I have this query, which spits out that I have an error in syntax. I cannot for the life of me understand what it is. I have a table, where one column is email and the other is subscribed (the latter of which is a boolean using tinyint). Any idea what's wrong with this syntax?
$query = "UPDATE $DB_TABLE SET $DB_IS_SUBSCRIBED_KEY = 0 WHERE $DB_EMAIL_KEY = $email";
Your email value needs to be wrapped in quotes.
UPDATE tablename SET columname = 1 WHERE emailcolumn = "email#email.com"
Related
Previously, this was working:
$patient_story_set_photos = $wpdb->get_results('SELECT * FROM wp_before_after WHERE patientID = '.$post->ID.' AND patient_display = 1');
However, when I try to add another AND condition like this:
$patient_story_set_photos = $wpdb->get_results('SELECT * FROM wp_before_after WHERE patientID = '.$post->ID.' AND patient_display = 1 AND period_taken = '.$set->period_taken);
I get the following error on screen:
WordPress database error: [Unknown column '1hour' in 'where clause']
SELECT * FROM wp_before_after WHERE patientID = 8175 AND patient_display = 1 AND period_taken = 1hour
Can't see why there's a problem, are you not allowed to use multiple AND conditions in SQL?
The problem is not the AND, the problem is your 1hour, 1hour unquoted means a reference to an object (database, table) named 1hour, you need to quote '1hour'.
If you write
SELECT * FROM wp_before_after
WHERE patientID = 8175
AND patient_display = 1
AND period_taken = '1hour'
you will compare the field periodtaken to a string (CHAR,VARCHAR,TEXT) equal to '1hour'.
I assume period_taken is a field typed CHAR,VARCHAR or TEXT
Before anything, DO NOT CONCATENATE SQL STRINGS nowadays it is a MUST (see how to do it properly https://stackoverflow.com/a/60496/3771219)
The problem you are facing is because, I presume, that the period_taken field is some sort of Char/Varchar/String field and when you are filtering by a "Stringy" field you must sorround your literals values with single quotes:
SELECT *
FROM wp_before_after
WHERE patientID = 8175
AND patient_display = 1
AND period_taken = '1hour'
Hope this help
I am trying to update mysql table MYTABLE using two value. One is STAR column which should be incremented by one on each query, and the second one is COMMENT column which should be concatenated with existing one on each time and separated by comma.
Below is the command I used, but not working.
$query = "update MYTABLE set STAR=STAR+1,COMMENT= CONCAT(COMMENT, ','.$comment) where ID='$id'";
$query = "update MYTABLE set STAR=STAR+1,COMMENT = CONCAT(COMMENT, ',', '$comment') where ID=$id";
where ID='$id'
is incorrect because $id might be a number, so, delete the "'".
Have you escaped the $comment variable ?
Otherwise you may use prepared statements with PDO :)
I hope you're using PDO...
you should but string in '' and update your query, it has error syntax :
$query = "update MYTABLE set STAR=STAR+1,COMMENT= CONCAT(COMMENT, '$comment') where ID='$id'";
To make it more secure, just use following code...
$query = "update MYTABLE
set `STAR` = `STAR`+1,
`COMMENT`= CONCAT(COMMENT, '$comment')
where `ID`='$id'";
Happy Coding...
String sql = ("insert into registration(pic) values(?) where email='"+Email+"' ");
i get error :error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where email='yyy#ymail.com'' at line 1
You have to use UPDATE query to pass it like
String sql = "UPDATE registration SET pic = ? WHERE email = '" + Email + "'";
Syntax for UPDATE query is
UPDATE table_name SET column_name = value;
Insert query format should be,
"insert into tablename (columnname) values(coulmnvalue)"
OR
"update registration set pic='' where email='"+Email+"'";
Yes. that is impossible.
Either you want:
insert into registration(pic) values(?)
Which will give you a new row;
Or you want an UPDATE:
UPDATE registration SET pic = ?
WHERE email = <EMAILYouWant>
Which will update an existing row where email = the record with the email you want to update the pic column.
I'm having a problem in retrieving last record id from database. This code below, is the closer I can get. But still, it return record id, as 0; ,then when I execute again, it will return, record of previous execute, not the current one.
sql = "insert into program (prog_det,budget,prog_obj,outcome,target_group,awareness,engagement,issue,seq_no) value ('"&prog_title&"','"&prog_budget&"','"&prog_obj&"','"&prog_result&"','"&prog_target&"','"&prog_aware&"','"&prog_involment&"','"&prog_issues&"','99');"
sql2 = "select last_insert_id() as last_id"
set kpi_prog_conn=Server.CreateObject("ADODB.Connection")
set kpi_prog_rs=Server.CreateObject("ADODB.Recordset")
kpi_prog_conn.Open ObjConn
kpi_prog_conn.Execute(sql)
kpi_prog_conn.Open sql2,objConn,adLockPessimistic
response.write kpi_prog_rs("last_id")
Your penultimate line looks wrong
Try
kpi_prog_rs.Open sql2,kpi_prog_conn,adLockPessimistic
IS the ID you are trying to retrieve is the Primary key of the corresponding table? Try using Scope_Identity() instead of last_insert_id()
Query - SELECT SCOPE_IDENTITY() AS [LAST_IDENTITY]
It returns you the last inserted id into the table
I don't have mysql but try:
sql2 = "select last_insert_id() as last_id;"
sql = "insert into program (prog_det,budget,prog_obj,outcome,target_group,awareness,engagement,issue,seq_no) value ('"&prog_title&"','"&prog_budget&"','"&prog_obj&"','"&prog_result&"','"&prog_target&"','"&prog_aware&"','"&prog_involment&"','"&prog_issues&"','99');" & sql2
set kpi_prog_conn=Server.CreateObject("ADODB.Connection")
kpi_prog_conn.Open ObjConn
set kpi_prog_rs = kpi_prog_conn.Execute(sql)
anotherRecordset = kpi_prog_rs.NextRecordset
response.write anotherRecordset("last_id")
I have a table with 27 varchar fields. I want to make all fields lowercase, but i want to do it in one short mysql call.
This does a single field:
UPDATE table
SET field = LOWER(field)
How do I do the equivalent of this (which doesn't work):
UPDATE table
SET * = LOWER(*)
You can't do it with your creative attempt SET * = LOWER(*) etc.
You can however do it like this:
UPDATE table SET
column1 = LOWER(column1),
column2 = LOWER(column2),
-- etc, listing all text type columns
columnN = LOWER(columnN);
The reason there's no "shortcut" is probably because this pattern is so infrequently needed.
The consensus is that this cannot be done in a single mysql query.
Here is a super quick PHP script that does this for N fields (thanks for the idea #alex):
$sql = "SHOW COLUMNS
FROM table";
$results = mysqli_query($dbcon,$sql);
while($column = mysqli_fetch_assoc($results))
{
$column = $column["Field"];
$sql = "UPDATE table
SET $column = LOWER($column)";
$success = mysqli_query($dbcon,$sql);
}