MySQL how to calculate after stock taking - mysql

Data tables in the following manner;
Firm | PartID | StockCount | Date | Type
-----------------------------------------------------------
1 | 71 | 5 | 2014-02-01 | Incoming Invoice
1 | 71 | -1 | 2014-02-09 | Send Invoice
1 | 71 | 10 | 2014-02-13 | Stocktaking ( !!! Of the Depot. )
1 | 71 | -1 | 2014-02-21 | Send Invoice
1 | 71 | 5 | 2014-02-28 | Incoming Invoice
This table is actually a stock is a fictionalized depiction of movement table. Counts in this table made ​​in the store, purchase and sales invoices include. In this way, entering the warehouse, from the warehouse and the warehouse will be collected in a table quantities actually counted. From the moment that made ​​the Census, stock values ​​should be calculated over the stated amount. Where the problem was coming.
How do I get the following result?
Firm | PartID | StockCount | Date | Type
-------------------------------------------------------
1 | 71 | 14 | NULL | NULL

You seem to want the sum of the stock after "stock taking", which I suspect is more normally called "doing inventory" in English.
select Firm, PartId, sum(StockCount) as StockCount, NULL as Date, NULL as Type
from table t
where Date >= (select max(Date)
from table t2
where t2.Firm = t.Firm and
t2.partid = t.partid and
t2.type = 'Stocktaking'
)
group by Firm, Partid;
If there may be no Stocktaking record, then go with a left join approach:
select Firm, PartId, sum(StockCount) as StockCount, NULL as Date, NULL as Type
from table t left join
(select Firm, PartId, max(Date) as maxDate
from table t
where t2.type = 'Stocktaking'
group by Firm, PartId
) as tfp
on t.Firm = tfp.Firm and t.PartId = tfp.PartId and t.Date >= tfp.MaxDate
group by t.Firm, t.PartId;

If I am reading it right:
SELECT firm, partid, count(stockCount) as stock_total
FROM yourtable
WHERE firm = 1
AND partid = 71
You'll need to group by if you want to select multiple parts, something like:
SELECT firm, partid, count(stockCount) as stock_total
FROM yourtable
WHERE firm = 1
GROUP BY partid

Try this
SELECT Firm,
PartID,
Count(StockCount),
Date AS NULL,
TYPE AS NULL
FROM TABLE
GROUP BY Firm,
PartID

Your explanation of the problem is unclear, but I assume it is what you want.
SELECT Firm, PartID, SUM(StockCount) as StockCount, NULL as Date, NULL as Type
FROM tbl T1
WHERE Date >= (SELECT Date FROM tbl T2
WHERE T2.Type = Stocktaking
AND T1.Firm =T2.Firm
AND T1.PartId = T2.PartId
)
GROUP BY Firm, PartID

Related

Joining multiple select sql statements (4 tables)

I need to join together 2 SQL statements and both of those statements work on their own. But I don't know how to combine both into 1 SQL statement.
I have two tables in 1st statement, TR120 and TR1201.
The SQL is this:
select
PRODUCT, PRICE, QUANTITY, INVOICE.DATE
from
TR1201
left join
(select
DATE, ID as INVOICE_ID, INVOICE
from TR120) as INVOICE on INVOICE.INVOICE_ID = ID
where
INVOICE.DATE >= '2016-06-01' and INVOICE.DATE <= '2016-06-30'
This returns a list of all the products I sold, with price, quantity and date of sales in a specific time frame from 01-06-16 till 30-06-16.
Now I need to find out the latest price that I bought product for in different two tables TR100 and TR1001 based on the product and date of sale from the 1st SQL statement.
select
PRODUCT, PRICE, SUP.DATE
from
TR1001
left join
(select
DATE, ID as SUP_ID, SUP_INVOICE
from TR100) as SUP on SUP.SUP_ID = ID
This returns a list of all the products that I have bought with a price and a date. I only need last record from this query based on product and date of purchased.
TR120
ID | INVOICE | DATE
1 | 000001 |2016-06-05
2 | 000002 |2016-06-15
3 | 000003 |2016-06-25
TR1201
ID | PRODUCT | PRICE A | QUANTITY
1 | A | 2,00 | 5
2 | A | 2,00 | 2
3 | A | 2,00 | 1
TR100
ID | SUP_INVOICE | DATE
1 | 160001 | 2016-05-30
2 | 160002 | 2016-06-16
TR1001
ID | PRODUCT | PRICE B
1 | A | 0,5
2 | A | 0,7
The result I am trying to get is this:
PRODUCT | PRICE A (tr1201) | QUANTITY | DATE (tr100) | PRICE B (tr1001)
A | 2 | 5 | 2016-05-30 | 0,5
A | 2 | 2 | 2016-05-15 | 0,5
A | 2 | 1 | 2016-05-16 | 0,7
That is all I want to do :(
Have you tried first_value?
FIRST_VALUE ( [scalar_expression ] )
OVER ( [ partition_by_clause ] order_by_clause [ rows_range_clause ] )
it works like this:
select distinct id,
first_value(price) over (partition by id (,sup) order by date DESC (latest, ASC for oldest)) as last_price
from table;
Documentation can be found here: https://msdn.microsoft.com/en-us/library/hh213018.aspx
I don't have your tables so cannot test and therefore am providing advice only.
I think what you need is an Outer apply like this instead of joins
select
T1.Product
, T1.Price
, T2.DATE -- Alias this
, T2.Price -- Alias this
, T3.DATE -- Alias this
, T3.Price -- Alias this
from T1
OUTER APPLY (
select top 1
Date
,Price
from table2
WHERE ID = T1.Id AND product = T1.Product-- plus any other joins
ORDER BY Date desc
) as T2
OUTER APPLY (
select top 1
Date
,Price
from table3
WHERE ID = T1.Id AND product = T1.Product-- plus any other joins
ORDER BY Date desc
) as T3

Deleting all but the most recent entry from single SQL table

I have a single SQL table that contains multiple entries for each customerID (some customerID's only have one entry which I want to keep). I need to remove all but the most recent entry per customerID, using the invoiceDate field as my marker.
So I need to go from this:
+------------+-------------+-----------+
| customerID | invoiceDate | invoiceID |
+------------+-------------+-----------+
| 1 | 1393995600 | xx |
| 1 | 1373688000 | xx |
| 1 | 1365220800 | xx |
| 2 | 1265220800 | xx |
| 2 | 1173688000 | xx |
| 3 | 1325330800 | xx |
+------------+-------------+-----------+
To this:
+------------+-------------+-----------+
| customerID | invoiceDate | invoiceID |
+------------+-------------+-----------+
| 1 | 1393995600 | xx |
| 2 | 1265220800 | xx |
| 3 | 1325330800 | xx |
+------------+-------------+-----------+
Any guidance would be greatly appreciated!
Write a query to select all the rows you want to delete:
SELECT * FROM t
WHERE invoiceDate NOT IN (
SELECT MAX(invoiceDate)
-- "FROM t AS t2" isn't supported by MySQL, see http://stackoverflow.com/a/14302701/227576
FROM (SELECT * FROM t) AS t2
WHERE t2.customerId = t.customerId
GROUP BY t2.customerId
)
This may take a long time on a big database.
If you're satisfied, change the query to a DELETE statement:
DELETE FROM t
WHERE invoiceDate NOT IN (
SELECT MAX(invoiceDate)
-- "FROM t AS t2" isn't supported by MySQL, see http://stackoverflow.com/a/14302701/227576
FROM (SELECT * FROM t) AS t2
WHERE t2.customerId = t.customerId
GROUP BY t2.customerId
)
See http://sqlfiddle.com/#!9/6e031/1
If you have multiple rows whose date is the most recent for the same customer, you would have to look for duplicates and decide which one you want to keep yourself. For instance, look at customerId 2 on the SQL fiddle link above.
Try out this one
with todelete as
(
select
CustomerId, InvoiceId, InvoiceDate, Row_Number() over (partition by CustomerId order by InvoiceDate desc) as Count
from DeleteDuplicate
)
delete from todelete
where count > 1
Let us asume that the table name is transaction_table.
create table test1 AS
select * from (
select * from transaction_table order by customerID, invoiceDate desc) temp
group by customerID
You will have the output data in test1 table.
delete from ex_4 where
rowid in
(select rowid
from ex_4 a
where to_date(invoicedate,'DDMMYYYY') = (select max(to_date(invoicedate,'DDMMYYYY')) from ex_4 b where a.customerid != b.customerid))
This is how it will be done in oracle.This query will delete all but most recently added row.Looking at your table structure i am assuming that the invoicedate column is varchar2 type so converting it to date used to_date function here

MySQL count daily new users VS returned users (cohort analysis)

The table structure is: user_id, Date (I'm used to work with timestamp)
for example
user id | Date (TS)
A | '2014-08-10 14:02:53'
A | '2014-08-12 14:03:25'
A | '2014-08-13 14:04:47'
B | '2014-08-13 04:04:47'
...
and for the next week I have
user id | Date (TS)
A | '2014-08-17 09:02:53'
B | '2014-08-17 10:04:47'
B | '2014-08-18 10:04:47'
A | '2014-08-19 10:04:22'
C | '2014-08-19 11:04:47'
...
and for today I have
user id | Date (TS)
A | '2015-05-27 09:02:53'
B | '2015-05-27 10:04:47'
C | '2015-05-27 10:04:22'
D | '2015-05-27 17:04:47'
I need to know how to perform a single query to find the number of users which are a "returned" user from the very beginning of their activity.
Expected results :
date | New user | returned User
2014-08-10 | 1 | 0
2014-08-11 | 0 | 0
2014-08-12 | 0 | 1 (A was active on 08/11)
2014-08-13 | 1 | 1 (A was active on 08/12 & 08/11)
...
2014-08-17 | 0 | 2 (A & B were already active )
2014-08-18 | 0 | 1
2014-08-19 | 1 | 1
...
2015-05-27 | 1 | 3 (D is a new user)
After some long search on Stackoverflow I found some material provided by https://meta.stackoverflow.com/users/107744/spencer7593 here : Weekly Active Users for each day from log but I didn't succeed to change his query to output my expected results.
Thanks for your help
Assuming you have a date table somewhere (and using t-sql syntax because I know it better...) the key is to calculate the mindate for each user separately, calculate the total number of users on that day, and then just declaring a returning user to be a user who wasn't new:
SELECT DateTable.Date, NewUsers, NumUsers - NewUsers AS ReturningUsers
FROM
DateTable
LEFT JOIN
(
SELECT MinDate, COUNT(user_id) AS NewUsers
FROM (
SELECT user_id, min(CAST(date AS Date)) as MinDate
FROM Table
GROUP BY user_id
) A
GROUP BY MinDate
) B ON DateTable.Date = B.MinDate
LEFT JOIN
(
SELECT CAST(date AS Date) AS Date, COUNT(DISTINCT user_id) AS NumUsers
FROM Table
GROUP CAST(date AS Date)
) C ON DateTable.Date = C.Date
Thanks to Stephen, I made a short fix on his query, which works well even it's a bit time consuming on large database :
SELECT
DATE(Stats.Created),
NewUsers,
NumUsers - NewUsers AS ReturningUsers
FROM
Stats
LEFT JOIN
(
SELECT
MinDate,
COUNT(user_id) AS NewUsers
FROM (
SELECT
user_id,
MIN(DATE(Created)) as MinDate
FROM Stats
GROUP BY user_id
) A
GROUP BY MinDate
) B
ON DATE(Stats.Created) = B.MinDate
LEFT JOIN
(
SELECT
DATE(Created) AS Date,
COUNT(DISTINCT user_id) AS NumUsers
FROM Stats
GROUP BY DATE(Created)
) C
ON DATE(Stats.Created) = C.Date
GROUP BY DATE(Stats.Created)

nested query & transaction

Update #1: query gives me syntax error on Left Join line (running the query within the left join independently works perfectly though)
SELECT b1.company_id, ((sum(b1.credit)-sum(b1.debit)) as 'Balance'
FROM MyTable b1
JOIN CustomerInfoTable c on c.id = b1.company_id
#Filter for Clients of particular brand, package and active status
where c.brand_id = 2 and c.status = 2 and c.package_id = 3
LEFT JOIN
(
SELECT b2.company_id, sum(b2.debit) as 'Current_Usage'
FROM MyTable b2
WHERE year(b2.timestamp) = '2012' and month(b2.timestamp) = '06'
GROUP BY b2.company_id
)
b3 on b3.company_id = b1.company_id
group by b1.company_id;
Original Post:
I keep track of debits and credits in the same table. The table has the following schema:
| company_id | timestamp | credit | debit |
| 10 | MAY-25 | 100 | 000 |
| 11 | MAY-25 | 000 | 054 |
| 10 | MAY-28 | 000 | 040 |
| 12 | JUN-01 | 100 | 000 |
| 10 | JUN-25 | 150 | 000 |
| 10 | JUN-25 | 000 | 025 |
As my result, I want to to see:
| Grouped by: company_id | Balance* | Current_Usage (in June) |
| 10 | 185 | 25 |
| 12 | 100 | 0 |
| 11 | -54 | 0 |
Balance: Calculated by (sum(credit) - sum(debits))* - timestamp does not matter
Current_Usage: Calculated by sum(debits) - but only for debits in JUN.
The problem: If I filter by JUN timestamp right away, it does not calculate the balance of all time but only the balance of any transactions in June.
How can I calculate the current usage by month but the balance on all transactions in the table. I have everything working, except that it filters only the JUN results into the current usage calculation in my code:
SELECT b.company_id, ((sum(b.credit)-sum(b.debit))/1024/1024/1024/1024) as 'BW_remaining', sum(b.debit/1024/1024/1024/1024/28*30) as 'Usage_per_month'
FROM mytable b
#How to filter this only for the current_usage calculation?
WHERE month(a.timestamp) = 'JUN' and a.credit = 0
#Group by company in order to sum all entries for balance
group by b.company_id
order by b.balance desc;
what you will need here is a join with sub query which will filter based on month.
SELECT T1.company_id,
((sum(T1.credit)-sum(T1.debit))/1024/1024/1024/1024) as 'BW_remaining',
MAX(T3.DEBIT_PER_MONTH)
FROM MYTABLE T1
LEFT JOIN
(
SELECT T2.company_id, SUM(T2.debit) T3.DEBIT_PER_MONTH
FROM MYTABLE T2
WHERE month(T2.timestamp) = 'JUN'
GROUP BY T2.company_id
)
T3 ON T1.company_id-T3.company_id
GROUP BY T1.company_id
I havn't tested the query. The point here i am trying to make is how you can join your existing query to get usage per month.
alright, thanks to #Kshitij I got it working. In case somebody else is running into the same issue, this is how I solved it:
SELECT b1.company_id, ((sum(b1.credit)-sum(b1.debit)) as 'Balance',
(
SELECT sum(b2.debit)
FROM MYTABLE b2
WHERE b2.company_id = b1.company_id and year(b2.timestamp) = '2012' and month(b2.timestamp) = '06'
GROUP BY b2.company_id
) AS 'Usage_June'
FROM MYTABLE b1
#Group by company in order to add sum of all zones the company is using
group by b1.company_id
order by Usage_June desc;

MySQL grouping by date range with multiple joins

I currently have quite a messy query, which joins data from multiple tables involving two subqueries. I now have a requirement to group this data by DAY(), WEEK(), MONTH(), and QUARTER().
I have three tables: days, qos and employees. An employee is self-explanatory, a day is a summary of an employee's performance on a given day, and qos is a random quality inspection, which can be performed many times a day.
At the moment, I am selecting all employees, and LEFT JOINing day and qos, which works well. However, now, I need to group the data in order to breakdown a team or individual's performance over a date range.
Taking this data:
Employee
id | name
------------------
1 | Bob Smith
Day
id | employee_id | day_date | calls_taken
---------------------------------------------
1 | 1 | 2011-03-01 | 41
2 | 1 | 2011-03-02 | 24
3 | 1 | 2011-04-01 | 35
Qos
id | employee_id | qos_date | score
----------------------------------------
1 | 1 | 2011-03-03 | 85
2 | 1 | 2011-03-03 | 95
3 | 1 | 2011-04-01 | 91
If I were to start by grouping by DAY(), I would need to see the following results:
Day__date | Day__Employee__id | Day__calls | Day__qos_score
------------------------------------------------------------
2011-03-01 | 1 | 41 | NULL
2011-03-02 | 1 | 24 | NULL
2011-03-03 | 1 | NULL | 90
2011-04-01 | 1 | 35 | 91
As you see, Day__calls should be SUM(calls_taken) and Day__qos_score is AVG(score). I've tried using a similar method as above, but as the date isn't known until one of the tables has been joined, its only displaying a record where there's a day saved.
Is there any way of doing this, or am I going about things the wrong way?
Edit: As requested, here's what I've come up with so far. However, it only shows dates where there's a day.
SELECT COALESCE(`day`.day_date, qos.qos_date) AS Day__date,
employee.id AS Day__Employee__id,
`day`.calls_taken AS Day__Day__calls,
qos.score AS Day__Qos__score
FROM faults_employees `employee`
LEFT JOIN (SELECT `day`.employee_id AS employee_id,
SUM(`day`.calls_taken) AS `calls_in`,
FROM faults_days AS `day`
WHERE employee.id = 7
GROUP BY (`day`.day_date)
) AS `day`
ON `day`.employee_id = `employee`.id
LEFT JOIN (SELECT `qos`.employee_id AS employee_id,
AVG(qos.score) AS `score`
FROM faults_qos qos
WHERE employee.id = 7
GROUP BY (qos.qos_date)
) AS `qos`
ON `qos`.employee_id = `employee`.id AND `qos`.qos_date = `day`.day_date
WHERE employee.id = 7
GROUP BY Day__date
ORDER BY `day`.day_date ASC
The solution I'm comming up with looks like:
SELECT
`date`,
`employee_id`,
SUM(`union`.`calls_taken`) AS `calls_taken`,
AVG(`union`.`score`) AS `score`
FROM ( -- select from union table
(SELECT -- first select all calls taken, leaving qos_score null
`day`.`day_date` AS `date`,
`day`.`employee_id`,
`day`.`calls_taken`,
NULL AS `score`
FROM `employee`
LEFT JOIN
`day`
ON `day`.`employee_id` = `employee`.`id`
)
UNION -- union both tables
(
SELECT -- now select qos score, leaving calls taken null
`qos`.`qos_date` AS `date`,
`qos`.`employee_id`,
NULL AS `calls_taken`,
`qos`.`score`
FROM `employee`
LEFT JOIN
`qos`
ON `qos`.`employee_id` = `employee`.`id`
)
) `union`
GROUP BY `union`.`date` -- group union table by date
For the UNION to work, we have to set the qos_score field in the day table and the calls_taken field in the qos table to null. If we don't, both calls_taken and score would be selected into the same column by the UNION statement.
After this, I selected the required fields with the aggregation functions SUM() and AVG() from the union'd table, grouping by the date field in the union table.