How to loop different numbers in Lottery game? - actionscript-3

Question

public class Lottery extends Sprite {
public var text0:TextField, text1:TextField, text2:TextField, text3:TextField, text4:TextField, text5:TextField;
public var backImage:Sprite, luckyBtn:Sprite, clearBtn:Sprite;
public var tfFormat:TextFormat = new TextFormat;
public function Lottery()
{
setTextFieldFormat();
loadGUI();
}
public function luckyDip(event:MouseEvent):void {
for (var i:uint = 0; i <= 49; i++) {
this["text" + i].text = Math.ceil(Math.random() * 49);
}
}
public function resetFields(event:MouseEvent):void {
for (var i:uint = 0; i <= 49; i++) {
this["text" + i].text = "";
}
}
How do I modify this so I can still generate a random sequence, but not repeat any of the entries?

Answer 1

In the lottery game you have limited numbers of results, for example: 5 numbers from 1-50. All you need is to create list of random unique numbers from 1-N.
//How to use, one of the results: 9,40,44,29,4
trace(lotteryGenerator(5));
private function lotteryGenerator(results: uint, maxValue:uint = 50):Array{
var i: uint, luckyNumber: uint, result: Array = [], added: uint;
while(added < results){
luckyNumber = 1 + Math.random() * (maxValue - 1);
if(result.indexOf(luckyNumber) == -1){
result.push(luckyNumber);
added++;
}
}
return result;
}