Check if there are multiple values in a column - mysql

Question

I have the following sql:
SELECT DISTINCT cp_pessoa.id, cp_pessoa.nome
FROM cp_pessoa
LEFT JOIN cp_habilidade_freelancer ON (cp_habilidade_freelancer.id_freelancer = cp_pessoa.id)
LEFT JOIN cp_habilidade ON (cp_habilidade.id = cp_habilidade_freelancer.id_habilidade)
WHERE cp_habilidade.id = 71 OR cp_habilidade.id = 695
LIMIT 0, 10
I only want people (cp_pessoa) who have all the skills (71, 695).
It may seem simple, but I'm struggling.
Examples:
If I use OR the following people with the following skills (1,2,71) are returned (people without the ability 695)
If I use AND the following people with the following skills (71, 695) are not returned

Answer 1

Is this homework? If so, the idea should suffice: You are looking for persons where the count of the associtated skills 71 and 695 is 2.
In case this is no homework, but a real task, then tell me so and I'll give you a complete SQL statement :-)
EDIT: The straight-forward way is to ask if both skills exist for a person:
select id, nome
from cp_pessoa p
where exists
(
select *
from cp_habilidade_freelancer hf
where hf.id_freelancer = p.id
and hf.id_habilidade = 71
)
and exists
(
select *
from cp_habilidade_freelancer hf
where hf.id_freelancer = p.id
and hf.id_habilidade = 695
);
The other way with querying cp_habilidade_freelancer just once:
select id, nome
from cp_pessoa p
where id in
(
select id_freelancer
from cp_habilidade_freelancer hf
where id_habilidade in (71, 695)
group by id_freelancer
having count(distinct id_habilidade) = 2
);
You could change count(distinct id_habilidade) to count(*) in case it is guaranteed that there are no duplicate skills for an id_freelancer in cp_habilidade_freelancer.