been defined.
When working with chains of tables in left or right outer joins, only the first (or last) tables are important, because they "drive" the query. "Drive" in the sense that they provide all the values even when there are no matches. So, the following should do what you want:
Select *
from t3 left outer join
t1
on T1.FK3 = T3.PK left outer join
t2
on T1.FK2 = T2.PK;
The example below shows the result for every Name that has a connection to Table2 (Table1 TId is PK, and TId in Table2 is the FK).
SELECT T1.Name, T1.Address
FROM Table1 AS T1
INNER JOIN Table2 AS T2
ON T1.TId = T2.TId;
I want a list of all Names from Table1 that have NO corresponding row in Table2. The other way around so to speak. How could this be done?
You need to use an Outer Join as shown below:
SELECT T1.Name, T1.Address
FROM Table1 AS T1
LEFT OUTER JOIN Table2 AS T2 ON T1.TId = T2.TId
WHERE T2.TId IS NULL