I try to select the the rows with the newest timestamp in change_date from a table in a LEFT JOIN. I really don't know why this query fails:
SELECT
i.ID, i.title, i.create_date,
u1.username creator_name,
u2.username assignee
FROM item i
LEFT JOIN user u1 ON u1.login_IDFK = i.creator_IDFK
LEFT JOIN user u2 ON u2.login_IDFK = i.assigned_to_IDFK
LEFT JOIN (
SELECT MAX(change_date), item_IDFK FROM item_state GROUP BY item_IDFK
) AS ist ON ist.item_IDFK = i.ID
I get the following error
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') AS ist ON ist.item_IDFK = i.ID' at line 2 (Code: 1064)
Query works great without the last LEFT JOIN
(SELECT change_date, item_IDFK FROM item_state GROUP BY item_IDFK)
You are using a group by clause without an aggregate. Each item in the select list must either be represented in the group by clause, or be part of an aggregate expression
I.E.
(Select Max(Change_Date), item_IDFK from item_state group by item_IDFK)
try to save your last subquery in a view table, and after that, left join from that table, and see if the syntax error persists.
Related
I have a query that works perfectly, however I need to change it a bit but it shows me an error and I can't figure out why. Below is the code before and after the changes I made:
BEFORE:
SELECT *,
(SELECT GROUP_CONCAT(pho_file_name) FROM post_images WHERE pho_post_id=posts.ID) AS photo_file_array
FROM users
INNER JOIN posts ON users.Id = posts.post_author
ORDER BY posts.ID;
AFTER:
SELECT *,
(SELECT GROUP_CONCAT(pho_file_name) FROM post_images WHERE pho_post_id=posts.ID) AS photo_file_array
FROM users WHERE users.Id = "1"
INNER JOIN posts ON users.Id = posts.post_author ON posts.post_date = "2020-12-04 07:51:21"
ORDER BY posts.ID;
It shows me the following error:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'INNER JOIN posts ON users.Id = posts.post_author AND posts.post_date "2020-12...' at line 4
I'm a newbie on MySql but from what I can understand I think the error occurs because of the the double ON inside the INNER JOIN. So, is it possible to add multiple ON inside the INNER JOIN? Thanks in advance!!
You have a few syntax issues, you can't put joins and where anywhere, you also need to use the correct delimiters and data types.
Try the following and note using table and column aliases makes for an easier-to-read query.
Additionally, consider not using select * and reference only the columns you actually require, if possible.
SELECT u.*, p.*, (
SELECT GROUP_CONCAT(i.pho_file_name)
FROM post_images i
WHERE i.pho_post_id = p.ID
) AS photo_file_array
FROM users u
JOIN posts p ON p.post_author = u.Id
AND p.post_date = '2020-12-04 07:51:21'
WHERE u.Id = 1
ORDER BY p.ID;
Here is a full working query. The errors (double ONclause, WHERE clause in the wrong position, wrong quotes) are corrected. Moreover, the ID is compared to an integer now and the post_date to a timestamp literal. I've used table aliases to get this more readable.
SELECT
u.*,
p.*,
(
SELECT GROUP_CONCAT(pi.pho_file_name)
FROM post_images pi
WHERE pi.pho_post_id = p.id
) AS photo_file_array
FROM users u
INNER JOIN posts p ON p.post_author = u.id
AND p.post_date = TIMESTAMP '2020-12-04 07:51:21'
WHERE u.id = 1
ORDER BY p.id;
As to the tables: I suggest you are more consistent with your column names. Why do you call the post ID post_author? One would assume a name here. Just call it post_id in every table. And you don't have to precede columns with abreviations like pho. Just qualify all columns with their tables like I did in my query.
I have a problem with the following statement:
SELECT SUM(foreseen_charges.commonCharge) as required, foreseen_charges.flatsId
LEFT JOIN (SELECT deposits.flatsId FROM deposits GROUP BY flatsId) deps
ON foreseen_charges.flatsId = deps.flatsId
FROM foreseen_charges GROUP BY foreseen_charges.flatsId
And I always getting this error:
You have an error in your SQL syntax; check the manual that corresponds
to your MySQL server version for the right syntax to use near 'LEFT
JOIN (SELECT deposits.flatsId FROM deposits GROUP BY flatsId) deps
ON f' at line 2
Could anyone help me?
Best Regards,
Cs
Put FROM before LEFT JOIN
SELECT SUM(foreseen_charges.commonCharge) as required,
foreseen_charges.flatsId
FROM foreseen_charges
LEFT JOIN (
SELECT deposits.flatsId
FROM deposits
GROUP BY flatsId
) deps ON foreseen_charges.flatsId = deps.flatsId
GROUP BY foreseen_charges.flatsId
You're doing things out of order. The general structure is:
SELECT (something) FROM table JOIN other-table ON table.var1=other-table.var2 WHERE situation
You're doing this:
SELECT (something) LEFT JOIN table ON table.var1=other-table.var2 FROM other-table
You can't join until you've declared both tables, and you can't relate other-table because you haven't declared it yet.
Unsure what the query is meant to accomplish, but this should fix your syntax error:
SELECT SUM(foreseen_charges.commonCharge) as required, foreseen_charges.flatsId
FROM foreseen_charges
LEFT JOIN (SELECT deposits.flatsId FROM deposits GROUP BY flatsId) deps
ON foreseen_charges.flatsId = deps.flatsId
GROUP BY foreseen_charges.flatsId
It's probably something I can't seem to understand with MySQL, but after wasting my day going through StackOverflow's related questions without fixing the issue, I decided to ask about it.
SELECT users.idUser, users.name, categoryName
FROM users
LEFT JOIN (
SELECT `translation` as categoryName
FROM localization,
usercategories
WHERE localization.`string` = usercategories.name
AND usercategories.idUserCategory = users.idUserCategory
)
as Something
WHERE users.idUser != 1
ORDER BY users.name ASC
Whichever query I tried today that would include a subquery, I would get the same syntax error at pretty much the same place: right after the subquery's alias (in this case, Something).
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE users.idUser != 1 ORDER BY users.name ASC LIMIT 0, 30' at line 11
This issue here is that you're missing the ON clause of your join. You need to select a condition to join the two tables together, like this:
SELECT stuff
FROM stuff
LEFT JOIN (other stuff)
ON stuff.something = otherstuff.something. // Add here.
You're JOIN criteria is non-ANSI and does not have an ON clause ... perhaps that is causing it? Try this, a bit more optimized:
SELECT Usr.idUser AS idUser
,Usr.name AS name
,UsrCat.translation AS categoryName
FROM users AS Usr
LEFT OUTER JOIN usercategories AS UsrCat
ON UsrCat.idUserCategory = Usr.idUserCategory
LEFT OUTER JOIN localization AS Lcl
ON Lcl.string = UsrCat.name
WHERE Usr.idUser <> 1
ORDER BY Usr.name ASC
No need for subquery, should be pretty performant.
You could re-organize your query so that it does not need a sub-query. This would also allow you the benefit of adding more columns to the select from any of the tables. Also, it is more correct.
SELECT
users.idUser,
users.name,
localization.`translation` as categoryName
FROM users
LEFT JOIN usercategories ON usercategories.idUserCategory = users.idUserCategory
LEFT JOIN localization ON localization.`string`= usercategories.name
WHERE users.idUser <> 1
ORDER BY users.name ASC
I have this query and appearently it's faulty?
I'm trying to join fices with mems so I can have the ficeID along with all the results from mems(These queries work individually). What am I doing wrong?
SELECT *
FROM mems
WHERE deleted <> -1
ORDER BY sort_mems
LEFT JOIN SELECT ficeID
FROM fices
Result:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LEFT JOIN SELECT ficeID FROM offices LIMIT 0, 30' at line 1
You have JOIN clause after ORDER BY. You should place it in FROM.
I suggest you define condition of a LEFT JOIN
Also, I suggest you surround you temp tables with brackets:
SELECT m.*, t1.officeID
FROM members m
LEFT JOIN offices t1
ON m.memberID = t1.memberID
WHERE m.deleted <> -1
ORDER BY m.sort_membername;
Yes, you have the LEFT JOIN in the wrong spot (it should go after your FROM clause, and you also seem to be missing a join criteria (the ON part, this tells the database how these tables are related):
SELECT *
FROM mems m
LEFT JOIN fices f
ON m.??? = f.???
WHERE deleted <> -1
ORDER BY sort_mems
I want to get all fields from one table and use DISTINCT with the second table.
I have this:
SELECT stats.*,
DISTINCT(visit_log.blog_id) AS bid
FROM stats
INNER JOIN visit_log ON stats.blog_id = visit_log.blog_id
But I get this error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'DISTINCT(visit_log.blog_id) AS bid FROM stats INNER JOIN visit_log ON stats.blog' at line 1
Any idea?
Instead of joining against visit_log, you can construct a derived table containing only the distinct blog_id values.
select stats.*, v.blog_id
from stats
inner join ( select distinct blog_id from visit_log where stats.blog_id = visit_log.blog_id ) as v
SELECT stats.*, dr.blog_id
FROM stats
INNER JOIN (SELECT DISTINCT(visit_log.blog_id) AS bid FROM visit_log) AS dr
ON stats.blog_id = dr.blog_id
You are only selecting blog_id from visit_log which is the column you are joining on. So your query is much like:
select *
from stats s
where
exists (select null from visit_log v where s.blog_id = v.blog_id)
select * from visit_log v where v.blog_id in/= (select s.blog_id from stats s)