here's my example table (room reservation system):
id available room_id
----------------------------
1 2014-02-05 4
2 2014-02-06 4
3 2014-02-07 4
4 2014-02-09 4
5 2014-02-10 4
i want to query if room with id 4 is available between 2014-02-05 and 2014-02-10.
i know i can query by using the BETWEEN operator, but the problem is that i need to consider continuous date ranges, so it should return zero records as the record for 2014-02-08 is missing.
any ideas?
thanks
Here is an idea. Count the number of rows that match and then compare these to the number of days in the period:
select room_id
from example
where available between date('2014-02-05') and date('2014-02-10')
group by room_id
having count(*) = datediff(date('2014-02-05'), date('2014-02-10')) + 1;
Related
I want to create a query to get the total number of produced products for each day in Microsoft Access.
Here are the few rows of my table as a sample:the table's name is Orders
ordernumber number of products Date
100 2 11-May-16
101 1 11-May-16
121 2 24-May-16
122 3 24-May-16
131 1 25-May-16
105 3 11-May-16
127 1 24-May-16
135 2 25-May-16
The desired output is :
TotalNoProducts Date
6 11-May-16
6 24-May-16
3 25-May-16
This is one of the more basic aggregate queries:
SELECT SUM([number of products]) As TotalNoProducts, CDate(Int([Date])) As TheDate
FROM Orders
GROUP BY CDate(Int([Date]))
Note that you can also build this query through the query builder, which is usually easier for beginners than using SQL
I have the following table, I am using MYSQL
BayNo FixDateTime FixType
1 04/05/2015 16:15:00 tyre change
1 12/05/2015 00:15:00 oil change
1 12/05/2015 08:15:00 engine tuning
1 04/05/2016 08:11:00 car tuning
2 13/05/2015 19:30:00 puncture
2 14/05/2015 08:00:00 light repair
2 15/05/2015 10:30:00 super op
2 20/05/2015 12:30:00 wiper change
2 12/05/2016 09:30:00 denting
2 12/05/2016 10:30:00 wiper repair
2 12/06/2016 10:30:00 exhaust repair
4 12/05/2016 05:30:00 stereo unlock
4 17/05/2016 15:05:00 door handle repair
on any given day need do find the highest number of fixes made on a given bay number, and if that calculated number is repeated then it should also appear in the resultset
so would like to see the result set as follows
BayNo FixDateTime noOfFixes
1 12/05/2015 00:15:00 2
2 12/05/2016 09:30:00 2
4 12/05/2016 05:30:00 1
4 17/05/2016 15:05:00 1
I manage to get the counts of each but struggling to get the max and keep the highest calculated repeated value. can someone help please
Calculate the fixes per day per BayNo
Find the max daily fixes per BayNo
Use the result from 2 to filter out the result from 1
Something like this:
SELECT fixes.*
FROM (
#1
SELECT BayNo,DATE(FixDateTime) as day,count(*) as noOfFixes
FROM yourTable
GROUP BY BayNo,day
) as fixes
JOIN (
#2
SELECT MAX(noOfFixes) as maxNoOfFixes,BayNo
FROM (
#1
SELECT BayNo,DATE(FixDateTime) as day,count(*) as noOfFixes
FROM yourTable
GROUP BY BayNo,day
) as t
GROUP BY BayNo
) as maxfixes ON fixes.BayNo = maxfixes.BayNo
#3
WHERE fixes.noOfFixes = maxfixes.maxNoOfFixes
You can run the repeated query (1) separately and store the result in a temporary table if needed.
I'm assuming the FixDateTime column is a an actual datetime or timestamp column. If it's not, you will need to use a different method to get the date from it.
I have a database about sports event that contains:
*User ID
*Amount of Points that the user got on that event
*Time (HH:MM:SS) that took the user to complete track.
How can I first sort them by no. of points, then if two users have same amount of points, by time (shorter is better); and then insert the places to rows?
I have database like that:
ID No. of Points Time Place
------------------------------------
1 15 00:56:00
2 13 00:55:15
3 17 01:00:00
4 17 00:57:00
5 19 00:52:15
I need to have it with places:
ID No. of Points Time Place
------------------------------------
1 15 00:56:00 4
2 13 00:55:15 5
3 17 01:00:00 3
4 17 00:57:00 2
5 19 00:52:15 1
I hope, you understand that. Sorry for bad English.
Best regards,
You can do this with update statement as follows.
SET #placeValue:=0;
UPDATE [Table Name] SET Place=#placeValue:=#placeValue+1 ORDER BY
[Amount of Points] DESC,Time ASC
Is it possible to retrieve the records from the table using month no and week no
for example I have a table
CustomerID CustomerName date(data type date)
1 sam 2016-06-1
2 dam 2016-06-2
3 kam 2016-06-8
4 ram 2016-06-9
4 ram 2016-07-8
how can i retrieve the month no 6 and week no 1 records
after the select query expected result is
CustomerID CustomerName date
1 sam 2016-06-1
2 dam 2016-06-2
it will give 2 records because date 1 and 2 fall under first week
if question is not clear please reply
thanks !
You can use month and week functions. Documentation here.
select * from table where month(`date`) = 6 and week(`date`) = 1
I have a table like this
id plan_id cancel_date paid_date
9 2 2015-08-05 2014-09-13
10 2 2015-09-08 2015-09-03
10 3 NULL 2015-09-10
11 3 NULL 2015-09-13
14 3 2015-09-28 2015-09-14
And I would like to select ids where there is a less than 30 days difference between cancel_date and paid_date (for a given plan), and they didn't acquired a new plan in less than 30 days.
In this case, this would mean returning id 14 only.
Update:
Whenever a user buy a new plan, we insert it to the table, with a different paid_date (paid_date is the date that the plan was acquired the first time).