different results for two queries - mysql

Question

Query 1 :
SELECT
SUM(aol_int) AS AOL,
SUM(android_phone_int) AS Android_Phone,
SUM(androidTablet_int) AS Android_Tablet,
SUM(apple_mail_int) AS Apple_Mail,
SUM(blackberry_int) AS Blackberry,
SUM(Eudora_int) AS Eudora,
SUM(gmail_int) AS Gmail,
SUM(hotmail_int) AS Hotmail,
SUM(lotus_notes_int) AS Lotus_Notes,
SUM(other_int) AS Other,
SUM(other_webmail_int) as Other_Web_Mail,
SUM(Outlook_int) AS Outlook,
SUM(Postbox_int) AS Postbox,
SUM(sparrow_int) AS Sparrow,
SUM(thunderbird_int) AS Thunderbird,
SUM(windowsLiveMail_int) AS Windows_Live_Mail,
SUM(yahoo_int) AS Yahoo,
SUM(iPad_int) AS iPad,
SUM(iPhone_int) AS iPhone,
SUM(iPod_int) AS iPod
FROM mytable;
Query 2:
select sum(aol_int + android_phone_int + androidtablet_int+apple_mail_int+blackberry_int+Eudora_int+gmail_int+hotmail_int+lotus_notes_int+other_int+other_webmail_int+Outlook_int+Postbox_int+sparrow_int+thunderbird_int+windowsLiveMail_int+yahoo_int+iPad_int+iPhone_int+iPod_int)
as total_percentage
FROM mytable;
When I am summing up the results of Query 1 I am getting different sum as compared to what I am getting via Query2. The value in Query2 is less than Query 1. Why is it like that?
TROUBLESHOOTING:
I tried to write my query like this:
SELECT SUM( ISNULL(aol_int,0) +
ISNULL(android_phone_int,0) +
ISNULL(androidtablet_int,0) +
ISNULL(apple_mail_int,0) +
ISNULL(blackberry_int,0) +
ISNULL(Eudora_int,0) +
ISNULL(gmail_int,0) +
ISNULL(hotmail_int,0) +
ISNULL(lotus_notes_int,0) +
ISNULL(other_int,0) +
ISNULL(other_webmail_int,0) +
ISNULL(Outlook_int,0) +
ISNULL(Postbox_int,0) +
ISNULL(sparrow_int,0) +
ISNULL(thunderbird_int,0) +
ISNULL(windowsLiveMail_int,0)+
ISNULL(yahoo_int,0) +
ISNULL(iPad_int,0) +
ISNULL(iPhone_int,0) +
ISNULL(iPod_int,0) )AS total_percentage
FROM mytable;
However, I am getting an error after running above query in the MySQL workbench:
Error Code: 1582. Incorrect parameter count in the call to native function 'ISNULL'. What is wrong here?

Answer 1

This could happen if some columns in some of the rows contain nulls. When this happens, all columns in a row with even a single null column would produce null in the chain of additions, so the row will add nothing to the total.
Here is a short demo of this effect. Setup:
create table test(x int null, y int null);
insert into test(x,y) values (1,null);
insert into test(x,y) values (null,2);
insert into test(x,y) values (3,3);
Queries:
select sum(x+y) from test; -- Shows 6
select sum(x)+sum(y) from test -- Shows 9
See this demo on sqlfiddle: link.