I have for example a query with return something as it
route value
1 3
2 2
3 4
4 5
5 1
then I need to put in 2 textbox the max and the min route so in sql this would be
select top 1 route from table where value=(select max(value) from table)
I add a image done in excel, how this would be.
I believe this is so easy but I dont have idea how to get it.
I got using expression, this was extactly expression
="Route "+
Convert.ToString (
Lookup(max(fields!value.Value),fields!value.Value ,fields!route.Value,"mydataset")
)
changing max for min, for the other...
thanks everyone.
I believe the query you're looking for would be:
With Min_Max_CTE as (
Select MIN(value) as Min_Value
, MAX(value) as Max_Value
From Table
)
Select Top 1 'Min' as Type
, T.route
, T.value
From Table T
Inner Join Min_Max_CTE CTE
on T.value = CTE.Min_Value
Union All
Select Top 1 'Max' as Type
, T.route
, T.value
From Table T
Inner Join Min_Max_CTE CTE
on T.value = CTE.Max_Value
Order by Type desc --This will put the Min Route first followed by the Max Route
Then, put that query into a dataset, and then create a tablix and use the Type, route, and value fields to return the minimum route and the maximum route. It should end up being set up just like your excel section with the min and max routes above.
You can do this SSRS by using a couple of separate tables. Your example data:
And two tables in the Designer:
Since the tables only have header rows, only the first row in the table will be displayed.
To make sure we get the MAX and MIN values in the two tables, each table needs to order its Dataset appropriately, i.e. by Value by descending and ascending respectively.
MAX table:
MIN table:
Which gives your expected result:
Related
I've the following data.
What I need like below
I need to minus order by 1 with 2.
Example : (1-2) and I've display the result in order by 3.
If the branch having order_by as 1 - display as it is.
Using MySQL, how can I get this result?
You can get this result with a UNION query. The first part selects all rows from your table, the second uses a self-join to find branches which have order_by values of both 1 and 2, and subtracts their due values to get the new due value:
SELECT *
FROM data
UNION ALL
SELECT 3, d1.branch, d1.due - d2.due
FROM data d1
JOIN data d2 ON d2.branch = d1.branch AND d2.order_by = 2
WHERE d1.order_by = 1
ORDER BY branch, order_by
Demo on dbfiddle
I am trying to write a quarry in a module for Dolibarr ERP. But module hase a part of code that is predefined and can not be changed. And I need to insert a SUM() function in it that will combine rows with similar id. That i know how to do in a regular MySQL:
SELECT fk_product AS prod, SUM(value) AS qty
FROM llx_stock_mouvement
WHERE type_mouvement = 2 AND label LIKE 'SH%'
GROUP BY fk_product
ORDER BY 1 DESC
LIMIT 26
that gives me what I want :
prod qty
1 13
2 10
BUT module has a predefined unchangeable code :
this part is predefined module writes it himself based on values provider in it:
SELECT DISTINCT
c.fk_product AS com,
c.value AS qty
THIS PART I CAN WRITE IN A MODULES GUI:
FROM
llx_stock_mouvement AS c
WHERE
type_mouvement = 2
AND label LIKE 'SH%'
And this part is predefined:
ORDER BY 1 DESC
LIMIT 26
I would appreciate any help and advice on question is there any workaround that can be done to make my desired and result ampere ? As it would using the first code I posted ?
If you can only modify the bit in the middle box then you might need to use a subquery;
--fixed part
SELECT DISTINCT
c.fk_product AS com,
c.value AS qty
--begin your editable part
FROM
(
SELECT fk_product,
SUM(value) AS value
FROM llx_stock_mouvement
WHERE type_mouvement = 2 AND label LIKE 'SH%'
GROUP BY fk_product
) c
--end your editable part
--fixed part
ORDER BY 1
DESC
LIMIT 26
I am stuck with the following issue. I have 1 table that looks like this:
field_number.. Value
````````````````````````````````
1 ......................... 1
2 ..........................1
3 ......................... 2
4 ..........................2
etc.
I want to group different fieldnumbers and have an average for the value column. So the output should be:
field_number................Value
name(1,2)...................... 1.............. ((1+1)/2)
name(3,4)...................... 2.............. ((2+2)/2)
I have checked previous questions but cannot find any question that covers this issue (I might search on the wrong keywords though). So if this has already been covered my appologies, but any help or a point to a previous answer would be appreciated.
** =============UPDATE============= **
I went through your suggestions but did not get it right. So I am trying to be more specific. I almost have the result I want apart from the fact I want to have a fixed value in one of my columns. I have the following query:
Select
Avg(wp_rg_lead_detail.value),
wp_rg_lead_detail.field_number,
From
wp_rg_lead_detail
Where
wp_rg_lead_detail.field_number In (15, 17, 24) A
UNION
Select
Avg(wp_rg_lead_detail.value),
wp_rg_lead_detail.field_number,
From
wp_rg_lead_detail
Where
wp_rg_lead_detail.field_number In (16, 108, 18)
etc.
This gives me a table with two columns
wp_rg_lead_detail.value................field_number
4.3 (average)..............................15 (first value of av calculation)
What I want is to change the field number (15 in this case) in a fixed value (text). What and how should I add this to the query?
SELECT avg(value) FROM table WHERE field_number in (1,2)
SELECT avg(value) FROM table WHERE field_number in (3,4)
If your table is really this simple, you can also get away with:
select distinct
Value,
count(Value) as '#'
from table_name
group by Value
If you acctually want to group by a range, than you can put the logic of the range in your grouping clause (see this fiddle)
select distinct
avg(Value) as average,
floor(Value),
count(Value) as '#'
from table_name
group by floor(Value)
In the fiddle I used grouping on whole integers, but you can make that as complex as you like (see, for instance, this example)
If you are actually also interested in your corresponding fields, use group_concat() like so
select
Value,
group_concat(
distinct field_number
order by Value
) as fields
from table_name tn1
group by Value
order by Value
output:
Value | fields
---------------------------------
1 | 1,2
2 | 3,4
See this fiddle implemented from this blog post
For a generalized answer.
SELECT CONCAT('name','(',GROUP_CONCAT(field_number),')') AS field_number,
AVG(Value) as Value
FROM table_name
group by table_name.`Value`
Hope this helps.
From this post, enter link description here
I would like to improve the query
SELECT `BetType`,
count(`BetType`) AS COUNT,
sum(`BetAmount`) AS BetAmountTotal,
sum(`Payout`) AS PayoutTotal
FROM `betdb`
LEFT JOIN `matchdb` ON `betdb`.`MatchID` = `matchdb`.`MatchID`
WHERE `betdb`.`MatchID`=135
GROUP BY `BetType`
thanks to Sadikhasan, who helped on this query
I would like to add another row showing the totals of the columns
BetType Count BetAmount Total Payout Total
Handi 2 60000 950000
Homerun Count 4 10000 0
Total 6 70000 950000
this seems to be needing another SELECT statement but how would I put another row explicitly showing the "Total" string and getting the sum of the previously used columns with Aggregate Functions?
You can use WITH ROLLUP modifier to GROUP BY, which will give you another row with totals, but the column you group on (BetType) will show NULL for that row. But nothing stops you from using COALESCE() to replace that NULL with 'Total' string.
SELECT COALESCE(`BetType`,'Total') AS BetType,
COUNT(*) AS `Count`,
sum(BetAmount) AS BetAmountTotal,
sum(Payout) AS PayoutTotal
FROM betdb
WHERE betdb.MatchID=135
GROUP BY BetType WITH ROLLUP
I have a table tbl_usertests from which i want to retrieve the user who have maximum testscore for each test.
Note: User here means usertestid which is unique.
Its colums are:
pk_usertestid attemptdate uploaddate fk_tbl_tests_testid fk_tbl_users_userid testscore totalquestionsnotattempted totalquestionscorrect totalquestionsincorrect totalquestions timetaken iscurrent
data :
1;NULL;"2010-06-24 22:48:07";"11";"3";"1";"53";"1";"21";"75";"92";"1"
2;NULL;"2010-06-25 01:21:37";"11";"4";"13";"0";"13";"62";"75";"801";"1"
3;NULL;"2010-06-25 01:21:50";"10";"4";"17";"5";"17";"53";"75";"640";"1"
4;NULL;"2010-06-25 01:24:23";"11";"4";"13";"0";"13";"62";"75";"801";"1"
5;NULL;"2010-06-25 01:24:47";"10";"4";"17";"5";"17";"53";"75";"640";"1"
6;NULL;"2010-06-25 01:36:04";"11";"5";"13";"0";"13";"62";"75";"801";"1"
7;NULL;"2010-06-25 01:47:26";"7";"5";"10";"1";"10";"49";"60";"302";"1"
My Query is :
SELECT max(`testscore`) , `fk_tbl_tests_testid` , `fk_tbl_users_userid` , `pk_usertestid`
FROM `tbl_usertests`
GROUP BY `fk_tbl_tests_testid`
This query output:
max(`testscore`) fk_tbl_tests_testid fk_tbl_users_userid pk_usertestid
10 7 5 7
17 10 4 3
13 11 3 1
But the problem is that if there are two users who have same score, it displays only one user because i have used group by clause.
For. e.g. testid =10 i have two records(pk_usertestid 3 and 5) but it displays 3 only.
I want the user whose upload date is less than the other user(in case of two users having same testscore). It should display for usertestid=3 since 3 upload date is less than 5.
Right now its displaying 3 but it is due to group by clause.
I am unable to construct the query.
Please help me on this
Thanks
Try this:
SELECT t.`fk_tbl_tests_testid` , t.`fk_tbl_users_userid` , t.`pk_usertestid`, maxscores.maxscore
FROM `tbl_usertests` t
JOIN (SELECT `fk_tbl_tests_testid`,max(`testscore`) as maxscore
FROM `tbl_usertests`
GROUP BY `fk_tbl_tests_testid`) maxscores ON t.`fk_tbl_tests_testid` = maxscores.`fk_tbl_tests_testid`
the logic behind is to separate the whole thing into two parts: get the maximum (or any other aggregate) values for each group (this is the subquery part), then for each element, join the corresponding aggregate. (JOIN it back to the riginal table)