I have table like this
my_table
id my_json
1 ['1','2','3']
2 ['2']
3 ['2','3']
...
12000 ....
I want to find all distinct values in json's arrays
like this
result
'1'
'2'
'3'
I have this code but i need split values to rows
set #items = (SELECT
GROUP_CONCAT(
REPLACE(REPLACE(lower(my_json), ']', ''), '[', '')
SEPARATOR ','
)
FROM my_table);
SELECT CONCAT ('[',#items,']') AS jarray;
result is
[1,2,3]
probably somebody have ideas?
You can use json_table:
select json_arrayagg(t2.v) from (select distinct t1.v from tbl t
cross join json_table(t.my_json, '$[*]' columns( v int path '$')) t1) t2
See fiddle.
Good day i would like to ask if this is possible in MySQL
SELECT id,label,name,age,sex FROM table LIMIT 3
Output
[row1] id,label,name,age,sex
[row2] id,label,name,age,sex
[row3] id,label,name,age,sex
My Output Needed
[row1] id
[row2] label
[row3] name
[row4] age
[row5] sex
[row6] id
[row7] label
[row8] name
[row9] age
[row10] sex
[row11] id
[row12] label
[row13] name
[row14] age
[row15] sex
You can do something like this:
SELECT * FROM
((SELECT id AS id1, 1 AS rownum, 'id' AS colname, id AS Data_value FROM mytable LIMIT 3)
UNION ALL
(SELECT id, 2, 'label', label FROM mytable LIMIT 3)
UNION ALL
(SELECT id, 3, 'name', name FROM mytable LIMIT 3)
UNION ALL
(SELECT id, 4, 'age', age FROM mytable LIMIT 3)
UNION ALL
(SELECT id, 5, 'sex', sex FROM mytable LIMIT 3)) A
ORDER BY id1, rownum
Here's a fiddle: https://www.db-fiddle.com/f/dvg6x1vBg6H5bDNp9VZxQa/4
I've added 3 additional column id AS id1, rownum and colname. The first two additional column is used for ORDER BY at the outer query. If you don't want to see the additional column, you can just type SELECT Data_value FROM ... at the outer query.
You can use group_concat() to aggregate rows by string concatenation. For the LIMIT to work you then need to use a derived table. But you should be careful with a LIMIT without an ORDER BY. As the order of a query result can be random unless an explicit ORDER BY is issued, you may get different results each time you run the query.
SELECT group_concat(id,
'\n',
label,
'\n',
name,
'\n',
age,
'\n',
sex
SEPARATOR '\n')
FROM (SELECT id,
label,
name,
age,
sex
FROM elbat
LIMIT 3) x;
If you just want to concatenate the columns but keep the rows just use concat().
SELECT concat(id,
'\n',
label,
'\n',
name,
'\n',
age,
'\n',
sex)
FROM elbat
LIMIT 3;
yes,you can use union all like below :
SELECT id FROM table LIMIT 3
union all
SELECT label FROM table LIMIT 3
union all
SELECT name FROM table LIMIT 3
union all
SELECT age FROM table LIMIT 3
union all
SELECT sex FROM table LIMIT 3
That what you looking is to Unpivot data. For more info about pivot and unpivot you can check here.
http://archive.oreilly.com/oreillyschool/courses/dba1/dba110.html
Unfortunately there is no easy way to unpivot in mysql.
The below script will work for MySQL 8.0
set #rowNum :=0;
set #string :=(
select group_concat(id,',',label,',',name,',',age,',',sex separator ',')
from (
select id, label, name, age, sex from mytable limit 3
) x
);
with recursive
R1 as ( select #string as items),
R2 as ( select 1 as n
union
select n + 1 from R2, R1
where n <= length(items) - length(replace(items, ',', '')))
select distinct #rowNum := #rowNum+1 as rowNum, substring_index(substring_index(items, ',', n), ',', -1) output from R2, R1;
I have a column as below
Products
jeans,oil
jeans,shampoo
I want to split the strings and use it in the same column using SQL. The result I want is
Products count
jeans 2
oil 1
shampoo 1
Could you please guide me in getting this result
Thank you
You are storing CSV data in your SQL table, which is not a good thing. But it looks like you are trying to move away from that, which is a good thing. Here is one option using a union with SUBSTRING_INDEX:
SELECT Products, COUNT(*) AS count
FROM
(
SELECT SUBSTRING_INDEX(Products, ',', 1) AS Products FROM yourTable
UNION ALL
SELECT SUBSTRING_INDEX(Products, ',', -1) FROM yourTable
) t
GROUP BY Products
ORDER BY
count DESC, Products;
Demo
Firstly you need to split the data into two columns like
SELECT CASE
WHEN name LIKE '%,%' THEN LEFT(name, Charindex(' ', products) - 1)
ELSE name
END,
CASE
WHEN name LIKE '%,%' THEN RIGHT(name, Charindex(' ', Reverse(products)) - 1)
END
FROM YourTable
then you need to union this with the same table... and the final code will look like...
select count( distinct abc), abc from
(
SELECT CASE
WHEN PA_NAME LIKE '% %' THEN LEFT(PA_NAME, Charindex(' ', PA_NAME) - 1)
ELSE PA_NAME
END [abc]
FROM phparty
union all
SELECT CASE
WHEN PA_NAME LIKE '% %' THEN RIGHT(PA_NAME, Charindex(' ', Reverse(PA_NAME)) -1)
END [abc]
FROM phparty
) t group by abc
here you can replace pa_name with your_column_name
I have this 3 columns tab
PRODUCT....CATEGORY......CLASS
X............1.............II
Y............1.............II
Z............1.............II
Y............2.............II
And I want to return a single row with all DISTINCT values of each column:
RESULT
X Y Z 1 2 II
What's the best way to get this result?
Assuming there are no duplicates between the columns, you can use group_concat():
select concat_ws(' ',
group_concat(distinct product separator ' '),
group_concat(distinct category separator ' '),
group_concat(distinct class separator ' ')
)
from tab t;
You can first collect all values in a subselect and then show these values with group_concat
select group_concat(v separator ' ')
from (select product as v from testa
union
select category as v from testa
union
select class as v from testa) t
SQLFiddle
I have a table of different attributes I want to sum, and then group concatenate them into a JSON string to make it easier to send over network. Here's a simplified table:
t1
type amount
'atr1' 10
'atr2' 10
'atr1' 17
'atr3' 20
'atr3' 4
I tried something like
select concat('{',
group_concat(
(select concat('"', type, '":', sum(amount)) from t1 group by type)
),
'}')
but failed.
I want to end up with '{"atr1":27,"atr2":10,"atr3":24}'
Try this query -
SELECT CONCAT('{', GROUP_CONCAT(c1), '}') FROM (
SELECT CONCAT('"', type, '":', SUM(amount)) c1 FROM t1 GROUP BY type
) t
something like
select
group_concat(concat('"', type, '":', TheSum))
FROM
(
SELECT SUM(amount) AS TheSum,type
FROM t1
GROUP BY type
) T