I have two tables:
users and users_img.
I need to create one query to select all users from users table that have zip column not empty AND have img column empty in users_images (both tables have user ids: users.id and users_img.user_id so those could be joined).
users
id
name
zip
last_time
users_ids
id
user_id (same as id in users)
img
I tried this:
SELECT * FROM `users` JOIN `users_ids` on users.id = users_ids.user_id
WHERE `zip` != '' AND `img` = '' ORDER BY `last_time` DESC
with no luck. I know is supposed to be quite simple.
it will also work for you
SELECT * FROM `users` as `u`
JOIN `users_ids` as `uid` on `u`.`id` = `uid`.`user_id`
WHERE `u`.`zip` IS NOT NULL
AND `uid`.`img` IS NULL
ORDER BY `u`.`last_time` DESC
I have modified your query to check for Null values also in OR
Try this:
SELECT * FROM `users`
LEFT JOIN `users_ids` on users.id = users_ids.user_id
WHERE (TRIM(`zip`) != '' OR `zip` is not null) AND
(TRIM(`img`) = '' OR `img` is null) ORDER BY `last_time` DESC
This worked:
SELECT * FROM `users` as `u`
LEFT JOIN `users_ids` as `uid` on `u`.`id` = `uid`.`user_id`
WHERE `u`.`zip` != ''
AND `uid`.`img` IS NOT NULL
ORDER BY `u`.`last_time` DESC
Is there a limit of subquerys where the referencing outer column is working on?
I tried this query:
SELECT
`userouter`.`id` AS `user_id`
FROM
`users` AS `userouter`
WHERE
123456 = (
SELECT
SUM(`tmp`.`sum`) AS `sum_total`
FROM
(
SELECT
SUM(`invoiceposition`.`number` * `invoiceposition`.`amount`) AS `sum`
FROM
`invoices` AS `invoice` INNER JOIN
`invoicepositions` AS `invoiceposition` ON
`invoice`.`id` = `invoiceposition`.`invoice`
WHERE
`invoice`.`user` = `userouter`.`id`
GROUP BY
`invoice`.`id`
) AS `tmp`
)
GROUP BY
`userouter`.`id`
And i get Error Code: 1054. Unknown column 'userouter.id' in 'where clause'
How can i reference the userouter.id in the sub-sub query?
As it seems in a normal way not possible to resolve the problem (double nested subquery reference to outer query), i now solved the problem by creating a mysql function with the user id as parameter.
hope this will help other searchers
Remove the double nesting.
SELECT
`userouter`.`id` AS `user_id`
FROM
`users` AS `userouter`
LEFT JOIN (
SELECT
`invoice`.`user` as `user_id`, SUM(`invoiceposition`.`number` * `invoiceposition`.`amount`) AS `sum`
FROM
`invoices` AS `invoice` INNER JOIN
`invoicepositions` AS `invoiceposition` ON
`invoice`.`id` = `invoiceposition`.`invoice`
WHERE
`invoice`.`user` = `userouter`.`id`
GROUP BY
`invoice`.`id`
) AS `tmp`
ON `tmp`.`user_id` = `userouter`.`id`
WHERE
123456 = `userouter`.`id`
GROUP BY
`userouter`.`id`
I've a table structured somewhat similar to this:
CREATE TABLE `user`
(`id` int, `name` varchar(7));
CREATE TABLE `email`
(`id` int, `email_address` varchar(50), `verified_flag` tinyint(1),`user_id` int);
CREATE TABLE `social`
(`id` int,`user_id` int);
INSERT INTO `user`
(`id`, `name`)
VALUES
(1,'alex'),
(2,'jon'),
(3,'arya'),
(4,'sansa'),
(5,'hodor')
;
INSERT INTO `email`
(`id`,`email_address`,`verified_flag`,`user_id`)
VALUES
(1,'alex#gmail.com','1',1),
(2,'jon#gmail.com','0',1),
(3,'arya#gmail.com','0',3),
(4,'sansa#gmail.com','1',4),
(5,'reek#gmail.com','0',3),
(6,'hodor#gmail.com','0',5),
(7,'tyrion#gmail.com','0',1)
;
INSERT INTO `social`
(`id`,`user_id`)
VALUES
(1,4),
(2,4),
(3,5),
(4,4),
(5,4)
;
What I want to get is all emails:
which are not verified
which belongs to a user who has no, i.e 0, verified emails
which belongs to a user who has no, i.e 0, social records
With the below query I'm able to apply the 1st and 3rd condition but not the 2nd one:
SELECT *
FROM `email`
INNER JOIN `user` ON `user`.`id` = `email`.`user_id`
LEFT JOIN `social` ON `user`.`id` = `social`.`user_id`
WHERE `email`.`verified_flag` = 0
GROUP BY `email`.`user_id`,`email`.`email_address`
HAVING COUNT(`social`.`id`) = 0
How can I achieve the result?
Here's the sqlfiddle as well
Interesting and tricky one.
I see you've got something going on there. But having and sub queries becomes a VERY bad idea when your tables become large.
See below for an approach. Don't forget to set up your indexes!
SELECT * from email
LEFT JOIN social on email.user_id = social.user_id
-- tricky ... i'm going back to email table to pick verified emails PER user
LEFT JOIN email email2 on email2.user_id = email.user_id AND email2.verified_flag = 1
WHERE
-- you got this one going already :)
email.verified_flag = 0
-- user does not have any social record
AND social.id is null
-- email2 comes in handy here ... we limit resultset to include only users that DOES NOT have a verified email
AND email2.id is null
ORDER BY email.user_id asc;
You can use the following query:
SELECT e.`id`, e.`email_address`, e.`verified_flag`, e.`user_id`
FROM (
SELECT `id`,`email_address`,`verified_flag`,`user_id`
FROM `email`
WHERE `verified_flag` = 0) AS e
INNER JOIN (
SELECT `id`, `name`
FROM `user` AS t1
WHERE NOT EXISTS (SELECT 1
FROM `email` AS t2
WHERE `verified_flag` = 1 AND t1.`id` = t2.`user_id`)
AND
NOT EXISTS (SELECT 1
FROM `social` AS t3
WHERE t1.`id` = t3.`user_id`)
) AS u ON u.`id` = e.`user_id`;
This query uses two derived tables:
e implements the first condition, i.e. returns all emails which are not verified
u implements the 2nd and 3rd condition, i.e. it returns a set of all users that have no verified emails and have no social records.
Performing an INNER JOIN between e and u returns all emails satisfying condition no. 1 which belong to users satisfying conditions no. 2 and 3.
Demo here
You can alternatively use this query:
SELECT *
FROM `email`
WHERE `user_id` IN (
SELECT `email`.`user_id`
FROM `email`
INNER JOIN `user` ON `user`.`id` = `email`.`user_id`
LEFT JOIN `social` ON `user`.`id` = `social`.`user_id`
GROUP BY `email`.`user_id`
HAVING COUNT(`social`.`id`) = 0 AND
COUNT(CASE WHEN `email`.`verified_flag` = 1 THEN 1 END) = 0 )
The subquery is used in order to select all user_id satisfying conditions no. 2 and 3. Condition no. 1 is redundant since if the user has no verified emails, then there is no way a verified email is related to this user.
Demo here
Simply run a Union Query:
SELECT `user_id`, `email_address`, `verified_flag`, 'No Email' as `Type`
FROM `email` RIGHT JOIN `user` ON `user`.`id` = `email`.`user_id`
WHERE `email`.`user_id` IS NULL
UNION
SELECT `user_id`, `email_address`, `verified_flag`, 'Not Verified' as `Type`
FROM `email` INNER JOIN `user` ON `user`.`id` = `email`.`user_id`
WHERE `email`.`verified_flag` = 0
UNION
SELECT `user_id`, `email_address`, `verified_flag`, 'No Social' as `Type`
FROM `email` INNER JOIN `user` ON `user`.`id` = `email`.`user_id`
LEFT JOIN `social` ON `user`.`id` = `social`.`user_id`
GROUP BY `user_id`, `email_address`, `verified_flag`
HAVING COUNT(IFNULL(`social`.`id`, 0)) = 0;
SELECT
u.id AS u_id
, u.name AS u_name
, e.email_address AS e_email
, e.verified_flag AS e_verify
, e.user_id AS e_uid
, s.id AS s_id
, s.user_id AS u_id
, COALESCE(ver_e.ver_email_count,0) as ver_email_count
FROM
email as e
LEFT OUTER JOIN
user as u
ON u.id = e.user_id
LEFT OUTER JOIN
social AS s
ON u.id = s.user_id
LEFT OUTER JOIN
(
SELECT
COUNT(email_address) AS ver_email_count
, user_id
FROM
email
) AS ver_e
ON u.id = ver_e.user_id
GROUP BY
e.user_id
HAVING e.verified_flag = 0
AND
ver_email_count = 0
AND
ISNULL(s.id)
Uses one derived table to get the number of verified email addresses each user has got
Here's a SQL statement:
SELECT DISTINCT `class`, `student_id` , `student_name`,
(
SELECT SUM( `credits` )
FROM `stumgr_scores` B
JOIN `stumgr_courses` USING ( `course_id` )
WHERE `year` =2012 AND A.`student_id` = B.`student_id`
) AS `total_credits`,
(
SELECT SUM( `credits` * `final_score` )
FROM `stumgr_scores` C
JOIN `stumgr_courses` USING ( `course_id` )
WHERE `year` =2012 AND A.`student_id` = C.`student_id`
) AS `total_scores`
FROM `stumgr_scores` A
NATURAL JOIN `stumgr_students`
WHERE `year` =2012 AND `grade` =2011
You may discover that these two select statement which use aggregate functions are similar. So, I want to merge them into one as following:
SELECT DISTINCT `class`, `student_id` , `student_name`,
(
SELECT
SUM( `credits` ) AS `total_credits`,
SUM( `credits` * `final_score` ) AS `total_scores`
FROM `stumgr_scores` B
JOIN `stumgr_courses` USING ( `course_id` )
WHERE `year` =2012 AND A.`student_id` = B.`student_id`
) AS `something`
FROM `stumgr_scores` A
NATURAL JOIN `stumgr_students`
WHERE `year` =2012 AND `grade` =2011
Of course, the SQL statement above doesn't work and I don't know what to do.
Besides, the query is very slow because of large data, do you have any suggestions? Thanks a lot.
I have had to guess at your table structure slightly, but you should be able to simplify this query massively by using JOINs rather than correlated subqueries:
SELECT st.student_id,
st.student_name,
c.class,
SUM(sc.credits) AS total_credits,
SUM(sc.credits * sc.final_score) AS total_scores
FROM stumgr_students st
INNER JOIN stumgr_scores sc
ON sc.student_id = st.student_id
INNER JOIN stumgr_courses c
ON c.course_id = st.course_id
GROUP BY st.student_id, st.student_name, c.class;
I have the following MySQL query, which produces the result I want:
SELECT
`l`.`status`,
`l`.`acquired_by`, `a`.`name` AS 'acquired_by_name',
`l`.`researcher`, `r`.`name` AS 'researcher_name',
`l`.`surveyor`, `s`.`name` AS 'surveyor_name'
FROM `leads` `l`
LEFT JOIN (
SELECT '0' AS 'id', 'Unassigned' AS 'name'
UNION ALL
SELECT `id`, `name`
FROM `web_users`
) `r` ON `r`.`id` = `l`.`researcher`
LEFT JOIN (
SELECT '0' AS 'id', 'Unassigned' AS 'name'
UNION ALL
SELECT `id`, `name`
FROM `web_users`
) `s` ON `s`.`id` = `l`.`surveyor`
LEFT JOIN (
SELECT '0' AS 'id', 'Unassigned' AS 'name'
UNION ALL
SELECT `id`, `name`
FROM `web_users`
) `a` ON `a`.`id` = `l`.`acquired_by`
WHERE `l`.`id` = 566
But as you can see, it has the same sub-query in it three times. Is there any way to execute this query once and store the result, so I can LEFT JOIN with the cached results instead of executing the same query three times?
I have tried storing it in a variable:
SET #usercache = (
SELECT '0' AS 'id', 'Unassigned' AS 'name'
UNION ALL
SELECT `id`, `name`
FROM `web_users`
)
...but this gives me an error:
1241 - Operand should contain 1 column(s)
...and some Googling on this error has left me none the wiser.
Does anyone know how I can make this query more efficient? Or am I just worrying about something that doesn't matter anyway?
I am using PHP/MySQLi if it makes any difference.
Do you really need the subqueries? How about this:
SELECT
`l`.`status`,
`l`.`acquired_by`, COALESCE(`a`.`name`, 'Unassigned') AS 'acquired_by_name',
`l`.`researcher`, COALESCE(`r`.`name`, 'Unassigned') AS 'researcher_name',
`l`.`surveyor`, COALESCE(`s`.`name`, 'Unassigned') AS 'surveyor_name'
FROM `leads` `l`
LEFT JOIN `web_users` `r` ON `r`.`id` = `l`.`researcher`
LEFT JOIN `web_users` `s` ON `s`.`id` = `l`.`surveyor`
LEFT JOIN `web_users` `a` ON `a`.`id` = `l`.`acquired_by`
WHERE `l`.`id` = 566
you cannot run it once - you are actually using it three times to get three different results...