Is there a way to write in mediawiki syntax to show the day of the week?
I'd like to be able to enter in something like #dateformat:2014-02-16|??? and get back Sunday, February 16, 2014
Yes, like this: {{#time: l, F d, Y |2014-02-16}}. Days of weeks are not always localized though, so you have to doublecheck that it works for all the languages you are using. Weekdays also won't work for dates before 1753.
Related
I have a problem with the date function in visualforce.
My code looks as following:
<apex:outputText value="{0, date, DD MMMM YYYY}">
<apex:param value="{!Opportunity.Invoice_Due_Date__c}" /> </apex:outputText>
Invoice_Due_Date__c is a simple datepicker with no specific rules.
Everytime a date is selected month and year are shown correctly, but day always has numbers higher than 150, which makes absolutly no sense.
Do I have to change the code or the settings of the custom field?
Visualforce follows Java's "simple date format" rules. <apex:outputText> documentation has example of yyyy.MM.dd rendering to 2004.11.20.
Capital D means day-in-year, 1 to 366 range :)
Pay attention to capital Y too, you want it lowercase. Uppercase one is used in some tricky reporting like if you have factory/warehouse/accounting team insisting new year doesn't always start on January 1st. Sometimes they'll swear to you July started on June 29th ;) Crazy people
Select to_date(to_char(date_part('year',current_date),'0000') || trim(to_char(date_part('month',current_date),'00')) || '01','YYYYMMDD')
So far, this is the best I can come up with.
I am also unable to find a comprehensive language reference for Netezza SQL that has all functions in it, so please include a source in your answer.
Use date_trunc('month', current_ date), which is documented here.
Start with the date, for what I needed today, was using current date/month. Then find the last day of the current month. That's the outer shell for the first day as a systematic output:
start with the current date
use add_months (-1) to subtract a month;
find the last day of the previous month;
add 1 day.
I then decided to test out on February (leap year and normal), finding the first from the first, and then adding in finding the first of the next month. Also checked looking at a month ago from a month ending 31st and 30th. I think this should be flexible.
select current_date,
last_day(add_months(current_date,-1))+1 as firstdt_currmos,
last_day(current_date) as lastdt_currmos
;
select last_day(add_months('02-29-2016',-1))+1 as firstdt_febleap,
last_day(add_months('02-28-2019',-1))+1 as firstdt_febnorm,
last_day(add_months('07-01-2019',-1))+1 as firstdt_first,
last_day(add_months(current_date,-1))+1 as firstdt_currmos,
last_day(current_date)+1 as firstdt_nextmos,
last_day(add_months('07-31-2019',-1))+1 as firstdt_mos31st,
date(add_months('07-31-2019',-1)) as mosago_31st,
date(add_months('06-30-2019',-1)) as mosago_30th
;
Im having problems with this.
I have this qlikview script which is run on the 15th of every month. This script intends to automatically take the last date of the previous month in the format of 'YYYY-MM-DD'.
For example today is 15th January 2017. I will run my script and it will give me a date of 31th December 2016 in the format 2016-12-31.
If it is 15th December 2016, I will get 30th November 2016 in the format 2016-11-30.
I want to set the date retrieved as a variable in the format yyyy-mm-dd to be used in another query.
Basically I tried
SET #vLastDate = DATE_FORMAT(select last_day(curdate() - INTERVAL 1 MONTH), '%Y-%m-%d');
but I receive an error that it does not execute. I am doing this in qlikview. Please help me identify my problem thank you.
You are trying to execute mysql functions in qlikview? That won't work.
Try in QV script:
let vLastDate = MonthEnd(AddMonths(Today(),-1));
If you need to change the date format, play around with the Date#() function, probably something like Date#(Field, 'YYYY-MM-DD'). Today() returns YYYY-MM-DD format so it will probably be fine.
I need current month name as default perameter name in my ssrs report. How can I get current month name using an ssrs expression?
For example "27-09-2012" would become "September"
and one more i need....
27-09-2012 to previous month name as well (August)
First question:
=MonthName(Month(Fields!datefield.Value))
Second question:
=MonthName(Month(DateAdd("m", -1, Today())))
I think the second question answer might be something like that, first converting the date to month then subtracting 1 from the month value and then converting it to month name.
Further reading:
SSRS Reports get Month name from Month Index or from date
Converting month number to month name in reporting services
OFF: I would change the date format you are using to 2012-09-27 as it works in every setting and should give you peace of mind when converting date formats.
Don't subtract 1 b/c it won't work for January.
Use this:
MonthName(Month(DateAdd("m", -1, CDate(Today))))
As a note, I tried the suggestion of =MonthName(Month(today())). What I would get is #error for whatever field the expression was in. However, =MonthName(str(Month(today()))) worked for me. I am unsure of whether or not the MonthName method changed to require a string or if it is some issue with my program. Just figured I would post this in case anyone else was having the same issue.
For Previous Month i found universal way : =MonthName(Month(CDate(Today()))-1,False) for SEPTEMBER (Full Month Name) 'OR'
=MonthName(Month(CDate(Today()))-1,True) for SEP (Short Month Name)
Examples:
'DD/MM/YYYY
"1/1/2009" should give `1`
"31/1/2009" should give `5`
"1/2/2009" should also give `5`
Format("1/2/2009", "ww") returns 6.
So, how can I get the correct result?
It's doing two things here which don't match your expectations, I think:
Assuming you want the week with Jan 1 in as week 1, and using Sunday as first day of the week
So it has week 1 running from Sunday 28th December 2008 to Saturday 3rd Jan 2009.
Week 6 would begin on Sunday 1st Feb by this method.
The ISO standard is for week 1 to be the one containing 4 days of January, or the first Thursday of the year (different ways of expressing the same thing).
You can specify this method of calculation and the first day of the week:
Format(SomeDate,"ww",vbMonday,vbFirstFourDays)
see here for syntax:
https://support.office.com/en-US/article/Format-Function-6F29D87B-8761-408D-81D3-63B9CD842530
Regardless of the day of the week your week starts on, you need to pass unambiguous date values. "31/1/2009" can only be one date (Jan 31st), but "1/2/2009" could be Jan. 2 (US style) or Feb. 1st (everybody else who has more sense that we USAns).
In this case, I'd use DateSerial() to make sure the date is not misinterpreted:
Format(DateSerial(2009,2,1), "ww", vbMonday)
While this is not causing your problem, because Access helpfully utilizes your system's localized date settings, I think it's something you should do anyway. You certainly are forced to do so in SQL in Access, so I don't think it's a bad habit in code and expressions.
This might work: Format(YourDate, "ww",vbMonday)
"Correct result" depends on the locale. Maybe VBA will let you pick a calendar-system, otherwise you're pretty much out of luck.
Note that First-Day-On-xxDay isn't your only problem. There is also variation on what a complete week is so Week 1 in one system could be Week 53 of the previous year in another system.
So test thoroughly and don't be seduced to "correct by 1".
There is a whole standard for week numbers: ISO-8601
http://en.wikipedia.org/wiki/ISO_8601#Week_dates
I had the same problem.
It showed week 53 and week 1, yet days in week 53 and week 1 are all in week 1
I first tried changing the date format in the Access Query to this:
OrderWeek: Format([OrderDate],"yyyy-ww",1,3) <-- But it did not do the trick.
You get dates like 2014-52 for week 52 and 2015-52 where it was week 1 before.
Also the sorting was not how I liked. It sorted the data as 2014-1, 2014-11, 2014-2 etc. I want it to show as 2014-01, 2014-02 .. 2014-11 etc.
So here is the new code to display both the year and the week correctly in an Access Query:
ActualWeek: IIf(DatePart("ww",[SomeDate])=53,DatePart("yyyy",[SomeDate])+1,DatePart("yyyy",[SomeDate])) & "-" & IIf(DatePart("ww",[SomeDate])=53,"01",IIf(DatePart("ww",[SomeDate])<10,"0" & DatePart("ww",[SomeDate]),DatePart("ww",[SomeDate])))
This now shows any days from week 53 as being part of week 1
If sunday is the first day of the week (as it is in some locales) then 6 is the correct weeknumber for "1/2/2009" (february 1. 2009)
In terms of the sorting, I had the same issue and used this code to resolve it:
IIf(Format([SomeDate],"ww")<10,Format([SomeDate],"yyyy-") & "0" & Format([SomeDate],"ww"),Format([SomeDate],"yyyy-ww"))
If the week number is less than 10, add a zero, else leave it as is.
Now the sorting is fine. Hope this helps somebody.