Suppose I have such a table:
+-----+---------+-------+
| ID | TIME | DAY |
+-----+---------+-------+
| 1 | 1 | 1 |
| 2 | 2 | 1 |
| 3 | 3 | 1 |
| 1 | 1 | 2 |
| 2 | 2 | 2 |
| 3 | 3 | 2 |
| 1 | 1 | 3 |
| 2 | 2 | 3 |
| 3 | 3 | 3 |
| 1 | 1 | 4 |
| 2 | 2 | 4 |
| 3 | 3 | 4 |
| 1 | 1 | 5 |
| 2 | 2 | 5 |
| 3 | 3 | 5 |
+-----+---------+-------+
I want to fetch a table which represents 2 IDs which got the largest sum of TIME within the last 3 days (means from 3 to 5 in a DAY column)
So the correct result would be:
+-----+---------+
| ID | SUM |
+-----+---------+
| 3 | 9 |
| 2 | 6 |
+-----+---------+
The original table is much larger and more complex. So i need a generic approach.
Thanks in advance.
And so I just learned that MySQL used LIMIT instead of TOP...
fiddle
CREATE TABLE tbl (ID INT,tm INT,dy INT);
INSERT INTO tbl (id, tm, dy) VALUES
(1,1,1)
,(2,2,1)
,(3,3,1)
,(1,1,2)
,(1,1,1)
SELECT ID
,SUM(SumTimeForDay) SumTimeFromLastThreeDays
FROM (SELECT ID
,SUM(tm) SumTimeForDay
FROM tbl
GROUP BY ID, dy
HAVING dy > MAX(dy) -3) a
GROUP BY id
ORDER BY SUM(SumTimeForDay) DESC
LIMIT 2
select t1.`id`, sum(t1.`time`) as `sum`
from `table` t1
inner join ( select distinct `day` from `table` order by `day` desc limit 3 ) t2
on t2.`da`y = t1.`day`
group by t1.`id`
order by sum(t1.`time`) desc
limit 2
Related
I'm looking to allow for a custom ordering logic through mySQL that allows the following data set:
+----+-----------------+------------+-------+--+
| ID | item | Popularity | Views | |
+----+-----------------+------------+-------+--+
| 1 | A special place | 3 | 10 | |
| 2 | Another title | 5 | 12 | |
| 3 | Words go here | 1 | 15 | |
| 4 | A wonder | 2 | 8 | |
+----+-----------------+------------+-------+--+
To return an order that alternates, row by row, by popularity and then by views, so the return results look like:
+----+-----------------+------------+-------+--+
| ID | item | Popularity | Views | |
+----+-----------------+------------+-------+--+
| 3 | Words go here | 1 | 15 | |
| 2 | Another title | 5 | 12 | |
| 4 | A wonder | 2 | 8 | |
| 1 | A special place | 3 | 10 | |
+----+-----------------+------------+-------+--+
Where you will see the first row returns the 'most popular', the second row returns the most views, the third row returns the second most popular, and the 4th row returns the 2nd most views.
Currently I'm gathering an entire table through mySQL twice, and then merging these results in PHP. This isn't going to cut it when the database is large. Is this possible in mysql at all?
I guess something along these lines could work. Consider the following:
DROP TABLE IF EXISTS my_table;
CREATE TABLE my_table
(id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,x INT NOT NULL
,y INT NOT NULL
);
INSERT INTO my_table VALUES
(1,3,10),
(2,5,12),
(3,1,15),
(4,2, 8)
(5,4, 1);
We can rank x and y in turn, and then arrange those ranks in a single list - so will have x1,y1,x2,y2,etc - but all rows will appear twice; once for the x rank and once for the y rank...
SELECT * FROM
(
( SELECT a.*, COUNT(*) rank FROM my_table a JOIN my_table b ON b.x <= a.x GROUP BY a.id )
UNION ALL
( SELECT a.*, COUNT(*) rank FROM my_table a JOIN my_table b ON b.y <= a.y GROUP BY a.id )
) n
ORDER BY rank
+----+---+----+------+
| id | x | y | rank |
+----+---+----+------+
| 5 | 4 | 1 | 1 |
| 3 | 1 | 15 | 1 |
| 4 | 2 | 8 | 2 |
| 4 | 2 | 8 | 2 |
| 1 | 3 | 10 | 3 |
| 1 | 3 | 10 | 3 |
| 5 | 4 | 1 | 4 |
| 2 | 5 | 12 | 4 |
| 2 | 5 | 12 | 5 |
| 3 | 1 | 15 | 5 |
+----+---+----+------+
Now we can just grab the lowest rank for each id...
SELECT id
, x
, y
FROM
(
( SELECT a.*, COUNT(*) rank FROM my_table a JOIN my_table b ON b.x <= a.x GROUP BY a.id )
UNION ALL
( SELECT a.*, COUNT(*) rank FROM my_table a JOIN my_table b ON b.y <= a.y GROUP BY a.id )
) m
GROUP
BY id,x,y
ORDER
BY MIN(rank);
+----+---+----+
| id | x | y |
+----+---+----+
| 3 | 1 | 15 |
| 5 | 4 | 1 |
| 4 | 2 | 8 |
| 1 | 3 | 10 |
| 2 | 5 | 12 |
+----+---+----+
Incidentally, this should be faster with variables - but I cannot make that solution work at present - senior moment, perhaps.
i am loosing it over the following problem:
i have a table with participants and points. each participant can have up to 11 point entries of which i only want the sum of the top 6.
in this example lets say we want the top 2 of 3
+----+---------------+--------+
| id | participantid | points |
+----+---------------+--------+
| 1 | 1 | 11 |
+----+---------------+--------+
| 2 | 3 | 1 |
+----+---------------+--------+
| 3 | 3 | 4 |
+----+---------------+--------+
| 4 | 2 | 3 |
+----+---------------+--------+
| 5 | 1 | 5 |
+----+---------------+--------+
| 6 | 2 | 10 |
+----+---------------+--------+
| 7 | 2 | 9 |
+----+---------------+--------+
| 8 | 1 | 3 |
+----+---------------+--------+
| 9 | 3 | 4 |
+----+---------------+--------+
as a result i want something like
+---------------+--------+
| participantid | points |
+---------------+--------+
| 2 | 19 |
+---------------+--------+
| 1 | 16 |
+---------------+--------+
| 3 | 8 |
+---------------+--------+
(it should be ordered DESC by the resulting points)
is this at all possible with mysql? in one query?
oh and the resulting participant ids should be resolved into the real names from another 'partcipant' table where
+----+------+
| id | name |
+----+------+
| 1 | what |
+----+------+
| 2 | ev |
+----+------+
| 3 | er |
+----+------+
but that should be doable with a join at some point... i know...
Using one of the answers from ROW_NUMBER() in MySQL for row counts, and then modifying to get the top.
SELECT ParticipantId, SUM(Points)
FROM
(
SELECT a.participantid, a.points, a.id, count(*) as row_number
FROM scores a
JOIN scores b ON a.participantid = b.participantid AND cast(concat(a.points,'.', a.id) as decimal) <= cast(concat(b.points,'.', b.id) as decimal)
GROUP BY a.participantid, a.points, a.id
) C
WHERE row_number IN (1,2)
GROUP BY ParticipantId
Had an issue with ties until I arbitrarily broke them with the id
I have two tables containing fields as below.
Table 1
| SetID | InQty | Day |
| 1 | 10 | 1 |
| 2 | 10 | 2 |
| 3 | 10 | 3 |
Table 2
| SetID | OtQty | Day |
| 1 | 1 | 5 |
| 1 | 2 | 6 |
| 1 | 3 | 7 |
SetID in table 2 is linked with SetId in table 1. Day is placed in place of date, just for convenience only. Expected Output,
| Day | InQty | OtQty |
| 1 | 10 | |
| 5 | | 1 |
| 6 | | 2 |
| 7 | | 3 |
Blank Space can be filled with NULL or Zero.
It appears you are querying ONLY for set ID = 1 otherwise, I would expect to see in/out values for Set 2 and 3. You should be able to get with a simple UNION
select t1.Day, t1.InQty, 0 OutQty
from Table1 t1
where SetID = 1
order by t1.Day
union select t2.Day, 0, t2.OtQty
from Table2 t2
where SetID = 1
Now, if you want totals spanning different "setID"s and keeping them differentiated from each other, just add the setID as a column and also add to the group by clause as well.
This question already has an answer here:
Top N per Group Sql problem in mysql
(1 answer)
Closed 9 years ago.
Suppose I have the next table:
+------------+---------+
| MovieId | rating |
+------------+---------+
| 1 | 4 |
| 1 | 3 |
| 1 | 2 |
| 1 | 4 |
| 1 | 5 |
| 2 | 3 |
| 2 | 4 |
| 2 | 2 |
| 3 | 1 |
| 3 | 2 |
| 3 | 3 |
| 3 | 5 |
| 4 | 4 |
| 4 | 2 |
+------------+---------+
I would like to get the average by group BUT using the first 2 elements on each group.
Example:
+------------+---------+
| MovieId | rating |
+------------+---------+
| 1 | 4 |
| 1 | 3 |
| 2 | 3 |
| 2 | 4 |
| 3 | 1 |
| 3 | 2 |
| 4 | 4 |
| 4 | 2 |
+------------+---------+
answer expected:
+------------+---------+
| MovieId | AVG |
+------------+---------+
| 1 | 3.5 |
| 2 | 3.5 |
| 3 | 1.5 |
| 4 | 3 |
+------------+---------+
This is the SQL query I have to get the AVG for all of the movies. But as I said, I would like to use just the first 2 elements for each group.
SELECT movieid, AVG(cast(rating as DECIMAL(10,2))) AS AVG
FROM ratings
group by movieid
If you can help me to make the SQL I appreciate. I will also use Linq just in case some of you know it.
In a SQL DBMS -- as in the relational model -- there is no "first". Do you mean any arbitrary 2 rows for each movie, or the two highest ratings, or something else?
If you can't define an order, then the query is meaningless.
If you can define an order, join the table to itself as I show in my canonical example to create a ranking, and select where RANK < 3.
FOR Mysql:-
select id, avg(rating)
from (SELECT a.*, #num := #num + 1 rownum,
(select count(*)
from movies m
where m.id<=a.id) last_count,
(select count(*)
from movies m1
where a.id=m1.id) grp_count
from movies a, (SELECT #num := 0) d) f
where grp_count-(last_count-rownum)<=2
group by id;
you can use rownum function in oracle. And row_number() function in sql server.
This is a solution in SQL
Create table #tempMovie (movieId int ,rating int)
INSERT INTO #tempMovie
Select * from table where movieidid=1 Limit 2
Union all
Select * from table where movieidid=2 Limit 2
Union all
Select * from table where movieidid=3 Limit 2
Union all
Select * from table where movieidid=4 Limit 2
Temporary table #tempmovie table will contain data like this
+------------+---------+
| MovieId | rating |
+------------+---------+
| 1 | 4 |
| 1 | 3 |
| 2 | 3 |
| 2 | 4 |
| 3 | 1 |
| 3 | 2 |
| 4 | 4 |
| 4 | 2 |
+------------+---------+
then apply group by
Select movieId, AVG(rating)
from #tempMovie
Group by movieId
Drop table #tempmovie
I have two tables, rating:
+-----------+-----------+-------------+----------+
| rating_id | entity_id | rating_code | position |
+-----------+-----------+-------------+----------+
| 1 | 1 | Quality | 0 |
| 2 | 1 | Value | 0 |
| 3 | 1 | Price | 0 |
+-----------+-----------+-------------+----------+
And rating_option
+-----------+-----------+------+-------+----------+
| option_id | rating_id | code | value | position |
+-----------+-----------+------+-------+----------+
| 1 | 1 | 1 | 1 | 1 |
| 2 | 1 | 2 | 2 | 2 |
| 3 | 1 | 3 | 3 | 3 |
| 4 | 1 | 4 | 4 | 4 |
| 5 | 1 | 5 | 5 | 5 |
| 6 | 2 | 1 | 1 | 1 |
| 7 | 2 | 2 | 2 | 2 |
| 8 | 2 | 3 | 3 | 3 |
| 9 | 2 | 4 | 4 | 4 |
| 10 | 2 | 5 | 5 | 5 |
| 11 | 3 | 1 | 1 | 1 |
| 12 | 3 | 2 | 2 | 2 |
| 13 | 3 | 3 | 3 | 3 |
| 14 | 3 | 4 | 4 | 4 |
| 15 | 3 | 5 | 5 | 5 |
+-----------+-----------+------+-------+----------+
I need a SQL query (not application level, must stay in the database) which will select a set of ratings randomly. A sample result would look like this, but would pick a random value for each rating_id on subsequent calls:
+-----------+-----------+------+-------+----------+
| option_id | rating_id | code | value | position |
+-----------+-----------+------+-------+----------+
| 1 | 1 | 1 | 1 | 1 |
| 8 | 2 | 3 | 3 | 3 |
| 15 | 3 | 5 | 5 | 5 |
+-----------+-----------+------+-------+----------+
I'm totally stuck on the random part, and grouping by rating_id has been a crap shoot so far. Any MySQL ninjas want to take a stab?
Thanks,
Joe
EDIT: I've tried rand() in a bunch of combinations, and I'm sure that it will be necessary to create the randomness of the result, but I cannot figure out how to return one random row for each of the rows in rating. I cannot use order by rand() limit 1 because I need three rows, and order by rand() limit 3 won't give me one of each rating_id, which is the ultimate goal. I need a combination of rand() and either subqueries or joins so that I can ensure one of each rating_id.
Alright, a little messy, but seems to do the job. Someone may know what they're doing better than I do that can clean this up:
SELECT random.rating_id, random.rand_option_id, r3.code, r3.value, r3.position
FROM
(SELECT r.rating_id,
(SELECT r2.option_id
FROM rating_option r2
WHERE r2.rating_id = r.rating_id
ORDER BY RAND() LIMIT 1) AS 'rand_option_id'
FROM rating_option r
GROUP BY r.rating_id
) random
LEFT JOIN rating_option AS r3 ON r3.option_id = rand_option_id
Results (varies every time, of course):
+-----------+----------------+------+-------+----------+
| rating_id | rand_option_id | code | value | position |
+-----------+----------------+------+-------+----------+
| 1 | 4 | 4 | 4 | 4 |
| 2 | 6 | 1 | 1 | 1 |
| 3 | 13 | 3 | 3 | 3 |
+-----------+----------------+------+-------+----------+
You could use the rand() function to do sorting in a select on the rating table.
For example:
select rating_id from rating order by rand() limit 1
As clarified in your comments, and the other posts above
select * from rating_option order by rand()
will return all records in a random order... However, if you want only X number, then inclue that as the limit as noted by others
select * from rating_option order by rand() limit 5 (or whatever number)
Have you looked into the rand() function?
SELECT column FROM table
ORDER BY RAND()
LIMIT 1
http://www.petefreitag.com/item/466.cfm
http://dev.mysql.com/doc/refman/5.0/en/mathematical-functions.html#function_rand
Sample code
select *
from rating_option
group by rating_id
order by rand()