I'm trying to adjust stock code that pulls data from two tables, in order to add a column from a third table.
Here is the original query:
SELECT a.*, b.*, a.id as jobid
from #__ja_jobs a
LEFT JOIN #__users b
ON a.user_id = b.id
WHERE 1=1
I tried this approach, but it did not seem to work.
SELECT a.*, b.*, c.user_id_value, a.id as jobid
from #__ja_jobs a
LEFT JOIN #__users b
ON a.user_id = b.id
WHERE 1=1
INNER JOIN #__ja_jobs_value c
ON a.id = c.id`
And I tried to also move the WHERE statement at the end, but still no luck. Any suggestions?
UPDATE: All fixed! I moved the WHERE to the end and then remembered a ridiculous rookie mistake - spaces at the end of all the lines.
Related
This query is NOT legal syntax and I'm trying to understand what the efficient way of writing it is. This is what I have:
SELECT a.*, b.id, lapsed FROM
( SELECT DATEDIFF(CURDATE(), MAX(day)) AS lapsed FROM c ) AS x
FROM first_table a
INNER JOIN second_table b ON a.id = b.some_id
INNER JOIN third_table c ON c.user_id = a.user_id
WHERE a.some_col = 'm'
AND b.num >= lapsed
There's three tables being joined. Normally this would be trivial, but the problem is my last part of the WHERE clause, specifically b.num >= lapsed is doing a comparison on a derived value. Is there a correct way to write this?
Haven't tested this, but if the subquery is correct then this should work.
I also assumed that the 'c' in the example of the question is also referring to that third_table and not some table/view called c.
And the INNER JOIN to third_table was commented out, since it's mostly useless to INNER JOIN table/views when you don't use any fields of it. Well, it could be used to limit on records that are in that table, but most often it's just useless to do that.
SELECT a.*, b.id, x.lapsed
FROM first_table a
INNER JOIN second_table b ON a.id = b.some_id
--INNER JOIN third_table c ON c.user_id = a.user_id
LEFT JOIN (
SELECT DATEDIFF(CURDATE(), MAX(day)) AS lapsed
FROM third_table
) AS x ON (1=1)
WHERE a.some_col = 'm'
AND b.num >= x.lapsed;
Given the MAX() aggregate, it looks like you want the latest day value for each user_id value from third_table.
To get that, we can write a query like this:
SELECT c.user_id
, DATEDIFF(CURDATE(),MAX(c.day)) AS lapsed
FROM third_table c
GROUP BY c.user_id
You can use the resultset from this query as a rowsource in another query, by using that query as a inline view in place of a table reference. (MySQL refers to an inline view as a "derived table".)
We just wrap that query in parens, and use it in place of where we would normally find a table reference. The inline view (derived table) will need to be assigned an alias.
For example:
SELECT a.*
, b.id
, d.lapsed
FROM first_table a
JOIN second_table b
ON b.some_id = a.id
JOIN ( SELECT c.user_id
, DATEDIFF(CURDATE(),MAX(c.day)) AS lapsed
FROM third_table c
GROUP BY c.user_id
) d
ON d.user_id = a.user_id
WHERE a.some_col = 'm'
AND b.num > d.lapsed
A query similar to that should run. But whether that returns the resultset you expect to achieve, that really depends on what result you are attempting to return. Absent a specification (apart from some invalid query syntax), we're just guessing.
I have 5 tables: a, b, c, d and e.
Each table is joined by an INNER JOIN on the id field.
My query is working perfectly fine as it is but I need to enhance it to count the result so I can echo it to the screen. I have not been able to get the count working.
There are very specific fields I am querying:
state_nm
status
loc_type
These are all parameters I enter manually into the query like so:
$_POST["state_nm"] = 'AZ'; ... // and for all other below values..
SELECT *
FROM main_table AS a
INNER JOIN table_1 AS b ON a.id = b.id
INNER JOIN table_2 AS c ON b.id = c.id
INNER JOIN blm table_3 AS d ON c.id = d.id
INNER JOIN table_4 AS e ON d.id = e.id
WHERE a.trq != ''
AND b.state_nm = '".$_POST["state_nm"]."'
AND b.loc_type LIKE \ "%".$_ POST ["loc_type"]."%\"
AND b.STATUS = '".$_POST["status"]."'
GROUP BY b.NAME
ORDER BY c.county ASC;
not sure I get exactly what is your goal here.
anyway, using "select *" and group by in the same query is not recommended and in some databases will raise an error
what I would do is something like that:
select a.name, count(*) from (
SELECT * FROM main_table as a
INNER JOIN table_1 as b
ON a.id=b.id
INNER JOIN table_2 as c
ON b.id=c.id
INNER JOIN blm table_3 as d
ON c.id=d.id
INNER JOIN table_4 as e
ON d.id=e.id
WHERE a.trq != ''
AND b.state_nm = '".$_POST["state_nm"]."'
AND b.loc_type LIKE \"%".$_POST["loc_type"]."%\"
AND b.status = '".$_POST["status"]."'
)a
group by a.name
the basic idea is to add an outer query and use group by on it...
hopefully this solves your problem.
In place of
SELECT *
in your query, you could replace that with
SELECT COUNT(*)
That query should return the number of rows that would be in the resultset for the query using SELECT *. Pretty easy to test, and compare the results.
I think that answers the question you asked. If not, I didn't understand your question.
I didn't notice the GROUP BY in your query.
If you want to get a count of rows returned by that query, wrap it in outer query.
SELECT COUNT(1) FROM (
/* your query here */
) c
That will give you a count of rows returned by your query.
Problem:
I'm trying to figure out how to join tables based on a condition in an SQL statement. I've spent an hour searching Google, SO, various websites and the MYSQL manual, but I just can't find the correct syntax for what I want to do.
I can't post the exact query I'm trying to get working, but I will post a simplified version for simplicity reasons.
Scenario:
Assuming I have three tables, a = person table, b = address table and c = car table.
Table b will always be joined to table a, becuase a person always lives at an address, but table c should only be joined to a if the value in the 'car_id' field is more than 0, because having a car is optional.
The query:
SELECT a.firstname, a.lastname, a.gender, a.address_id, b.address_firstline, b_address_secondline, b.postcode, c.car_manufacturer, c.car_model
FROM a
INNER JOIN b ON b.id = a.address_id
INNER JOIN c ON c.id = a.car_id AND a.car_id > 0
WHERE a.id = 1
The query above will run fine for a person with the id of 1 because he owns a car. However, if the query is run for a person with the id of 2, the query will return 0 rows because she does not own a car.
How do I make this second JOIN optional? I've tried using the IF ELSE statement, but I'm forever getting syntax errors. Could someone point me in the right direction here? Thanks in advance
You should use left outer join to join c with a.
SELECT a.firstname, a.lastname, a.gender, a.address_id, b.address_firstline, b_address_secondline, b.postcode, c.car_manufacturer, c.car_model
FROM a
INNER JOIN b ON b.id = a.address_id
LEFT OUTER JOIN c ON c.id = a.car_id AND a.car_id > 0
WHERE a.id = 1
Use LEFT JOIN instead of INNER JOIN on table c.
Unilateral joins work on this scenario.
A brief explanation.
a INNER JOIN b ON a.field1 = b.field1 returns every row for which both a.field1 and b.field1 exist and are equal
a LEFT JOIN b ON a.field1 = b.field1 returns every row from table a and returns every row in table b for which a.field1 = b.field1, and null values for non-matching values on table b.
RIGHT JOIN is analogous to LEFT JOIN
Can anyone help me with this query?
I have three tables (A;B;C)
A <--1....N---> B <--1....N---> C
I want all A rows having C.dates (the greatest)
SELECT A.*, MAX(C.dates)
FROM A
JOIN B ON B.A_fk = A.id
JOIN C ON C.B_fk = B.id
GROUP BY A.id
This JOIN will exclude results which wont have LEFT join. That is, if any row from A wont have B row or any row from B wont have any C row, then the row wont show. To overcome this you can use LEFT JOIN instead of JOIN.
SELECT A.*, MAX(C.dates)
FROM A
LEFT JOIN B ON B.A_fk = A.id
LEFT JOIN C ON C.B_fk = B.id
GROUP BY A.id
EDIT: Sorry didnt noticed that you needed the greatest value of C.data. There you have it. You have to use MAX function in SELECT and GROUP BY A.id
I'm coming across this situation alot, I'll have a query that will have one table needed in a join condition that may have no entries therefore requiring me to use a LEFT JOIN. I can't wrap my head around the syntax when it's used with more than 1 join.
I'll have:
SELECT A.*, B.*, C.*
FROM A, B, C
WHERE A.id = C.id
AND C.aid = A.id
AND B.cid = C.id
Along comes D with the possibility of being empty and I have to rewrite the query and run into problems.
How can I simply join D to any one of these tables?
You're much better off explicitly specifying all of your JOINs. That should make things much clearer.
SELECT A.*, B.*, C.*, D.*
FROM A
INNER JOIN C
ON C.aid = A.id
INNER JOIN B
ON B.cid = C.id
LEFT JOIN D
ON C.did = d.id
My advice is to never specify more than one column on FROM clause.
For clarity, it's better to always:
Use JOIN clause
Use aliases
Specify columns of joined tables on left side of equal sign
Example:
SELECT a.*, b.*, c.*
FROM ATable a
INNER JOIN BTable b
ON b.id = a.id
INNER JOIN CTable c
ON c.id = a.id
WHERE a.someColumn = 'something'
Not sure about MySQL, but in some other SQL flavors, you can use the same on UPDATES and DELETES, like:
DELETE FROM a
FROM ATable a
INNER JOIN BTable b
ON b.id = a.id
INNER JOIN CTable c
ON c.id = a.id
WHERE a.someColumn = 'something'
or
UPDATE a
SET something = newValue
FROM ATable a
INNER JOIN BTable b
ON b.id = a.id
INNER JOIN CTable c
ON c.id = a.id
WHERE a.someColumn = 'something'
The syntax below should help you. The basic premise is whatever table is listed LEFT is the required.. the table (or alias) on the right is optional. I understand you don't quite get it, and your syntax sample shows that (not meant to criticize) as you are joining from A -> C and C back to A on a different field. If this is the case where two fields are in the "C" table that BOTH point to A, you would re-join to A as a second alias...
select
Want.*,
Maybe.*,
SecondA.*,
B.*
From
A as Want
LEFT JOIN C as Maybe
on Want.ID = Maybe.ID
JOIN A as SecondA
on Maybe.AID = SecondA.ID
JOIN B
on Maybe.ID = B.cID
So, this query is stating I want everything from Table A (alias Want -- left side/first table in the list) Regardless of there being a match in Table C (alias Maybe) where the ID keys match.
Notice the next joins going down from "C" back to the second instance of "A" and table B. I have those as just joins... So the relationship between the "Maybe" alias, and that of second instance of "A" and "B" are JOIN (required).
Hopefully this gives some better clarification on HOW it works.
Now, for your real-life query. If you can describe what you are looking for, and your sample table structures / result expections, listing that could offer more explicit solution to your needs.
Hope this will help
SELECT
A.*, B.*, C.*
FROM A
inner join C on(A.id = C.id)
inner join B on(B.cid = C.id)