Linux Bash file use Directory name - mysql

Question

What I have is a few script files that are used for crons for different buildings in my company, but what I'm running into is I'm having to go into each file and change the OAK3 to a different building id, as well as the oak3(lowercase). The files are all located in there respectives warehouses folder ex: Desktop/CRON/OAK3. What I would like it to do, is if it's OAK3 use OAK3, and oak3(lowercase) instead of having to go into each file everytime we create a new db for a warehouse.
I am new to the linux world so I'm not sure if there is a way, and haven't found anything on google.
Example.sh
/usr/bin/mysqlimport --host=localhost -u root -ppassword --local --verbose -C --delete test \
/workplace/gwwallen/ETLdump/OAK3/oak3_count_portal.txt --ignore-lines=1
Desired effect is possible
/usr/bin/mysqlimport --host=localhost -u root -ppassword --local --verbose -C --delete test \
/workplace/gwwallen/ETLdump/$WAREHOUSE_ID/$warehouse_id_count_portal.txt --ignore-lines=1

Answer 1

If i get what you want, which I´m not sure, this will help to do all new databases
databases=`mysql -B -r -u ${user} --skip-column-names -p${pass} --execute='show databases'`
for db in $databases; do
## now loop through the above array
echo $db # current DB
mysqldump -u $user --password=$pass $db > "$db.sql" #dump db to file
done

Answer 2

Using a combination of dirname and basename with the Bash special variable $0, you can get all of what you need.
The running script's filename is $0. Meanwhile dirname $0 will give you the directory path of the executing file. But you don't want the full path, just the last part, which basename will provide. realpath is used to expand the directory so . is not used.
Getting just the last directory name:
$ ls
tmp.sh # Ok, there's our file
$ dirname tmp.sh
. # The . is current directory
$ dirname $(realpath tmp.sh)
/home/mjb/OAK3 # so we expand it with realpath
$ basename $(dirname $(realpath tmp.sh))
OAK3 # then take only the last one with basename
So here's how it will work for you:
# Get the directory name
warehouse=$(basename $(dirname $(realpath $0)))
# And lowercase it with `tr` into a new variable
warehouse_lcase=$(echo $warehouse | tr '[:upper:]' '[:lower:]')
# Substitute the variables
/usr/bin/mysqlimport --host=localhost -u root -ppassword --local --verbose -C --delete test \
/workplace/gwwallen/ETLdump/${warehouse}/${warehouse_lcase}_count_portal.txt --ignore-lines=1
See also: Can a Bash script tell which directory it's stored in?

Answer 3

There is lot easier way to figure out the basename of the current-working-directory: pwd -PL | sed sg.\*/ggg
[san#alarmp OAK3]$ pwd; pwd -PL | sed sg.\*/ggg
/opt/local/OAK3
OAK3
So, if I understand your requirement correctly, if you don't wanna change the script(s) manually by hand, you can do this whilst inside that particular directory:
$ cat example.sh
/usr/bin/mysqlimport --host=localhost -u root -ppassword --local --verbose -C --delete test \
/workplace/gwwallen/ETLdump/OAK3/oak3_count_portal.txt --ignore-lines=1
#
$ this_dir=$(pwd -PL | sed sg.\*/ggg)
#
$ sed -e "s/${this_dir}/\${WAREHOUSE_ID}/g" example.sh
/usr/bin/mysqlimport --host=localhost -u root -ppassword --local --verbose -C --delete test \
/workplace/gwwallen/ETLdump/${WAREHOUSE_ID}/oak3_count_portal.txt --ignore-lines=1
#
$ sed -e "s/$(echo $this_dir | tr '[:upper:]' '[:lower:]')/\${warehouse_id}/g" example.sh
/usr/bin/mysqlimport --host=localhost -u root -ppassword --local --verbose -C --delete test \
/workplace/gwwallen/ETLdump/OAK3/${warehouse_id}_count_portal.txt --ignore-lines=1
Use -i option to make the change permanent in-file (without creating a new one) like this:
sed -ie "s/${this_dir}/\${WAREHOUSE_ID}/g" example.sh