im testing now for +10hours to get a database structure with a primary key (id)
and a partition by bigint. but nothing will work :/
is that possible?
maybe anybody could give a me good hint ;)
CREATE TABLE IF NOT EXISTS `test` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`uniqueID` bigint(20) DEFAULT NULL,
`value` int(11) DEFAULT NULL,
`m1` text CHARACTER SET utf8,
`m2` text CHARACTER SET utf8,
`m3` text CHARACTER SET utf8,
`m4` text CHARACTER SET utf8,
`m5` text CHARACTER SET utf8,
PRIMARY KEY (`id`),
UNIQUE KEY `uniqueID` (`uniqueID`),
KEY `value` (`value`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci PACK_KEYS=1 DELAY_KEY_WRITE=1 ROW_FORMAT=DYNAMIC
/*!50500 PARTITION BY RANGE COLUMNS(uniqueID)
(PARTITION p1 VALUES LESS THAN ('0') ENGINE = MyISAM,
PARTITION p2 VALUES LESS THAN ('1') ENGINE = MyISAM,
PARTITION p3 VALUES LESS THAN ('2') ENGINE = MyISAM,
PARTITION p4 VALUES LESS THAN ('3') ENGINE = MyISAM,
PARTITION p5 VALUES LESS THAN ('4') ENGINE = MyISAM,
PARTITION p6 VALUES LESS THAN ('5') ENGINE = MyISAM,
PARTITION p7 VALUES LESS THAN ('6') ENGINE = MyISAM,
PARTITION p8 VALUES LESS THAN ('9') ENGINE = MyISAM,
PARTITION p9 VALUES LESS THAN (MAXVALUE) ENGINE = MyISAM) */;
with this partition, i will split the bigint values by the first number - example:
16275214652090176103 would be a part of partition p2
this database will take 100M records :/
thanks advance
The column you are partitioning on must be part of the primary key of the table, and I believe, it must be the last column in the primary key. So, if you were to define your primary key as PRIMARY KEY (id, uniqueID), you should be able to partition on uniqueID.
That being said, given that your uniqueID field is a bigint and you are trying to partition based on the bigint being less than a string, I'm not sure what you are trying to do will work as desired. Perhaps using hash partitioning rather than range partitioning would be more use to you? For more details see https://dev.mysql.com/doc/refman/5.1/en/partitioning-hash.html
Related
When I tried to create new table table_new by using DDL of existing table table1. To achieve this, following command returned its DDL.
show create table table1
Its DDL is at the bottom of the page, I'd like to set partition in snapshot_date.
and want to set them from 2022-01-01 to 2027-01-01 in each day. I tried to set them manually, but they take long time.
My question is
Are there any good way to achieve this?
What is /*!50500 in following DDL ?
If someone has an opinion or materials, please let me know. Thanks
CREATE TABLE `table_new` (
`snapshot_day` date NOT NULL,
`A` varchar(14) NOT NULL,
`B` char(10) NOT NULL,
`C` char(10) DEFAULT NULL,
KEY `INDEX` (`A`,`B`,`C`,`snapshot_day`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4
/*!50500 PARTITION BY RANGE COLUMNS(snapshot_day)
(PARTITION p20220101 VALUES LESS THAN ('2022-01-01') ENGINE = InnoDB,
PARTITION p20220102 VALUES LESS THAN ('2022-01-02') ENGINE = InnoDB,
PARTITION p20220103 VALUES LESS THAN ('2022-01-03') ENGINE = InnoDB,
PARTITION p20220104 VALUES LESS THAN ('2022-01-04') ENGINE = InnoDB,
PARTITION p20220105 VALUES LESS THAN ('2022-01-05') ENGINE = InnoDB,
PARTITION p20220106 VALUES LESS THAN ('2022-01-06') ENGINE = InnoDB,
PARTITION p20220107 VALUES LESS THAN ('2022-01-07') ENGINE = InnoDB,
PARTITION p20220108 VALUES LESS THAN ('2022-01-08') ENGINE = InnoDB,
PARTITION p20220109 VALUES LESS THAN ('2022-01-09') ENGINE = InnoDB,
PARTITION p20220110 VALUES LESS THAN ('2022-01-10') ENGINE = InnoDB,
PARTITION p20220111 VALUES LESS THAN ('2022-01-11') ENGINE = InnoDB,
PARTITION p20220112 VALUES LESS THAN ('2022-01-12') ENGINE = InnoDB) */
I have created a table using mysql partition using range and have inserted millions of data.
CREATE TABLE `PART_SAMPLE ` (
`TRANSACTION_ID` bigint(25) NOT NULL AUTO_INCREMENT,
`TASK_ID` int(11) DEFAULT NULL,
`STATUS_CODE` int(10) DEFAULT NULL,
`FIELD10` int(5) DEFAULT NULL,
KEY `TXN_ID` (`TRANSACTION_ID`),
KEY `TASK_IDX` (`TASK_ID`),
KEY `id_idx_task_status` (`TASK_ID`,`STATUS_CODE`),
KEY `IDX_STATUS` (`STATUS_CODE`),
KEY `Fld_idx` (`FIELD10`)
) ENGINE=MyISAM AUTO_INCREMENT=12249932 DEFAULT CHARSET=latin1
/*!50100 PARTITION BY RANGE (FIELD10)
(PARTITION p0 VALUES LESS THAN (0) ENGINE = MyISAM,
PARTITION p1 VALUES LESS THAN (1) ENGINE = MyISAM,
PARTITION p2 VALUES LESS THAN (2) ENGINE = MyISAM,
........
PARTITION p9 VALUES LESS THAN (9) ENGINE = MyISAM,
PARTITION p10 VALUES LESS THAN MAXVALUE ENGINE = MyISAM) */
Each Field10(0-10) value is having 3 million data each.
But when am executing a select query as this
select TASK_ID,STATUS_CODE,count(*) from PART_SAMPLE where FIELD10=X group by TASK_ID,STATUS_CODE;
x can be any value in the partition
for x value 0,2,5,8 it is taking only 10 seconds to retrive result but for rest it is taking abount 50s to rerive the result. As per my understating since data is same for all Fields almost same time has to be taken for any Field10 value. Why this time difference is coming
I want to use mysql partition tables to partition a table into YEAR and the WEEK number. I know exactly how to do this with mysql merge tables but partition tables are different. Can someone please help with the following table schema?
CREATE TABLE `tableName` (
`id` int(10) NOT NULL AUTO_INCREMENT,
`dateandtime` datetime NOT NULL,
`othervalue` int(10) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM;
Also does it have to be in a certain engine?
And if I store the dateandtime as a int(10) timestamp how would I do it?
CREATE TABLE `tableName` (
`id` int(10) NOT NULL AUTO_INCREMENT,
`dateandtime` int(10) NOT NULL,
`othervalue` int(10) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM;
MySQL 5.1 cannot do partition by date, so you must you workaround... Usually you partition by function TO_DAYS(dateandtime), for example like this:
CREATE TABLE tbl (
... ) ENGINE=InnoDB
PARTITION BY RANGE (to_days(dateandtime)) (
PARTITION pNULL VALUES LESS THAN (0) ENGINE = InnoDB,
PARTITION p20111218 VALUES LESS THAN (TO_DAYS('2011-12-18')) ENGINE = InnoDB,
PARTITION p20111225 VALUES LESS THAN (TO_DAYS('2011-12-25')) ENGINE = InnoDB,
PARTITION pNew VALUES LESS THAN MAXVALUE ENGINE = InnoDB
)
I defined here 4 partitions - the first is just for sake of completeness, so that insert of date in future won't fail. (You can't INSERT a value for which a partition does not exist.) The first partition is for performance - NULL values will be petentionally stored there. The middle 2 partitions are actually being used, each keeping one week of data.
You can drop old partition (this is very fast compared to just DELETEing old rows) using ALTER TABLE tbl DROP PARTITION xyz. You can add new partitions by splitting the last partition:
ALTER TABLE tbl REORGANIZE PARTITION pNew INTO (
PARTITION p20120115 VALUES LESS THAN (TO_DAYS('2012-01-16')),
...
PARTITION pNew VALUES LESS THAN (MAXVALUE)
);
I update MySQL versition from 5.0 to 5.5. and I am new for studying mysql partition. firstly, I type:
SHOW VARIABLES LIKE '%partition%'
Variable_name Value
have_partitioning YES
Make sure that the new version support partition. I tried to partition my table by every 10 minutes, then INSERT, UPDATE, QUERY huge data into this table for a test.
First, I need create a new table, I type my code:
CREATE TABLE test (
`id` int unsigned NOT NULL auto_increment,
`words` varchar(100) collate utf8_unicode_ci NOT NULL,
`date` varchar(10) collate utf8_unicode_ci NOT NULL,
PRIMARY KEY (`id`),
FULLTEXT KEY `index` (`words`)
)
ENGINE=MyISAM
DEFAULT CHARSET=utf8
COLLATE=utf8_unicode_ci
AUTO_INCREMENT=0
PARTITION BY RANGE (MINUTE(`date`))
(
PARTITION p0 VALUES LESS THAN (1322644000),
PARTITION p1 VALUES LESS THAN (1322644600) ,
PARTITION p2 VALUES LESS THAN (1322641200) ,
PARTITION p3 VALUES LESS THAN (1322641800) ,
PARTITION p4 VALUES LESS THAN MAXVALUE
);
It return alert: #1564 - This partition function is not allowed, so what is this problem? thanks.
UPDATE
Modify date into int NOT NULL, and PARTITION BY RANGE MINUTE(date) into PARTITION BY RANGE COLUMNS(date)
CREATE TABLE test (
`id` int unsigned NOT NULL auto_increment,
`words` varchar(100) collate utf8_unicode_ci NOT NULL,
`date` int NOT NULL,
PRIMARY KEY (`id`),
FULLTEXT KEY `index` (`words`)
)
ENGINE=MyISAM
DEFAULT CHARSET=utf8
COLLATE=utf8_unicode_ci
AUTO_INCREMENT=0
PARTITION BY RANGE COLUMNS(`date`)
(
PARTITION p0 VALUES LESS THAN (1322644000),
PARTITION p1 VALUES LESS THAN (1322644600) ,
PARTITION p2 VALUES LESS THAN (1322641200) ,
PARTITION p3 VALUES LESS THAN (1322641800) ,
PARTITION p4 VALUES LESS THAN MAXVALUE
);
Then caused new error: #1214 - The used table type doesn't support FULLTEXT indexes
I am so sorry, mysql not support fulltext and partition at the same time.
See partitioning limitations
FULLTEXT indexes. Partitioned tables do not support FULLTEXT indexes or searches. This includes partitioned tables employing the MyISAM storage engine.
One issue might be
select MINUTE('2008-10-10 56:56:98') returns null, the reason is Minute function returns minute from time or datetime value, where as in your case date is varchar
MINUTE function returns in either date/datetime expression. Again, A partitioning key must be either an integer column or an expression that resolves to an
integer but inyour case it's VARCHAR
I have the following table structure with live data in it:
CREATE TABLE IF NOT EXISTS `userstatistics` (
`user_id` int(10) unsigned NOT NULL,
`number_logons` int(7) unsigned NOT NULL DEFAULT '0',
`number_profileminiviews` int(7) unsigned NOT NULL DEFAULT '0',
`number_profilefullviews` int(7) unsigned NOT NULL DEFAULT '0',
`number_mailsreceived` int(7) unsigned NOT NULL DEFAULT '0',
`number_interestreceived` int(7) unsigned NOT NULL DEFAULT '0',
`number_favouratesreceived` int(7) unsigned NOT NULL DEFAULT '0',
`number_friendshiprequestreceived` int(7) unsigned NOT NULL DEFAULT '0',
`number_imchatrequestreceived` int(7) unsigned NOT NULL DEFAULT '0',
`yearweek` int(6) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`user_id`,`yearweek`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
I want to convert this to a partitioned table with the following structure:
CREATE TABLE IF NOT EXISTS `userstatistics` (
`user_id` int(10) unsigned NOT NULL,
`number_logons` int(7) unsigned NOT NULL DEFAULT '0',
`number_profileminiviews` int(7) unsigned NOT NULL DEFAULT '0',
`number_profilefullviews` int(7) unsigned NOT NULL DEFAULT '0',
`number_mailsreceived` int(7) unsigned NOT NULL DEFAULT '0',
`number_interestreceived` int(7) unsigned NOT NULL DEFAULT '0',
`number_favouratesreceived` int(7) unsigned NOT NULL DEFAULT '0',
`number_friendshiprequestreceived` int(7) unsigned NOT NULL DEFAULT '0',
`number_imchatrequestreceived` int(7) unsigned NOT NULL DEFAULT '0',
`yearweek` int(6) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`user_id`,`yearweek`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1
/*!50100 PARTITION BY RANGE (yearweek)
(PARTITION userstats_201108 VALUES LESS THAN (201108) ENGINE = InnoDB,
PARTITION userstats_201109 VALUES LESS THAN (201109) ENGINE = InnoDB,
PARTITION userstats_201110 VALUES LESS THAN (201110) ENGINE = InnoDB,
PARTITION userstats_201111 VALUES LESS THAN (201111) ENGINE = InnoDB,
PARTITION userstats_201112 VALUES LESS THAN (201112) ENGINE = InnoDB,
PARTITION userstats_201113 VALUES LESS THAN (201113) ENGINE = InnoDB,
PARTITION userstats_201114 VALUES LESS THAN (201114) ENGINE = InnoDB,
PARTITION userstats_201115 VALUES LESS THAN (201115) ENGINE = InnoDB,
PARTITION userstats_201116 VALUES LESS THAN (201116) ENGINE = InnoDB,
PARTITION userstats_201117 VALUES LESS THAN (201117) ENGINE = InnoDB,
PARTITION userstats_201118 VALUES LESS THAN (201118) ENGINE = InnoDB,
PARTITION userstats_201119 VALUES LESS THAN (201119) ENGINE = InnoDB,
PARTITION userstats_201120 VALUES LESS THAN (201120) ENGINE = InnoDB,
PARTITION userstats_201121 VALUES LESS THAN (201121) ENGINE = InnoDB,
PARTITION userstats_max VALUES LESS THAN MAXVALUE ENGINE = InnoDB) */;
How can I do this conversion?
Simply changing the first line of the second SQL statement to
ALTER TABLE 'userstatistics' (
Would this do it?
Going from MySQL 5.0 to 5.1.
First, you need to be running MySQL 5.1 or later. MySQL 5.0 does not support partitioning.
Second, please be aware of the difference between single-quotes (which delimit strings and dates) and back-ticks (which delimit table and column identifiers in MySQL). Use the correct type where appropriate. I mention this, because your example uses the wrong type of quotes:
ALTER TABLE 'userstatistics' (
That should be:
ALTER TABLE `userstatistics` (
Finally, yes, you can restructure a table into partitions with ALTER TABLE. Here's an exact copy & paste from a statement I tested on MySQL 5.1.57:
ALTER TABLE userstatistics PARTITION BY RANGE (yearweek) (
PARTITION userstats_201108 VALUES LESS THAN (201108) ENGINE = InnoDB,
PARTITION userstats_201109 VALUES LESS THAN (201109) ENGINE = InnoDB,
PARTITION userstats_201110 VALUES LESS THAN (201110) ENGINE = InnoDB,
PARTITION userstats_201111 VALUES LESS THAN (201111) ENGINE = InnoDB,
PARTITION userstats_201112 VALUES LESS THAN (201112) ENGINE = InnoDB,
PARTITION userstats_201113 VALUES LESS THAN (201113) ENGINE = InnoDB,
PARTITION userstats_201114 VALUES LESS THAN (201114) ENGINE = InnoDB,
PARTITION userstats_201115 VALUES LESS THAN (201115) ENGINE = InnoDB,
PARTITION userstats_201116 VALUES LESS THAN (201116) ENGINE = InnoDB,
PARTITION userstats_201117 VALUES LESS THAN (201117) ENGINE = InnoDB,
PARTITION userstats_201118 VALUES LESS THAN (201118) ENGINE = InnoDB,
PARTITION userstats_201119 VALUES LESS THAN (201119) ENGINE = InnoDB,
PARTITION userstats_201120 VALUES LESS THAN (201120) ENGINE = InnoDB,
PARTITION userstats_201121 VALUES LESS THAN (201121) ENGINE = InnoDB,
PARTITION userstats_max VALUES LESS THAN MAXVALUE ENGINE = InnoDB);
Note that this causes a table restructure, so if you already have a lot of data in this table, it will take a while to run. Exactly how long depends on how much data you have, and your hardware speed, and other factors. Be aware that while the table is being restructured, it is locked and unavailable for reading and writing by other queries.
Look this
http://dev.mysql.com/doc/refman/5.1/en/alter-table.html about the alter table.
Then in particular the alter table.
ADD/DROP/COALESCE/REORGANIZE partition sql provides almost all the functions to manage your partitions.
note that hash can be only used to integer.
ALTER TABLE ... ADD PARTITION creates no temporary table except when used with NDB tables. ADD or DROP operations for RANGE or LIST partitions are immediate operations or nearly so. ADD or COALESCE operations for HASH or KEY partitions copy data between changed partitions; unless LINEAR HASH or LINEAR KEY was used, this is much the same as creating a new table (although the operation is done partition by partition). REORGANIZE operations copy only changed partitions and do not touch unchanged ones.