Add many-to-many select into existing query - mysql

I have a query set up to return comments given from one user to another.
Now we want to allow the ability to rate these comments.
I've added a new table that has 3 fields: comment_id, user_id, and score.
How can I grab an array of {user_id,score} for any comment fetched?
Will I need to loop through the comments after they are fetched and run a second query? This approach could result in adding several extra queries.
Can it be done with a single query?
Here's the function I have now:
function getAllComments($args) {
if(empty($_SESSION['user']['id'])) return false;
$limit = 5;
if(isset($args['limit'])) $limit = $args['limit'];
$page = 1;
if(isset($args['page'])) $page = $args['page'];
$data = array();
$offset = ($page-1)*$limit;
$sql = "SELECT c.*,CONCAT(u1.firstName,' ',u1.lastName) AS owner,u1.title AS ownerTitle,CONCAT_WS(' ',u2.firstName,u2.lastName) AS senderName,u2.title AS senderTitle,a.name AS actionName,a.behavior
FROM comment AS c
JOIN user AS u1 ON c.recipient = u1.id
JOIN user AS u2 ON c.sender = u2.id
JOIN action AS a ON c.action = a.id
WHERE c.type=1";
if(isset($args['location'])) $sql .= " AND u1.location=?";
$sql .= " ORDER BY date DESC";
$sql .= " LIMIT ?";
$sql .= " OFFSET ?";
try {
$db = DB::getInstance();
$stmt = $db->dbh->prepare($sql);
$n = 1;
//THESE MUST STAY IN THE SAME ORDER TO MATCH THE ? PLACEHOLDERS
if(isset($args['location'])) $stmt->bindValue(($n++), $args['location'], PDO::PARAM_INT);
$stmt->bindValue(($n++), $limit, PDO::PARAM_INT);
$stmt->bindValue(($n++), $offset, PDO::PARAM_INT);
$result = $stmt->execute();
$stmt->setFetchMode(PDO::FETCH_ASSOC);
$rows = array();
if($result !== false) {
while($row = $stmt->fetch()) {
$rows[] = $row;
}
$data['comments'] = $rows;
return $data;
}else {
logit('Query Failed');
return false;
}
}catch(PDOException $e) {
logit($e->getMessage());
return false;
}
}

If you for example wanted all {comment_id, user_id, score} associated with the comments of user 5, your query would involve an INNER JOIN and look something like:
SELECT s.comment_id, s.user_id, s.score FROM CommentScore s
INNER JOIN Comment c
ON c.comment_id = s.comment_id
WHERE c.user_id = 5

Related

PHP - How to group from multiple sql queries

I got
for($i = $start_date;$start_date <= $end_date;$i->modify('+1 day')) {
$i->format('Y-m-d').'<br />';
$dates = $i->format('Y-m-d');
echo $query = "
SELECT md.dish_id
, md.daydate
, d.id
, d.dish_name
, d.weight
, d.price
FROM dishes d
LEFT
JOIN menu_details md
ON d.id = md.dish_id
WHERE md.daydate = '$dates'
";
$result = mysql_query($query);
}
while($row = mysql_fetch_array($result)) {
echo 'Date: '.$row['daydate'].'Name: '.$row['dish_name'].'<br />';
}
how can i row 'dish_name' for every date on a new row.In the database there are more then 1 row with same date=
You should try to avoid running queries in loops...
Try:
$query = "SELECT md.dish_id, md.daydate, d.id, d.dish_name, d.weight, d.price
FROM dishes d
LEFT JOIN menu_details md ON (d.id = md.dish_id)
WHERE md.daydate BETWEEN '$start_date' AND '$end_date'
GROUP BY md.daydate ";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)) {
echo 'Date: '.$row['daydate'].'Name: '.$row['dish_name'].'<br />';
}
What is the group by for? I think it may cause you to lose some of the results...

MySQL order by $variable

I am trying to think of a way to order the results from the highest number to the lowest one.
The problem here is that those numbers will be from a different table and I am not sure how I should do it.
Please check out below.. *
Thanks!
*Edit:
I know that I suck at coding but still :)
What I need is instead of ORDER BY id to be Order by $results (highest number to lower)
Current Code I am using:
$query = "SELECT * FROM tablea WHERE id > 1 AND status = '1' ORDER BY id ASC;";
$result = #mysql_query($query);
for ($i=0; $i < #mysql_num_rows ($result); $i++) {
$row = #mysql_fetch_array($result);
$total = $total + 1;
$results = '';
$noinv = '';
$query2 = "SELECT SUM(number) FROM tableb WHERE id = '$row[id]' AND cur = '1' AND type = '1' AND pos = '1';";
$result2 = #mysql_query($query2);
$row2 = #mysql_fetch_array($result2);
if ($row2['SUM(number)'] == '') {
$row2['SUM(number)'] = '0.00';
}
$query3 = "SELECT SUM(number) FROM tableb WHERE id = '$row[id]' AND cur = '1' AND type = '1' AND pos = '2';";
$result3 = #mysql_query($query3);
$row3 = #mysql_fetch_array($result3);
if ($row3['SUM(number)'] == '') {
$row3['SUM(number)'] = '0.00';
}
$results = $row3['SUM(number)'] - $row2['SUM(number)'];
print $row['id'].' '.$row['status'].' '.$results;
}
your question is unclear, but try to give you general answer
select A.column1,A.column2,A.column3,count(B.*) total
from table A, table B
where A.Id=B.Id
group by A.Id
order by total desc

How to get PDO to select from more than one table

Here is my code:
$sql= ("SELECT R.cr_id,R.time,R.reply,U.user_id,U.user_name FROM tb_user U, conversation_reply R WHERE R.user_id_fk=U.user_id and R.c_id_fk='$c_id' ORDER BY R.cr_id ASC LIMIT 20");
$stmt = $conn->prepare($sql);
$stmt->execute();
$row=$stmt->fetchAll();
foreach ($row as $laww) {
echo $laww['$user_name'].":". $laww['reply']. "<br>";
}
}////END
I get only the result from $laww['reply'] but not $laww['$user_name']
Can anyone helpe me ?

Assistance required converting MySQL function to PDO

I'm currently converting MySQL to PDO, I'm unsure if I wrote this function correctly,I'm also unsure of how to use sqlfiddle, so I resort to Stackoverflow.
If correct, anything to better the current code?
MySQL example :
PUBLIC FUNCTION Insert_Update($_iD, $update, $uploads){
$update = mysql_real_escape_string($update);
$time = time();
$_iP = $_SERVER['REMOTE_ADDR'];
$query = mysql_query("SELECT post_iD,message FROM `Posts` WHERE uid_fk='$_iD' ORDER by post_iD DESC LIMIT 1") or die(mysql_error());
$result = mysql_fetch_array($query);
if ($update!=$result['message']) {
$uploads_array = explode(',',$uploads);
$uploads = implode(',',array_unique($uploads_array));
$query = mysql_query("INSERT INTO `Posts` (message, uid_fk, _iP,created,uploads) VALUES (N'$update', '$_iD', '$_iP','$time','$uploads')") or die(mysql_error());
$newquery = mysql_query("SELECT M.post_iD, M.uid_fk, M.message, M.created, U._iUsername FROM Posts M, users U where M.uid_fk=U._iD and M.uid_fk='$_iD' order by M.post_iD desc limit 1 ");
$result = mysql_fetch_array($newquery);
return $result;
} else {
return false;
}
}
PDO Example:
PUBLIC FUNCTION Insert_Update($_iD, $update, $uploads){
$sth = $this->db->prepare("SELECT post_iD,message FROM `Posts` WHERE uid_fk = :id ORDER by post_iD DESC LIMIT 1")
$sth->execute(array('id' => $_iD));
$result = $sth->FetchAll(PDO::FETCH_ASSOC);
if ( $update!=$result['message'] ){
$uploads_array = explode(',',$uploads);
$uploads = implode(',',array_unique($uploads_array));
$sth = $this->db->prepare("INSERT INTO Posts (message, uid_fk, _iP,created,uploads) VALUES ( :update, :id, :ip, :time, :uploads)")
$sth->bindValue(':update', $update);
$sth->bindValue(':id', $_iD);
$sth->bindValue(':ip', $_SERVER['REMOTE_ADDR']);
$sth->bindValue(':time', time());
$sth->bindValue(':uploads', $uploads);
$sth->execute()
$sth = $this->db->prepare("
SELECT M.post_iD, M.uid_fk, M.message, M.created, U._iUsername
FROM Posts M, users U
WHERE M.uid_fk=U._iD
AND M.uid_fk = :id
ORDER by M.post_iD DESC LIMIT 1 ");
$sth->execute(array(':id' => $_iD));
$result = $sth->FetchAll(PDO::FETCH_ASSOC);
return $result;
} else {
return false;
}
}

making SQL more efficiency by making two queries into one instead of having a loop

I have the following code and was wondering how I could simplify it into one MYSQL statement
$sql = "SELECT sesionID
FROM `juegos_sesiones`
WHERE `usuarioID` = ".$_SESSION['MM_UserID'];
$query = mysql_query($sql, $cnx) or die(mysql_error());
//$row_rsPaises = mysql_fetch_assoc($rsPaises);
$exercises = mysql_num_rows($query);
echo $exercises;
//find total points
while( $row = mysql_fetch_array($query)){
$sql2 = 'SELECT correct_answers FROM `juegos_sesiones_detalle` WHERE `sesionID` = '.$row['sesionID'];
$query2 = mysql_query($sql2, $cnx) or die(mysql_error());
$details2 = mysql_fetch_assoc($query2);
$counter = $counter + $details2['correct_answers'];
}
echo '<br />'.$counter;
SELECT sum(correct_answers) as total_correct_answers
FROM `juegos_sesiones_detalle` d
INNER JOIN `juegos_sesiones` s on s.`sesionID` = d.`sesionID`
WHERE `usuarioID` = $_SESSION['MM_UserID']
You can read about joins here
You can write single query by using INNER JOIN as:
SELECT correct_answers
FROM juegos_sesiones_detalle a
INNER JOIN juegos_sesiones b
ON a.sesionID = b.usuarioID;
Try this :
$sql = "SELECT correct_answers FROM `juegos_sesiones_detalle` jsd
JOIN `juegos_sesiones` js
ON jsd.sesionID = js.`sesionID`
WHERE js.usuarioID = ".$_SESSION['MM_UserID'];