i am trying to add incremented values to a new column in table.
Here is a sample structure of table
---------------------
Name - class - id
---------------------
abbc - 2 - null
efg - 4 - null
ggh - 6 - null
---------------------
i want to write a query that will generate unique id's for all records in table
Here is the query i have tried but show null
set #i=0;
update table1 set id =(#i:=#i+1);
What you have shown should work; the id column should be getting assigned values.
I tested your statement; I verified it works on my database. Here's the test case I ran:
CREATE TABLE table1 (`name` VARCHAR(4), class TINYINT, id INT);
INSERT INTO table1 (`name`,class) VALUES ('abbc',2),('efg',4),('ggh',6);
SET #i=0;
UPDATE table1 SET id =(#i:=#i+1);
SELECT * FROM table1;
Note that MySQL user variables are specific to a database session. If the SET is running in one session, and the UPDATE is running another session, that would explain the behavior you are seeing. (You didn't mention what client you ran the statements from; most clients reuse the same connection, and don't churn connections for each statement, I'm just throwing that out as a possibility.)
To insure that #i variable is actually initialized when the UPDATE statement runs, you can do the initialization in the UPDATE statement by doing something like this:
UPDATE table1 t
CROSS
JOIN (SELECT #i := 0) s
SET t.id =(#i:=#i+1);
I tested that, and that also works on my database.
try this query my friend:
set #i=0;
update table1 set id =(select #i:=#i+1);
SQL Fiddle
SET #a = 0;
UPDATE table_name SET id = #a:=#a+1;
Use AUTOINCREMENT parameter for the respective column instead. This parameter will put an unique auto incremented value in the respective column.
Related
I have a table in MYSQL database with two fields:
Id (auto increment field).
Post_Id.
When I insert a new record both fields should have the same value. So I should update post_id with Id value, and at the same time make sure that I update the field with the right value not with any other new inserted record value.
I tried this SQL statement but it was very slow and I was not sure that I select the right value:
set #auto_id := (SELECT AUTO_INCREMENT
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME='table_name'
AND TABLE_SCHEMA=DATABASE() );
update table_name set post_id= #auto_id where id=#auto_id ;
I don't have long experience with MySQL and I cannot change the table structure .
The approach you followed is not transaction safe as well.
The best option I can think about is to use trigger
Edit: According to #lagripe's mentionings
CREATE TRIGGER sometrigger
AFTER INSERT ON sometable
BEGIN
SET NEW.post_id := (SELECT id from sometable order by DESC limit 1) + 1 ; // you may need +1 here. I couldn't test it.
END
or you may consider to use LAST_INSERT_ID
insert into table_name values ( .... );
update table_name set post_id = LAST_INSERT_ID();
but why do you need two columns with the same id at first place?
if you really need why don't you use computed/generated columns?
CREATE TABLE Table1(
id DOUBLE,
post_id DOUBLE as (id)
);
you can use triggers :
CREATE TRIGGER UpdatePOST_id
BEFORE INSERT ON table_db
FOR EACH ROW
SET NEW.post_id := (select id from table_db order by id DESC LIMIT 1)+1 ;
from now on, whatever you insert your as a value in post_id column will be replaced with the id inserted automatically.
Test :
|id|post_id|
|20| 20 |
|21| 21 |
|22| 22 |
|23| 23 |
To drop the trigger :
DROP trigger UpdatePOST_id
I have a table with primary key (its name is "id") defined as auto_increment. I use NULL in INSERT statements to "fill" the id value. It works, of course. However now I need to "move" an existing record to a new primary key value (the next available, the value is not so much important, but it must be a new one, and the last one if ordered by id). How can I do it in an "elegant" way? Since the "use NULL at INSERT" does not work too much with UPDATE:
update idtest set id=NULL where id=1;
This simply makes the id of the record zero. I would expect to do the same thing as with INSERT, but it seems my idea was incorrect.
Of course I can use "INSERT ... SELECT" statement, then a DELETE on the old one, or I can use something like MAX(id) + 1 to UPDATE the id of the old record in one step, etc, but I am curious if there is a finer solution.
Also, the MAX(id) solution doesn't seem to work either by the way:
mysql> update idtest set id=max(id)+1 where id=3;
ERROR 1111 (HY000): Invalid use of group function
mysql> update idtest set id=(select max(id)+1 from idtest) where id=3;
ERROR 1093 (HY000): You can't specify target table 'idtest' for update in FROM clause
This is the way I believe:
UPDATE users SET id = (SELECT `AUTO_INCREMENT`
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_SCHEMA = 'test'
AND TABLE_NAME = 'users') WHERE id = 2;
select * from users;
I used by own tables substitute yours.
test is database name, users is table name and id is AUTO_INCREMENT in my case.
EDIT: My Query above works perfect but its side effects are somewhat 'dangerous', upon next insert as AUTO_INCREMENT value will collide with this recently updated record so just next single insert will fail. To avoid that case I've modified above query to a transaction:
START transaction;
UPDATE users SET id = (SELECT `AUTO_INCREMENT`
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_SCHEMA = 'test'
AND TABLE_NAME = 'users') WHERE id = 2;
#renew auto increment to avoid duplicate warning on next insert
INSERT IGNORE INTO users(username) values ('');
COMMIT
Hope this will help someone if not OP.
The way you are trying to update same table is wrong but you can use join on same table
update idtest t
join (select id +1 as id
from idtest order by id desc
limit 1) t1
set t.id=t1.id
where t.id=3;
or
update idtest t
join (select max(id) +1 as id
from idtest ) t1
set t.id=t1.id
where t.id=3;
You can use the REPLACE INTO clause to do the trick.
From the manual:
REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted. See Section 13.2.5, "INSERT Syntax".
EDIT
My mistake (in the comments) that you have to have two unique constraint to achieve this:
When you use the auto_increment value to REPLACE the record, the record will be replaced with the give ID and will not change (however the AI value will increment).
You have to exclude the AI column from the query. You can do that if you have one more UQ constraint.
Check this SQLFiddle demo: http://sqlfiddle.com/#!2/1a702e
The first query will replace all the records (but the id's value will not change).
The second one will replace it too, and the new AI value will be used. (Please note, that the second query does not contain the id column, and there is a UQ constraint on the some column).
You can notice, that the second query uses higher AI values than it is excepted: this is because the first replace incremented the AI value.
If you do not have two unique keys (one for the AI and one for another columns), the REPLACE statement will work as a normal INSERT statement!
(Ofcourse you can change one of the UNIQUE KEYs with a PRIMARY KEY)
SELECT LAST_INSERT_ID() as id FROM table1
Why does this query sometimes return the last inserted id of another table other than table1?
I call it in Node.js (db-mysql plugin) and I can only do queries.
LAST_INSERT_ID() can only tell you the ID of the most recently auto-generated ID for that entire database connection, not for each individual table, which is also why the query should only read SELECT LAST_INSERT_ID() - without specifying a table.
As soon as you fire off another INSERT query on that connection, it gets overwritten. If you want the generated ID when you insert to some table, you must run SELECT LAST_INSERT_ID() immediately after doing that (or use some API function which does this for you).
If you want the newest ID currently in an arbitrary table, you have to do a SELECT MAX(id) on that table, where id is the name of your ID column. However, this is not necessarily the most recently generated ID, in case that row has been deleted, nor is it necessarily one generated from your connection, in case another connection manages to perform an INSERT between your own INSERT and your selection of the ID.
(For the record, your query actually returns N rows containing the most recently generated ID on that database connection, where N is the number of rows in table1.)
SELECT id FROM tableName ORDER BY id DESC LIMIT 1
I usually select the auto-incremented ID field, order by the field descending and limit results to 1. For example, in a wordpress database I can get the last ID of the wp_options table by doing:
SELECT option_id FROM wp_options ORDER BY option_id DESC LIMIT 1;
Hope that helps.
Edit - It may make sense to lock the table to avoid updates to the table which may result in an incorrect ID returned.
LOCK TABLES wp_options READ;
SELECT option_id FROM wp_options ORDER BY option_id DESC LIMIT 1;
Try this. This is working
select (auto_increment-1) as lastId
from information_schema.tables
where table_name = 'tableName'
and table_schema = 'dbName'
Most easy way:
select max(id) from table_name;
I only use auto_increment in MySQL or identity(1,1) in SQL Server if I know I'll never care about the generated id.
select last_insert_id() is the easy way out, but dangerous.
A way to handle correlative ids is to store them in a util table, something like:
create table correlatives(
last_correlative_used int not null,
table_identifier varchar(5) not null unique
);
You can also create a stored procedure to generate and return the next id of X table
drop procedure if exists next_correlative;
DELIMITER //
create procedure next_correlative(
in in_table_identifier varchar(5)
)
BEGIN
declare next_correlative int default 1;
select last_correlative_used+1 into next_correlative from correlatives where table_identifier = in_table_identifier;
update correlatives set last_correlative_used = next_correlative where table_identifier = in_table_identifier;
select next_correlative from dual;
END //
DELIMITER ;
To use it
call next_correlative('SALES');
This allows you to reserve ids before inserting a record. Sometimes you want to display the next id in a form before completing the insertion and helps to isolate it from other calls.
Here's a test script to mess around with:
create database testids;
use testids;
create table correlatives(
last_correlative_used int not null,
table_identifier varchar(5) not null unique
);
insert into correlatives values(1, 'SALES');
drop procedure if exists next_correlative;
DELIMITER //
create procedure next_correlative(
in in_table_identifier varchar(5)
)
BEGIN
declare next_correlative int default 1;
select last_correlative_used+1 into next_correlative from correlatives where table_identifier = in_table_identifier;
update correlatives set last_correlative_used = next_correlative where table_identifier = in_table_identifier;
select next_correlative from dual;
END //
DELIMITER ;
call next_correlative('SALES');
If you want to use these workarounds:
SELECT id FROM tableName ORDER BY id DESC LIMIT 1
SELECT MAX(id) FROM tableName
It's recommended to use a where clause after inserting rows. Without this you are going to have inconsistency issues.
in my table inv_id is auto increment
for my purpose this is worked
select `inv_id` from `tbl_invoice`ORDER BY `inv_id` DESC LIMIT 1;
How can I edit the latest row in the database. I only know it's the last one. I don't know its id.
I don't know which language you are working with, in PHP's mySQL functions you can use
mysql_insert_id()
there are similar function in every other mySQL client library I know of.
Also, there is a native mySQL function!
LAST_INSERT_ID() (with no argument)
returns the first automatically
generated value that was set for an
AUTO_INCREMENT column by the most
recently executed INSERT statement to
affect such a column. For example,
after inserting a row that generates
an AUTO_INCREMENT value, you can get
the value like this:
mysql> SELECT LAST_INSERT_ID();
-> 195
Of course, a primary key with AUTO_INCREMENT is required for these functions to work.
For a table with an auto_increment id field:
UPDATE tbl SET col1 = 'val1' WHERE id = MAX(id);
If it's a row that has been inserted in your script (the same script from which you want to update it) and there is an auto_increment column on your table, you can get that auto_increment value, using functions such as those, for PHP :
mysql_insert_id
mysqli_insert_id
PDO::lastInsertId
There should be an equivalent for probably any language you can possibly be using for your application.
If your are trying to do an update from another script than the one in which you did the insert, and still have an auto_increment column, the best way will probably be to update the row that has the biggest value for that column :
update your_table
set your_column = ...
where id = max(id)
Or, in two steps (not sure it'll work in one) :
select max(id) as id from your_table
update your_table set your_column = ... where id = [what you got with thr first query]
You can also use UPDATE table SET ... WHERE id=LAST_INSERT_ID() (supposing the last insert was on the table you want to query).
I would not use TWO steps to find the last insert ID simply because a new record could be added in the mean time.
Depending on your version, you should be able to call $handle->last_id(); or $handle->{mysql_insertid};
Chris
I want to do all these update in one statement.
update table set ts=ts_1 where id=1
update table set ts=ts_2 where id=2
...
update table set ts=ts_n where id=n
Is it?
Use this:
UPDATE `table` SET `ts`=CONCAT('ts_', `id`);
Yes you can but that would require a table (if only virtual/temporary), where you's store the id + ts value pairs, and then run an UPDATE with the FROM syntax.
Assuming tmpList is a table with an id and a ts_value column, filled with the pairs of id value, ts value you wish to apply.
UPDATE table, tmpList
SET table.ts = tmpList.ts_value
WHERE table.id = tmpList.id
-- AND table.id IN (1, 2, 3, .. n)
-- above "AND" is only needed if somehow you wish to limit it, i.e
-- if tmpTbl has more idsthan you wish to update
A possibly table-less (but similar) approach would involve a CASE statement, as in:
UPDATE table
SET ts = CASE id
WHEN 1 THEN 'ts_1'
WHEN 2 THEN 'ts_2'
-- ..
WHEN n THEN 'ts_n'
END
WHERE id in (1, 2, ... n) -- here this is necessary I believe
Well, without knowing what data, I'm not sure whether the answer is yes or no.
It certainly is possible to update multiple rows at once:
update table table1 set field1='value' where field2='bar'
This will update every row in table2 whose field2 value is 'bar'.
update table1 set field1='value' where field2 in (1, 2, 3, 4)
This will update every row in the table whose field2 value is 1, 2, 3 or 4.
update table1 set field1='value' where field2 > 5
This will update every row in the table whose field2 value is greater than 5.
update table1 set field1=concat('value', id)
This will update every row in the table, setting the field1 value to 'value' plus the value of that row's id field.
You could do it with a case statement, but it wouldn't be pretty:
UPDATE table
SET ts = CASE id WHEN 1 THEN ts_1 WHEN 2 THEN ts_2 ... WHEN n THEN ts_n END
I think that you should expand the context of the problem. Why do you want/need all the updates to be done in one statement? What benefit does that give you? Perhaps there's another way to get that benefit.
Presumably you are interacting with sql via some code, so certainly you can simply make sure that the three updates all happen atomically by creating a function that performs all three of the updates.
e.g. pseudocode:
function update_all_three(val){
// all the updates in one function
}
The difference between a single function update and some kind of update that performs multiple updates at once is probably not a very useful distinction.
generate the statements:
select concat('update table set ts = ts_', id, ' where id = ', id, '; ')
from table
or generate the case conditions, then connect it to your update statement:
select concat('when ', id, ' then ts_', id) from table
You can use INSERT ... ON DUPLICATE KEY UPDATE. See this quesion: Multiple Updates in MySQL
ts_1, ts_2, ts_3, etc. are different fields on the same table? There's no way to do that with a single statement.