I am attempting to find records in my DB that's end_date is within 24 hours of the current time.
Here is the query I am currently running
select *
FROM record r
WHERE NOW() BETWEEN r.end_date AND DATE_ADD(r.end_date, INTERVAL -1 DAY);
This doesn't bring back any of the records with an end_date within 24 hours, am I using the DATE_ADD function wrong?
I think this is what you need:
select *
FROM record r
where
r.end_date >= date_add(now(), INTERVAL -1 DAY)
I am trying to retrieve all data from table in a specific month, my date format in the database table is 2016-06-19 I am need to find with the respect of a selected date, like if I select 2016-05-22
it will retrieve 2016-05-07 to 2016-06-06 interval values from the table.
And also to all the values in this month which is 05 month, I am using mysqli with PHP. I have tried using this query
SELECT * FROM t_tenancy_details WHERE
agreement_date >= DATE_FORMAT( CURRENT_DATE - INTERVAL 1 MONTH, '%Y/%m/01' )AND
agreement_date < DATE_FORMAT( CURRENT_DATE, '%Y/%m/01' )
This works fine for the running month, But problem is that if I select a previous month it does not work.
It's not very clear from the question as to what is needed. Based on the 2 requirements that I could understand:
Get everything surrounding the given date (i.e. +-15 days from the given date):
SELECT *
FROM t_tenancy_details
WHERE agreement_date >= DATE_SUB(#d, INTERVAL 15 DAY)
AND agreement_date <= DATE_ADD(#d, INTERVAL 15 DAY);
Get all the records where the month is same as the month in the given date:
SELECT *
FROM t_tenancy_details
WHERE MONTH(agreement_date) = MONTH(#d)
AND YEAR(agreement_date) = YEAR(#d);
where #d is the input date, in your case - CURRENT_DATE
Should be this
SELECT * FROM t_tenancy_details
WHERE (YEAR(t_tenancy_details) => YEAR(CURRENT_DATE - INTERVAL 1 MONTH)
AND MONTH(agreement_date) => MONTH(CURRENT_DATE - INTERVAL 1 MONTH))
AND (YEAR(t_tenancy_details) <= YEAR(CURRENT_DATE)
AND MONTH(agreement_date) <= MONTH(CURRENT_DATE))
I have a query that I need to modify to use data variables to search counts for the last 30 days from today and group by date. My SQL server's /tmp/ directory (15GB) keeps filling up and the query fails.
SELECT DATE(`date_time`) AS DAY
, COUNT(DISTINCT(rcid)) AS COUNT
, COUNT(DISTINCT(tunnelip)) AS TAILS
FROM primarydata
WHERE SERVER LIKE"%VOE%"
AND DATE_SUB(NOW(), INTERVAL 30 DAY) and NOW()
GROUP BY DAY;
Can you run the query manually in a shell? Looks like you're almost there. It may be failing on the group by. At this point in the execution it doesn't know what column DAY is.
Try: GROUP BY DATE(date_time)
Instead of: GROUP BY DAY.
Your date check is missing the column name to test, and also missing the BETWEEN keyword between the two dates.
SELECT
DATE(`date_time`) AS DAY,
COUNT(DISTINCT (rcid)) AS COUNT,
COUNT(DISTINCT (tunnelip)) AS TAILS
FROM primarydata
WHERE SERVER LIKE "%VOE%"
AND date_time BETWEEN DATE_SUB(NOW(), INTERVAL 30 DAY) AND NOW()
GROUP BY DAY;
Try this:
SELECT
DATE(`date_time`) AS DAY,
COUNT(DISTINCT (rcid)) AS COUNT,
COUNT(DISTINCT (tunnelip)) AS TAILS
FROM primarydata
WHERE SERVER LIKE
"%VOE%" AND `date_time` BETWEEN DATE_SUB(NOW(), INTERVAL 30 DAY) AND NOW()
GROUP BY `date_time`;
Thanks all. I got t to work using CURDATE()
AND `date_time` BETWEEN CURDATE() - INTERVAL 30
SELECT
DATE(`date_time`) AS DAY,
COUNT(DISTINCT (rcid)) AS COUNT,
COUNT(DISTINCT (tunnelip)) AS TAILS
FROM primarydata
WHERE SERVER LIKE "%VOE%" AND `date_time` BETWEEN CURDATE() - INTERVAL 30 DAY AND NOW() GROUP BY DAY;
I have tried to filter records but with the use of now function as given below
select * from table where date>= DATE_SUB( NOW( ) ,INTERVAL 90 DAY )
What I need is a select statement that can filter its records for a week or month from the current date but without using NOW() function
if you are using java you could make use of the following code
String timeStamp = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(Calendar.getInstance().getTime());
or you could use curdate() of mysql
Since I found it hard to understand the question I provide the following possibilities:
Try for all dates in a week from now:
SELECT * FROM table
WHERE date BETWEEN CURDATE() AND DATE_ADD(CURDATE() ,INTERVAL 1 WEEK)
and for all dates in a month from now:
SELECT * FROM table
WHERE date BETWEEN CURDATE() AND DATE_ADD(CURDATE() ,INTERVAL 1 MONTH)
If you are looking for all dates of the current month use
SELECT * FROM table
WHERE MONTH(date)=MONTH(CURDATE()) AND YEAR(date)=YEAR(CURDATE())
or for all dates of the current week use
SELECT * FROM table
WHERE WEEK(date)=WEEK(CURDATE()) AND YEAR(date)=YEAR(CURDATE())
I need to select data from MySQL database between the 1st day of the current month and current day.
select*from table_name
where date between "1st day of current month" and "current day"
Can someone provide working example of this query?
select * from table_name
where (date between DATE_ADD(LAST_DAY(DATE_SUB(CURDATE(), interval 30 day), interval 1 day) AND CURDATE() )
Or better :
select * from table_name
where (date between DATE_FORMAT(NOW() ,'%Y-%m-01') AND NOW() )
I was looking for a similar query where I needed to use the first day of a month in my query.
The last_day function didn't work for me but DAYOFMONTH came in handy.
So if anyone is looking for the same issue, the following code returns the date for first day of the current month.
SELECT DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY);
Comparing a date column with the first day of the month :
select * from table_name where date between
DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY) and CURRENT_DATE
select * from table_name
where `date` between curdate() - dayofmonth(curdate()) + 1
and curdate()
SQLFiddle example
I have used the following query. It has worked great for me in the past.
select date(now()) - interval day(now()) day + interval 1 day
try this :
SET #StartDate = DATE_SUB(DATE(NOW()),INTERVAL (DAY(NOW())-1) DAY);
SET #EndDate = ADDDATE(CURDATE(),1);
select * from table where (date >= #StartDate and date < #EndDate);
Complete solution for mysql current month and current year, which makes use of indexing properly as well :)
-- Current month
SELECT id, timestampfield
FROM table1
WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY)
AND timestampfield <= LAST_DAY(CURRENT_DATE);
-- Current year
SELECT id, timestampfield
FROM table1
WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFYEAR(CURRENT_DATE)-1 DAY)
AND timestampfield <= LAST_DAY(CURRENT_DATE);
select * from table
where date between
(date_add (CURRENT_DATE, INTERVAL(1 - DAYOFMonth(CURRENT_DATE)) day)) and current_date;
select * from <table>
where <dateValue> between last_day(curdate() - interval 1 month + interval 1 day)
and curdate();
I found myself here after needing this same query for some Business Intelligence Queries I'm running on an e-commerce store. I wanted to add my solution as it may be helpful to others.
set #firstOfLastLastMonth = DATE_SUB(LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH)),INTERVAL DAY(LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH)))-1 DAY);
set #lastOfLastLastMonth = LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH));
set #firstOfLastMonth = DATE_SUB(LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH)),INTERVAL DAY(LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH)))-1 DAY);
set #lastOfLastMonth = LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH));
set #firstOfMonth = DATE_ADD(#lastOfLastMonth, INTERVAL 1 DAY);
set #today = CURRENT_DATE;
Today is 2019-10-08 so the output looks like
#firstOfLastLastMonth = '2019-08-01'
#lastOfLastLastMonth = '2019-08-31'
#firstOfLastMonth = '2019-09-01'
#lastOfLastMonth = '2019-09-30'
#firstOfMonth = '2019-10-01'
#today = '2019-10-08'
A less orthodox approach might be
SELECT * FROM table_name
WHERE LEFT(table_name.date, 7) = LEFT(CURDATE(), 7)
AND table_name.date <= CURDATE();
as a date being between the first of a month and now is equivalent to a date being in this month, and before now. I do feel that this is a bit easier on the eyes than some other approaches, though.
SELECT date_sub(current_date(),interval dayofmonth(current_date())-1 day) as first_day_of_month;
I had some what similar requirement - to find first day of the month but based on year end month selected by user in their profile page.
Problem statement - find all the txns done by the user in his/her financial year. Financial year is determined using year end month value where month can be any valid month - 1 for Jan, 2 for Feb, 3 for Mar,....12 for Dec.
For some clients financial year ends on March and some observe it on December.
Scenarios - (Today is `08 Aug, 2018`)
1. If `financial year` ends on `July` then query should return `01 Aug 2018`.
2. If `financial year` ends on `December` then query should return `01 January 2018`.
3. If `financial year` ends on `March` then query should return `01 April 2018`.
4. If `financial year` ends on `September` then query should return `01 October 2017`.
And, finally below is the query. -
select #date := (case when ? >= month(now())
then date_format((subdate(subdate(now(), interval (12 - ? + month(now()) - 1) month), interval day(now()) - 2 day)) ,'%Y-%m-01')
else date_format((subdate(now(), interval month(now()) - ? - 1 month)), '%Y-%m-01') end)
where ? is year end month (values from 1 to 12).
The key here is to get the first day of the month. For that, there are several options. In terms of performance, our tests show that there isn't a significant difference between them - we wrote a whole blog article on the topic. Our findings show that what really matters is whether you need the result to be VARCHAR, DATETIME, or DATE.
The fastest solution to the real problem of getting the first day of the month returns VARCHAR:
SELECT CONCAT(LEFT(CURRENT_DATE, 7), '-01') AS first_day_of_month;
The second fastest solution gives a DATETIME result - this runs about 3x slower than the previous:
SELECT TIMESTAMP(CONCAT(LEFT(CURRENT_DATE, 7), '-01')) AS first_day_of_month;
The slowest solutions return DATE objects. Don't believe me? Run this SQL Fiddle and see for yourself 😊
In your case, since you need to compare the value with other DATE values in your table, it doesn't really matter what methodology you use because MySQL will do the conversion implicitly even if your formula doesn't return a DATE object.
So really, take your pick. Which is most readable for you? I'd pick the first since it's the shortest and arguably the simplest:
SELECT * FROM table_name
WHERE date BETWEEN CONCAT(LEFT(CURRENT_DATE, 7), '-01') AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN DATE(CONCAT(LEFT(CURRENT_DATE, 7), '-01')) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (DATE(CURRENT_DATE) - INTERVAL (DAYOFMONTH(CURRENT_DATE) - 1) DAY) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (DATE(CURRENT_DATE) - INTERVAL (DAYOFMONTH(CURRENT_DATE)) DAY + INTERVAL 1 DAY) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN DATE_FORMAT(CURRENT_DATE,'%Y-%m-01') AND CURDATE;
I used this one
select DATE_ADD(DATE_SUB(LAST_DAY(now()), INTERVAL 1 MONTH),INTERVAL 1 day) first_day
,LAST_DAY(now()) last_day, date(now()) today_day
All the responses here have been way too complex. You know that the first of the current month is the current date but with 01 as the date. You can just use YEAR() and MONTH() to build the month date by inputting the NOW() method.
Here's the solution:
select * from table_name
where date between CONCAT_WS('-', YEAR( NOW() ), MONTH( NOW() ), '01') and DATE( NOW() )
CONCAT_WS() joins a series of strings with a separator (a dash in this case).
So if today is 2020-08-28, YEAR( NOW() ) = '2020' and MONTH( NOW() ) = '08' and then you just need to append '01' at the end.
Voila!
Get first date and last date from month and year.
select LAST_DAY(CONCAT(year,'.',month,'.','01')) as registerDate from user;
select date_add(date_add(LAST_DAY(end_date),interval 1 DAY),interval -1 MONTH) AS closingDate from user;
SET #date:='2012-07-11';
SELECT date_add(date_add(LAST_DAY(#date),interval 1 DAY),
interval -1 MONTH) AS first_day