how can i print 11 numbers in 2 div,in each div i need 8 names(4 td's in each row)second div from 9,how can i do this? - html

Question

<%
int apps = 11;
int noOfDiv = apps % 3, k, m;
for (int i = 1; i <= 2; i++) {
out.println("<div>");
out.println("<table>");
for (int j = 1; j <= 2; j++) {
out.println("<tr>");
for (k = 1; k <= 4; k++) {
out.println("<td>");
out.println("" + k + "");
out.println("</td>");
}
out.println("</tr>");
}
out.println("</table>");
out.println("</div>");
}
%>
for this i'm getting output as
1234
1234
in div1
1234
1234
in div2 ,
but i need
1234
5678
in div1 and
9 10 11
in div2 if i have total 11 numbers

Answer 1

You can do that by using following code;
<%
int apps = 11;
int noOfDiv = apps % 3, k, m;
for (int i = 1; i <= 2; i++) {
out.println("<div>");
out.println("<table>");
for (int j = 1; j <= 2; j++) {
out.println("<tr>");
int temp = (j-1)*4 +1;
for (k = temp; k <= temp+3; k++) {
out.println("<td>");
out.println("" + k + "");
out.println("</td>");
}
out.println("</tr>");
}
out.println("</table>");
out.println("</div>");
}
out.println("<div><table><tr><td>" + (apps - 2) + "</td><td>" + (apps - 1) + "</td><td>" + apps + "</td></tr></table></div>");
%>

Answer 2

It is because you prints k for k = 1 to 4, and to correct use an extra variable say capital K = 1 before any loop, then replace:
for (k = 1; k <= 4; k++) // print 1 to 4
as:
int noOfDiv = apps % 3, k, m, K = 1; // Added K = 1
// rest of your codes ...
for (k = K; k <= K + 3; k++){
// code you already have to print small `k`
K += 4;
}