My issue is that I have a table apidata that holds multiple rows of data for each domain. So when I query apidata I naturally get multiple rows as a result. Is there any way to turn those rows into columns? I ask because I'm already using a query to pull the domain data (page title, URL, top level domain, ip address etc) and I need to add the api data with it. I believe I have to do this in two queries but I would love to at least have one row per domain to make the query and loop as fast a possible.
So the question is, can I create columns out of rows on the fly?
Heres a SQL Fiddle => http://sqlfiddle.com/#!2/8e408/4
(Note, I didnt put the whole database in the fiddle just the tables that effect the query. If you think somethings missing that you need, let me know.)
Tool_Runs (id_sha is the main lookup value for tool runs)
| ID | ID_SHA |
+----+------------------------------------------+
| 1 | 68300DF58B2A8A6E098CB0B3D1A9AE80BBE5897A |
Domains (Run_id is FK to tool_runs.id)
| ID | RUN_ID |
+----+--------+
| 1 | 1 |
API Data
| ID | DOMAIN_ID | EXPORT_COLUMN | COLUMN_TITLE | VALUE |
+----+-----------+------------------+-------------------+-------+
| 1 | 1 | referringDomains | Referring Domains | 10 |
+----+-----------+------------------+-------------------+-------+
| 2 | 1 | linkCount | Backlink Count | 55 |
Heres my query now:
SELECT a.domain_id, a.export_column, a.column_title, a.value
FROM apidata AS a WHERE domain_id IN
(
SELECT d.id FROM tool_runs AS t
JOIN domains AS d ON d.run_id = t.id
WHERE id_sha = '68300DF58B2A8A6E098CB0B3D1A9AE80BBE5897A'
)
ORDER BY a.domain_id
And what I get is:
| DOMAIN_ID | EXPORT_COLUMN | COLUMN_TITLE | VALUE |
+-----------+------------------+-------------------+----------+
| 1 | referringDomains | Referring Domains | 10 |
+-----------+------------------+-------------------+----------+
| 1 | linkCount | Backlink Count | 55 |
But what I want is
| DOMAIN_ID | referringDomains | referringDomains_TITLE | linkCount | linkCount_TITLE |
+-----------+------------------+------------------------+-----------+-----------------+
| 1 | 10 | Referring Domains | 55 | Backlink Count |
What you are trying to is to pivot the table rows into columns. Unfortunately MySQL doesn't have a native pivot table operator, but you can use the CASE expression to do so:
SELECT
a.Domain_id,
MAX(CASE WHEN a.export_column = 'referringDomains' THEN a.value END) AS referringDomains,
MAX(CASE WHEN a.export_column = 'referringDomains' THEN a.column_title END) AS referringDomains_TITLE,
MAX(CASE WHEN a.export_column = 'linkCount' THEN a.value END) AS linkCount,
MAX(CASE WHEN a.export_column = 'linkCount' THEN a.column_title END) AS linkCount_TITLE
FROM apidata AS a
WHERE domain_id IN
(
SELECT d.id FROM tool_runs AS t
JOIN domains AS d ON d.run_id = t.id
WHERE id_sha = '68300DF58B2A8A6E098CB0B3D1A9AE80BBE5897A'
)
GROUP BY a.domain_id;
Updated SQL Fiddle Demo
Note that: If you want to do so for all the values in the export_column, you have to write a CASE expression for each value. But you can do that using dynamic sql like this:
SET #ecvalues = NULL;
SET #ectitles = NULL;
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT CONCAT('MAX(IF(a.export_column = ''',
a.export_column, ''', a.value , NULL)) AS ', '''', a.export_column , '''')
) INTO #ecvalues
FROM apidata a;
SELECT
GROUP_CONCAT(DISTINCT CONCAT('MAX(IF(a.export_column = ''',
a.export_column, ''', column_title , NULL)) AS ', '''', CONCAT(a.export_column , '_Titles'), '''')
) INTO #ectitles
FROM apidata a;
SET #sql = CONCAT('SELECT
a.Domain_id, ', #ectitles , ',', #ecvalues, '
FROM apidata AS a
WHERE domain_id IN
(
SELECT d.id FROM tool_runs AS t
JOIN domains AS d ON d.run_id = t.id
WHERE id_sha = ''68300DF58B2A8A6E098CB0B3D1A9AE80BBE5897A''
)
GROUP BY a.domain_id;');
prepare stmt
FROM #sql;
execute stmt;
You can put that query inside a stored procedure.
Updated SQL Fiddle Demo
Just as a complement to the #MahmoudGamal answer you should know that for any new registry (EXPORT_COLUMN) you will have to add a new case statement.
So in order to do it dynamic you can create a procedure as described on this post at dba.stackexchange.
How to transpose/convert rows as columns in mysql
It shows how to do it dynamically.
If you want columns, go ahead and pivot as the example above. If you only want a single string, for some reporting reason, go ahead and do:
SELECT group_concat(CONCAT_WS(' ',a.domain_id, a.value, a.column_title, a.export_column, 'next row string separator'))
FROM apidata AS a WHERE domain_id IN
(
SELECT d.id FROM tool_runs AS t
JOIN domains AS d ON d.run_id = t.id
WHERE id_sha = '68300DF58B2A8A6E098CB0B3D1A9AE80BBE5897A'
)
ORDER BY a.domain_id
Related
I'm having trouble using/understanding the SQL ALL operator. I have a table FOLDER_PERMISSION with the following columns:
+----+-----------+---------+----------+
| ID | FOLDER_ID | USER_ID | CAN_READ |
+----+-----------+---------+----------+
| 1 | 34353 | 45453 | 0 |
| 2 | 46374 | 342532 | 1 |
| 3 | 46374 | 32352 | 1 |
+----+-----------+---------+----------+
I want to select the folders where all the users have permission to read, how could I do it?
Use aggregation and having:
select folder_id
from t
group by folder_id
having min(can_read) = 1;
Gordon's answer seems better but for the sake of completeness, using ALL a query could look like:
SELECT x1.folder_id
FROM (SELECT DISTINCT
fp1.folder_id
FROM folder_permission fp1) x1
WHERE 1 = ALL (SELECT fp2.can_read
FROM folder_permission fp2
WHERE fp2.folder_id = x1.folder_id);
If you have a table for the folders themselves replace the derived table (aliased x1) with it.
But this only respects users present in folder_permissions. If not all users have a reference in that table you possibly won't get the folders really all users can read.
You can do aggregation :
SELECT fp.FOLDER_ID
FROM folder_permission fp
GROUP BY fp.FOLDER_ID
HAVING SUM( can_read = 0 ) = 0;
You can also express it :
SELECT fp.FOLDER_ID
FROM folder_permission fp
GROUP BY fp.FOLDER_ID
HAVING MIN(CAN_READ) = MAX(CAN_READ) AND MIN(CAN_READ) = 1;
If you wanted to return the full matching records, you could try using some exists logic:
SELECT ID, FOLDER_ID, USER_ID, CAN_READ
FROM yourTable t1
WHERE NOT EXISTS (SELECT 1 FROM yourTable t2
WHERE t2.FOLDER_ID = t1.FOLDER_ID AND t2.CAN_READ = 0);
Demo
The existence of a matching record in the above exists subquery would imply that there exist one or more users for that folder who do not have read access rights.
I'm trying to make a link between 2 tables on mySQL but, i think it's a little bit harder than i thought.
I have 3 tables
* One which registers my rules informations
* One which registers my transfers informations
* One which make the pivot between the two first.
CREATE TABLE `rules` (
`id` int,
`Name` varchar(10)
);
INSERT INTO `rules` (`id`, `name`) VALUES
(1,'a'),
(2,'b'),
(3,'c'),
(4,'d');
CREATE TABLE `pivot` (
`id_rule` int,
`id_transfert` int
);
INSERT INTO `pivot` (`id_rule`, `id_transfert`) VALUES
(1,1),
(1,2),
(2,1),
(2,2),
(2,3);
CREATE TABLE `transferts` (
`id` int,
`aeroport` varchar(50),
`station` varchar(50)
);
INSERT INTO `transferts` (`id`, `aeroport`,`station`) VALUES
(1,'GVA','Flaine'),
(2,'GNB','La Tania'),
(3,'GNB','Flaine');
What i'm trying to do is to get all my rules with a column which gather all linked transfers as a JSON string. Like below
------------------------------------------------------------------------
| id | name | transferts |
------------------------------------------------------------------------
| 1 | a | {"GVA": "Flaine"} |
------------------------------------------------------------------------
| 2 | b | {"GVA": "Flaine", "GNB": "Flaine", "La Tania"} |
------------------------------------------------------------------------
What i do actually is this :
SELECT
rule.id, rule.name,GROUP_CONCAT(stations.transferts SEPARATOR ",") as transferts
FROM
rules rule
LEFT OUTER JOIN
pivot pivot
on
(pivot.id_rule = rule.id)
LEFT OUTER JOIN
(
SELECT id,
CONCAT(aeroport, ":",
GROUP_CONCAT(station)
) AS transferts
FROM transferts
GROUP BY aeroport
) stations
on
(pivot.id_transfert = stations.id)
GROUP BY
rule.id
But this is returning me a "null" value. I don't see what i'm doing wrong.
Is there someone who can help me please ?
FYI, I was inspired by this link
MySQL: GROUP_CONCAT with LEFT JOIN
With a MySQL version prior to 5.7.22 you can't use the JSON built-in functions.
You'll have to use a few imbricated GROUP_CONCAT subqueries to obtain your JSON string.
As told in the comments, your expected JSON string is not valid. The following answer will differ from your expected result, to fix this issue.
I suggest you proceed with a first query to get a column with the "aeroport" names, and another column with the associated stations formatted as a list, for each couple of "rule.id + aeroport_name".
This gives the following query:
mysql> select rules.id, name, concat ('"', aeroport, '":') as aeroport_name, group_concat('"', station, '"') as station_list
-> from rules
-> inner join pivot on rules.id = pivot.id_rule
-> inner join transferts on pivot.id_transfert = transferts.id
-> group by rules.id, aeroport_name;
+------+------+---------------+---------------------+
| id | name | aeroport_name | station_list |
+------+------+---------------+---------------------+
| 1 | a | "GNB": | "La Tania" |
| 1 | a | "GVA": | "Flaine" |
| 2 | b | "GNB": | "La Tania","Flaine" |
| 2 | b | "GVA": | "Flaine" |
+------+------+---------------+---------------------+
4 rows in set (0,00 sec)
Then, we are going to use this query as a subquery to associate each "station_list" to its given aeroport, in a rule id context, within a single string.
This give the following encapsulation:
mysql> select id, name, group_concat(aeroport_name, '[', station_list, ']') as aeroport_list
-> from (
-> select rules.id, name, concat ('"', aeroport, '":') as aeroport_name, group_concat('"', station, '"') as station_list
-> from rules
-> inner join pivot on rules.id = pivot.id_rule
-> inner join transferts on pivot.id_transfert = transferts.id
-> group by rules.id, aeroport_name
-> ) as isolated group by id;
+------+------+----------------------------------------------+
| id | name | aeroport_list |
+------+------+----------------------------------------------+
| 1 | a | "GNB":["La Tania"],"GVA":["Flaine"] |
| 2 | b | "GNB":["La Tania","Flaine"],"GVA":["Flaine"] |
+------+------+----------------------------------------------+
2 rows in set (0,00 sec)
And finally, we can now add the final "{}" encapsulation to our string, by adding a top level query over this:
mysql> select id, name, concat('{', aeroport_list, '}') as conf
-> from (
-> select id, name, group_concat(aeroport_name, '[', station_list, ']') as aeroport_list
-> from (
-> select rules.id, name, concat ('"', aeroport, '":') as aeroport_name, group_concat('"', station, '"') as station_list
-> from rules
-> inner join pivot on rules.id = pivot.id_rule
-> inner join transferts on pivot.id_transfert = transferts.id
-> group by rules.id, aeroport_name
-> ) as isolated group by id
-> ) as full_list;
+------+------+------------------------------------------------+
| id | name | conf |
+------+------+------------------------------------------------+
| 1 | a | {"GNB":["La Tania"],"GVA":["Flaine"]} |
| 2 | b | {"GNB":["Flaine","La Tania"],"GVA":["Flaine"]} |
+------+------+------------------------------------------------+
2 rows in set (0,01 sec)
I have an old database of entries from an abandoned "Joomgalaxy" Joomla plugin.
There are three tables, joomgalaxy_entries, joomgalaxy_fields, and joomgalaxy_entries_data
The id from the entries table matches the entry_id in the entries_data table, but the actual field name is saved in another table, fields
Can someone please help me with the correct SQL statement to obtain results like you can see below in Ultimate Goal? My MySQL knowledge is very basic, and from my searching it sounds like I need to use a LEFT JOIN, but I have no idea how to use the value from field_name as the column name for returned values
Thank You!!
joomgalaxy_entries
---------------------------------------
| id | title | longitude | latitude |
---------------------------------------
| 50 | John | -79.333333 | 43.669999 |
| 51 | Bob | -79.333333 | 43.669999 |
---------------------------------------
joomgalaxy_fields
This is just two examples below to keep it simple, there are more than just these two, so it would have to be able to handle dynamically using the field_name as the column name.
--------------------------------
| id | field_type | field_name |
--------------------------------
| 1 | textbox | websiteurl |
| 2 | dropdown | occupation |
--------------------------------
joomgalaxy_entries_data
"Technically" there shouldn't be any duplicate entries (fieldid and entry_id), so from my understanding that shouldn't affect using the field_name from above as the column name, but what if there ends up being one?
-------------------------------------
| fieldid | field_value | entry_id |
-------------------------------------
| 1 | google.com | 50 |
| 2 | unemployed | 50 |
| 1 | doctor.com | 51 |
| 2 | doctor | 51 |
-------------------------------------
Ultimate Goal
Ultimately trying to get this type of result, so I can then use that statement in MySQL Workbench to export the data that would look like this:
------------------------------------------------------------------
| id | title | longitude | latitude | websiteurl | occupation |
------------------------------------------------------------------
| 50 | John | -79.333333 | 43.669999 | google.com | unemployed |
| 51 | Bob | -79.333333 | 43.669999 | doctor.com | doctor |
------------------------------------------------------------------
EDIT:
There are more than just the two fields websiteurl and occupation, I was just using those two as examples, there are numerous fields that are all different, so in theory pulling the value from field_name would be used for the column name
You can use some conditional logic, like a CASE statement, along with an aggregate function like max() or min() to return those values as columns:
SELECT je.id,
je.title,
je.longitude,
je.latitude,
max(case when jf.fieldid = 1 then jed.field_value end) as WebsiteUrl,
max(case when jf.fieldid = 2 then jed.field_value end) as Occupation
FROM joomgalaxy_entries je
INNER JOIN joomgalaxy_entries_data jed
on je.id = jed.entry_id
GROUP BY je.id,
je.title,
je.longitude,
je.latitude
Using an INNER JOIN will only return the joomgalaxy_entries rows that have values in each table, if you want to return all joomgalaxy_entries even if there are no matching rows to join on in the other tables, then change the INNER JOIN to a LEFT JOIN.
You can write a simple SELECT query like this:
SELECT je.id, je.title, je.longitude, je.latitude,
(SELECT field_value FROM joomgalaxy_entries_data WHERE fieldid = 1 AND entry_id = je.id) AS websiteurl,
(SELECT field_value FROM joomgalaxy_entries_data WHERE fieldid = 2 AND entry_id = je.id) AS occupation
FROM joomgalaxy_entries je;
First step is easy:
SELECT JE.id, JE.title, JE.longitude, JE.latitude
FROM joomgalaxy_entries JE
Now you need to JOIN:
SELECT JE.id, JE.title, JE.longitude, JE.latitude,
JD.*
FROM joomgalaxy_entries JE
JOIN joomgalaxy_entries_data JD
ON JE.id = JD.entry_id
Now you need convert rows to columns
SELECT JE.id, JE.title, JE.longitude, JE.latitude,
MIN(CASE WHEN fieldid = 1 THEN JD.field_value END) as WebsiteUrl,
MIN(CASE WHEN fieldid = 2 THEN JD.field_value END) as Occupation
FROM joomgalaxy_entries JE
JOIN joomgalaxy_entries_data JD
ON JE.id = JD.entry_id
GROUP BY JE.id, JE.title, JE.longitude, JE.latitude
This depend on you only have two field for each entry, if number of field is dynamic you would need a different aproach.
This should work:
select id, title, longitude, latitude,
(select field_value from joomgalaxy_entries_data jed
where fieldid = (select id from joomgalaxy_fields
where field_name = 'websiteurl')
and jed.entry_id = je.id
) as websiteurl,
(select field_value from joomgalaxy_entries_data jed
where fieldid = (select id from joomlgalaxy_fields
where field_name = 'occupation')
and jed.entry_id = je.id) as occupation
from joomgalaxy_entries je;
Note that the reason to have a left join would be if either websiteurl or occupation were null, however, this solution should work in that case anyway.
Well, that certainly makes it a bit more difficult... :) Honestly, I'm not sure what you're asking is possible with a static sql query. I'm sure someone will speak up, however, if I'm wrong.
That said, I do have a few options you can try:
Option 1 - Generate the SQL Dynamically
Assuming this is mysql, if you execute the following SQL, it will generate the subqueries dynamically:
select concat('(select field_value from joomgalaxy_entries_data jed ',
'where fieldid = (select id from joomgalaxy_fields ',
'where field_name = ''', field_name, ''') ',
'and jed.entry_id = je.id) as ', field_name, ',')
from joomgalaxy_fields;
Take the result of that command, copy-paste it into a text editor and add the following at the beginning:
select id, title, longitude, latitude,
And the rest of this at the end:
from joomgalaxy_entries je;
Then run your new uber-query and go grab a cup of copy, lunch, or a good night's sleep depending on how much data is in your database.
Alternatively, you could add all of this to a stored procedure so you don't have to hand edit the SQL. Also, note that my syntax works for MySQL. Other databases have different concatenation operators so you may have to work around that if applicable. Also, with 50+ subqueries there is a good chance this uber-query will be quite slow, maybe too slow to make this option viable.
Option 2 - Create a table structured the way you want, and populate it
Hopefully, this is self-explanatory, but just create a new table with all of the necessary columns from the joomgalaxy_fields table. Then populate each column separately with a long series of what should be pretty straightforward sql commands. Granted this option is only viable if the database is no longer in use which I believe you indicated. From there the result is just:
select * from my_new_table;
I have a table similar to the one shown below.
-----------------------------
JOB ID | parameter | result |
-----------------------------
1 | xyz | 10 |
1 | abc | 15 |
2 | xyz | 12 |
2 | abc | 8 |
2 | mno | 20 |
-----------------------------
I want the result as shown below.
parameter | result 1 | result 2 |
----------------------------------
xyz | 10 | 12 |
mno | NULL | 20 |
abc | 15 | 8 |
----------------------------------
My goal is to have a single table which can compare the result values of two different jobs. It can be two or more jobs.
you want to simulate a pivot table since mysql doesn't have pivots.
select
param,
max(case when id = 1 then res else null end) as 'result 1',
max(case when id = 2 then res else null end) as 'result 2'
from table
group by param
SQL FIDDLE TO PLAY WITH
If you are using MySQL there are no "outer join" need to use union right and left join:
Something like:
select t1.parameter, t1.result 'Result 1', t2.result 'Result 2' from
table as t1 left join table as t2
on t1.parameter=t2.parameter
where t1.'JOB ID' = 1 and t2.'JOB ID' = 2
union
select t1.parameter, t1.result 'Result 1', t2.result 'Result 2' from
table as t1 right join table as t2
on t1.parameter=t2.parameter
where t1.'JOB ID' = 1 and t2.'JOB ID' = 2
If the SQL with full outer join will make it more easier:
select t1.parameter, t1.result 'Result 1', t2.result 'Result 2' from
table as t1 outer join table as t2
on t1.parameter=t2.parameter
where t1.'JOB ID' = 1 and t2.'JOB ID' = 2
In Postgres, you can use something like:
select parameter, (array_agg(result))[1], (array_agg(result))[2] from my_table group by parameter;
The idea is: aggregate all the results for a given parameter into an array of results, and then fetch individual elements from those arrays.
I think that you can achieve something similar in MySQL by using GROUP_CONCAT(), although it returns a string instead of an array, so you cannot easily index it. But you can split by commas after that.
select q1.parameter, q2.result as r1, q3.result as r2
from
(select distinct parameter from temp2) q1
left join (select parameter, result from temp2 where job_id = 1) q2
on q1.parameter = q2.parameter
left join (select parameter, result from temp2 where job_id = 2) q3
on q1.parameter = q3.parameter;
It works, but it's not efficient. Still, since I'm gathering you are trying to solve something more complex than what's presented, this might help form your general solution.
While I'm at it, here's a slightly cleaner solution:
select distinct q1.parameter, q2.result as r1, q3.result as r2
from
temp2 q1
left join (select parameter, result from temp2 where job_id = 1) q2
on q1.parameter = q2.parameter
left join (select parameter, result from temp2 where job_id = 2) q3
on q1.parameter = q3.parameter;
I have 3 tables: questions, options, comments_to_options(opt_comments).
I want to write a query that returns in each row the following values, concatenated:
A question, all options to it, all comments to each option.
My query is:
select
concat('{', '"qid":"', q.q_id, '", "qt":"', q.q_title,
'", "op":[', group_concat('{"oi":"', o.op_id, '", "ot":"', o.opt_value, '", ', oc_list, '}'
order by o.opt_upvotes desc), ']}')
as r
from questions q, options o,
(select o.op_id as ocid, concat('"oc":[', group_concat('{"oci":"', oc.opt_com_id, '", "occ":"', oc.opt_com_value, '"}'
order by oc.opt_com_added_at), ']')
as oc_list
from options o, opt_comments oc
where oc.opt_com_to=o.op_id
group by o.op_id)
as r2
where o.op_id=r2.ocid
and q.q_id=o.option_to
group by q.q_id
order by q.q_added_at desc
limit 3;
But the above query gives only those options that have at least one comment to them.
How should I modify?
You are using the old JOIN syntax with comma-separated lists of tables and subqueries. That syntax is correct, but generates INNER JOIN operations. Such joins suppress rows that don't match the join criterion.
You need to adopt the LEFT JOIN syntax. Without refactoring your entire query, I will say that you should change
FROM a,
(select something from z) AS b
WHERE a.value=b.value
to
FROM a
LEFT JOIN (select something from z) AS b ON a.value=b.value
Also, beware, you may encounter the character-string length limit in GROUP_CONCAT(). Read this:
MySQL and GROUP_CONCAT() maximum length
Use "left join".
Example:
create table opt (oid int,name varchar(100));
insert into opt values (1,'opt1');
insert into opt values (2,'opt2');
insert into opt values (3,'opt3');
create table optcom (oid int,com varchar(100));
insert into optcom values (1,'opt1_1');
insert into optcom values (1,'opt1_2');
insert into optcom values (3,'opt3_1');
When using "simple join":
select opt.*,optcom.* from opt join optcom on opt.oid=optcom.oid;
+------+------+------+--------+
| oid | name | oid | com |
+------+------+------+--------+
| 1 | opt1 | 1 | opt1_1 |
| 1 | opt1 | 1 | opt1_2 |
| 3 | opt3 | 3 | opt3_1 |
+------+------+------+--------+
When "left join":
select opt.*,optcom.* from opt left join optcom on opt.oid=optcom.oid;
+------+------+------+--------+
| oid | name | oid | com |
+------+------+------+--------+
| 1 | opt1 | 1 | opt1_1 |
| 1 | opt1 | 1 | opt1_2 |
| 2 | opt2 | NULL | NULL |
| 3 | opt3 | 3 | opt3_1 |
+------+------+------+--------+
To follow up on the above responses, the SQL amended to use outer joins:-
SELECT CONCAT('{', '"qid":"', q.q_id, '", "qt":"', q.q_title,'", "op":[', GROUP_CONCAT('{"oi":"', o.op_id, '", "ot":"', o.opt_value, '", ', oc_list, '}' ORDER BY o.opt_upvotes DESC), ']}') AS r
FROM options o
LEFT OUTER JOIN questions q
ON q.q_id = o.option_to
LEFT OUTER JOIN
(
SELECT o.op_id AS ocid,
CONCAT('"oc":[', GROUP_CONCAT('{"oci":"', oc.opt_com_id, '", "occ":"', oc.opt_com_value, '"}' ORDER BY oc.opt_com_added_at), ']') AS oc_list
FROM options o
INNER JOIN opt_comments oc
ON oc.opt_com_to=o.op_id
GROUP BY o.op_id
) r2
ON o.op_id = r2.ocid
GROUP BY q.q_id
ORDER BY q.q_added_at DESC
LIMIT 3;
Looking at this I am unsure about the join to the sub query. This appears to be bringing back an encoded string, but beyond the actual join nothing from this sub query is actually used.
As such I am unsure if that sub query is just being used to narrow down the rows returned (in which case joining against it using an INNER JOIN would be appropriate - and you may as well not bring back the encoded string), or if you have posted a cut down version of the query that you have been trying to debug.