MYSQL get count of each column where it equals a specific value - mysql

Question

I recently set up a MYSQL database connected to a form filled with checkboxes. If the checkbox was selected, it would insert into the associated column a value of '1'; otherwise, it would receive a value of '0'.
I'd like to eventually look at aggregate data from this form, and was wondering if there was any way I could use MYSQL to get a number for each column which would be equal to the number of rows that had a value of '1'.
I've tried variations of:
select count(*) from POLLDATA group by column_name
which was unsuccessful, and nothing else I can think of seems to make sense (admittedly, I'm not all too experienced in SQL).
I'd really like to avoid:
select count(*) from POLLDATA where column_1='1'
for each column (there close to 100 of them).
Is there any way to do this besides typing out a select count(*) statement for each column?
EDIT:
If it helps, the columns are 'artist1', 'artist2', ....'artist88', 'gender', 'age', 'city', 'state'. As I tried to explain below, I was hoping that I'd be able to do something like:
select sum(EACH_COLUMN) from POLLDATA where gender='Male', city='New York City';
(obviously EACH_COLUMN is bogus)

Answer 1

SELECT SUM(CASE
WHEN t.your_column = '1' THEN 1
ELSE 0
END) AS OneCount,
SUM(CASE
WHEN t.your_column='0' THEN 1
ELSE 0
END) AS ZeroCount
FROM YOUR_TABLE t

Answer 2

If you are just looking for the sheer number of 1's in the columns, you could try…
select sum(col1), sum(col2), sum(col3) from POLLDATA

Answer 3

A slightly more compact notation is SUM( IF( expression ) ).
For the askers example, this could look something like:
select
count(*) as total,
sum(if(gender = 'MALE', 1, 0)) as males,
sum(if(gender = 'FEMALE', 1, 0)) as females,
sum(if(city = 'New York City', 1, 0)) as newYorkResidents
from POLLDATA;
Example result:
+-------+-------+---------+------------------+
| total | males | females | newYorkResidents |
+-------+-------+---------+------------------+
| 42 | 23 | 19 | 42 |
+-------+-------+---------+------------------+

Answer 4

select count(*) from POLLDATA group by column_name
I dont think you want to do a count cause this will also count the records with a 0.
try
select column_naam,sum(column_name) from POLLDATA group by column_name
or
select column_naam,count(*) from POLLDATA
where column_name <> 0
group by column_name
only adds the 0

Answer 5

Instead of strings why not store actual numbers, 1 or 0.
Then you could use the sql SUM function.

Answer 6

When the query begins to be a little too complicated, maybe it's because you should think again about your database structure. But if you want to keep your table as it is, you could use a prepared statement that automatically calculates all the sums for you, without specifying every single column:
SELECT
CONCAT(
'SELECT ',
GROUP_CONCAT(CONCAT('SUM(', `column_name`, ') AS sum_', `column_name`)),
' FROM POLLDATA WHERE gender=? AND city=?')
FROM `information_schema`.`columns`
WHERE `table_schema`=DATABASE()
AND `table_name`='POLLDATA'
AND `column_name` LIKE 'artist%'
INTO #sql;
SET #gender := 'male';
SET #city := 'New York';
PREPARE stmt FROM #sql;
EXECUTE stmt USING #gender, #city;
Please see fiddle here.