I'm working in a content management system that allows me limited (no) access to the stylesheets, but does allow me to insert CSS into certain templates. So I have this:
<div class="inside_widget">
<div class="input"><span class="form_label">Form stuff</span></div>
<div class="input"><span class="form_label">Form stuff</span></div>
<div class="input"><span class="form_label">Form stuff</span></div>
etc...
</div>
Where inside_widget, input, and form_label are all defined in a sheet I can't touch. I want to put some custom CSS on "form_label" without having to touch every single span.
I tried using the style attribute in the containing div, but that did not work.
<div class="inside_widget" style=".form_label {color:#FFFFFF;}" >
Note: I want to retain everything else in the inside_widget styling, and not have to define a whole new class.
I think what the OP is trying to achieve is not having to repeat the style="" attribute for every single <span> in his form.
This can be done by simply adding your own class name to the enclosing div's classes:
<div class="inside_widget myclass" ...>
<!-- ... -->
</div>
Then make your own secondary stylesheet and define myclass:
.myclass span
{
color: #ffffff;
}
You can put this secondary CSS either in a <style> tag in the HTML itself, or in its own CSS file linked in.
You could do it this below.
<span class="form_label" style="color:#FFFFFF;">Form Stuff</span>
Inline styles like this will overwrite any css rules in a stylesheet, unless in the stylesheet they have a rule with !important
you do not know css right? will look like
<div class="inside_widget" style="color:#FFFFFF;" >
but I suggest you create a new css file and add whatever you want in the same
Related
I'm working on a webpage and I have an issue, I've created a css function for my image
#my_linkedin {
background: url("../img/linkedin.png");
}
but my isssue is that when I'm calling the class in my HTML, the image doesn't appear.
<div class="col-lg-4 ml-auto text-center mb-5 mb-lg-0">
<a onclick="window.open(this.href,'_blank');return false;" class="my_linkedin" href="https://www.linkedin.com" target="_self"></a>
</div>
My file is called creative.css and I also have the same file but minified. The issue is that on the webpage, the css are coming from the minified file, so how can I import my css who's coming from the creative.cssplease ? Because I don't want to have to put it in the minified one.
Thanks.
In this case you can have 2 problems.
First - link just empty and it width and height are equals to 0. So you cant see you backdround.
Second - I can see that you are using #my_linkedin as a selector which means that you is searching by id, replace to .my_linkedin.
You want .my_linkedin { ... }. # is for writing styles to match elements with matching id="..." attributes. . is for classes.
Some errors here.
You are referring to a css rule, not function.
You are defining a css rule for a specific id, but on your html your element don't have an id, instead it have a class.
#someid {
color: red;
}
.someclass {
color: green
}
<p class="someid">BLACK</p>
<p class="someclass">GREEN</p>
<p id="someid">RED</p>
<p id="someclass">BLACK</p>
Your problem isn't related to whether or not the file is minified. Your selector applies to an element with id="my_linkedin, but your HTML doesn't have such an element. You can either change class="my_linkedin to id="my_linkedin" or you can change the CSS selector to read .my_linkedin
In CSS you don't call that a function. The #my_linked part is called a selector and the stuff inside the curly braces are called properties. Likewise, you can't call anything in CSS as you would in a programming language.
I am using jsonform (https://github.com/joshfire/jsonform) in order to generate forms from json schema, and the jsonform requires his own css for the form, but i am using another css for my site's template.
Is there a way to apply a css only on a specific tag ? for example only to the html inside ?
I am using rails, so the head is not changing from page to page.
thanks.
If you're using a CSS preprocessor (i.e. SASS, LESS, SCSS, etc.) then it might be an easy job to just indent your custom css under one class/id/tag. You can check this SO question: apply CSS style to particular elements dynamically.
Try this>>>
<link rel="stylesheet" type="text/css" href="theme1.css">
<link rel="stylesheet" type="text/css" href="theme2.css">
Inside theme 1 you would link to certain classes and in theme2 you would link to other classes. Please comment back if you need more help or this is not ideal
for example html
<div id="test" class="testing"></div>
the css would be
#test{color:red;}/*for ids*/
.testing{color:red}/*for classes*/
the styling in the curly brackets can be changed to what you want and the classes and ids can be in any external css if you link your page to it using link rel=
Yes you can. You need to give an ID to the body of your HTML doc if you want to target only that page, or give an ID or class to the element you need to.
<!-- HTML -->
<div class="your-class">
Your content
In the CSS:
.your-class {
your: style;
}
or
<!-- HTML -->
<body id="your-id-name">
<div class="generic-class">
Your content
/* using CSS */
body#your-id-name {
your: style;
}
body#your-id-name .generic-class {
your: style;
}
Hope it helps ;-)
Yes, offcourse there is, that's what CSS is all about.
If you add an ID or a class to the containing element that holds the form, you can add that ID or class to all the CSS selectors in the JSONform css.
for instance:
<div class="jsonform">
{json form goes here}
</div>
and then in your jsonform css, prepend '.jsonform' to all the necessary selectors:
.jsonform input.text {border:none...}
.jsonform input.submit {background-color:...}
I had a look at that jsonform css. I'm amazed that it just uses the complete Twitter bootstrap CSS, there's quite a lot of styling in there that will definitely override your own CSS. I would try to strip out anything that's not directly needed for the form, like body, img, p and h1 declarations.
Maybe the form works fine without the extra styling; you can then apply your own CSS to the form elements...
The CSS included with jsonform is Bootstrap, but the README.md in the /deps directory states that usage of this file is optional. As long as you don't include bootstrap.css in your HTML, you can style the form controls however you'd like/avoid Bootstrap overriding your own styles.
If you want to keep using Bootstrap for jsonform ONLY, you can try "namespacing" the Bootstrap styles using LESS or SASS. Have a look at the first two answers to 'How to namespace Twitter Bootstrap so styles don't conflict' for an idea how to do that with LESS.
I have some classes that are used for Styling and all of them display using block mode.. I would like to convert them all to inline.. Is there a simple way to convert them all to inline, instead of manually going to each class to convert them individually to inline...
Section of your code:
<div class="contentbody">
<p>
Register here!
</p>
<a href="{% url 'parent_register_step1' %}"
class="bbutton textshadowclass boxshadow">
<div class="boxshadowinset green">
Register
</div>
</a>
<p>
Forgot your password?
</p>
<a href="{% url 'parent_forgot_password' %}"
class="bbutton textshadowclass boxshadow">
<div class="boxshadowinset green">
Reset Password
</div>
</a>
</div>
I would like to change the classes bbutton, textshadowclass, box shadow, boxshadowinset green into inline.. What is the simplest way?
Note: This classes are used in other sections of the page. I would like to change the certain section to be inline only. It shouldn't affect the whole page...
Let me explain more in detail what i am doing:
I would like to convert this into inline such that the register and reset password appear on the same line...
To only select the classes that are instead the contentbody class, you need a CSS element>element Selector:
div.contentbody>.bbutton, div.contentbody>.textshadowclass, ... {
display: inline;
}
(add more classes to the list if you want others included as well)
Additional note: If you permanently need these classes to be inline, then I would suggest to just (once) going to each class and add an inline class to each element, this keeps your code clearer in the long run.
Edit:
use the union selector (sorry I cannot find a more official link) to select elements that have multiple classes set:
div.contentbody>.boxshadowinset.green {
display: inline;
}
Note the . (and no space) between boxshadowinset and green
I do believe this is supported by modern browsers, but IE6 does seem to have some problems with it.
One way is just to apply an id to your wrapping element.
<div class="contentbody" id="contentbody">
Then in your css, add the styling
div#contentbody a, div#contentbody div{ display: inline; }
Due to CSS Element Hierarchy, they will all take the inline style rather than their own style.
Basic example here. http://jsfiddle.net/H97c5/2/
I have a menu with links in the following form, in which I am trying to highlight the current menu item. I can't seem to get it working. Please advice as to what I am doing wrong
HTML
<body id="home">
<div id="topMenu">
<div class="nav-home" id="topMenuBlock"><p>Home</p></div>
<div id="nav-about"><p>About</p></div>
<div id="nav-rates"><p>Rates</p></div>
<div id="nav-faq"><p>FAQ</p></div>
<div id="nav-contact"><p>Contact</p></div>
<div id="nav-careers"><p>Careers</p></div>
</div>
<div id="rightTopMenu"></div>
</div>...other stuff</body>
Then for the CSS I have the following:
#home a.nav-home{ border-bottom:2px solid white; }
Do the links HAVE to be in a List, or can I leave them in div's, and if so, how can I make this work?
Thanks.
You've a little bit of a mess here.
Do the links HAVE to be in a List, or can I leave them in div's?
They don't have to be, but they probably should be. There's not good reason to use the strange markup you have chosen, you should definitely consider switching to a list and <li> tags.
Problem with duplicate ids
You have <body id="home"> and <a href="" id="home">
You also have several instances of id="topMenuBlock" (I see you fixed this in your edit.)
You cannot have more than one element with the same id. id attributes must be unique, always. Use class names instead, if anything.
You are using this selector: #home a.nav-home {} but it doesn't match anything. There is no <a class="nav-home">. You can use something like:
#home {} because that's the id of the <a> element you want
.nav-home a {} - Selects the <a> inside an element with class="nav-home"
Perhaps you have the concept of ids and classes mixed up. Ids are supposed to uniquely identify HTML elements, whereas classes can be used as many times as you like. Right now you have 6 elements with the id #topMenuBlock. You should make a .topMenuBlock class instead. I would also make a #nav-home id instead of a class since there should only be one such element on each page.
Secondly, there is no need for the <p> tags you have within your <a> tags. In fact, it's against HTML standards to do so since anchors are inline elements and paragraphs are block-level elements.
Lastly, your CSS selector that sets the border is incorrect because the .nav-home div is not contained within an <a> element. Use this CSS instead (assuming you change nav-home to be an id rather than a class):
#nav-home{ border-bottom:2px solid white; }
Fix these issues and then see what happens. If you're new to HTML and CSS, I would recommend going through some tutorials, such as the ones found at http://www.w3schools.com/.
Your class identifier should be in the <a /> tag
You have
<div class="nav-home" id="topMenuBlock"><p>Home</p></div>
but you want
<div class="something" id="topMenuBlock"><a class = "nav-home" href="" id="home"><p>Home</p></a></div>
Modify your CSS class accordingly.
I'm using WordPress to host a blog. They have a tag cloud widget. The tags are like this. The class name changes with each tag
<a class="tag-link-9" title="1 topic" style="font-size: 8pt;">Blah Blah</a>
<a class="tag-link-10" title="1 topic" style="font-size: 8pt;">Blah Blah X</a>
The parent element is <div class="tagcloud">
Normally, with the theme I'm using, I can add custom styles like this
.custom .tag-link-1- {font-size: 10px}
but with the class name changing each tag, I have to constantly add new styles. Is there a way to do a CSS that will capture all the tag-links independent of the number?
Not in a backwards compatible way, no.
CSS 3
a[class^='tag-link-'] {
font-size:10px;
}
I would define a numberless class to hold all the common style info.
.tag-link { font-size:10px; }
Then attach it to each element.
<a class="tag-link tag-link1">Link</a>
You have two options that will work well for you in this scenario.
Option 1: Use CSS Selectors
If your tags are wrapped within some kind of a div, such that:
<div id="tag-cloud">
<a class="tag-link-9" title="1 topic" style="font-size: 8pt;">Blah Blah</a>
.
.
.
</div>
Use this CSS:
#tag-cloud a { ... } /* Each tag will be styled */
Option 2: Use jQuery!
If you can't figure out option 1, you can always use jQuery to style the element:
$('a[class^="tag-link"]').css( ... );
Refer to this for documentation on how to use the CSS function in jQuery
Option 3: Modify the Wordpress Widget file
You could always go into your wordpress files and modify what gets displayed in the output. I'd recommend removing style="font-size: 8pt;" bit, and then using Option 1 to style the links.
The downside to Option 3 is that you lose the Tag Cloud functionality that makes the links bigger when they appear more often. That might not matter to you, but it's something to consider.
If all tags are getting the same style can you not do:
.tagcloud a {font-size: 10px}
If not please clarify your question.
Thanks!
edit if you are not worried about css validation you can use .custom a {font-size:10px !important;} to override inline styles. If using jQuery is an option, remove the inline styles: $('.tagcloud a').removeAttr('style');