Call a function if String number is inferior to 0? - actionscript-3

Question

I've got this code in my Toolbar.as :
var money = 9999;
argent.text = String(money);
trace(money);
How do I do to say
if (money < 0){
callFunction();
}
?
Thank you very much for your answers
EDIT
I've tried everything.
Here's what I did :
var money:int = 9999;
argent.text = money.toString();
trace(money);
stageRef.addEventListener("checkingMoney", checkMoney, false, 0, true);
I've add the EventListner in order to check the money (as nothing was triggering the condition if money<0 before).
And then :
public function checkMoney(event):void{
var money;
trace("checking");
if (parseInt(money) < 0){
trace("dangerous");
}
}
So the function is well triggered (the trace "checking" is on), but even the number is under 0 (-4600), the trace "dangerous" do NOT appear..
I don't understand.

Answer 1

You need to read up on how datatyping works. It works similarly in all OOP-based languages, so an AS3-specific article really isn't necessary. Avoid anything regarding PHP datatypes, though.
For what you have posted, though, you have done a few things incorrectly.
First off, every object (whether it be a variable, function, or class), should always have the datatype declared. You can get away with not doing it, but your app will run slightly faster if you do and there is less chance of compiler warnings.
So
var money = 9999;
should be
var money:int = 9999; // could also use Number (AS3's float) or uint
You should avoid hard-casts such as String(money), as well. This can be slow and can cause errors. For casting a Number to a String, you should always use Number.toString(), as that is its intended purpose and I believe it is optimized whereas other cast types are not.
if (money < 0) is actually correct. It may have been throwing IDE warnings because you didn't set the type of money. If you need to compare a numeric String value, you need to cast it back to a number using Number(var). Note that casting a String to Number is one of the few times you want to use a hard cast DataType(object) instead of a soft cast (object as DataType).

Answer 2

I don't get the problem.
1st of all money variable is missing a type.
If money is int here than:
var money:int = 9999;
argent.text = money.toString();
trace(money);
if (money < 0){
callFunction();
}
and that should work.
If for some reason money is String in here than:
var money:String = "9999";
argent.text = money;
trace(money);
if (Number(money) < 0){
callFunction();
}

Answer 3

I don't usually do this, but I'm posting a second answer because your edit is drastically different than what you originally posted. For future reference, please post the entire code that is relevant. You seemed to have missed some context originally and forced us to solve the wrong problem (don't get me wrong, it still needed to be fixed but it was not the issue at hand)
So what you are seeing is a scope issue. Basically, an object declared in an object (be it a Class, Function, loop, or conditional) is only available within that object and within child objects. Additionally, all objects declared in the top-level scope of a class must have an access modifier (public, private, internal, protected, etc).
So let's assume this class structure:
public class ClassName {
public function ClassName();
public function checkMoney();
}
An object declared in the constructor (ClassName()) is not available in checkMoney(). So you need to do one of two things:
Declare the object in top-level scope:
public class ClassName {
private var money:int;
public function ClassName(){
money = 9999;
checkMoney()
}
public function checkMoney() {
// you now have access to money
}
}
or pass the object into the function:
public class ClassName {
public function ClassName(){
var money:int = 9999;
checkMoney(money);
}
public function checkMoney(value:Number) {
// check "value" here. Note that Numbers and Strings are NOT passed be reference, so changing the value will NOT change the original variable
}
}