I'm doing a mySQL tutorial to learn how to write sql statements. I keep getting this:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''add_delete_record' ( 'id' int(11) NOT NULL AUTO_INCREMENT, 'content' text' at line 1
This is the sql I am using:
CREATE TABLE IF NOT EXISTS 'add_delete_record' (
'id' int(11) NOT NULL AUTO_INCREMENT,
'content' text NOT NULL,
PRIMARY KEY ('id')
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
This is the exact code the tutorial gave, so I am not sure if the tutorial is just older than my version of mysql(v5.5) or if I have something tiny wrong that I am missing.
You should be using backticks(`) instead of single quotes (').
CREATE TABLE IF NOT EXISTS `add_delete_record` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`content` text NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
sql fiddle
Just remove all single quotes from everywhere the query will run fine.
Related
I ran into a new problem today, when I was dealing with a mysql query that works on 10.1.19-MariaDB localhost, but not on MySQL 5.7.21-0ubuntu0.16.04.1-log:
CREATE TABLE testing (
pageid INT UNSIGNED NOT NULL AUTO_INCREMENT,
position SMALLINT UNSIGNED NOT NULL,
PRIMARY KEY (pageid),
UNIQUE position (position)
) ENGINE=InnoDB CHARSET=utf8
In MySQL 5.6 it works without any hickups (fiddle), however, in MySQL 5.7.21 (fiddle) it throws:
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'position (position)) ENGINE=InnoDB CHARSET=utf8' at line 1
I figured out a solution by replacing UNIQUE position (position) with UNIQUE (position).
But I am wondering, what the underlying problem is, why it works with the other db system, and I am not sure if my solution is correct.
MySQL doesn't allow you to create an index with the same name of the column
The following code works for MySQL (fiddle)
CREATE TABLE testing (
pageid INT UNSIGNED NOT NULL AUTO_INCREMENT,
position SMALLINT UNSIGNED NOT NULL,
PRIMARY KEY (pageid),
UNIQUE idx_position (position)
) ENGINE=InnoDB CHARSET=utf8
That's why it is so important to wrap field and table names in backticks in MySQL (and their derivatives):
Try this (same query and index names, only added backticks):
CREATE TABLE `testing` (
`pageid` INT UNSIGNED NOT NULL AUTO_INCREMENT,
`position` SMALLINT UNSIGNED NOT NULL,
PRIMARY KEY (`pageid`),
UNIQUE `position` (`position`)
) ENGINE=InnoDB CHARSET=utf8;
please give me recommendation my query does not working
SQL query:
CREATE TABLE `amenities` (
`amenities_id` int(11) NOT NULL auto_increment,
`pic` varchar(100) NOT NULL,
`des` text NOT NULL,
PRIMARY KEY (`amenities_id`)
) TYPE=MariaDB AUTO_INCREMENT=13
MySQL said: Documentation
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'TYPE=MariaDB AUTO_INCREMENT=13' at line 6
There is no type table option, you possibly want to define the table engine
and there is no mariadb engine try
CREATE TABLE amenities ( amenities_id int(11) NOT NULL auto_increment,
pic varchar(100) NOT NULL, des text NOT NULL, PRIMARY KEY (amenities_id) )
AUTO_INCREMENT=13,
engine=innodb
Or leave out the engine option if you want to default the table to the database engine/
Hope this works.
CREATE TABLE amenities (
amenities_id int(11) NOT NULL auto_increment,
pic varchar(100) NOT NULL,
des text NOT NULL,
PRIMARY KEY (amenities_id)
) AUTO_INCREMENT=13
The TYPE keyword was replaced by ENGINE long ago.
The ENGINEs are InnoDB, MyISAM, MEMORY, ARIA and possibly others. Not MySQL, nor MariaDB.
The error message ... near 'TYPE ... points exactly at or after the offending syntax: TYPE in this case. (Not AUTO_INCREMENT, which was later)
AUTO_INCREMENT=13 is produced by SHOW CREATE TABLE for possible reloading. However, it is rarely useful otherwise. It is also mostly harmless.
DROP TABLE IF EXISTS `amenities`;
CREATE TABLE `amenities` (
`amenities_id` int(11) NOT NULL AUTO_INCREMENT,
`pic` varchar(100) NOT NULL,
`des` text,
PRIMARY KEY (`amenities_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
Create new Table amenities where amenities_id is a PRIMARY KEY that will be auto increment. another table field pic is a varchar data type and des is a text data type that is used for rich text.
Just a note, I'm pretty new to SQL.
I'm using MySQL and using the app SequelPro.
I receive this error when I try to make a table:
"You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(id)
) ENGINE=InnoDB DEFAULT CHARSET=utf8' at line 4"
This is the code I'm using to make my table:
CREATE TABLE klout_scores_3 (
id INT(11) NOT NULL AUTO_INCREMENT,
score INT(11)
PRIMARY KEY (id)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
score INT(11)
You want a comma , at end of that line.
Your query is being interpreted like this:
CREATE TABLE klout_scores_3 (
id INT(11) NOT NULL AUTO_INCREMENT,
score INT(11) PRIMARY KEY
(id)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
The (id) part is really confusing to MySQL and it's raising an error right there. Although adding a , after the INT(11) part will fix it, a better solution is to move the declaration:
CREATE TABLE klout_scores_3 (
id INT(11) NOT NULL AUTO_INCREMENT PRIMARY KEY,
score INT(11)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
It's a little concerning that you have a table name like klout_scores_3, as that suggests you have N of these tables. Relational database design and database normalization
rules strongly frowns on this, you should have a singular table with some kind of ..._id column to relate the scores to whatever record that 3 identifies.
I'm trying to put together a MySQL database for a forum, And when I try to make a section table I keep encountering a problem
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'TYPE = INNODB' at line 7
Here's the code:
CREATE TABLE sections (
sect_id INT(8) NOT NULL AUTO_INCREMENT,
sect_name VARCHAR(255) NOT NULL,
sect_desc VARCHAR(255) NOT NULL,
UNIQUE INDEX sect_name_unique (sect_name),
PRIMARY KEY (sect_id)
) TYPE=INNODB;
Use the following query
CREATE TABLE IF NOT EXISTS sections (
sect_id INT(8) NOT NULL AUTO_INCREMENT,
sect_name VARCHAR(255) NOT NULL,
sect_desc VARCHAR(255) NOT NULL,
UNIQUE INDEX sect_name_unique (sect_name),
PRIMARY KEY (sect_id)
) ENGINE=InnoDB
To mention the type of engine use ENGINE keyword.
i get this error when i try to inport to data base
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '('id')
) TYPE=MyISAM AUTO_INCREMENT=6' at line 4
DROP TABLE IF EXISTS `categories`;
CREATE TABLE `categories` (
`id` int(5) NOT NULL auto_increment,
`category` varchar(50) NOT NULL default '',
PRIMARY KEY ('id')
) TYPE=MyISAM AUTO_INCREMENT=6 ;
You are using ' here
PRIMARY KEY ('id')
id is in this case a string, not the column name. Use backticks instead.
PRIMARY KEY (`id`)
You have two issues with the code, remove the single quotes around the id in the primary key declaration. You can use backticks or nothing.
And change the Type=MyISAM to:
ENGINE=MyISAM
From the MySQL Docs:
The older term TYPE is supported as a synonym for ENGINE for backward compatibility, but ENGINE is the preferred term and TYPE is deprecated.
So the script will be:
DROP TABLE IF EXISTS `categories`;
CREATE TABLE `categories` (
`id` int(5) NOT NULL auto_increment,
`category` varchar(50) NOT NULL default '',
PRIMARY KEY (id)
) ENGINE=MyISAM AUTO_INCREMENT=6 ;
See SQL Fiddle with Demo
Try this:
DROP TABLE IF EXISTS `categories`;
CREATE TABLE `categories` (
`id` int(5) NOT NULL auto_increment,
`category` varchar(50) NOT NULL default '',
PRIMARY KEY (`id`)
) ENGINE=MYISAM AUTO_INCREMENT=6
The problems is that PRIMARY KEY ('id') should use backquotes insted of quotes
1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM disc_disc WHERE disc_id=NULL' at line 1 SQL=SELECT disc_id, disc_name, FROM disc_disc WHERE disc_id=NULL
// zjistit jmeno diskuse
$disc_name = "";
$sql = sprintf("SELECT disc_id, disc_name, " .
"FROM disc_disc " .
"WHERE disc_id=%s",
quote_smart($disc_id));
$db->setQuery($sql);
$rec = $db->loadObjectList();
if ($db->getErrorNum()) {
JError::raiseWarning( 500, $db->stderr() );
}