I have an hourglass like vector shape and I'd like to use it to mask an image. I'd like to feather the edges - have a soft falloff in transparency that follows the contours of the hour glass. Any ideas how I can do this?
I tried using a gradient fill on a closed shape (using beginGradientFill() and curveTo() functions) but that falloff doesn't follow the contour of the vector shape, it can only go one direction.
Maybe there is a better solution but until somebody comes up with it... I assume you could do the following:
Draw whatever shape you want to use as mask into a transparent bitmap.
Scale a bit the bitmap down (or use a matrix while drawing its bitmapdata).
Apply a blur filter to it.
Put the bitmap's center to the masked clip's center so they are aligned.
Set the masked clip's cacheAsBitmap property to true.
Related
I have a bit problem with rotationX and rotationY.
It's cool if i just do a roationX and rotaionY below
_eventParent.rotationY =_differentX;
_eventParent.rotationX =_differentY;
However once i have assign a mouse move to the _eventParent. The roationX and roationY change perspectively while the mouse is moving. so instead the item remain the same size. it increase and decrease size prospectively. any idea why is it doing this? is there a possibility to stop this behavior?
Thanks
Please find the image below.
Perspective allows part of your shape to look closer to you than other parts. The problem is that perspective has a center, or "vanishing point" and by default, it is fixed. As you move your shape farther away from the vanishing point, the perspective changes, causing your shape to widen or narrow.
You can fix this by updating the vanishing point so that it is always at the same coordinates as your shape. Since the shape will always be at the vanishing point, the perspective shouldn't change.
To do this, create a perspectiveProjection for your shape:
_eventParent.transform.perspectiveProjection = new PerspectiveProjection();
PerspectiveProjection is located in the flash.geom package, so don't forget to import it.
Then whenever you update your shape's position, update it's vanishing point:
_eventParent.transform.perspectiveProjection.projectionCenter =
new Point(_eventParent.x, _eventParent.y);
You might need to offset the vanishing point by a set number of pixels to get the perspective looking the way you want it to.
Correct me if I misunderstood your question. Your question is that if you apply rotation to the movieClip object, then why does the size appear to be changing?
For simplification, Let's not apply rotation on both X and Y axis. Let's take a rectangular movie clip and onMouseMove we do ++myMovieClip.rotationX;
Now, this statement is going to apply rotation on the object about the X-axis and one would get a perspective of the movie clip flipping across X -axis and this flipping will show as change in size of the object.
The same applies to rotating across y-axis.
I am trying to understand masks in actionscript..Everything seems to make sense to me but one part of the code
function mouseM(event:MouseEvent):void {
if (mouseclick == 1) {
mask_mc.graphics.beginFill(0x000000);
mask_mc.graphics.drawEllipse(mouseX, mouseY, 70, 60);
mask_mc.graphics.endFill();
}
}
I am not sure how to exactly ask this question but here it goes. why does the mask have "begin fill" with a black color? wouldn't that paint the the image in black (I know it doesn't, it just reveals it)? what is the exact function of beginfill (besides revealing the image lool)? like how does it exactly work? sorry if it sounds ridiculously off.. but that part of the code was really screwing me up in understanding masks
What you are doing is drawing a shape to be used as a mask. In this case, a circle.
It doesn't matter what colour it is as Flash is only interested in the shape of the mask, not the colour.
Once the circle is drawn, Flash checks what part of the circle overlap the object you're masking so that every pixel the circle is not covering will be invisible. I guess it should really be called an anti-mask as the circle dictates which parts of your image wont be masked but it's just become the general convention to call the circle (or whatever shape you use) the mask.
Again, you're just creating a shape to be used as a mask. Setting the colour is just so the object can essentially exist.. because you can't exactly have a transparent circle.
Feel free to change the colour to anything and you'll see it makes no difference, the shape is all that matters.
I need to place a transparent sprite over another sprite. The overlaying sprite will acept some mouse events. When a user move mouse over upper sprite a curve will be drawn. After it'll be processed it will be drawn on the base sprite (and erased on upper).
The idea I have now is to place the sprite, draw a rectange of size equal to sizes of sprite and set alpha to 0.
The question is a bit dump: maybe the proposed solution is not the best. Is there a better way to set width and height (as far a I understand Sprite.width = w; will not help)?
Thank you in advance!
You can't set dimensions directly, while you can draw over that Sprite. So you can do like this:
graphics.beginFill(0,0); // zero alpha fill
graphics.lineStyle(0,0,0); // invisible lines
graphics.drawRect(0,0,width,height);
graphics.endFill();
This way your Sprite can have its alpha remaining at 1, to not hide anything that's its child. Then, whatever curve you would decide to draw in that Sprite, you can draw within a child Shape object, via graphics.moveTo and graphics.lineTo.
UPDATE: According to comments below, setting alpha to 0 won't work with newer Flash player versions, so alpha should be set to a nonzero amount for the events to register on the overlapping sprite.
graphics.beginFill(0x808080,0.01); // almost zero alpha fill
I have a BitmapData object named myBitmapData. It was loaded of PNG of size 104x104. This PNG represents a red circle on the transparent background.
There is also a Sprite object named myBackground. I want render that red circle into myBackground.
myBackground.graphics.beginBitmapFill(myBitmapData);
myBackground.graphics.drawRect(0, 0, myBitmapData.width, myBitmapData.height);
myBackground.graphics.endFill();
addChild(myBackground);
Everything is fine. I see a red circle in the left top of myBackground.
But when I change the third line to
myBackground.graphics.drawRect(0, 52, myBitmapData.width, myBitmapData.height);
and expect my circle to be translated 52 pixels down, I actually obtain something strange (for me :)): there are two red half-circles (they form like hourglass).
So, the question is: how do I render myBitmapData into the random position of myBackground?
P.S.
In the case of
myBackground.graphics.drawRect(0, 104, myBitmapData.width, myBitmapData.height);
it is circle again :)
This is caused by beginBitmapFill's default repeat = true parameter. There's an example in the docs. Disabling the repetition won't work though, you'd just get a half circle then.
There are several ways to fix this:
Use a Matrix with a translation (displacement) as argument in beginBitmapFill.
Draw the rectangle at 0,0 on another Sprite, and move that sprite to where you want it on the background.
Don't draw directly to the background, but to another bitmap using copyPixels. Then fill the background with that bitmap.
I'm trying to code a 3d wall like
http://www.flashloaded.com/flashcomponents/3dwall/
The shape I am looking to create is like a bath or arena where it is a curve cornered rectangle with sloping sides.
The image below shows what i'm trying to achieve if viewed from above. I hope that helps.
Can anyone give me some ideas on the maths to create this shape using primitive rectangle shapes.
Thanks,
Josh
http://en.wikipedia.org/wiki/Matrix_multiplication
http://en.wikipedia.org/wiki/Transformation_matrix
http://www.devmaster.net/wiki/Transformation_matrices
A rectangle has 4 3D points (vectors)
Define a vector this way
To move/rotate/scale just multiply each vector by the transformation matrix.
This matrix rotates around X-axis:
For perpective projection (camera) look at: http://en.wikipedia.org/wiki/3D_projection
For example: you can create rectangles and rotate them around an axis to create a cylinder like this:
(source: flashloaded.com)
your pit:
note: the angle is not correct, it should be pi-a (180ยบ-a)
create all rectangles centered at origin (0,0,0), then rotate them as needed and move to desired position. I recommend you to code the matrix routines first like rotate(), move(), scale() and a simple paint function (just line drawing, without perspective) the rest is just playing with the matrices.