How can I execute insert queries while retrieving data from database?
I mean that after running a select query where I am retrieving data using a while loop, I also want to insert some fields into another table.
I want to execute inserts forcefully in PHP code.
I tried:
$firstview=mysql_query("insert into kadam_firstview(jobtype,jobname,admin_id,date,datetime)values('".$trial."','".$jobname."','".$adminid."','".$time."','".$date."')");
$firstview.execute();
But it doesn't work.
i want to run upper query inside select query as i am getting data from select query at that same time i want to save those data inside another table but query giving error which is mentioned above
I think your question is more for php developer then for dba.
Anyway if I understand you correctly you would like to select a record set from a table and insert this values (or modified one) into another table?
<?php
$db = new mysqli("host", "username", "password", "databasename");
$result = $db->query("SELECT * FROM table_name");
while ($row = $result->fetch_object()) {
$trail = $row->trail;
$jobname = $row->jobname;
$adminid = 25;
$time = $row->time;
$date = $row->date;
$query = "insert into kadam_firstview(jobtype,jobname,admin_id,date,datetime) values('".$db->escape_string($trial)."','".$db->escape_string($jobname)."','".$db->escape_string($adminid)."','".$db->escape_string($time)."','".$db->escape_string($date)."')";
$db->query($query);
}
this will copy the rows from the table "table_name" into the table "kadam_firstview" and set the adminid to 25.
http://php.itronic.at/manual/en/class.mysqli.php
Related
I'm trying to insert an item into a table using both posted variables and something from another table. I'm not quite sure where I am going wrong because nothing is being added to the table. I'm super confused. Here is my code:
$stmt = $conn->prepare("INSERT INTO Student_Choices (Username,T1_Choice,T2_Choice,T3_Choice,Current_DB)
VALUES (:username,:t1choice,:t2choice,:t3choice, db.DB)
SELECT DB FROM Current_DB as db
");
$stmt->bindParam(':username', $_SESSION['username']);
$stmt->bindParam(':t1choice', $_POST["term1sport"]);
$stmt->bindParam(':t2choice', $_POST["term2sport"]);
$stmt->bindParam(':t3choice', $_POST["term3sport"]);
$stmt->execute();
The SELECT DB FROM Current_DB as db is not valid inside the INSERT sentence. Just execute this query first, then get the DB value into a variable, and finally use it with bindParam() as you do with the other parameters: Something like this:
/* Get the database name. */
$stmt = $conn->prepare("SELECT DB FROM DB_Year");
$stmt->execute();
$res = $stmt->fetchAll();
$db = $res[0]['DB'];
/* Execute the insert statement. */
$stmt = $conn->prepare(
"INSERT INTO Student_Choices (Username, T1_Choice, T2_Choice, T3_Choice, Current_DB)
VALUES (:username, :t1choice, :t2choice, :t3choice, :db)"
);
$stmt->bindParam(':username', $_SESSION['username']);
$stmt->bindParam(':t1choice', $_POST["term1sport"]);
$stmt->bindParam(':t2choice', $_POST["term2sport"]);
$stmt->bindParam(':t3choice', $_POST["term3sport"]);
$stmt->bindParam(':db', $db);
$stmt->execute();
To design this INSERT query, start by using SELECT to create the result set you want to insert.
SELECT :username AS Username,
:t1choice AS t1choice,
:t2choice AS t2choice,
:t3choice AS t3Choice,
DB
FROM Current_DB
Then use that result set as the data source for your insert.
INSERT INTO Student_Choices
(Username,T1_Choice,T2_Choice,T3_Choice,Current_DB)
SELECT :username AS Username,
:t1choice AS t1choice,
:t2choice AS t2choice,
:t3choice AS t3Choice,
DB
FROM Current_DB
Notice how the SELECT operation replaces the VALUES() clause.
(Careful, unless you put an appropriate WHERE clause on the SELECT, you may get lots of rows inserted, one for each row in Current_DB.)
I am trying to insert records in 2 different mysql tables. Here's the situation:
Table 1: is_main that contains records of resorts with a primary key called id.
Table 2: is_features that contains a list of features that a resort can have (i.e. beach, ski, spa etc...). Each feature has got a primary key called id.
Table 3: is_i2f to connect each resort id with the feature id. This table has got 2 fields: id_i and id_f. Both fields are primary key.
I have created a form to insert a new resort, but I'm stuck here. I need a proper mysql query to insert a new resort in the is_main table and insert in is_i2f one record for each feature it has, with the id of the resort id id_i and the id of the feature id id_f.
$features = ['beach','relax','city_break','theme_park','ski','spa','views','fine_dining','golf'];
mysql_query("INSERT INTO is_main (inv_name, armchair, holiday, sipp, resort, price, rooms, inv_length, more_info)
VALUES ('$name', '$armchair', '$holiday', '$sipp', '$resort', '$price', '$rooms', '$length', '$more_info')");
$id = mysql_insert_id();
foreach($features as $feature) {
if(isset($_POST[$feature])) {
$$feature = 1;
mysql_query("INSERT INTO is_i2f (id_i, id_f) VALUES (" . $id . ", ?????????????? /missing part here????/ ); }
else {
$$feature = 0; }
}
Thanks.
Please, I'm going CrAzY!!!!!!!!!!!!!!
This may not be relevant to you, but...
Would it not make more sense to leave the link table unpopulated? You can use JOINs to then select what you need to populate the various views etc in your application
i.e. query to get 1 resort with all features:
SELECT
Id,
f.Id,
f.Name
FROM IS_MAIN m
CROSS JOIN IS_FEATURES f
WHERE m.Id = $RequiredResortId
Please find the answer on Mysql insert into 2 tables.
If you want to do multiple insert at a time you can write a SP to fulfill your needs
If I understand you correctly you could concatenate variable amount of to be inserted/selected values into one query. (This is the second query which needs an id from the first.)
//initializing variables
$id = mysql_insert_id();
$qTail = '';
$i = -1;
//standard beginning
$qHead = "INSERT INTO `is_i2f` (`id`,`feature`) VALUES ";
//loop through variable amount of variables
foreach($features] as $key => $feature) {
$i++;
//id stays the same, $feature varies
$qValues[$i] = "('{$id}', '{$feature}')";
//multiple values into one string
$qTail .= $qValues[$i] . ',';
} //end of foreach
//concatenate working query, need to remove last comma from $qTail
$q = $qHead . rtrim($qTail, ',');
Now you should have a usable insert query $q. Just echo it and see how it looks and test if it works.
Hope this was the case. If not, sorry...
I have simple query:
$table_name = 'v_c_holi_2012';
$STH_h3 = $DBH_R->query("SELECT DATE(date_time) AS day_h
FROM `$table_name`
");
and it is working ok.
But I must do this query with table name and when I try this:
$table_name = 'v_c_holi_2012';
$STH_h3 = $DBH_R->query("SELECT `$table_name`.DATE(date_time) AS day_h
FROM `$table_name`
");
or
$table_name = 'v_c_holi_2012';
$STH_h3 = $DBH_R->query("SELECT v_c_holi_2012.DATE(date_time) AS day_h
FROM `$table_name`
");
this is not working (Fatal error: Call to a member function fetch_assoc() on a non-object).
What I 'm doing wrong?
The date function should not have the table prefix since it is a system function.
Instead you need to put the table alias before your field date($table_name.date_time).
By the way, you don't need to if you select from only one table.
I believe $table_name.DATE(date_time) should be DATE($table_name.date_time)
You should apply the table name to the thing that's in the table (i.e. the field name), not the DATE function (which has nothing to do with your table).
i.e.
$table_name = 'v_c_holi_2012';
$STH_h3 = $DBH_R->query(
"SELECT DATE(`$table_name`.`date_time`) AS `day_h`
FROM `$table_name`"
);
I have a table with 27 varchar fields. I want to make all fields lowercase, but i want to do it in one short mysql call.
This does a single field:
UPDATE table
SET field = LOWER(field)
How do I do the equivalent of this (which doesn't work):
UPDATE table
SET * = LOWER(*)
You can't do it with your creative attempt SET * = LOWER(*) etc.
You can however do it like this:
UPDATE table SET
column1 = LOWER(column1),
column2 = LOWER(column2),
-- etc, listing all text type columns
columnN = LOWER(columnN);
The reason there's no "shortcut" is probably because this pattern is so infrequently needed.
The consensus is that this cannot be done in a single mysql query.
Here is a super quick PHP script that does this for N fields (thanks for the idea #alex):
$sql = "SHOW COLUMNS
FROM table";
$results = mysqli_query($dbcon,$sql);
while($column = mysqli_fetch_assoc($results))
{
$column = $column["Field"];
$sql = "UPDATE table
SET $column = LOWER($column)";
$success = mysqli_query($dbcon,$sql);
}
In my table I have an userID that is auto-incremented. In the same row I have an idHash. Is it possible to generate the idHash (simply an MD5 sum) from it directly with the same INSERT statement so that I don't have to SELECT the id, and then UPDATE the idHash again?
Problem is: I do not know the userID before it is being generated (auto-incremented) by MySQL.
Thanks
Frank
PS: I'm using PHP.
PPS: This question is all about a SINGLE INSERT. I know that I can use PHP or other languages to manually select the data and then update it.
I don't believe you can do it within a single INSERT statement.
What you probably could do is use an INSERT trigger, that both determines the new ID, hashes it, and then updates the record.
One solution I can recommend is using the last insert ID instead of re-querying the table. Here is a simplified example:
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$query = "INSERT INTO users VALUES (....)";
$mysqli->query($query);
$newUserID = $mysqli->insert_id;
$query = "UPDATE users SET idHash = MD5(userID) WHERE userID = $newUserID";
$mysqli->query($query);
/* close connection */
$mysqli->close();
?>
AFAIK there's no "secure" way for doing this in the same query if you're using auto_increment.
However, if rows are never deleted in your table, you can use this little trick :
insert into mytable (col1, col2, col3, idhash)
values ('', '', '', md5(select max(id) from mytable))
I don't understand why you need to hash the id though, why not use the id directly ?
This seems to work for me:
CREATE TABLE tbl (id INT PRIMARY KEY AUTO_INCREMENT, idHash TEXT);
INSERT INTO tbl (idHash) VALUES (MD5(LAST_INSERT_ID() + 1));
SELECT *, MD5(id) FROM tbl;
Note this will only work on single-row inserts as LAST_INSERT_ID returns the insert ID of the first row inserted.
Performing MD5(column_name) on an auto_increment value does not work as the value has not been generated yet, so it is essentially calling MD5(0).
PHP snippet
<?
$tablename = "tablename";
$next_increment = 0;
$qShowStatus = "SHOW TABLE STATUS LIKE '$tablename'";
$qShowStatusResult = mysql_query($qShowStatus) or die ( "Query failed: " . mysql_error() . "<br/>" . $qShowStatus );
$row = mysql_fetch_assoc($qShowStatusResult);
$next_increment = $row['Auto_increment'];
echo "next increment number: [$next_increment]";
?>
This will get you the next auto-increment and then you can use this in your insert.
Note: This is not perfect (Your method is imperfect as you will effectively have 2 primary keys)
From: http://blog.jamiedoris.com/geek/560/