I have a MySQL update script I'd like to run from the command line, but I want to be able to pass a stage domain variable to the script.
I know this won't work, but it's the best way I can describe what I'm trying to do:
$ -uroot -hlocalhost mydatabase --execute "SET #domain = 'mydomain.dev' " < ./sql/update_domain.sql
Inside the script, I'm using the #domain variable, to update some configuration variables in a config table, using commands like this:
UPDATE my_cfg SET value = #domain WHERE name = 'DOMAIN';
Basically I want to prefix the SET #domain on the update_domain.sql file.
Any ideas how I can rectify my approach?
In your BATCH File :
mysql -e "set #domain=PARAMVALUE;source ./sql/update_domain.sql"
And in you SQL file :
UPDATE my_cfg SET value = #domain WHERE name = 'DOMAIN';
you can do that with sed like this:
echo "UPDATE my_cfg SET value = '#domain#' WHERE name = 'DOMAIN'" | sed 's/#domain#/mydomain.dev/' | mysql -uusername -ppassword dbname
or update.sql has UPDATE:
cat update.sql | sed 's/#domain#/mydomain.dev/' | mysql -uusername -ppassword dbname
This works for me:
system("(echo \"SET #domain = 'newstore.personera.abc';\"; cat sql/set_domain.sql) > /tmp/_tmp.sql")
system("mysql -uroot -hlocalhost newstore.personera.dev < /tmp/_tmp.sql")
system("rm /tmp/_tmp.sql")
...calling with system() from Capistrano.
I've found a better solution.
--init-command=name SQL Command to execute when connecting to MariaDB server.
mysql --init-command="SET #foo = 1; SET #bar = 2" -e "SELECT #foo, #bar, VERSION()"
Output:
+------+------+-------------------------------------+
| #foo | #bar | VERSION() |
+------+------+-------------------------------------+
| 1 | 2 | 10.6.3-MariaDB-1:10.6.3+maria~focal |
+------+------+-------------------------------------+
It also works with file redirection.
Related
I am trying to check if a MYSQL user exists. This is as far as I have got. I fall down on capturing the answer from the output.
#!/bin/bash
echo -e "What is the MYSQL username called"
read DBUSER
if [ -z "$DBUSER" ]
then
exit
mysql -uUSER -pPASS -e "SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER')";
if
yes
do this
else
do this
this is the output I am getting
+-----------------------------------------------------+
| EXISTS(SELECT 1 FROM mysql.user WHERE user = 'bob') |
+-----------------------------------------------------+
| 1 |
+-----------------------------------------------------+
Can any one help please
Thanks very much for your help. Here is the final result working.
It needs the -sse
RESULT_VARIABLE="$(mysql -uUSER -pPASS -sse "SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER')")"
if [ "$RESULT_VARIABLE" = 1 ]; then
echo "TRUE"
else
echo "FALSE"
fi
Assigning the result to a variable can be done like this:
RESULT_VARIABLE="$(mysql -uUSER -pPASS -se "SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER')")"
And you can also alias a column in MySQL, btw.
SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER') AS does_it_exist
I have a linux script that gets a variable and I store it to var JOB_EXEC_ID
I am trying to pass the value of this to a MySQL query
Here is MySQL query set-up
print "JOB EXEC ID value for DataMeer Job ${LOADJOB} is : ${JobExecId} " |
tee -a ${LOGDIR}/${LOGFILE}
#Log on to MySQL to get the DataId
#Remove first the output file that would house the dataid
rm -f ${SCRDIR}/list_dataid.csv
mysql -u root -pmonday1 ${DAPDBNAME} < ${SCRDIR}/dataid_query.nosql
SQLRTN=$?
if [[ ${SQLRTN} != 0 ]]
then
print "Return code from sqlcall - DAP : ${SQLRTN}" |
tee -a ${LOGDIR}/${LOGFILE}
print "Exiting $Script - 55 " |
tee -a ${LOGDIR}/${LOGFILE}
exit 55
fi
The file dataid_query.nosql looks like this:
set #job_exec_id=10151
select d.id DataId
from data d inner join dap_job_configuration djc on d.dap_job_configuration__id = djc.id
left outer join dap_job_execution dje on djc.id = dje.dap_job_configuration__id and dje.created_data__id = d.id
where dje.id=#job_exec_id
into OUTFILE "/home/app1ebb/cs/list_dataid.csv"
I want to pass the value of JOB_EXEC_ID to the set command that is currently hardcoded right now with a value of 10151
in place of
mysql -u root -pmonday1 ${DAPDBNAME} < ${SCRDIR}/dataid_query.nosql
SQLRTN=$?
this lines
sed "1 s/[0-9]*$/${JOB_EXEC_ID}/" > /tmp/dataid_query.nosql
mysql -u root -pmonday1 ${DAPDBNAME} < /tmp/dataid_query.nosql
SQLRTN=$?
rm /tmp/dataid_query.nosql
This is the normal output:
mysql> select module_id from Modules where Module_name = 'STP_XENA';
+-----------+
| module_id |
+-----------+
| 3 |
+-----------+
1 row in set (0.00 sec)
Can I get answer for the query as only "3"
I need something like,
mysql> select module_id from Modules where Module_name = 'STP_XENA';
3
mysql>
But not from bash or console. Is there any option to do this ?
You cannot do it inside MySQL editor, AFAIK. If you execute the script from console, then adding -B switch can get you desired result.
> mysql -B -u username -p password -e "select module_id from Modules where Module_name = 'STP_XENA';" DBNAME
will yield value with column name:
module_id
3
Also, if you add --skip-column-names
> mysql -B --skip-column-names -u username -p password -e "select module_id from Modules where Module_name = 'STP_XENA';" DBNAME
will yield only value (minus column name):
3
HTH
EDIT: You may start mysql with --skip-column-names switch. I am not sure about -B though. If you are able to start with -B, then great.
You want to use the query result in something like a bash script?
If so, you could do with:
mysql -u{user} -p{password} -s -N -e "select module_id from Modules where Module_name = 'STP_XENA'" database_name
Example:
module_id = `mysql -u{user} -p{password} -s -N -e "select module_id from Modules where Module_name = 'STP_XENA'" database_name`
echo $module_id
My Bash script makes an array from MySQL:
info_tmp=$(mysql --batch --silent -u root -ppassword database -e "SELECT id,info1,info2 FROM table WHERE id=1")
info=($(for i in $info_tmp;do echo $i;done))
info1=${info[1]}
My problem is, that, if info1 is an empty string in the database, then $info1 became info2.
How can I put an empty string into $info array?
Mysql Database:
Id | info1 | info2
1 | | data2
2 | data3 | data4
$info_tmp
1 data2
2 data3 data4
Thank you for your answer
This is the final code that worked (#Barmar):
IFS="|"
info_tmp=$(mysql --batch --silent -u root -ppassword database -e "SELECT CONCAT_WS('|', id,info1,info2) FROM table WHERE id=1")
info=(${info_tmp// / })
info1=${info[1]}
If there's a character that shouldn't appear in any of the columns, use that as a delimiter.
IFS="|"
info_tmp=$(mysql --batch --silent -u root -ppassword database -e "SELECT CONCAT_WS('|', id,info1,info2) FROM table WHERE id=1")
This works because bash doesn't merge sequences of non-whitespace delimiters in IFS, only whitespace characters.
I'm not sure what the point of the for loop that copies $info_tmp to $info is, but you need to do the same thing there. If you use whitespace as your word delimiter, you'll never be able to get empty array values from command substitution.
What about temporarily adding a single character in your for-loop:
info_tmp=$(mysql --batch --silent -u root -ppassword database -e "SELECT id,info1,info2 FROM table WHERE id=1")
info=($(for i in $info_tmp;do echo " "$i;done))
info1=$(${info[1]} | cut -c 2-)
Im new in bash scripting.
I want to save sql-query outputs in variable, but
actually I must connect for every query to mysql with:
mysql -u $MYUSER -p$MYPASS -D database
and want to save every output in seperatly variable
sample query is: SELECT domain FROM domains WHERE user='$USER'
to
$variable1 = FIRST_OUTPUT
$variable2 = 2ND_OUTPUT
thank you
Taken from bash script - select from database into variable, you can read the query result into a variable.
Example
mysql> SELECT * FROM domains;
+-------+---------+
| user | domain |
+-------+---------+
| user1 | domain1 |
| user2 | domain2 |
| user3 | domain3 |
+-------+---------+
Usage
$ myvar=$(mysql -D$MYDB -u$MYUSER -p$MYPASS -se "SELECT domain FROM domains")
$ echo $myvar
domain1 domain2 domain3
echo is the bash command for output. You can then split $myvar into separate variables:
$ read var1 var2 var3 <<< $myvar
$ echo $var1
domain1
$ echo $var2
domain2
You can combine these two commands into a single one:
read var1 var2 var3 <<< $(mysql -D$MYDB -u$MYUSER -p$MYPASS -se "SELECT domain FROM domains")
It is possible to store the results into arrays (useful if you don't know how many records there):
$ read -ra vars <<< $(mysql -D$MYDB -u$MYUSER -p$MYPASS -se "SELECT domain FROM domains")
$ for i in "${vars[#]}"; do
$ echo $i
$ done
domain1
domain2
domain3
Another way of doing is:
dbquery=`mysql -D$MYDB -u$MYUSER -p$MYPASS -se "SELECT domain FROM domains"`
dbquery_array=( $( for i in $dbquery ; do echo $i ; done ) )
The first line stores all the output from the query in a varriable dbquery in a array-like-way. The second line converts the dbquery into an array dbquery_array with a simple for loop.
I did this
variable=mysql -u root -ppassworrd database << EOF
select MAX(variable) AS a from table where variable2 = 'SOMETEXT' AND day(datevalue) >= 22;
EOF
I hope it helps