Having an issue with a JOIN statement.
I'm trying to get a total per name, and not the current 1 with a ton of other same name records
SELECT a.`name`,
(SELECT COUNT(b.`id`)
FROM `host1_hosting` AS b
WHERE b.`id` = c.`host1_servers_host1_hosting_1host1_hosting_idb`) AS HostingCount
FROM `host1_servers` AS a
LEFT JOIN `host1_servers_host1_hosting_1_c` AS c ON c.`host1_servers_host1_hosting_1host1_servers_ida` = a.`id`
ORDER BY a.`name`
Example Returned
Name HostingCount
Name 1
Name 1
Name 1
Where it should be:
Name 3
I'm sure this is simple, but it's early monday, and I'm foggy
Query 2
SELECT a.`name`, COUNT(d.`id`)
FROM `host1_servers` AS a
JOIN `host1_servers_host1_hosting_1_c` AS c ON c.`host1_servers_host1_hosting_1host1_servers_ida` = a.`id`
JOIN `host1_hosting` AS d ON d.`id` = c.`host1_servers_host1_hosting_1host1_hosting_idb`
ORDER BY a.`name`
Gets me 1 name record, but a total of all COUNT
Your second query needs a group by:
SELECT a.`name`, COUNT(d.`id`)
FROM `host1_servers` AS a
JOIN `host1_servers_host1_hosting_1_c` AS c ON c.`host1_servers_host1_hosting_1host1_servers_ida` = a.`id`
JOIN `host1_hosting` AS d ON d.`id` = c.`host1_servers_host1_hosting_1host1_hosting_idb`
GROUP BY a.name
ORDER BY a.`name`;
Without the GROUP BY, MySQL interprets the query as an aggregation query to produce one row. The count() is the overall count. The column name is chosen arbitrarily from one of the rows (using a MySQL extension that wouldn't work in any other database).
EDIT:
If you want to keep all names from the first table and do the count, use left outer join:
SELECT a.`name`, COUNT(d.`id`)
FROM `host1_servers` a LEFT OUTER JOIN
`host1_servers_host1_hosting_1_c` c
ON c.`host1_servers_host1_hosting_1host1_servers_ida` = a.`id` LEFT OUTER JOIN
`host1_hosting` d
ON d.`id` = c.`host1_servers_host1_hosting_1host1_hosting_idb`
GROUP BY a.name
ORDER BY a.`name`;
Related
Is a nested SELECT statement possible in sql? I'm working on a problem and I can't seem to get the data that I want. This is the sql that Im querying:
SELECT derived.municipality, count(*) as counts, derived.bearing
from (SELECT m.name as municipality, count(*) as totalcount, sum(f.no_of_bearing_trees) as bearing
from farmer_profile f
inner join barangay b on f.barangay_id = b.id
inner join municipality m on b.municipality_id = m.id
inner join province p on m.province_id = p.id
group by b.name) as derived
group by derived.municipality, derived.bearing
Here is the sample data im working with. I want to get the sum of all the bearing and total counts when i put a where clause at the bottom (eg. where derived.bearing < 20). All of those bearings with less than 20 will totaled as well as their counts. I'm not sure if a subquery is needed again or not.
I suspect that you want to filter on municipalities whose bearing sum is less than 20. If so, you can use a having clause for this:
select
m.name as municipality,
count(*) as totalcount,
sum(f.no_of_bearing_trees) as bearing
from farmer_profile f
inner join barangay b on f.barangay_id = b.id
inner join municipality m on b.municipality_id = m.id
inner join province p on m.province_id = p.id
group by b.name
having sum(f.no_of_bearing_trees) < 20
MySQL is lax about column aliases in the having clause, so you can also do:
having bearing < 20
I have two tables that doesn't have relationship and I do a left and right join to simulate a full join on them and select some data.
the manner of displaying data is right but values are wrong, its looks like they selected more than once.
my tables are something like this :
TABLE 1 (bargains)
trade_date ---- profit
TABLE 2 (general_cost)
date ----- cost
this is the query that i write :
select b.trade_date, coalesce(sum(b.profit),0), coalesce(sum(g.cost),0)
from bargains as b
left join general_cost as g on b.trade_date = g.date group by b.trade_date
union
select g.date, coalesce(sum(b.profit),0), coalesce(sum(g.cost),0) from
bargains as b
right join general_cost as g on b.trade_date = g.date group by g.date
this is the result of query :
for example in date 1395-9-28 the sum of profit column should be 440 and sum of cost column should be 800
if it's help you should know that there is three row with this date in bargains table and two row in general_cost table
Yes, your query duplicates the matching records because those are included in both left and the right join. You need to exclude the matching records from one of the queries. I usually exclude them from the 2nd query of the union:
select b.trade_date, coalesce(sum(b.profit),0), coalesce(sum(g.cost),0)
from bargains as b
left join general_cost as g on b.trade_date = g.date group by b.trade_date
union
select g.date, coalesce(sum(b.profit),0), coalesce(sum(g.cost),0) from
bargains as b
right join general_cost as g on b.trade_date = g.date
where b.date is null //include only the records from general_cost that are not matched
group by g.date
UPDATE
If you have multiple records in both tables with the same date, then you need to do the summing per table separately in subqueries, otherwise the matching records do get duplicated:
select b.trade_date, b.profit, coalesce(g.cost,0)
from (select trade_date, sum(profit) as profit from bargains group by trade_date) as b
left join (select date, sum(cost) as cost from general_cost group by date) as g on b.trade_date = g.date
union
select g.date, 0, sum(g.cost) from //all profits has been summed up in the above query, so here we can use 0 in place of profit
bargains as b
right join general_cost as g on b.trade_date = g.date
where b.trade_date is null //include only the records from general_cost that are not matched
group by g.date
I am trying to create an SQL query that displays some information from different tables. But I'm getting the error Subquery returns more than 1 row SQL. I want it to display more than one row.
SELECT c.Name,
jn.ID,
jn.ActualWeight as GrossWt,
jn.JobNo,
COUNT(distinct jn.JobNo) as Jobs,
COUNT(distinct jd.JobID) as Dbriefs,
COUNT(distinct jn.OutTurn) as Outturns,
(select Status from jobstat where CompanyID = jn.CompanyID AND Status = "DEL") as Delivery
FROM job_new jn
LEFT JOIN customer c ON jn.CompanyID = c.Company_ID
LEFT JOIN job_debriefs jd ON jn.JobNo = jd.JobID
LEFT JOIN jobstat js ON jn.CompanyID = js.CompanyID
WHERE jn.CompanyID = 36
I've tried adding GROUP BY and ORDER BY but that doesn't work either. If I remove the select State.... line it only displays one row when it should be displaying over a hundred
You need a group by:
SELECT c.Name, jn.ID, jn.ActualWeight as GrossWt, jn.JobNo,
COUNT(distinct jn.JobNo) as Jobs,
COUNT(distinct jd.JobID) as Dbriefs,
COUNT(distinct jn.OutTurn) as Outturns,
jobstat
FROM job_new jn LEFT JOIN
customer c
ON jn.CompanyID = c.Company_ID LEFT JOIN
job_debriefs jd
ON jn.JobNo = jd.JobID LEFT JOIN
jobstat js
ON jn.CompanyID = js.CompanyID
WHERE jn.CompanyID = 36
GROUP BY c.Name, jn.ID, jn.ActualWeight as GrossWt, jn.JobNo, js.status
I'm not sure what the subquery is supposed to be doing, so I'm guessing with regards to js.status.
The problem with your original query is the use of COUNT() in the SELECT. This turns the query into an aggregation query. Without a GROUP BY, exactly one row is returned. In most other databases, you would normally get an error.
I have 5 tables: a, b, c, d and e.
Each table is joined by an INNER JOIN on the id field.
My query is working perfectly fine as it is but I need to enhance it to count the result so I can echo it to the screen. I have not been able to get the count working.
There are very specific fields I am querying:
state_nm
status
loc_type
These are all parameters I enter manually into the query like so:
$_POST["state_nm"] = 'AZ'; ... // and for all other below values..
SELECT *
FROM main_table AS a
INNER JOIN table_1 AS b ON a.id = b.id
INNER JOIN table_2 AS c ON b.id = c.id
INNER JOIN blm table_3 AS d ON c.id = d.id
INNER JOIN table_4 AS e ON d.id = e.id
WHERE a.trq != ''
AND b.state_nm = '".$_POST["state_nm"]."'
AND b.loc_type LIKE \ "%".$_ POST ["loc_type"]."%\"
AND b.STATUS = '".$_POST["status"]."'
GROUP BY b.NAME
ORDER BY c.county ASC;
not sure I get exactly what is your goal here.
anyway, using "select *" and group by in the same query is not recommended and in some databases will raise an error
what I would do is something like that:
select a.name, count(*) from (
SELECT * FROM main_table as a
INNER JOIN table_1 as b
ON a.id=b.id
INNER JOIN table_2 as c
ON b.id=c.id
INNER JOIN blm table_3 as d
ON c.id=d.id
INNER JOIN table_4 as e
ON d.id=e.id
WHERE a.trq != ''
AND b.state_nm = '".$_POST["state_nm"]."'
AND b.loc_type LIKE \"%".$_POST["loc_type"]."%\"
AND b.status = '".$_POST["status"]."'
)a
group by a.name
the basic idea is to add an outer query and use group by on it...
hopefully this solves your problem.
In place of
SELECT *
in your query, you could replace that with
SELECT COUNT(*)
That query should return the number of rows that would be in the resultset for the query using SELECT *. Pretty easy to test, and compare the results.
I think that answers the question you asked. If not, I didn't understand your question.
I didn't notice the GROUP BY in your query.
If you want to get a count of rows returned by that query, wrap it in outer query.
SELECT COUNT(1) FROM (
/* your query here */
) c
That will give you a count of rows returned by your query.
I'm not that into MySQL joins, so maybe you could give me a hand. I've got the following tables:
Table a
Fields ID,name
Table b
Fields aID,cID,ID,found
Table c
Fields ID,name
The result I want to get is the following: I want all the records where b.found = 1. Of these records I don't want a.id or a.name, but I want the number of records that would have been returned if I would have wanted so. So if there are five records that have b.found = 1 and c.id = (for example) 3, then I want a returned value of 5, c.id and c.name.
Someone is able to do this?
Actually this is what I want to get from the database:
A list of all records in table C and a count of records in table B that has found = 1 and b.c_id = c.id
Table: a
Fields: ID, name
Table: b
Fields: aID, cID, found
Table: c
Fields: ID, name
SELECT c.ID, c.name, COUNT(1)
FROM b
JOIN c ON c.ID = b.cID AND b.found=1
GROUP BY c.ID
SELECT c.id, c.name, COUNT(*)
FROM c
INNER JOIN b
ON c.id = b.c_id
AND b.found = 1
GROUP BY c.id, c.name
SELECT COUNT(*), c.id, c.name
FROM a, b, c
WHERE a.id = b.a.id AND c.id = b.a.id AND b.found = 1 AND c.id = idThatIAmSearchingFor
Apologies if I didn't get the syntax exact, but I believe that's the basic structure you want. The COUNT function returns the number of rows found by the query.
Something like:
SELECT count(`c`.*),
`c`.`id`,
`c`.`name`
FROM `b`
JOIN `c`
ON `c`.`id` = `b`.`c_id`
WHERE `b.found` = 1
I think this would provide the required output -
select count(*), b.cID, c.name from b
inner join c on c.id=b.cID and b.found=1
group by b.cID
SELECT COUNT(*) AS Count, c.id, c.name
FROM b join a on a.id = b.a_id
WHERE b.found = 1
GROUP BY c.Id;
COUNT returns count of records in each group from GROUP BY.