I need to tabulate the data from three tables for a report. Please see this query
SELECT
DATE( sale.sale_time ) AS dat,
location.location_name as location,
sale.sale_id AS total_orders,
SUM( CASE sale.is_cancelled WHEN 0 THEN sale.sale_amount ELSE 0 END ) AS sales,
SUM( CASE sale.is_cancelled WHEN 0 THEN sale.sale_discount ELSE 0 END ) AS discounts,
SUM( CASE sale.is_cancelled WHEN 0 THEN sale.sale_tax ELSE 0 END ) AS taxes,
COUNT( DISTINCT sale.customer_id ) AS total_customers,
SUM( CASE WHEN DATE( person.added_on ) = DATE( sale.sale_time ) THEN 1 ELSE 0 END ) AS new_customers,
SUM( CASE sale.is_cancelled WHEN 1 THEN 1 ELSE 0 END ) AS cancelled_orders
FROM
sales AS sale
INNER JOIN locations AS location ON location.location_id = sale.location_id
INNER JOIN people AS person ON person.person_id = sale.customer_id
GROUP BY
dat,location
The results for new_customers is showing wrong, often more than total_customers. Where is it wrong, and how to correct this?
The results are like this:
dat location total_orders sales discounts taxes new_customers total_customers cancelled_orders
15-03-14 Location1 52 1355 0 129.04 4 2 0
16-03-14 Location1 56 280 0 30 2 1 0
16-03-14 Location2 59 2518 0 212.2 3 6 2
As you might have guessed from the query, sales table has the columns sale_id,sale_time,sale_cost,sale_discount,sale_tax,sale_amount, is_cancelled (tinyint with values 0 or 1), and customer_id
People table has the columns person_id, first_name, added_on
By comparing the date(salessale_time) to date(person.added_on), I want to list customers added on that date
I modified the query to the following to get new customers also in the result set.
SELECT DATE(sale.sale_time) AS dat, location.location_name as location, (sale.sale_id) AS total_orders,
SUM(CASE sale.is_cancelled WHEN 0 THEN sale.sale_amount ELSE 0 END) AS sales,
SUM(CASE sale.is_cancelled WHEN 0 THEN sale.sale_discount ELSE 0 END) AS discounts,
SUM(CASE sale.is_cancelled WHEN 0 THEN sale.sale_tax ELSE 0 END) AS taxes,
count(distinct(sale.customer_id)) AS total_customers,
(select count(person_id) from people where date(added_on) = date(sale.sale_time) and person_id = sale.customer_id) as new_customers,
SUM(CASE sale.is_cancelled WHEN 1 THEN 1 ELSE 0 END) AS cancelled_orders
FROM sales AS sale
INNER JOIN locations AS location ON location.location_id = sale.location_id
GROUP BY dat,location;
Related
Currently I'm displaying all my data in a single day after comparing 2 of my tables like so:
with X as (
select l.*,
(select status_from from logs where logs.refno = l.refno and logs.logtime >= '2021-10-01' order by logs.logtime limit 1) logstat
from listings l
where l.added_date <= '2021-10-01'
)
, Y as (select X.*, ifnull(X.logstat, X.status) stat from X)
SELECT
sum(case when status.text= 'Action' and Y.id is not null then 1 else 0 end) as `Action`,
sum(case when status.text= 'Draft' and Y.id is not null then 1 else 0 end) as `Draft`,
sum(case when status.text= 'Let' and Y.id is not null then 1 else 0 end) as `Let`,
sum(case when status.text= 'Sold' and Y.id is not null then 1 else 0 end) as `Sold`,
sum(case when status.text= 'Publish' and Y.id is not null then 1 else 0 end) as `Publish`
from status
left join Y on Y.stat = status.code
The logs table records all status changes for a product, but not the initial entry made in for the product, and the listings table displays what is the current status of the product as of today, and when this product was added to the table. Now to get the total data of a particular day, I'm using this statement which checks for everything in logs table that happened after selected date and everything in listings table that happened before the selected date. This returns the right output.
Now to get the output of dates 2021-10-01, 2021-10-02 and 2021-10-03, I have to get it by individually selecting all the dates. So I want a way where I can select the start date and end date and that will give me all the data in that timeframe and group them by their dates like so:
Date
Publish
Action
Let
Sold
Draft
2021-10-01
0
3
0
1
1
2021-10-02
0
2
0
1
2
2021-10-03
0
2
0
1
2
Dbfiddle: https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=a4db2d923a1b48f2fc2291bc58ffb6cc
We have a table with data from different nodes and one of the column will have status report as "compliant or non-compliant", sample data as below
I want to filter the table in such a way that if any of the checks on a node shows non compliant, it should be flagged as non-compliant and rest as compliant. Using below query i am able to do it
SELECT COUNT(*) AS total_nodes,
SUM(fully_compliant = 0) AS Non_compliant_nodes,
SUM(fully_compliant = 1) AS compliant_nodes
FROM (
SELECT Node, CASE WHEN SUM(Status = 'Compliant') = COUNT(*) THEN 1 ELSE 0 END AS fully_compliant
FROM your_table GROUP BY Node
)
Now, i want to group and split the result by dept as below, how can i achieve this
I think you're looking for this:
select dept,
count(*) as total_nodes,
sum(case when non_compliant_chk = 0 then 1 else 0 end) as compliant_nodes,
sum(case when non_compliant_chk > 0 then 1 else 0 end) as non_compliant_nodes
from (
select dept,
node,
sum(case when 'Non-Compliant' then 1 else 0 end) as non_compliant_chk
from your_table
group by dept,
node
) v
group by dept;
With few modifications to what Brian suggested, I am able to get the desired result
select dept,
count(*) as total_nodes,
sum(case when non_compliant_chk = 0 then 1 else 0 end) as compliant_nodes,
sum(case when non_compliant_chk > 0 then 1 else 0 end) as non_compliant_nodes
from (
select dept,
node,
COUNT(CASE WHEN Compliance-Status = 'Non-Compliant' THEN 1 END) 'non_compliant_chk'
from table WHERE DOR >= DATE(NOW()) - INTERVAL 7 DAY
group by Dept,
Node
) v
group by Dept;
I have a query that retrieves from a customer:
sum of time expent on his tickets (every ticket can have 1 or more interventions)
average resolution time
category of each ticket
The query:
SELECT SUM(f.duree) as total_time, SUM(timestampdiff(second, t.datec, t.date_close))/COUNT(distinct t.rowid) as average_resolution, COUNT(distinct t.rowid) as tickets,
SUM( CASE t.category_code WHEN 'WITHOUT_MAINTENANCE' THEN 1 ELSE 0 END) as sin_mantenimiento,
SUM( CASE t.category_code WHEN 'WITH_MAINTENANCE' THEN 1 ELSE 0 END) as con_mantenimiento,
SUM( CASE t.category_code WHEN 'WITH_BILLABLE_MAINTENANCE' THEN 1 ELSE 0 END) as con_mantenimiento_facturable,
SUM( CASE t.category_code WHEN 'NO_BILLABLE_COASER_WARRANTY' THEN 1 ELSE 0 END) as no_facturable_garantia_coaser,
SUM( CASE t.category_code WHEN 'OFERTADO' THEN 1 ELSE 0 END) as ofertado
FROM llx_ticketsup as t
JOIN llx_element_element as ee on ee.fk_source = t.rowid
JOIN llx_fichinter as f on f.rowid = ee.fk_target
WHERE t.fk_soc = 47 AND t.fk_statut = 8
where
llx_ticketsup is main tickets table
llx_fichinter is table where interventions from tickets are stored
llx_element_element is table between tickets and interventions
My problem is, if one ticket has more than 1 intervention, on sum of category types to know how many are from this category and how many from the other, it sums interventions instead tickets. For example, if query returns 2 tickets and they have a total of 6 interventions, it returns 6 tickets of category WITHOUT_MAINTENANCE, instead 2 tickets of category WITHOUT_MAINTENANCE.
Whats wrong? Thanks.
Nothings 'wrong' that's expected behaviour try using a sub query to get the duration. Something like
SELECT (select sum(f.duree) from llx_fichinter as f on f.rowid = ee.fk_target) as total_time, SUM(timestampdiff(second, t.datec, t.date_close))/COUNT(distinct t.rowid) as average_resolution, COUNT(distinct t.rowid) as tickets,
SUM( CASE t.category_code WHEN 'WITHOUT_MAINTENANCE' THEN 1 ELSE 0 END) as sin_mantenimiento,
SUM( CASE t.category_code WHEN 'WITH_MAINTENANCE' THEN 1 ELSE 0 END) as con_mantenimiento,
SUM( CASE t.category_code WHEN 'WITH_BILLABLE_MAINTENANCE' THEN 1 ELSE 0 END) as con_mantenimiento_facturable,
SUM( CASE t.category_code WHEN 'NO_BILLABLE_COASER_WARRANTY' THEN 1 ELSE 0 END) as no_facturable_garantia_coaser,
SUM( CASE t.category_code WHEN 'OFERTADO' THEN 1 ELSE 0 END) as ofertado
FROM llx_ticketsup as t
JOIN llx_element_element as ee on ee.fk_source = t.rowid
WHERE t.fk_soc = 47 AND t.fk_statut = 8
If that doesn't work add sample data and expected result to the question as text so we can play with it.
Could i calc for each row column Profit ?
SELECT
SUM(CASE WHEN m.billable = 0 THEN r.rate ELSE 0 END) AS Revenue, -- 33 + 34 + 456 + 52...etc = 5500
SUM(CASE WHEN m.billable = 1 AND m.optimized = 0 THEN r.rate ELSE 0 END) AS Costs,-- 33 + 4...etc = 339
5500 - 339 AS Profit -- I need to get this difference
FROM messages AS m
JOIN rates AS r ON (r.id = m.rate_id )
GROUP BY
m.client_account_id,
m.mcc,
m.mnc
I want to get
| Revenue | Costs | Profit
5500 500 5000
Move your query into a subquery, then subtract the results.
SELECT Revenue, Costs, Revenue - Costs AS Profit
FROM (
SELECT
SUM(CASE WHEN m.billable = 0 THEN r.rate ELSE 0 END) AS Revenue,
SUM(CASE WHEN m.billable = 1 AND m.optimized = 0 THEN r.rate ELSE 0 END) AS Costs
FROM YourTable) AS x
Joining your two tables, and showing the results grouped by account, it would be:
SELECT client_account_id, mmc, mnc, Revenue, Costs, Revenue - Costs AS Profit
FROM (
SELECT
m.client_account_id, m.mmc, m.mnc
SUM(CASE WHEN m.billable = 0 THEN r.rate ELSE 0 END) AS Revenue,
SUM(CASE WHEN m.billable = 1 AND m.optimized = 0 THEN r.rate ELSE 0 END) AS Costs
FROM messages AS m
JOIN rates AS r ON r.id = m.rate_id
GROUP BY m.client_account_id, m.mmc, m.mnc
) AS x
Simply put it in a sub query :
SELECT Revenue - Costs as Profit
FROM (
SELECT
SUM(CASE WHEN m.billable = 0 THEN r.rate ELSE 0 END) AS Revenue,
SUM(CASE WHEN m.billable = 1 AND m.optimized = 0 THEN r.rate ELSE 0 END) AS Costs
) as temp
I am using SUM ( CASE WHEN ) to count number of Yes and No, it work fine.
I am havin problem counting number of matching mobile number from two tables. It dont seem to be counting correctly.
There is a MobileNO field in dairy table and mobile field in the sales table
SELECT
D.Username,
SUM(CASE WHEN D.type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN D.type = 'No' THEN 1 ELSE 0 END) as No,
SUM(CASE WHEN D.type = '' THEN 1 ELSE 0 END) as Other,
(SELECT SUM(CASE WHEN D.MobileNo = S.mobile THEN 1 ELSE 0 END) from sales as S) as Sales,
COUNT(*) as TOTAL FROM dairy as D
WHERE source = 'Company' AND UNIX_TIMESTAMP(CheckDate) >= 1293840000 AND UNIX_TIMESTAMP(CheckDate) <= 1322697600
group by D.Username order by TOTAL DESC
SELECT
D.Username,
SUM(CASE WHEN D.type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN D.type = 'No' THEN 1 ELSE 0 END) as No,
SUM(CASE WHEN D.type = '' THEN 1 ELSE 0 END) as Other,
SUM(CASE WHEN S.mobile IS NULL THEN 0 ELSE 1 END) as Sales,
COUNT(*) as TOTAL
FROM dairy as D
LEFT JOIN (SELECT DISTINCT mobile FROM sales) as S ON D.MobileNo = S.mobile
WHERE source = 'Company' AND UNIX_TIMESTAMP(CheckDate) >= 1293840000 AND UNIX_TIMESTAMP(CheckDate) <= 1322697600
group by D.Username order by TOTAL DESC