I am trying to write a pivot function in MySQL workbench and many of the places I've looked have not been super relevant.
I currently have:
order_ID Part Description Order number
1 103 A 1
2 104 B 1
3 103 A 2
4 105 C 3
5 103 A 4
6 105 C 4
7 107 D 4
I would like to create:
Order Part1 Description Part2 Description Part3 Description
1 103 A 104 B
2 103 A
3 105 C
4 103 A 105 C 107 D
I can keep the primary key in the output, but it is not necessary. The problem I am running into is that many pivot functions involve using distinct parts names to move them; however, I have over 500 parts. I also would like to move the description and the part together so they are next to each other--most pivot functions are not powerful enough to address that.
I did write a macro to do this in Excel, but it must be done in a database because of further analysis in R and I am pulling data from a database and I must automate any changes made to the data. As a result, I DO NOT have a choice in how the data is organized and laid out. Please do not mention normalizing data or other database techniques because I am trying to fix the data and how messy it is, but I DO NOT have a choice in how the data is inputted.
Some resources I used to gain experience with pivoting in MySQL, but I have not been able to get any code to work.
MySQL pivot table
mysql pivoting - how can I fetch data from the same table into different columns?
http://en.wikibooks.org/wiki/MySQL/Pivot_table
http://buysql.com/mysql/14-how-to-automate-pivot-tables.html
Select group_concat(Table.column1) as anything,
group_concat(Table.column2 separator ';')
AS Anything2, Table.`column3`
FROM Table
group by Table.column3;
Alter TABLE Table ADD
`newcolumn1` varchar(100) DEFAULT '' after `column3`;
Alter TABLE MB ADD
`newcolumn2` varchar(500) DEFAULT '' after `newcolumn1`;
UPDATE Table SET
`newcolumn1` = IF (
LOCATE(',', column1) >0,
SUBSTRING(column1, 1,LOCATE(',', column1)-1),
column1
),
`newcolumn2` = IF(
LOCATE(',', column1) > 0,
SUBSTRING(column1, LOCATE(',', column1)+1),
'');
UPDATE Table SET
newcolumn2 = SUBSTRING_INDEX(newcolumn2, ',', 1);
UPDATE Table SET
newcolumn3 = SUBSTRING_INDEX(newcolumn3, ',', 1);
This code achieved exactly the format I wanted above.
Related
I have a function in MySQL that needs to be run about 50 times (not a set value) in a query. the inputs are currently stored in an array such as
[1,2,3,4,5,6,7,8,9,10]
when executing the MySQL query individually it's working fine, please see below
column_name denotes the column it's getting the data for, in this case, it's a DOUBLE in the database
The second value in the MOD() function is the input I'm supplying MySQL from the aforementioned array
SELECT id, MOD(column_name, 4) AS mod_output
FROM table
HAVING mod_output > 10
To achieve the output I require* the following code works
SELECT id, MOD(column_name, 4) AS mod_output1, MOD(column_name, 5) AS mod_output2, MOD(column_name, 6) AS mod_output3
FROM table
HAVING mod_output1 > 10 AND mod_output2 > 10 AND mod_output3 > 10
However this obviously is extremely dirty, and when having not 3 inputs, but over 50, this will become highly inefficient.
Appart from calling over 50 individual querys, is there a better way to acchieve the same sort (see below) of output?
In escennce i need to supply MySQL with a list of values and have it run MOD() over all of them on a specified column.
The only data I need returned is the id's of the rows that match the MOD() functions output with the specified input (see value 2 of the MOD() function) where the output is less than 10
Please note, MOD() has been used as an example function, however, the final function required *should* be a drop in replacement
example table layout
id | column_name
1 | 0.234977
2 | 0.957739
3 | 2.499387
4 | 48.395777
5 | 9.943782
6 | -39.234894
7 | 23.49859
.....
(The title may be worded wrong, I'm not quite sure how else you'd explain what I'm trying to do here)
Use a join and derived table or temporary table:
SELECT n.n, t.id, MOD(t.column_name, n.n) AS mod_output
FROM table t CROSS JOIN
(SELECT 4 as n UNION ALL SELECT 5 UNION ALL SELECT 6 . . .
) n
WHERE MOD(t.column_name, n.n) > 10;
If you want the results as columns, you can use conditional aggregation afterwards.
Consider the following mysql table:
ID WeightS AmountS WeightM AmountM WeightL AmountL Someothercolumnshere
1 6 3 10 2 18 2 ...
I need to reorganize this data into a pivot-friendly table, where each piece in the amount columns should be one result row. E.g. from the first two columns, WeightS and AmountS, the SELECT should produce 3 result rows, each having a weight of 2 kgs (=6 kgs total). So the full result table should be like this:
Weight Someothercolumnshere
2 ...
2 ...
2 ...
5 ...
5 ...
9 ...
9 ...
I don't even know if there's a SQL syntax which is able to do this kind of operation? I've never had a request like this before. Worst case scenario, I have to do it in php instead, but I think MYSQL is a lot more fun :p
I've built the schema on sqlfiddle, but I'm afraid that's all I've got.
You need a Tally table for the task like this. Create as much rows as needed in it.
Create table Tally(`N` int);
insert into Tally( `N`) values(1),(2),(3),(4),(5);
Then
(select `ID`, `WeightS`/`AmountS`, `Someothercolumnshere`
from Catches
join Tally on Catches.`AmountS` >= Tally.`N`
)
UNION ALL
(select `ID`, `WeightL`/`AmountL`, `Someothercolumnshere`
from Catches
join Tally on Catches.`AmountL` >= Tally.`N`
)
UNION ALL
(select `ID`, `WeightM`/`AmountM`, `Someothercolumnshere`
from Catches
join Tally on Catches.`AmountM` >= Tally.`N`
)
I have 2 tables in a MySQL database (storeskus). The first is FBM_Orders and the second is IM_INV.
I am trying the query
SELECT `FBM_Orders`.`order-id`,`FBM_Orders`.`order-item-id`,`FBM_Orders`.`purchase-date`,
`FBM_Orders`.`promise-date`,`FBM_Orders`.`buyer-name`,`FBM_Orders`.`sku`,
`FBM_Orders`.`product-name`,`FBM_Orders`.`quantity-purchased`,
`FBM_Orders`.`recipient-name`,`IM_INV`.`LOC_ID`,`IM_INV`.`QTY_ON_HND`
FROM `FBM_Orders`
LEFT JOIN `IM_INV` ON `FBM_Orders`.`sku` = `IM_INV`.`ITEM_NO`
WHERE `FBM_Orders`.`quantity-to-ship` > 0
ORDER BY `FBM_Orders`.`purchase-date`, `IM_INV`.`LOC_ID` ASC;
Because the IM_INV table has a 2-part primary key: ITEM_NO & LOC_ID, I am getting 4 lines for each ITEM_NO with the QTY_ON_HND for each of the 4 locations (LOC_ID).
I am fairly new to SQL so I'm thrilled to have gotten this far, but how can I make it so that the result is a single line per ITEM_NO but with a column for each LOC_ID with its QTY_ON_HND?
Example:
My current result is
FBM_Order.sku FBM_Order.quantity-purchased IM_INV.LOC_ID QTY_ON_HND
'SCHO645256' 1 AF 2
'SCHO645256' 1 LO 2
'SCHO645256' 1 S 3
'SCHO645256' 1 SL 1
How can I change that to
FBM_Order.sku FBM_Order.quantity-purchased QTY_ON_HND_AF QTY_ON_HND_LO QTY_ON_HND_S QTY_ON_HND_SL
'SCHO645256' 1 2 2 3 1
?
Thanks!
You may load it as you already do and treat it inside your application, but if you really wanna make that inside your MySQL, try GROUP CONCAT and JSON as follows:
SELECT
GROUP_CONCAT(JSON_OBJECT(
'LOC_ID', IM_INV.LOC_ID,
'QTY_ON_HND', QTY_ON_HND
))
{another fields}
FROM `FBM_Orders`
LEFT JOIN `IM_INV` ON `FBM_Orders`.`sku` = `IM_INV`.`ITEM_NO`
WHERE `FBM_Orders`.`quantity-to-ship` > 0
GROUP BY `FBM_Orders`.`order-id`;
Note: JSON is just available for MySQL 5.7+ and may slow down your query a little bit. You're still gonna need convert your data to array inside your application. So it's half done inside your app and half inside your database.
I have a some entries in database table rows as follows.
101 - 1
101 - 2
101 - 3
102 - 1
102 - 2
102 - 3
103
I need to get the result of SELECT Query for count as '3' since there are 101 and 102 are the only number before the -.
So is there any way to find the unique value in db table columns before a character?
EDIT : I have entries even without the - .
In case your entries have always the format you have provided us, you just have to find the position of the '-' character, split the values, get the first n characters and count the distinct values
This works for SQL Server, otherwise informs us about what DBMS you are using or replace the functions with the ones of your DBMS on your own
SELECT COUNT(DISTINCT SUBSTRING(val,0,CHARINDEX('-', val))) from YourTable
create table T1
(
id int primary key identity,
col1 varchar(20)
)
insert into T1 values('101 - 1'),('101 - 2'),('101 - 3'),('102 - 1'),('102 - 2'),('102 - 3')
select SUBSTRING(col1,0,CHARINDEX(' ',col1)) as 'Value',count(*) as 'Count' from T1 group by SUBSTRING(col1,0,CHARINDEX(' ',col1))
I have a strange query to perform from a website. I have sets of arrays that contain pertinent ids from a many tables - 1 table per array. For example (the array name is the name of the table):
Array Set 1:
array "q": 1,2,3
array "u": 1,5
array "k": 7
Array Set 2:
array "t": 2,12
array "o": 8, 25
Array Set 3 (not really a set):
array "e": 5
I have another table, Alignment, which is not represented by the arrays. It performs a one to many relationship, allowing records from tables q,u, and k (array set 1, and recorded as relType/relID in the table) to be linked to records from t and o (array set 2, recorded as keyType/keyID) and e (array set 3, recorded as keyType/keyID). Example below:
Table: Alignment
id keyType keyID relType relID
1 e 5 q 1
2 o 8 q 1
3 o 8 u 1
4 t 2 q 2
5 t 2 k 7
6 t 12 q 1
So, in record 6, a record with an id of 12 from table t is being linked to a record with an id of 1 from table q.
I have to find missing links. The ideal state is that each of the ids from array set 1 have a record in the alignment table linking them to at least 1 record from array set 2. In the example, alignment record 1 does not count towards this goal, because it aligns a set 1 id to a set 3 id (instead of set 2).
Scanning the table, you can quickly see that there are some missing ids from array set 1: "q"-3 and "u"-5.
I've been doing this with script, by looping through each set 1 array and looking for a corresponding record, which generates a whole bunch of sql calls and really kills any page that calls this function.
Is there some way I could accomplish this in a single sql statement?
What would I like the results to look like (ideally):
recordset (consisting magically of data that didn't exist in the table):
relType | relID
q 3
u 5
However, I would be elated with even a binary type answer from the database - were all the proper ids found: true or false? (Though the missing records array is required for other functions, but at least I'd be able to choose between the fast and slow options).
Oh, MySQL 5.1.
User Damp gave me an excellent answer using a temporary table, a join, and an IS NULL statement. But it was before I added in the wrinkle that there was a third array set that needed to be excluded from the results, which also ruins the IS NULL part. I edited his sql statement to look like this:
SELECT *
FROM k2
LEFT JOIN alignment
USING ( relType, relID )
HAVING alignment.keyType IS NULL
OR alignment.keyType = "e"
I've also tried it with a Group By relID (i always thought that was a requirement of the HAVING clause). The problem is that my result set includes "q"-1, which is linked to all three types of records ("o","t", and "e"). I need this result excluded, but I'm not sure how.
Here's the sql I ended up with:
SELECT *
FROM k2
LEFT JOIN (
SELECT *
FROM alignment
WHERE keyType != 'e' and
(
(relType = 'q' AND relID IN ( 1, 2, 3 ))
OR
(relType = 'u' AND relID IN ( 1, 5 ))
OR
(relType = 'k' AND relID IN ( 7 ))
)
)A
USING ( relType, relID )
HAVING keyType Is Null
I have to dump the values for the IN qualifiers with script. The key was not to join to the alignment table directly.
You can try to go this route:
DROP TABLE IF EXISTS k2;
CREATE TEMPORARY TABLE k2 (relType varchar(10),relId int);
INSERT INTO k2 VALUES
('q',1),
('q',2),
('q',3),
('u',1),
('u',5),
('k',7);
SELECT * FROM k2
LEFT JOIN Alignment USING(relType,relId)
HAVING Alignment.keyType IS NULL
This should work well for small tables. Not sure about very large ones though...
EDIT
If you wanted to add a WHERE statement the query would be as follow
SELECT * FROM k2
LEFT JOIN Alignment USING(relType,relId)
WHERE Alignment.keyType != 'e'
HAVING Alignment.keyType IS NULL