well I eventually got to a max() on one table pulling correctly using max() - took me sometime to understand what was going on and reading the limits of mysql when using it
I have spent a some time doing some demo data on sqlfiddle (one below is with just the max on the one table
http://sqlfiddle.com/#!2/fff224/1
what i would like (and to absorb as ive tried for the last 2 hours on getting this to work) is how to incorporate another tables that dont need to use max (i have included these in the sqlfiddle
the result i would be after would be
case_number full_address case owner client compiled date(max()) recommendation
1000 1 high street bob london 14/12/2012 let
1001 2 high street ken Compton 13/12/2013 sell
1002 3 high street ken Leeds 14/12/2013 sell
completing the inner joins between from client\staff\ to case process im fine with its just this nested select max im falling over on
SELECT p.case_number
, p.full_address
, s.case_owner_name 'case owner'
, c.client_name client
, r.compiled_date
, r.recommendation
FROM case_process p
JOIN staff s
ON s.case_owner_number = p.case_owner_number
JOIN client c
ON c.client_number = p.client_number
JOIN reporting r
ON r.case_number = p.case_number
JOIN (SELECT case_number,MAX(compiled_date) max_compiled_date FROM reporting GROUP BY case_number) x
ON x.case_number = r.case_number
AND x.max_compiled_date = r.compiled_date;
+-------------+---------------+------------+---------+---------------+----------------+
| case_number | full_address | case owner | client | compiled_date | recommendation |
+-------------+---------------+------------+---------+---------------+----------------+
| 1000 | 1 high street | Bob | London | 2012-12-14 | let |
| 1001 | 2 high street | Ken | Compton | 2013-12-13 | sell |
| 1002 | 3 high street | Ken | Leeds | 2012-12-14 | sell |
+-------------+---------------+------------+---------+---------------+----------------+
3 rows in set (0.00 sec)
fiddle of same... http://sqlfiddle.com/#!2/fff224/7
Related
I’ve a database where I store each product submitted by the curators, and there I register if it was approved. I need to generate a list where I show their score, ordered by the one who has more submitted (subm) and approved (appr). For that I need to get the approval rate (with the division of appr/subm) and we call it ar (Approval rate), and then I need a second operation to get the cs (Curator Score), which is the result of appr*(ar*ar).
The final output should be as the following:
| Curator | subm | appr| ar | cs |
------------------------------------------------
| 1 | 21 | 20 | 95.24% | 18.14058957 |
| 4 | 13 | 12 | 92.31% | 10.22485207 |
| 2 | 10 | 7 | 70.00% | 3.43 |
| 3 | 2 | 2 |100.00% | 2 |
To get the values from the table I use
SELECT curator, SUM(prop) subm, SUM(date) appr
FROM control
GROUP BY curator
ORDER BY cs
But I need to add somewhere:
SUM(appr/subm) ar, SUM(appr*(ar*ar)) cs
But I don’t know how to do this.
It's probably simplest to use your existing query as a subquery:
SELECT *, appr/subm AS ar, appr*(appr/subm*appr/subm)) AS cs
FROM (SELECT curator, SUM(prop) subm, SUM(date) appr
FROM control
GROUP BY curator) c
ORDER BY cs
I got table:
id | nick | clanid | kills | deaths | map
1 | xdd | 2 | 123 | 23 | 'map_1'
2 | xd | 1 | 23 | 32 | 'map_1'
this table continuing with similar records. I need to get only 1 result, it's should be clanid and coef(kills/deaths), of course i need the clan with higher coef. This table got many records with players which have different clanids, kills, deaths and map.
The complete result i need: it's clanid with higher coef at current map.I tried SQL like that:
SELECT `clanid`, SUM(kills)/SUM(deaths) as 'coef'
FROM `test_user_stats`
WHERE `map`='map_1'
But that returs only 1 record with last clanid and his coef.
What i have to do next?(i obviously need to use LIMIT 1 and ORDER BY coef, but i got problems even without going so far).
Two tables...
people (personid, name, mainordering)
entries (userid, personid, altordering)
"personid" is the common field. My app displays a draggable list users can move around. When done, they click to "lock" in their order.
Table : people
+----------+---------+--------------+
| personid | name | mainordering |
+----------+---------+--------------+
| 1 | Bob | 2 |
| 2 | Charlie | 4 |
| 3 | Jim | 1 |
| 4 | Doug | 3 |
+----------+---------+--------------+
So using mainordering, it would display:
Jim
Bob
Doug
Charlie
entries table might have (for user 16):
+--------+----------+-------------+
| userid | personid | altordering |
+--------+----------+-------------+
| 16 | 1 | 3 |
| 16 | 2 | 1 |
| 16 | 3 | 2 |
| 16 | 4 | 4 |
+--------+----------+-------------+
So if user 16 has already submitted his entry BUT NOT LOCKED IT IN, I want to display his list using altordering. i.e.
Charlie
Jim
Bob
Doug
I'm struggling with the proper join to use. Here is what I tried and isn't working (it's simply ordering by mainordering still)...
$sql = "SELECT * from entries
WHERE userid=".$_SESSION['userid']."
LEFT JOIN people ON entries.personid = people.personid
ORDER BY altordering";
Any thoughts would be much appreciated. Thank you...
Are you sure you don't get an error when using WHERE before JOIN?
It should work like this:
SELECT people.*
FROM people
JOIN entries ON entries.personid = people.personid
WHERE entries.userid={$_SESSION['userid']}
ORDER BY entries.altordering
I assume entries.personid will always have a matching person in people, so you should use an INNER JOIN. You would use FROM entries LEFT JOIN people if you wanted to retrieve altordering even for non-existing people.
I have a table apartment as below
aid | aname
1 | dream home
2 | My hub
3 | Lake view
another table apartment_details
id | aid | bhk | size | facing
1 | 1 | 2 | 1200 | east
2 | 1 | 2 | 1200 | west
3 | 1 | 2 | 1000 | south
4 | 1 | 2 | 1000 | north
I have written the query as
SELECT distinct ap.aid, ap.aname, al.bhk, (select group_concat(distinct concat(al.bhk,'BHK - ',al.size)) from apartment_details as al where al.id = ap.aid) as details
When I tried to display details using foreach I get the output as
2BHK - 1200
2BHK - 1200
2BHK - 1000
2BHK - 1000
In this query it is considering bhk, size, facing in distinct and the output obtained is based on facing. This looks something like I am displaying duplicate data or something the same data is repeating as there is no facing displayed. How can I display only distinct values based on bhk, size and not facing so that I get the output as
2BHK - 1200
2BHK - 1000
Can anyone help me in solving this issue? Thanks in advance
To my way of thinking, in general, there is no problem in SQL for which GROUP_CONCAT is the solution. So, with that in mind, let's start with this:
SELECT DISTINCT bhk,size FROM apartment_details
Assuming a table as below
| ID | NAME | ROLE | MGRID |
---------------------------
| 1 | ONE | 5 | 5 |
| 2 | TWO | 5 | 5 |
| 3 | THREE | 5 | 6 |
| 4 | FOUR | 5 | 6 |
| 5 | FIVE | 15 | 7 |
| 6 | SIX | 25 | 8 |
| 7 | SEVEN | 25 | 7 |
| 8 | EIGHT | 5 | 8 |
How do I get a list of all employees reporting to an employee, including the ones who are in subsequent reporting levels below?
I mean, given emp id 5, I should get [1, 2] and given 7, I should get [1, 2, 5, 7]. How do I get this done?
Will self joins be of help here? Need to brush up my knowledge on joins now.
SELECT id
FROM emp
START WITH id = 7
CONNECT BY NOCYCLE mgrid = PRIOR id
SQLFIDDLE LINK
Here is a SQL statement using Oracle.
select id, name, role, mgrID
from employees
start with id = 7
connect by NoCycle prior id = mgrid;
Please note that the manager for employee 7 is the employee 7 - they are their own manager. This will cause an error - "Connect By loop in user data'. By using the NoCycle keyword you can tell Oracle to detect this and avoid the error.
Does this solve your issue?
I know this isn't exactly what you were asking, but if you are willing to choose a finite number of level's to recurse it isn't too bad to write.
SELECT table_2.id
FROM table LEFT JOIN
(table AS table_1 LEFT JOIN table AS table_2 ON table_1.id = table_2.MgrID)
ON table.id = table_1.MgrID
WHERE (((table.id)=7));
ETC.