If the table has the following data
num | date_ | s | i_id
-------+-------------+------------------------+---------
1 | 2013-12-12 | (2,1,2013-12-12,80.56) | 2
1 | 2013-12-12 | (3,1,2013-12-12,70.56) | 3
1 | 2013-12-10 | (4,1,2013-12-10,90.76) | 4
2 | 2013-12-10 | (5,2,2013-12-10,90.76) | 5
2 | 2013-12-06 | (6,2,2013-12-06,90.76) | 6
3 | 2013-12-06 | (7,3,2013-12-06,90.76) | 7
3 | 2013-12-06 | (8,3,2013-12-06,90.76) | 8
i want a query which will give num,i_id for the records which have different dates for same num.
It should return num-1,2 and the corresponding i_id.
How should i proceed?
This should work in PostgreSQL with an version number >= 9.0
SELECT
num
, array_to_string(array_agg(i_id ORDER BY num), ',')
FROM a
GROUP BY num
see demo http://sqlfiddle.com/#!15/25502/5
And it look like in your comment that you want to have the MAX(date_)
SELECT
num
, MAX(date_)
, array_to_string(array_agg(i_id ORDER BY num), ',')
FROM a
GROUP BY num
see demo http://sqlfiddle.com/#!15/25502/6
select num, group_concat(i_id) as iids
from your_table
group by num
having count(distinct date_) > 1
Related
I have a table I am trying to use two aggregate values to create another column. For example
My table looks like this
| id | col_a | col_b
---------------------
| 1 | 5 | 10
| 1 | 15 | 20
| 2 | 1 | 2
| 2 | 3 | 4
| 2 | 5 | 6
And I want the output to be
| id | total_a | total_b | grand_total
---------------------------------------
| 1 | 20 | 30 | 50
| 2 | 9 | 12 | 21
And I tried
SELECT id,
SUM(col_a) AS total_a,
SUM(col_b) AS total_b,
(total_a + total_b) AS grand_total
FROM my_table
GROUP BY id
But that gives me an error Unknown column 'total_a' in 'field list'
I also tried using variables like this, but I don't think I am using variables correctly here.
SELECT id,
#a := SUM(col_a) AS total_a,
#b := SUM(col_b) AS total_b,
(SELECT #a + #b) AS grand_total
FROM my_table
GROUP BY id
What am I doing wrong here? It seems like this should be simple.
Nevermind. I figured it out. It is in fact really simple
SELECT id,
SUM(col_a) AS total_a,
SUM(col_b) AS total_b,
(SUM(col_a) + SUM(col_b)) AS grand_total
FROM my_table
GROUP BY id
I have a problem with SQLcode
I have a table
id | content | id_user | id_store
1 | abc | 1 | 10
2 | xzy | 1 | 10
3 | abc | 1 | 10
4 | abc | 1 | 11
5 | abc | 1 | 12
My problem is how i got the result is the count of max (id_store) which is 2* value >= max(id_store)
This is a example, result will be
id_store | count(...)
10 | 3
because (3*2) > max of count = 3
Tks everyone
It's very difficult to understand your question. Try to use the next query
SELECT id_store,COUNT(*) CountOfStore
FROM `Your Table`
GROUP BY id_store
HAVING 2*COUNT(*) >= (
SELECT MAX(CountOfStore) -- max of all CountOfStore
FROM
(
SELECT COUNT(*) CountOfStore -- count of store for each id_store
FROM `Your Table`
GROUP BY id_store
)
)
Hope I understood you rightly.
I am trying to do transformation on a table in Mysql. I can't figure out how to do it. Could anyone tell me how to do it? The input and output is given. I would like to know how it is done?
Input table
+-------------+------------+------------------+-------------------+
| Employee_ID | Start_Date | Termination_Date | Performance_Level |
+-------------+------------+------------------+-------------------+
| 1 | 1/1/2007 | 3/1/2007 | Low |
| 2 | 6/5/2004 | Null | Medium |
| 3 | 4/3/2003 | Null | High |
| 4 | 9/1/2002 | 4/15/2007 | Medium |
| 5 | 4/6/2007 | 11/1/2007 | Low |
| 6 | 7/1/2007 | Null | High |
| 7 | 3/2/2005 | 8/1/2007 | Low |
+-------------+------------+------------------+-------------------+
Ouput Table
+---------+-----------------------------------+-----------------+-------------------+----------------+
| Period | Total_Employees_at_end_of_quarter | High_Performers | Medium_Performers | Low_Performers |
+---------+-----------------------------------+-----------------+-------------------+----------------+
| Q1-2007 | 4 | 1 | 2 | 1 |
| Q2-2007 | 4 | 1 | 1 | 2 |
| Q3-2007 | 4 | 2 | 1 | 1 |
| Q4-2007 | 3 | 2 | 1 | 0 |
+---------+-----------------------------------+-----------------+-------------------+----------------+
This is what I tried
select * from emp
where date(sdate)< date'2007-04-01' and (date(tdate)> date'2007-03-31' or tdate is null);
select * from emp
where date(sdate)< date'2007-07-01' and (date(tdate)> date'2007-06-30' or tdate is null);
select * from emp
where date(sdate)< date'2007-010-01' and (date(tdate)> date'2007-09-30' or tdate is null);
select * from emp
where date(sdate)< date'2008-01-01' and (date(tdate)> date'2007-12-31' or tdate is null);
I have the individual queries but I want a single query which will give the outputs.
The approach taken below is to create a driver table for each quarter, with information about the year and quarter. This is then joined to the employee table, using a non-equijoin. Employees who start in or before the quarter and end after the quarter are active at the end of quarter.
It uses one trick for the date comparisons, which is to convert the year-quarter combination into a quarter count, by multiplying the year by 4 and adding the quarter. This is a convenience for simplifying the date comparisons.
select driver.qtryr, count(*) as TotalPerformers,
sum(Performance_level = 'High') as HighPerformers,
sum(Performance_level = 'Medium') as MediumPerformers,
sum(Performance_level = 'Low') as LowPerformers
from (select 2007 as yr, 1 as qtr, 'Q1-2007' as qtryr union all
select 2007 as yr, 2 as qtr, 'Q2-2007' as qtryr union all
select 2007 as yr, 3 as qtr, 'Q3-2007' as qtryr union all
select 2007 as yr, 4 as qtr, 'Q4-2007' as qtryr
) driver left outer join
Table1 emp
on year(emp.start_date)*4+quarter(emp.start_date) <= driver.yr*4+qtr and
(emp.termination_date is null or
year(emp.termination_date)*4+quarter(emp.termination_date) > driver.yr*4+qtr
)
group by driver.qtryr
sqlfiddle
try this
SELECT QUARTER('2008-04-01');
http://dev.mysql.com/doc/refman/5.6/en/date-and-time-functions.html#function_quarter
and CONCAT()
i have two tables
td_sell
|----------|----------------|------------------|
| id | user_id | price |
|----------------------------------------------|
| 1 | 2 | 10 |
|----------------------------------------------|
| 2 | 1 | 5 |
|----------------------------------------------|
| 3 | 2 | 3 |
|----------------------------------------------|
and td_commsion
|----------|----------------|------------------|
| id | user_id | price |
|----------------------------------------------|
| 1 | 1 | 3 |
|----------------------------------------------|
| 2 | 1 | 5 |
|----------------------------------------------|
| 3 | 2 | 3 |
|----------------------------------------------|
now i want a sql query like this
SELECT (SUM(td_sell.price) + SUM(td_comission.price)) AS his_earning
FROM td_sell, td_comission
WHERE td_sell.user_id='1'
AND td_comission.user_id='1'
but its showing abnormal result
the result should be 13, but its showing 29
This will work:
SELECT (SELECT SUM(s.price) FROM td_sell s WHERE s.user_id = 1)
+
(SELECT SUM(c.price) FROM td_comission c WHERE c.user_id = 1)
DEMO: SqlFiddle
You are getting the sum of the Cartesian join of the two tables.
http://en.wikipedia.org/wiki/Cartesian_product
SELECT sum(price)
FROM (
SELECT * FROM td_sell
UNION ALL
SELECT * FROM td_commission
) a
where a.user_id=1
Here's a SQL Fiddle:
Fiddle
You need to do the sum separately on each table, before combining the results. Here is one way:
select (sell + commission) as his_earning
from (select SUM(td_sell.price) as sell
from td_sell
where td_sell.user_id='1'
) s cross join
(select SUM(td_comission.price) as commission
from td_comission
where td_comission.user_id='1'
) c
I have a table like this:
| id | date | user_id |
----------------------------------------------------
| 1 | 2008-01-01 | 10 |
| 2 | 2009-03-20 | 15 |
| 3 | 2008-06-11 | 10 |
| 4 | 2009-01-21 | 15 |
| 5 | 2010-01-01 | 10 |
| 6 | 2011-06-01 | 10 |
| 7 | 2012-01-01 | 10 |
| 8 | 2008-05-01 | 15 |
I’m looking for a solution how to select user_id where the difference between MIN and MAX dates is more than 3 yrs. For the above data I should get:
| user_id |
-----------------------
| 10 |
Anyone can help?
SELECT user_id
FROM mytable
GROUP BY user_id
HAVING MAX(`date`) > (MIN(`date`) + INTERVAL '3' YEAR);
Tested here: http://sqlize.com/MC0618Yg58
Similar to bernie's approach, I'd keep date formats native. I'd also probably list the MAX first as to avoid an ABS call (secure a positive number is always returned).
SELECT user_id
FROM my_table
WHERE DATEDIFF(MAX(date),MIN(date)) > 365
DATEDIFF just returns delta (in days) between two given date fields.
SELECT user_id
FROM (SELECT user_id, MIN(date) m0, MAX(date) m1
FROM table
GROUP by user_id)
HAVING EXTRACT(YEAR FROM m1) - EXTRACT(YEAR FROM m0) > 3
SELECT A.USER_ID FROM TABLE AS A
JOIN TABLE AS B
ON A.USER_ID = B.USER_ID
WHERE DATEDIFF(A.DATE,B.DATE) > 365