I want to be able to select the amount of times the data in columns Somedata_A and Somedata_B has changed from the from the previous row within its column. I've tried using DISTINCT and it works to some degree. {1,2,3,2,1,1} will show 3 when I want it to show 4 course there's 5 different values in sequence.
Example:
A,B,C,D,E,F
{1,2,3,2,1,1}
A compare to B gives a difference, B compare to C gives a difference . . . E compare to F gives not difference. All in all it gives 4 differences within a set of 6 values.
I have gotten DISTINCT to work but it does not really do the trick for me. And to add more to the question I'm really not interested it the whole range, lets say just the 2 last days/entries per Title.
Second I'm concern about performance issues. I tried the query below on a real set of data and it got interrupted probably due to timeout.
SQL Fiddle
MySQL 5.5.32 Schema Setup:
CREATE TABLE testdata(
Title varchar(10),
Date varchar(10),
Somedata_A int(5),
Somedata_B int(5));
INSERT INTO testdata (Title, Date, Somedata_A, Somedata_B) VALUES
("Alpha", '123', 1, 2),
("Alpha", '234', 2, 2),
("Alpha", '345', 1, 2),
("Alpha", '349', 1, 2),
("Alpha", '456', 1, 2),
("Omega", '123', 1, 1),
("Omega", '234', 2, 2),
("Omega", '345', 3, 3),
("Omega", '349', 4, 3),
("Omega", '456', 5, 4),
("Delta", '123', 1, 1),
("Delta", '234', 2, 2),
("Delta", '345', 1, 3),
("Delta", '349', 2, 3),
("Delta", '456', 1, 4);
Query 1:
SELECT t.Title, (SELECT COUNT(DISTINCT Somedata_A) FROM testdata AS tt WHERE t.Title = tt.Title) AS A,
(SELECT COUNT(DISTINCT Somedata_B) FROM testdata AS tt WHERE t.Title = tt.Title) AS B
FROM testdata AS t
GROUP BY t.Title
Results:
| TITLE | A | B |
|-------|---|---|
| Alpha | 2 | 1 |
| Delta | 2 | 4 |
| Omega | 5 | 4 |
Something like this may work: it uses a variable for row number, joins on an offset of 1 and then counts differences for A and B.
http://sqlfiddle.com/#!2/3bbc8/9/2
set #i = 0;
set #j = 0;
Select
A.Title aTitle,
sum(Case when A.SomeData_A <> B.SomeData_A then 1 else 0 end) AVar,
sum(Case when A.SomeData_B <> B.SomeData_B then 1 else 0 end) BVar
from
(SELECT Title, #i:=#i+1 as ROWID, SomeData_A, SomeData_B
FROM testdata
ORDER BY Title, date desc) as A
INNER JOIN
(SELECT Title, #j:=#j+1 as ROWID, SomeData_A, SomeData_B
FROM testdata
ORDER BY Title, date desc) as B
ON A.RowID= B.RowID + 1
AND A.Title=B.Title
Group by A.Title
This works (see here) (FYI: Your results in the question do not match your data - for instance, for Alpha, ColumnA: it never changes from 1. The answer should be 0)
Hopefully you can adapt this Statement to your actual data model
SELECT t1.title, SUM(t1.Somedata_A<>t2.Somedata_a) as SomeData_A
,SUM(t1.Somedata_b<>t2.Somedata_b) as SomeData_B
FROM testdata AS t1
JOIN testdata AS t2
ON t1.title = t2.title
AND t2.date = DATE_ADD(t1.date, INTERVAL 1 DAY)
GROUP BY t1.title
ORDER BY t1.title;
Related
Now i need to make similar query but need to several criteria
Here is my table
`transaksi` (`transid`, `idpinj`, `tanggal`,`sisapokok`, `sisajasa`
(1, 1, '2018-01-01', 1000, 100, 1),
(2, 1, '2018-01-05', 1000, 100, 3),
(3, 2, '2018-02-04', 1000, 100, 4),
(4, 2, '2018-02-08', 1000, 100, 5),
(5, 1, '2018-02-19', 1000, 100, 3),
(6, 3, '2018-02-22', 1000, 100, 2),
(7, 2, '2018-03-09', 1000, 100, 3),
(8, 3, '2018-03-10', 1000, 100, 3)
(9, 3, '2018-03-12', 1000, 100, 4)
(10, 1, '2018-03-17', 1000, 100, 4)
(11, 4, '2018-03-19', 1000, 100, 3)
(12, 2, '2018-03-20', 1000, 100, 4)
DB Fiddle table
From the table above i need to get output as follow
Month sisapokok sisajasa
Jan-2018 1000 100 ->row2
Feb-2018 4000 400 ->+ row3+5
Mar-2018 12000 1200 ->+ row9+10+11+12
First I need to get sum(sisapokok) and sum(sisajasa) for each idpinj where date is max(tanggal), status between 3 and 4. This value then sum as total per month
Make cumulative sum each month for the last 12 month
I try this query but it get the max(date) from all records not max(date) by month and each idpinj.
SELECT a.idpinj,a.sisapokok
FROM transaksi a
INNER JOIN
(
SELECT idpinj, MAX(tanggal) tgl
FROM transaksi
GROUP BY idpinj
) b ON a.idpinj = b.idpinj
AND a.tanggal = b.tgl
ORDER BY `a`.`idpinj` ASC
Not sure exactly what you are asking for but see if this helps:
select monthyear, sum(sisapokok)sisapokok, sum(sisajasa)sisajasa from (
select cast(month(tanggal) as varchar)+'-'+cast(year(tanggal) as varchar) monthyear, sum(sisapokok)sisapokok, sum(sisajasa)sisajasa
from #transaksi
group by cast(month(idpinj) as varchar)+'-'+cast(year(tanggal) as varchar) , tanggal) a
group by monthyear
Based on the fiddle data
select yyyy,mm,
#s:=#s+sisapokok sisapokok,
#t:=#t+sisajasa sisajasa
from
(
select yyyy,mm,sum(sisapokok) sisapokok,sum(sisajasa) sisajasa
from
(
select year(tanggal) yyyy,month(tanggal) mm, sisapokok,sisajasa
from transaksi t
join
(
select year(tanggal) yyyy,month(tanggal) mm,idpinj,max(transid) maxid
from `transaksi`
where status in(3,4)
group by year(tanggal),month(tanggal),idpinj
) s on s.maxid = transid
) t
group by yyyy,mm
) u
,(select #s:=0,#t:=0) r
order by yyyy,mm
+------+------+-----------+----------+
| yyyy | mm | sisapokok | sisajasa |
+------+------+-----------+----------+
| 2018 | 1 | 2000 | 2003 |
| 2018 | 2 | 5000 | 2303 |
| 2018 | 3 | 13000 | 3103 |
+------+------+-----------+----------+
3 rows in set (0.00 sec)
Note the inner query finds the last relevant id and the code progresses outward to use variables to calculate running totals.
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I have data like in this mysql table:
id customer_id int_proc inventory
1 A 1 1
2 A 4 1
3 A 5 1
4 A 0 2
5 A 5 2
6 A 6 2
7 B 6 1
8 B 7 1
9 B 9 1
10 B 9 2
11 B 9 2
12 C 22 1
I want to get all data from the latest 2 int_proc values for every inventory and where the customer_id is A and B.
My result should be like this:
id customer_id int_proc inventory
2 A 4 1
3 A 5 1
5 A 5 2
6 A 6 2
8 B 7 1
9 B 9 1
10 B 9 2
11 B 9 2
Any help is greatly appreciated.
You can use Mysql's user defined variables and give a rank to rows per customer and per inventory with in a same customer group,below query will give 2 latest int_proc per inventory and same customer group if you want to get latest n number of records just change where clause to where t2.r <= n
select
t2.id,
t2.customer_id,
t2.int_proc,
t2.inventory
from (
select t.*,
#r:= case when #g = t.customer_id
then
case when #sg = t.inventory
then #r+1
else 1 end
else 1 end r,
#g:= t.customer_id g,
#sg:= t.inventory sg
from test t
cross join (select #g:=null,#sg:=null,#r:=null) t1
where t.customer_id in('A','B')
order by t.customer_id,t.inventory,t.int_proc desc
) t2
where t2.r <= 2
order by id
Fiddle Demo
Edit for duplicate values
If you have duplicated rows for the int_proc you have to add another sub case statement to check for repeated values and rank them accordingly
select
t2.id,
t2.customer_id,
t2.inventory,
t2.int_proc
from (
select t.*,
#r:= case when #g = t.customer_id
then
case when #sg = t.inventory
then
case when #sr <> t.int_proc
then #r+1
else #r end
else 1 end
else 1 end r,
#g:= t.customer_id g,
#sg:= t.inventory sg,
#sr:= t.int_proc sr
from test t
cross join (select #g:=null,#sg:=null,#r:=null,#sr:=null) t1
where t.customer_id in('A','B')
order by t.customer_id,t.inventory,t.int_proc desc
) t2
where t2.r <= 2
order by id
Fiddle Demo 2
#MKhalidJunaid: your solution worked for quite a while. However, we now get multiple results sets instead of the only two latest int_proc's. Can you please execute the following table at http://www.sqlfiddle.com/#!2/e81fdf/2
(this might be due to the unordered rows of data?)
CREATE TABLE test
(`id` int, `customer_id` varchar(1), `int_proc` int, `inventory` int)
;
INSERT INTO test
(`id`, `customer_id`, `int_proc`, `inventory`)
VALUES
(1, 'A', 1, 1),
(2, 'A', 4, 1),
(3, 'A', 5, 1),
(4, 'A', 0, 1),
(5, 'A', 5, 1),
(6, 'A', 6, 1),
(7, 'A', 6, 1),
(8, 'A', 7, 1),
(9, 'A', 9, 1),
(10, 'B', 91, 2),
(11, 'B', 92, 2),
(12, 'B', 93, 2),
(13, 'B', 95, 2),
(14, 'B', 95, 2),
(15, 'C', 22, 1)
;
I need to count whether there are three consecutive failed login attempts of the user in last one hour.
For example
id userid status logindate
1 1 0 2014-08-28 10:00:00
2 1 1 2014-08-28 10:10:35
3 1 0 2014-08-28 10:30:00
4 1 0 2014-08-28 10:40:00
In the above example, status 0 means failed attempt and 1 means successful attempt.
I need a query that will count three consecutive records of a user with status 0 occurred in last one hour.
I tried below query
SELECT COUNT( * ) AS total, Temp.status
FROM (
SELECT a.status, MAX( a.id ) AS idlimit
FROM loginAttempts a
GROUP BY a.status
ORDER BY MAX( a.id ) DESC
) AS Temp
JOIN loginAttempts t ON Temp.idlimit < t.id
HAVING total >1
Result:
total status
2 1
I don't know why it display status as 1. I also need to add a where condition on logindate and status field but don't know how would it work
For consecutive count you can use user defined variables to note the series values ,like in below query i have use #g and #r variable, in inner query i am storing the current status value that could be 1/0 and in case expression i am comparing the value stored in #g with the status column if they both are equal like #g is holding previous row value and previous row's status is equal to the current row's status then do not change the value stored in #r,if these values don't match like #g <> a.status then increment #r with 1, one thing to note i am using order by with id column and assuming it is set to auto_increment so for consecutive 1s #r value will be same like #r was 3 for first status 1 and the again status is 1 so #r will 3 until the status changes to 0 same for status 0 vice versa
SELECT t.userid,t.consecutive,t.status,COUNT(1) consecutive_count
FROM (
SELECT a.* ,
#r:= CASE WHEN #g = a.status THEN #r ELSE #r + 1 END consecutive,
#g:= a.status g
FROM attempts a
CROSS JOIN (SELECT #g:=2, #r:=0) t1
WHERE a.`logindate` BETWEEN '2014-08-28 10:00:00' AND '2014-08-28 11:00:00'
ORDER BY id
) t
GROUP BY t.userid,t.consecutive,t.status
HAVING consecutive_count >= 3 AND t.status = 0
Now in parent query i am grouping results by userid the resultant value of case expression i have name is it as consecutive and status to get the count for each user's consecutive status
One thing to note for above query that its necessary to provide the
hour range like i have used between without this it will be more
difficult to find exactly 3 consecutive statuses with in an hour
Sample data
INSERT INTO attempts
(`id`, `userid`, `status`, `logindate`)
VALUES
(1, 1, 0, '2014-08-28 10:00:00'),
(2, 1, 1, '2014-08-28 10:10:35'),
(3, 1, 0, '2014-08-28 10:30:00'),
(4, 1, 0, '2014-08-28 10:40:00'),
(5, 1, 0, '2014-08-28 10:50:00'),
(6, 2, 0, '2014-08-28 10:00:00'),
(7, 2, 0, '2014-08-28 10:10:35'),
(8, 2, 0, '2014-08-28 10:30:00'),
(9, 2, 1, '2014-08-28 10:40:00'),
(10, 2, 1, '2014-08-28 10:50:00')
;
As you can see from id 3 to 5 you can see consecutive 0s for userid 1 and similarly id 6 to 8 userid 2 has consecutive 0s and they are in an hour range using above query you can have results as below
userid consecutive status consecutive_count
------ ----------- ------ -------------------
1 2 0 3
2 2 0 3
Fiddle Demo
M Khalid Junaid's answer is great, but his Fiddle Demo didn't work for me when I clicked it.
Here is a Fiddle Demo which works as of this writing.
In case it doesn't work later, I used the following in the schema:
CREATE TABLE attempts
(`id` int, `userid` int, `status` int, `logindate` datetime);
INSERT INTO attempts
(`id`, `userid`, `status`, `logindate`)
VALUES
(1, 1, 0, '2014-08-28 10:00:00'),
(2, 1, 1, '2014-08-28 10:10:35'),
(3, 1, 0, '2014-08-28 10:30:00'),
(4, 1, 0, '2014-08-28 10:40:00'),
(5, 1, 0, '2014-08-28 10:50:00'),
(6, 2, 0, '2014-08-28 10:00:00'),
(7, 2, 0, '2014-08-28 10:10:35'),
(8, 2, 0, '2014-08-28 10:30:00'),
(9, 2, 1, '2014-08-28 10:40:00'),
(10, 2, 1, '2014-08-28 10:50:00')
;
And this as the query:
SELECT t.userid,t.consecutive,t.status,COUNT(1) consecutive_count
FROM (
SELECT a.* ,
#r:= CASE WHEN #g = a.status THEN #r ELSE #r + 1 END consecutive,
#g:= a.status g
FROM attempts a
CROSS JOIN (SELECT #g:=2, #r:=0) t1
WHERE a.`logindate` BETWEEN '2014-08-28 10:00:00' AND '2014-08-28 11:00:00'
ORDER BY id
) t
GROUP BY t.userid,t.consecutive,t.status
HAVING consecutive_count >= 3 AND t.status = 0;
In my mysql table I have a field which is a 4 letter Myers-Briggs personality type. I would like to search through the table and match when the personality type matches the one in the query by having 2 aspects in common. The way I understand this, it is really just finding the longest common subsequence of the two and testing that it is >= 2
Example:
'ISTJ' would match with 'INFJ', because the length of the common subsequence is 'IJ' >= 2
and
'ISTJ' would not match with 'INFP', because the length of the common subsequence is 'I' <= 2
Is there a way to do this in a mysql query? I am using CakePHP for the querying, so if you know how to do this with Cake that would also be helpful.
The Myer-Briggs personality types are positional. This means that you can compare character by character.
Here is one method, where you just have to put in the comparison string once:
select t.*
from (select t.*,
(case when substring(t.MyerBriggs, 1, 1) = substring(const.comp, 1, 1)
then 1 else 0
end) as MB1,
(case when substring(t.MyerBriggs, 2, 1) = substring(const.comp, 2, 1)
then 1 else 0
end) as MB2,
(case when substring(t.MyerBriggs, 3, 1) = substring(const.comp, 3, 1)
then 1 else 0
end) as MB3,
(case when substring(t.MyerBriggs, 4, 1) = substring(const.comp, 4, 1)
then 1 else 0
end) as MB4
from t cross join
(select 'INFJ' as comp) const
)
where (MB1+MB2+MB3+MB4) >= 2
You can actually simplify this in MySQL as:
select t.*
from t cross join
(select 'INFJ' as comp) const
where (if(substring(t.MyerBriggs, 1, 1) = substring(const.comp, 1, 1), 1, 0) +
if(substring(t.MyerBriggs, 2, 1) = substring(const.comp, 2, 1), 1, 0) +
if(substring(t.MyerBriggs, 3, 1) = substring(const.comp, 3, 1), 1, 0) +
if(substring(t.MyerBriggs, 4, 1) = substring(const.comp, 4, 1), 1, 0)
) >= 2
If I understand the Myers-Briggs thingy properly, there are two possibilities for each of the four categorisation axis, and the order of the letters is constant (and therefore carries no meaning).
In this case, you could use four two-state columns like the below, instead of one string:
CREATE TABLE profile (
user_id INT,
EI ENUM ('E', 'I'),
SN ENUM ('S', 'N'),
TF ENUM ('T', 'F'),
JP ENUM ('J', 'P')
);
Profile 'ISTJ' would be inserted like this:
INSERT INTO profile VALUE (1, 'I', 'S', 'T', 'J');
Matching with profile 'INFJ' would look like this:
SELECT * FROM profile WHERE
(EI = 'I') + (SN = 'N') + (TF = 'F') + (JP = 'J') >= 2
I have a database of results for a season of 25 games. However only each persons best ten scores count.
Can anybody tell me how to sum just the top ten scores of each person AND show the minimum score that was used in that sum (their tenth best).
The database has PlayerName, TournamentID, Points
eg.
- TounamentID PlayerName Points
- 1 Jo 100
- 1 Tel 50
- 1 Kevin 75
- 2 Jo 100
- 2 Tel 50
- 2 Kevin 75
- 3 Jo 100
- 3 Tel 50
- 3 Kevin 75
- 4 Jo 100
- 4 Tel 50
- 4 Kevin 75
- 5 Jo 100
- 5 Tel 50
- 5 Kevin 75 etc
Many thanks in advance
EDIT 1
At the moment I have this kind of working though it doesn't handle duplicate scores very well and can actual end up adding up the top 11 if there's a duplicate;
SELECT X.PlayerName, Sum(X.Points) AS SumOfPoints, Min(X.Points) AS Target
FROM SoP11PreBats AS X
WHERE (((10)>(SELECT count(*)
FROM SoP11PreBats
WHERE PlayerName = X.PlayerName
AND Points > X.Points )))
GROUP BY X.PlayerName
ORDER BY Sum(X.Points) DESC;
Something like this would work for one player at a time:
SELECT SUM(n), MIN(n) FROM
(SELECT points AS n
FROM table
WHERE PlayerName = ?
ORDER BY n DESC
LIMIT 10
)
I'm not sure how to expand it to produce a table for every player.
SELECT test.playername, sum(top10.score), MIN(top10.score)
FROM test
LEFT JOIN (SELECT playername, score FROM test ORDER BY score DESC LIMIT 10) top10
ON top10.playername = test.playername
GROUP BY test.playername
Edit: Turns out the above approach using a subselect and join is not going to do the trick. Because you limit the results in the subselect it is not going to lead to a set of max 10 records PER playername.
The next approach would be to do something like
SELECT pk, name, score from test where
pk IN (SELECT pk FROM test t2 WHERE t2.name = name ORDER BY score DESC LIMIT 10)
This could create the proper set of records to join with. However LIMIT is not supported inside an IN clause (yet). So this won't compile.
EIDT2: The final approach I can think of goes like this:
select distinct test.name
, (SELECT sum(t2.score) FROM (select t3.score FROM test t3 WHERE t3.name = test.name ORDER BY score desc LIMIT 10) t2)
, (SELECT min(t2.score) FROM (select t3.score FROM test t3 WHERE t3.name = test.name ORDER BY score desc LIMIT 10) t2)
FROM test
This one also won't compile because the most inner test.name in the where can't be resolved properly.
I don't think that what you want to do can currently be done in 1 single query on mysql, but I'm curious if someone can proof me wrong.
Ok I got it working but it's about the most nasty sql hack I could think of and I'm not sure you should even consider to put it in production like this. It also only runs on mysql:
select PlayerName, sum(Points), min(Points) from
(select distinct SoP11PreBats.PlayerName, (SELECT t2.Points FROM test t2 WHERE t2.PlayerName = SoP11PreBats.PlayerName ORDER BY Points desc LIMIT 1) as Points FROM test
UNION ALL
select distinct SoP11PreBats.PlayerName, (SELECT t2.Points FROM test t2 WHERE t2.PlayerName = SoP11PreBats.PlayerName ORDER BY Points desc LIMIT 1,1) as Points FROM test
UNION ALL
select distinct SoP11PreBats.PlayerName, (SELECT t2.Points FROM test t2 WHERE t2.PlayerName = SoP11PreBats.PlayerName ORDER BY Points desc LIMIT 2,1) as Points FROM test
UNION ALL
select distinct SoP11PreBats.PlayerName, (SELECT t2.Points FROM test t2 WHERE t2.PlayerName = SoP11PreBats.PlayerName ORDER BY Points desc LIMIT 3,1) as Points FROM test
UNION ALL
select distinct SoP11PreBats.PlayerName, (SELECT t2.Points FROM test t2 WHERE t2.PlayerName = SoP11PreBats.PlayerName ORDER BY Points desc LIMIT 4,1) as Points FROM test
UNION ALL
select distinct SoP11PreBats.PlayerName, (SELECT t2.Points FROM test t2 WHERE t2.PlayerName = SoP11PreBats.PlayerName ORDER BY Points desc LIMIT 5,1) as Points FROM test
UNION ALL
select distinct SoP11PreBats.PlayerName, (SELECT t2.Points FROM test t2 WHERE t2.PlayerName = SoP11PreBats.PlayerName ORDER BY Points desc LIMIT 6,1) as Points FROM test
UNION ALL
select distinct SoP11PreBats.PlayerName, (SELECT t2.Points FROM test t2 WHERE t2.PlayerName = SoP11PreBats.PlayerName ORDER BY Points desc LIMIT 7,1) as Points FROM test
UNION ALL
select distinct SoP11PreBats.PlayerName, (SELECT t2.Points FROM test t2 WHERE t2.PlayerName = SoP11PreBats.PlayerName ORDER BY Points desc LIMIT 8,1) as Points FROM test
UNION ALL
select distinct SoP11PreBats.PlayerName, (SELECT t2.Points FROM test t2 WHERE t2.PlayerName = SoP11PreBats.PlayerName ORDER BY Points desc LIMIT 9,1) as Points FROM test
) top10
group by name
I have a feeling this will not work:
SELECT *
FROM
( SELECT pd.PlayerName
, ( SELECT SUM(t10.Points)
FROM
( SELECT t10.Points
FROM SoP11PreBats AS t10
WHERE t10.PlayerName = pd.PlayerName
ORDER BY t10.Points DESC
LIMIT 10
) AS x
) AS Sum10
, ( SELECT t10.Points
FROM SoP11PreBats AS t10
WHERE t10.PlayerName = pd.PlayerName
ORDER BY t10.Points DESC
LIMIT 1 OFFSET 9
) AS TenthBest
FROM
( SELECT DISTINCT PlayerName
FROM SoP11PreBats
) AS pd
) AS y
ORDER BY Sum10 DESC
But this will:
SELECT pb.PlayerName AS PlayerName
, COALESCE(SUM(p.Points),0) + pb.TenthBest*(10-COUNT(p.Points))
AS SumOfPoints
, pb.TenthBest AS Target
FROM
( SELECT pd.PlayerName
, ( SELECT t10.Points
FROM SoP11PreBats AS t10
WHERE t10.PlayerName = pd.PlayerName
ORDER BY t10.Points DESC
LIMIT 1 OFFSET 9
) AS TenthBest
FROM
( SELECT DISTINCT PlayerName
FROM SoP11PreBats
) AS pd
) AS pb
LEFT JOIN SoP11PreBats AS p
ON p.PlayerName = pb.PlayerName
AND p.Points > pb.TenthBest
GROUP BY pb.PlayerName
ORDER BY SumOfPoints DESC
This works (see test output below):
set #count:=0, #player:='';
SELECT
PlayerName,
SUM(Points) as sum_top_10,
MIN(Points) as min_top_10
FROM (SELECT PlayerName, Points
FROM (SELECT
Points,
#count := if (#player != PlayerName, 0, #count + 1) as count,
#player := PlayerName as PlayerName
FROM (SELECT PlayerName, Points FROM SoP11PreBATS order by 1, 2 desc) x) y
where count < 10) z
group by 1;
Here's the test, using OP's data, plus extra rows for 'Jo' to make more than 10 rows:
create table SoP11PreBATS (TounamentID int, PlayerName text, Points int);
delete from SoP11PreBATS;
insert into SoP11PreBATS values
(1, 'Jo', 100), (1, 'Tel', 50), (1, 'Kevin', 75), (2, 'Jo', 100), (2, 'Tel', 50),
(2, 'Kevin', 75), (3, 'Jo', 100), (3, 'Tel', 50), (3, 'Kevin', 75), (4, 'Jo', 100),
(4, 'Tel', 50), (4, 'Kevin', 75), (5, 'Jo', 100), (5, 'Tel', 50), (5, 'Kevin', 75),
(5, 'Jo', 50), (6, 'Jo', 75), (7, 'Jo', 100), (8, 'Jo', 50), (9, 'Jo', 75),
(10, 'Jo', 50), (11, 'Jo', 75), (12, 'Jo', 100);
select * from SoP11PreBATS where playername = 'Jo' order by points desc;
+-------------+------------+--------+
| TounamentID | PlayerName | Points |
+-------------+------------+--------+
| 1 | Jo | 100 |
| 2 | Jo | 100 |
| 3 | Jo | 100 |
| 4 | Jo | 100 |
| 5 | Jo | 100 |
| 7 | Jo | 100 |
| 12 | Jo | 100 |
| 6 | Jo | 75 |
| 9 | Jo | 75 |
| 11 | Jo | 75 |
| 5 | Jo | 50 |
| 8 | Jo | 50 |
| 10 | Jo | 50 |
+-------------+------------+--------+
-- Inspection shows Jo should have 925 as sum and 75 as min
-- Ran query above and got:
+------------+------------+------------+
| PlayerName | sum_top_10 | min_top_10 |
+------------+------------+------------+
| Jo | 925 | 75 |
| Kevin | 375 | 75 |
| Tel | 250 | 50 |
+------------+------------+------------+
-- Test output correct
I think this works, and it only uses one derived table:
SELECT #row := 0, #pp := NULL, #min := 0;
SELECT Player,
SUM(Points) AS Points,
MIN(Points) AS MinPoints
FROM (
SELECT Player,
Points,
#row := IF(
IFNULL(#pp, '') <> Player AND NOT (#pp := Player),
1,
#row + 1
) AS Row
FROM SoP11PreBats
ORDER BY Player, Points DESC
) tmp
WHERE tmp.Row <= 10
GROUP BY Player;
Test data:
CREATE TABLE `SoP11PreBats` (
`TournamentID` int(11) NOT NULL,
`Player` varchar(255) NOT NULL,
`Points` int(11) NOT NULL
);
INSERT INTO SoP11PreBats (TournamentID, Player, Points) VALUES
(15, 'Jo', 10),
(14, 'Jo', 20),
(13, 'Jo', 30),
(12, 'Jo', 40),
(11, 'Jo', 50),
(10, 'Jo', 60),
( 9, 'Jo', 70),
( 8, 'Jo', 80),
( 7, 'Jo', 90),
( 6, 'Jo', 100),
( 5, 'Jo', 110),
( 4, 'Jo', 120),
( 3, 'Jo', 130),
( 2, 'Jo', 140),
( 1, 'Jo', 150),
( 1, 'Tel', 15),
( 2, 'Tel', 25),
( 3, 'Tel', 35),
( 4, 'Tel', 45),
( 5, 'Tel', 55),
( 6, 'Tel', 65),
( 7, 'Tel', 75),
( 8, 'Tel', 85),
( 9, 'Tel', 95),
(10, 'Tel', 105),
(11, 'Tel', 115),
(12, 'Tel', 125),
(13, 'Tel', 135),
(14, 'Tel', 145),
(15, 'Tel', 155),
( 1, 'Kevin', 10),
( 2, 'Kevin', 20),
( 3, 'Kevin', 30),
( 4, 'Kevin', 40),
( 5, 'Kevin', 50),
( 6, 'Kevin', 60),
( 7, 'Kevin', 70),
( 8, 'Kevin', 80),
( 9, 'Kevin', 90),
(10, 'Kevin', 100),
(11, 'Kevin', 110),
(12, 'Kevin', 120),
(13, 'Kevin', 130),
(14, 'Kevin', 140),
(15, 'Kevin', 150);
Result:
+--------+--------+-----------+
| Player | Points | MinPoints |
+--------+--------+-----------+
| Jo | 1050 | 60 |
| Kevin | 1050 | 60 |
| Tel | 1100 | 65 |
+--------+--------+-----------+