Need to Optimise the following MySQL query - mysql

I've tried this query successfully with a limit. The following query runs endless without limit:
SELECT o.product_sku
FROM order_table o
WHERE EXISTS (SELECT 1
FROM (SELECT DISTINCT u.type_id,
u.charge_type,
u.billed_weight
FROM ups_table u
WHERE charge_type = 'order_shipping_table'
AND NOT billed_weight = '0'
) dtm
WHERE o.order_id = dtm.type_id)
GROUP BY product_sku
HAVING Count(product_sku) > 1

First of all you don't need these subqueries with DISTINCT and so on:
SELECT o.product_sku
FROM order_table o
WHERE EXISTS (SELECT 1
FROM ups_table u
WHERE charge_type = 'order_shipping_table'
AND NOT billed_weight = '0'
AND type_id=o.order_id
)
GROUP BY product_sku
HAVING Count(product_sku) > 1
I don't know your table structure (what do you want to count in the HAVING?) but you can try to change EXISTS to JOIN:
SELECT o.product_sku
FROM order_table o
JOIN ups_table u on (u.type_id=o.order_id)
AND (u.charge_type = 'order_shipping_table')
AND NOT (billed_weight = '0')
GROUP BY product_sku
HAVING Count(DISTINCT o.order_id) > 1
And you need indexes on o.order_id, o.product_sku, u.type_id,u.charge_type, u.billed_weight

Related

Subquery and Filter Eloquent Laravel using Yajra Datatables

I want to view bonus recapitulation from transaction and i try write code in phpmyadmin like
SELECT
tbl2.name, b.nama_bonus,
SUM(
CASE
WHEN b.nama_bonus REGEXP 'saldo' THEN tbl2.jumlah_transaksi * b.nominal_bonus
WHEN b.nama_bonus REGEXP 'bintang' AND tbl2.nama_kategori REGEXP 'transfer' THEN FLOOR(tbl2.total_nominal_transaksi / b.keterangan_bonus)
ELSE FLOOR(tbl2.total_nominal_transaksi / b.keterangan_bonus)
END
) AS bonus_member
FROM
(
SELECT tbl1.*, u.name, pc.nama_kategori, COUNT(tbl1.nominal_transaksi) AS jumlah_transaksi, SUM(tbl1.nominal_transaksi) AS total_nominal_transaksi FROM
(
SELECT no_invoice, product_category_id, nominal_transaksi, user_id, status_transaksi_id FROM transactions
WHERE status_transaksi_id = 1
) AS tbl1
JOIN users u ON u.id = tbl1.user_id
JOIN product_categories pc ON pc.id = tbl1.product_category_id
GROUP BY u.id, pc.id
) AS tbl2
JOIN bonus b ON b.product_category_id = tbl2.product_category_id
GROUP BY b.nama_bonus, tbl2.name
ORDER BY tbl2.name
And the result is result query image
how to implement mysql code with eloquent using yajra datatables and also filter the data?

Convert Subquery with ORDER BY in 'ON' clause to Join for optimization

I have this query:
SELECT prod.ProductID, prod.Name, prod.ProdExtID, ls.ProdServiceID
FROM Products prod
LEFT JOIN ProductServices ls ON ls.ProdServiceID=(SELECT ProdServiceID FROM
ProductServices WHERE ProductID=prod.ProductID ORDER BY Modified DESC LIMIT
1) ;
This query returns 175 rows
I want to convert this to JOIN.
I used below query:
SELECT prod.ProductID, prod.Name, prod.ProdExtID, ls1.ProductServicesID
FROM Products prod
inner join ProductServices ls on ls.ProductID=prod.ProductID
inner JOIN (SELECT ProductServicesID, ProductID, max(Modified) as Modified
FROM
ProductServices group by Modified) as ls1 ON ls.ProductServicesID =
ls1.ProductServicesID and ls.Modified = ls1.Modified and ls.ProductID =
ls1.ProductID;
which doesn't return correct result. Can I get some direction on this.
The purpose is to optimize the query. Would it be good idea to use join in place of original query.
Thanks!
Try this:
SELECT ProductID
, Name
, ProdExtID
, ProdServiceID
FROM
(
SELECT prod.ProductID
, prod.Name
, prod.ProdExtID
, ls.ProdServiceID
, RANK() OVER(PARTITION BY ls.ProdServiceID ORDER BY ls.Modified DESC) AS rnk
FROM Products prod
LEFT JOIN ProductServices ls ON ls.ProductID=prod.ProductID
) x
WHERE rnk = 1
So basically: your join needs to be on ProductID but you only want the most recent ProdServiceID, right?
try this select query please.
Here you get the serviceid which corresponds to productid and the last modiied
SELECT prod.ProductID, prod.Name, prod.ProdExtID, ls.ProdServiceID
FROM Products prod
LEft join ProductServices ls on ls.ProductID=prod.ProductID
inner JOIN (SELECT ProductID, max(Modified) as Modified
FROM
ProductServices group by ProductID) as ls1 ON ls.ProductID =
ls1.ProductID and ls.Modified = ls1.Modified;

Join with Max and pre-Max row

I have two tables 'sites' and 'index_log'. Table 'sites' is a information about sites(userid, name, description ...) Table index_log have columns date, index_count and siteid. So I want to get last and previous index_log row for each site, where userid = 10. This's my variant:
SELECT ff.id,
ff.siteurl,
ff.last_count,
ff.last_date,
il2.index_count as previous_count,
MAX(il2.date) as previous_date
FROM (
SELECT s.siteurl,
s.id,
il.index_count as last_count,
MAX(il.date) as last_date
FROM sites s
LEFT JOIN index_logs il ON il.siteid = s.id
WHERE s.userid = 10
GROUP BY s.id
) as ff
LEFT JOIN index_logs il2 ON il2.siteid = ff.id AND il2.date < ff.last_date
GROUP BY ff.id
But in this variant index_count column(last and previous) do not match with max date row. I hope for your help.
this will gives you last 2 log entries per sites.id
; with CTE as
(
SELECT s.siteurl, s.id, il.index_count, il.date,
RN = ROW_NUMBER() OVER (PARTITION BY s.id ORDER BY il.date DESC)
FROM sites s
JOIN index_logs il ON il.siteid = s.id
WHERE s.userid = 10
)
SELECT *
FROM CTE
WHERE RN <= 2

MySQL use inner query in where clause

I have wrote the following SQL:
SELECT s.*, (SELECT COUNT(*) FROM orders o WHERE o.schedule_id = s.schedule_id AND o.content_id = s.content_id) as numofbookings
FROM schedules s
WHERE content_id = '{$contentid}'
AND DATEDIFF(`schedule_datetime_from`, now()) > 0
AND (SELECT COUNT(*) FROM orders o WHERE o.schedule_id = s.schedule_id AND o.content_id = s.content_id) < s.schedule_capacity
ORDER BY `s`.`schedule_datetime_from` ASC
Although I am concerned this could be wrote better without querying the orders table twice.
I tried AND numofbookings < s.schedule_capacity although this give error column not found.
SELECT s.*, COUNT(o.schedule_id) AS numofbookings
FROM schedules s
LEFT JOIN orders o
ON s.schedule_id = o.schedule_id
AND s.content_id = o.content_id
WHERE s.content_id = '{$contentid}'
AND DATEDIFF(s.schedule_datetime_from, now()) > 0
GROUP BY s.schedule_id, s.content_id
HAVING COUNT(o.schedule_id) < s.schedule_capacity
ORDER BY s.schedule_datetime_from ASC

Some sort of join statement?

How do I put these two queries into a single query?
select count(id) as cnt from {$site_id}.proofingv2_packages where active='1'
select count(id) as cnt from {$site_id}.proofingv2_package_options where active='1' and parent={$row["id"]} order by sort
$row['id'] is the id field from the first query. I am trying to determine if there are any valid packages. A valid package must be active and have at least 1 active option. Running 2 queries for this doesn't seem right.
Can anyone help?
select count(id) as cnt from
{$site_id}.proofingv2_packages pp
INNER JOIN
{$site_id}.proofingv2_package_options
pt ON pp.active = pt.Active AND
pp.Active = 1
if the id is the PK or FK on the same on both tables use this query
select count(id) as cnt from
{$site_id}.proofingv2_packages pp
INNER JOIN {$site_id}.proofingv2_package_options pt ON pp.id= pt.id
AND pp.Active = 1
SELECT IF(count(*) > 0, 1, 0) AS isValid
FROM {$site_id}.proofingv2_packages pp
INNER JOIN {$site_id}.proofingv2_package_options ppo ON ppo.parent = pp.id
WHERE pp.active = '1'
AND ppo.active = '1'
This should return 1 if there are valid packages or 0 if not